The problem is the $_FILES['thumbnailPic'] is not picking values from HTML form .I have tried so many solutions but its just not working :(
The HTML code is :
<label >Thumbnail Picture<text>*</text></label><br>
<input type="file" name='thumbnailPic' id="pic"><br>
<label >Original Picture<text>*</text></label><br>
<input type="file" name='originalPic' id="pic"><br>
<input type="submit" name="AddStock" id= "formAddStock" value="Add Stock">
The php code is :
if(!isset($_FILES['thumbnailPic']))
{
echo '<p>Please select a file</p>';
}
else
{
$spID=NULL;
$Quant=$_POST['quantity'];
$Siz=$_POST['Size'];
$imgfp = fopen($_FILES['originalPic']['tmp_name'],'rb');
$stmt = $connection->prepare("INSERT INTO stitchedproduct (sp_id,quantity,size,p_id,color_id,sp_thumbnail,sp_OriginalPic) VALUES (?,?, ?, ?,?,?,?)");
$stmt->bindParam(1, $spID);
$stmt->bindParam(2, $Quant);
$stmt->bindParam(3, $Siz);
$stmt->bindParam(4, $ProductID);
$stmt->bindParam(5, $colour);
$stmt->bindParam(6, $imgfp);
$stmt->bindParam(7, $imgfp);
//$stmt->bindParam(1, $spID);
$stmt->execute();
}
First of all verify that in your HTML code in the <form> tag you have added the enctype="multipart/form-data" attribute.
So your form starting will be like:
<form action="" method="post" enctype="multipart/form-data">
<!-- It's a file-upload form -->
Refer to POST method uploads - Handling file uploads for more.
To check if a file has been successfully uploaded use the "error" key:
if (UPLOAD_ERR_OK === $_FILES["thumbnailPic"]["error"]){
// File uploaded
}
Refer to Error Messages Explained - Handling file uploads for more.
Tip regarding image uploads:
To check if the uploaded file is an image you can check it as:
if (getimagesize($_FILES["thumbnailPic"]["tmp_name"])){
// It's perhaps an image
}
else
{
// Can not be identified as an image
}
Refer here for more.
(and think about the consequences for a moment, what if an image format is known to be used in attacks? what if the getimagesize function returns true but it actually is not an image, but a trojan horse of an image?)
To check file is Uploaded or not :
if (file_exists($_FILES['file_name']['tmp_name']) || is_uploaded_file($_FILES['file_name']['tmp_name'])) {
echo 'Your file has been uploaded';
}
else
{
echo 'Please Select file to Upload';
}
Working 100% for me.
Several possibilities and solution for this issues.
You have to use the enctype="multipart/form-data in your form.
Check the post_max_size and upload_max_filesize in our php.ini file.
if you are uploading image size greater than the values stored in
the post_max_size and upload_max_filesize , then file won't get
uploaded
You can check the error in the file using
$_FILES["thumbnailPic"]["error"]
Related
I'm trying to add a path of an uploaded image to the database in order to use it to display it as a thumbnail for a post. I found a tutorial and I used this code to upload the image. However it gets to the else statement and I just get the exit("Error While uploading image on the server"); I have a form to collect the data:
<form action='' method='post' enctype="multipart/form-data">
<p><label>Title</label><br />
<input id="title-input" type='text' name='postTitle' value='<?php if(isset($error)){ echo $_POST['postTitle'];}?>'></p>
<p><label>Description</label><br />
<textarea id="textarea" name='postDesc' cols='20' rows='5'><?php if(isset($error)){ echo $_POST['postDesc'];}?></textarea></p>
<p><label>Content</label><br />
<textarea name='postCont' cols='20' rows='5'><?php if(isset($error)){ echo $_POST['postCont'];}?></textarea></p>
<p><label>Image</label><input type="file" name="uploadedimage">
</p>
<input type='submit' name='submit' value='Submit'>
<input type='reset' name='submit' value='Reset'>
</form>
<?php include 'add-post-handler.php' ?>
And here is the code I used to upload the image:
function GetImageExtension($imagetype)
{
if(empty($imagetype)) return false;
switch($imagetype)
{
case 'image/bmp': return '.bmp';
case 'image/gif': return '.gif';
case 'image/jpeg': return '.jpg';
case 'image/png': return '.png';
default: return false;
}
}
if (!empty($_FILES["uploadedimage"]["name"])) {
$file_name=$_FILES["uploadedimage"]["name"];
$temp_name=$_FILES["uploadedimage"]["tmp_name"];
$imgtype=$_FILES["uploadedimage"]["type"];
$ext= GetImageExtension($imgtype);
$imagename=$_FILES["uploadedimage"]["name"];
$target_path = "../img/".$imagename;
if(move_uploaded_file($temp_name, $target_path)) {
$query_upload="INSERT INTO blog_images (imgPath) VALUES
('$target_path')";
mysqli_query($link, $query_upload) or die("error in $query_upload == ----> ".mysql_error());
}else{
exit("Error While uploading image on the server");
}
}
PS: I also have some doubts on how can I get the imageID to be related with the postID considering that are both submitted from the same form.(I made a relation between the two tables but it's on the primary keys so I'm not sure if it's correct)
Thanks for your help!
Looking at the Code:
move_uploaded_file returns FALSE on two premises (stated in the PHP Docs):
If filename is not a valid upload file, then no action will occur, and
move_uploaded_file() will return FALSE.
If filename is a valid upload file, but cannot be moved for some
reason, no action will occur, and move_uploaded_file() will return
FALSE. Additionally, a warning will be issued.
My best guess is, with the information you provided:
Your path is not writeable by your application/webserver, so it won't be moved
Make sure the application (the webserver) can write in your path: '../img/' by issuing a chmod to give the directory the correct rights for the webserver user.
Security Advice (not related to question):
Your application has in this state a potential SQLi in $target_path. You should think about using prepared statements
https://dev.mysql.com/doc/apis-php/en/apis-php-mysqli.quickstart.prepared-statements.html
Your form writes POST Data directly to output. This leads to XSS. You should always encode special characters in your output.
https://www.owasp.org/index.php/Cross-site_Scripting_%28XSS%29
Make sure, only images can be uploaded and scripts can't be executed in this '../img' path. Somebody could exploit your upload to upload a script and execute it.
easiest way to prevent SQLi in this case would be hashing the imagename and setting the extension with the $ext variable:
[...]
$ext=GetImageExtension($imgtype);
if($ext === FALSE) {
exit("Couldn't determine the filetype correctly. Please upload pictures only.");
}
$imagename=md5($_FILES["uploadedimage"]["name"].time()).$ext;
$target_path = "../img/".$imagename;
[...]
The time() is only included, so somebody can upload pictures with the same name.
you could always give your images a specific class that you know directs to all images you want to thumbnail and apply a CSS rule/code that will automatically make them img-thumbnail.
<div class="imgT">
then set your CSS thumbnail
Thanks everyone for answering. In the end I got it. I found that the problem was with the php.ini settings. This is the link that helped me -> Why would $_FILES be empty when uploading files to PHP?. Thanks PaulF for posting it. The problem was that the limit for uploading files was just 2MB or something like that.
For everyone having the same issues make sure you check that link and check this settings in your php.ini file.
file_uploads = On
post_max_size = 100M
upload_max_filesize = 100M
I am trying to enter some data into a database and upload an image to a specific directory. I am using the following script which is a modified version of the top voted answer to this question: How to store file name in database, with other info while uploading image to server using PHP?
require($_SERVER['DOCUMENT_ROOT']."/settings/functions.php");
// This is the directory where images will be saved
$target = $_SERVER['DOCUMENT_ROOT']."/safetyarticles/images/";
$target = $target . basename( $_FILES['article_img']['name']);
date_default_timezone_set("America/Chicago");
// This gets all the other information from the form
$article_name = $_POST['article_title'];
$article_date = date("m/d/Y");
$article_creator = $_POST['article_creator'];
$article_views = "0";
$article_content = $_POST['article_content'];
$article_content_2 = $_POST['article_content_2'];
$article_img = ($_FILES['article_img']['name']);
$article_credit = $_POST['article_credit'];
// Connect to database
$conn = getConnected("safetyArticles");
// moves the image
if(move_uploaded_file($_FILES['article_img']['tmp_name'], $target))
{
// if upload is a success query data into db
mysqli_query($conn, "INSERT INTO currentArticles (article_name, article_date, article_creator, article_content, article_content_2, article_img, article_credit)
VALUES ('$article_name', '$article_date', '$article_creator', '$article_views', '$article_content', '$article_content_2', '$article_img', '$article_credit')") ;
echo "The file ". basename( $_FILES['article_img']['name']). " has been uploaded, and your information has been added to the directory";
}
else {
echo "Sorry, there was a problem uploading your file.";
}
I have successfully connected to my database since my getConnected() function contains error handling for if the connection fails.
For some reason I keep getting the Sorry, there was a problem uploading your file. error from the bottom of the script.
Am I missing something? All I did was change some minor lines here and there such as how the database connects, and the variables. I also moved the query to only happen if the file uploads.
I'm not sure what I'm missing.
Is it also possible to modify this current script to rename the image to whatever the value of $article_name is? For example if the article name is "This Is The First Article" then the image would be this-is-the-first-article.jpg?
My HTML form is:
<form method="post" action="http://example.com/admin/articleCreate.php" enctype='multipart/form-data'>
<input type="text" name="article_title" placeholder="What Is The Name Of This Article?" id="article_title_input">
<textarea name="article_content" placeholder="Write The Top Half Of Your Article Here." id="article_content_input"></textarea>
<input type="file" name="article_img" placeholder="If The Article Has An Image, Upload It Here." id="article_img_input">
<textarea name="article_content_2" placeholder="Write The Bottom Half Of Your Article Here." id="article_content_2_input"></textarea>
<input type="text" name="article_creator" placeholder="Who Is Writing This Article?" id="article_creator_input">
<input type="text" name="article_credit" placeholder="If This Article Is Copied, What Website Was It Taken From?" id="article_credit_input">
<input type="submit" value="Submit">
</form>
And I did var_dump(is_uploaded_file($_FILES['article_img']['tmp_name'])); and it's returnign true.
Sidenote edit: This being before you edited your question with only one of them being renamed. https://stackoverflow.com/revisions/36367407/4
$_FILES['photo']
$_FILES['uploadedfile']
are two different file arrays and you're using name="article_img" as the name attribute.
You need to use the same one for all of them.
Error reporting http://php.net/manual/en/function.error-reporting.php would have told you about it.
Add error reporting to the top of your file(s) which will help find errors.
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
// Then the rest of your code
Sidenote: Displaying errors should only be done in staging, and never production.
Additional edit:
$target = $target . basename( $_FILES['photo']['name']);
if that's your real edit, still the wrong array name.
I think the problem is in this line:
if(move_uploaded_file($_FILES['photo']['tmp_name'], $target))
Change it to this:
if(move_uploaded_file($_FILES['article_img']['tmp_name'], $target))
Your html has:
<input type="file" name="article_img" placeholder="If The Article Has An Image, Upload It Here." id="article_img_input">
And your php is waiting for $_FILES['photo']['tmp_name']
Change your html file input to:
<input type="file" name="photo" placeholder="If The Article Has An Image, Upload It Here." id="article_img_input">
So I have a bit of a problem. I was looking at a tutorial for video uploads and I came across this tutorial.
https://www.youtube.com/watch?v=SibODOJle6Q
It seems that my move_uploaded_files is not working and it is trivial for me to see his code work which I copied and the result is completely different.
Could I get some help with this please?
my Code below
<html>
<head>
<title>Video Upoad</title>
<link rel='stylesheet' href='stylesheet.css'/>
</head>
<body>
<?php
require('connect.php');
?>
<div id='box'>
<form method ='post' enctype='multipart/form-data'>
<?php
if(isset($_FILES['video'])){
$name= $_FILES['video']['name'];
$type = explode('.',$name);
$type=end($type);
$size= $_FILES['video']['size'];
$random_name=rand();
$tmp = $_FILES['video']['tmp_name'];
if($type !='mp4' && $type != 'MP4' && $type!='flv'){
$message = "Video Format is not supported!";
}else{
move_uploaded_file($tmp, 'viddata/'.$random_name.'.'.$type);
$message ="The Upload was successful";
mysql_query("INSERT INTO video VALUES ('','$name','viddata/$random_name.$type')");
}
echo $message.'<br/><br/>';
//echo $type.'<br/>';
//echo $name.'<br/>';
}
?>
Select Video: <br/>
<input type='file' name='video' />
<br/><br/>
<input type='submit' value='Upload' />
</form>
</div>
<div id='box'>
</div>
</body>
</html>
It does insert into the database and everything except moving the file to the destination.
You should consider the following:
Make sure you have viddata folder.
Check the file size of the file you are trying to upload if it exceeds the upload_max_filesize.
If it does, you can configure your php.ini and set the upload_max_filesize to your preferred size, then reset your XAMPP Control Panel.
Check also the permission of the folder/directory you are trying to upload the file.
You should also set conditions on the files being uploaded by the user, like setting the condition for file type and size before you upload process it.
Start by checking the return value, errors and warnings. The documentation says:
Return Values
Returns TRUE on success.
If filename is not a valid upload file, then no action will occur, and
move_uploaded_file() will return FALSE.
If filename is a valid upload file, but cannot be moved for some
reason, no action will occur, and move_uploaded_file() will return
FALSE. Additionally, a warning will be issued.
There are also some good examples with more comprehensive error checking.
I having trouble with the move_uploaded_file function on my website.
The whole idea is that in a form, i insert the title, description and a screenshot of a project. Everything is working just fine. It saves the title and description with an id and the creation date in a mysql database and moves the file to a folder on the server.
The problem however is that some files are transferred to folder and some aren't. The problem seems to be in the files, but i can't seem to figure out what the problem is.
It is not the filesize; i have files of 5/6MB that are placed in the folder without any problems, and i have files that are around 3MB that arent. The extension isn't the problem either, they are both .jpg.
Are there any other requirements that a .jpg file should meet, in order to be uploaded?
I'm 99% certain the problem isn't in my code, as it uploads some files without a problem, but here is my code anyway.
The HTML part:
<form action="" method="post" enctype="multipart/form-data">
<h2>Title*</h2>
<input type="text" id="title" name="title">
<h2>Description*</h2>
<textarea id="descr" name="descr" cols="40" rows="4"></textarea>
<h2>Add file*</h2>
<input type="file" id="file" name="file">
<h2><input type="submit" id="submit" name="submit" value="Uploaden"></h2>
<p id="requirements">Fields marked with * are required.</p>
</form>
And this is the PHP part:
if (isset($_POST['submit'])) {
$destination = "../uploadedfiles/" . basename($_FILES['file']['name']);
if (move_uploaded_file($_FILES['file']['tmp_name'], $destination)) {
echo '<p id="succes">File has been uploaded</p>';
} else {
echo '<p id="error">File has not been uploaded</p>';
}
$title = $_POST['title'];
$descr = $_POST['descr'];
$name = ($_FILES['file']['name']);
include "../connect/connect.php";
if ($title == "" || $descr == "") {
echo '<p id="error">Fill in the required fields</p>';
} else {
$query = "INSERT INTO file(title, descr, name, created) VALUES ('{$title}', '{$descr}', '{$name}', NOW())";
$upload = $connect->query($query);
if ($upload) {
echo '<p id="succes">Info is stored in database</p>';
} else {
echo '<p id=error>Failed to store info in database</p>';
}
}
}
A bunch of stuff might be going wrong. move_uploaded_file is very pick and sometimes doesn't behave how it is documented. I had problems with it once and honestly, copy archive the same result in most cases if properly implemented.
There are reports of lone filenames causing trouble. 249 chars on $destination seems to be the limit.
not only upload_max_filesize must be set but also post_max_size
utf-8 names might be a problem
If you have problems where the uploaded file seems unaccessible, try to use copy() instead. There are reports of people not being able to find the file just after upload, move_uploaded_file just limits path over copy, the results are the same if you dont input any user var.
For some reason my PDF upload form is failing consistently, I have this code:
<?php
if($_POST["submit"] == "Add PDF to Comm and Special Projects")
{
$addsubp = $_POST["addsubp"];
$addsubp_name = $_POST["addsubp_name"];
$commuploadedfile = $_FILES['uploadedfile']['name'];
$sqldoc = "INSERT INTO projects_links (pid, display_name, link) VALUES ('".$addsubp."','".$addsubp_name."','".$commuploadedfile."')";
mysql_query($sqldoc) or die(mysql_error());
echo "<BR>";
$target_path = "D:\\Hosting\\69903\\html\\pdfs\\comm\\";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "<br>The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded<br>";
} else{
echo "<br>There was an error uploading the file, please try again.<br>";
}
}
?>
<form method="post">
Add PDF to Project for Committees and Special Projects <br>Choose Project<select name="addsubp"><?php
$query = "SELECT
projects.*
FROM
projects";
$showresult = mysql_query($query);
$csp_c = 1;
while($buyarray = mysql_fetch_assoc($showresult))
{
echo "<option value=".$buyarray['id'].">".$buyarray["pname"]."</option>";
}
?></select><br>
Choose Display Name for PDF <input type="text" name="addsubp_name" /> <Br>
Choose PDF: <input name="uploadedfile" type="file" /> <Br>
<input type="submit" value="Add PDF to Comm and Special Projects" name="submit" />
</form>
I have made sure that the application has write privileges to the "comm" directory. I have godaddy and used the file manager to make sure of that. I have had problems with permissions in this project before, so I know this isn't case. It keeps printing
There was an error uploading the file, please try again.
It doesn't attempt to upload any PDF at all, what am I doing wrong?
thanks!
You may have permissions issues, but for file uploads your form tag should contain the proper enctype attribute.
<form enctype="multipart/form-data" method="POST">
and defining a file size limit is also a good idea:
<input type="hidden" name="MAX_FILE_SIZE" value="1000000" />
try checking the Upload error message: http://php.net/manual/en/features.file-upload.errors.php
Your code is blindly assuming the file upload succeeded. At bare minimum you should have something like
if ($_FILES['uploadedfile']['error'] === UPLOAD_ERR_OK) {
... handle the upload
}
Your code is vulnerable to SQL injection. You do not escape any of the 3 values you're inserting into the database
You're creating the database record before making sure the file was successfully moved into the target directory. What happens if the file can't be written for any reason (as it is now with your problem)? The database will say it's there, file system will say it isn't
You're not checking for file collisions. If two seperate uploads send "file.txt", the second upload will overwrite the first one.
You're storing the files with the user-supplied name, which is under user control. If this file is web-accessible, anyone with access to your upload form can upload anything they want (e.g. a php file) and the server will happily execute it for them.