Select from last ID and older than it by 25 [MySQL] - php

I have posts which has fields (ID,title,date) What I'm looking for it to select rows order by date desc just limit for 25 records
lets say if we run that one it will show the last row with ID (600) like this:
(600,601,602,.....,625)
so I want after that to select another 25 records but min(id) before the last one (600) so it will be like this
(575,576,577,.....,599)

For example consider that the first result gives the descending last five IDs.
SELECT idprocess FROM process ORDER BY idprocess DESC LIMIT 5
248034
248033
248032
248031
248030
You could use a SELECT into a temporary table to mess with your result set's ORDER BY and LIMIT. The sub-query LIMIT should be the sum of the records you want back and how many you want skipped off the end.
SELECT t1.idprocess FROM
(SELECT idprocess FROM process ORDER BY idprocess DESC LIMIT 10) AS t1
ORDER BY idprocess ASC LIMIT 5
248025
248026
248027
248028
248029

Related

PHP - Select random row from table

My table has around 10k rows. How can I query select 1 random row of the last 10 added rows? I have a date column that is datetime of when the row was added.
This is one I use to get the last 10 rows:
SELECT id FROM mytable order by date desc LIMIT 10
I know I can do SELECT id FROM mytable ORDER BY RAND() LIMIT 1 but that just choose any random row, not from the last 10 rows.
One method uses a subquery:
SELECT t.*
FROM (SELECT id
FROM mytable
ORDER BY date DESC
LIMIT 10
) t
ORDER BY rand()
LIMIT 1;
This version uses the syntax conventions for MySQL.
You can use select * in the subquery to fetch the whole row.

PHP MYSQL ORDER BY DESC then ASC

I have got this MYSQL
SELECT * FROM chat WHERE To_='$NameId' OR From_='$NameId' ORDER BY `DATE` DESC LIMIT 0,50
This code returns me data in this order
1 newest
2 newest
3 newest
4 newest
5 newest
But i want data to be returned in this way
5 newest
4 newest
3 newest
2 newest
1 newest
How can i do that?
Use this :
SELECT * FROM (select * from chat where To_='$NameId' OR From_='$NameId' ORDER BY DATE DESC LIMIT 0,50) sub ORDER BY DATE ASC
As I understand you want to change direction of records after getting first 50 records.
You can use sub-query feature of MySQL. Assume that result of your query is new, shiny table. So write SQL for desired result using this table (actually it is data set). (In our case we rename it as results)
SELECT * FROM (select * from chat where To_='$NameId' OR From_='$NameId' ORDER BY DATE DESC LIMIT 0,50) as results ORDER BY results.DATE ASC
Also if you have "count" of results you can do same thing using single-level query. Think about that;
SELECT * FROM chat WHERE To_='$NameId' OR From_='$NameId' ORDER BY `DATE` ASC LIMIT ***MyCount***,50
MySQL will not force you to rename your sub-query results but renaming
them results in more readable SQL codes.

SQLite Last Records in Order Added [duplicate]

I want to select last 50 rows from MySQL database within column named id which is primary key. Goal is that the rows should be sorted by id in ASC order, that’s why this query isn’t working
SELECT
*
FROM
`table`
ORDER BY id DESC
LIMIT 50;
Also it’s remarkable that rows could be manipulated (deleted) and that’s why following query isn’t working either
SELECT
*
FROM
`table`
WHERE
id > ((SELECT
MAX(id)
FROM
chat) - 50)
ORDER BY id ASC;
Question: How is it possible to retrieve last N rows from MySQL database that can be manipulated and be in ASC order ?
You can do it with a sub-query:
SELECT * FROM
(
SELECT * FROM table ORDER BY id DESC LIMIT 50
) AS sub
ORDER BY id ASC;
This will select the last 50 rows from table, and then order them in ascending order.
SELECT * FROM table ORDER BY id DESC LIMIT 50
save resources make one query, there is no need to make nested queries
SELECT * FROM table ORDER BY id DESC, datechat DESC LIMIT 50
If you have a date field that is storing the date (and time) on which the chat was sent or any field that is filled with incrementally (order by DESC) or de-incrementally (order by ASC) data per row put it as second column on which the data should be ordered.
That's what worked for me!!!! Hope it will help!!!!
Use it to retrieve last n rows from mysql
Select * from tbl order by id desc limit 10;
use limit according to N value.
if anyone need this
you can change this into
SELECT
*
FROM
`table`
WHERE
id > ((SELECT
MAX(id)
FROM
chat) - 50)
ORDER BY id ASC;
into
SELECT
*
FROM
`table`
WHERE
id > (SELECT MAX(id)- 50 FROM chat)
ORDER BY id ASC;
select * from Table ORDER BY id LIMIT 30
Notes:
* id should be unique.
* You can control the numbers of rows returned by replacing the 30 in the query

Get random top 3 record from database : php-mysql

I want to create a random image banner which fetches the image data from a MySQL database.
And I only want to fetch the latest three records, randomly.
How can I fetch the the 3 most recent records, in a random order?
I am the following query:
SELECT * FROM bottom_advt WHERE bottom_advt_page_name='News' ORDER BY RAND() LIMIT 1
but it's not working.
You said 3 records. So try:
SELECT * FROM bottom_advt WHERE bottom_advt_page_name='News' ORDER BY RAND() LIMIT 3
You're limiting your results to one with LIMIT 1. Change it to LIMIT 3 to get three results.
Try this if you want one of the last three records:
SELECT * FROM bottom_advt WHERE bottom_advt_page_name='News' AND id+3>last_insert_id() ORDER BY RAND() LIMIT 1
You could use this:
SELECT *
FROM bottom_advt
WHERE ID IN (SELECT * FROM (
SELECT id
FROM bottom_advt
WHERE bottom_advt_page_name='News'
ORDER BY id DESC
LIMIT 3) last)
ORDER BY RAND()
LIMIT 1
Subquery will return the last 3 id that have bottom_advt_page_name='News', and the outer query will randomly select one of those.
Please see fiddle here.

Php MySQL Most Liked Query for last 100 Records

I am using this query:
SELECT * from likes GROUP BY url ORDER BY count(*) DESC LIMIT 6
to fetch most liked record from my table 'likes'. It is working perfect for fetching most liked content of all time.
But now to I want to select the 6 most liked record from the last 100 records.
What will be the query for it ?
SELECT * FROM (select * from likes order by date desc limit 100) xx
Group by URL order by count(*) limit 6
Obtain the primary keys of the last 100 entries and narrow your query to it. Probably extremely easy if you have auto-increment keys.
SELECT * from likes
GROUP BY url
ORDER BY count(*) DESC
WHERE ID > MAX(ID)-100
LIMIT 6

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