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Read the longest string from an array in PHP 5.3
(3 answers)
Closed 2 years ago.
$array =array("AB","ABC","ABCD","ABCDE","BD");
Requirement: find the longest element in the array
Output:ABCDE
$array =array("AB","ABC","ABCD","ABCDE","BD");
$longstring = $array[0];
foreach( $array as $string ) {
if ( strlen( $string ) > strlen( $longstring ) ) {
$longstring = $string;
}
}
echo $longstring;
First we are iterate the array with help of foreach loop. in foreach loop we check $result is less than array value. if array value is greater then $result array then we override previous value of $result with new value. if we found greatest length than previous array element then we are storing new length & key of new element in variable.
$array =array("AB","ABC","ABCD","ABCDE","BD");
$result = $resultkey = 0;
foreach($array as $key=>$value) {
if($result < strlen($value) ) {
$result = strlen($value);
$resultkey = $key;
}
}
echo 'longest value:' $result;
echo 'result :' $array[$resultkey]
Output:
longest value: 5
result :ABCDE
You could sort the array by string length using strlen and usort and get the first item:
$array =array("AB","ABC","ABCD","ABCDE","BD");
usort($array, function($x, $y) { return strlen($y)-strlen($x); });
echo $array[0];
Result:
ABCDE
Demo
Try this, though it's a bit confusing.
<?php //php 7.0.8
$array = array("AB","ABC","ABCD","ABCDE","BD");
$longertext = array_search(max($array), $array)-1; //4-1 =3
// minus 1 because it's counting the actual position not starts with 0 it returns 4
echo $longertext; //equals 3
echo "\n";
echo $array[$longertext]; //equals ABCDE
?>
The actual test: http://rextester.com/OTI23127
I'd like to count how many numbers and letters are in the variable using PHP. Below if my code:
$lot_num = strtoupper('e1,1,2,3,4,5,7,8,9,10,11,12,13,14,15,16,17,18,e18');
echo 'END UNIT: '.substr_count($lot_num, 'E').'<br />';
the code will count how many letter E are there in my lot_num variable but i would also like to count how many numbers are in the variable. Supposed, E1 and E18 should not be included when counting numbers.
I hope you can help me guys.
Try this: explode on , to get array that can be counted.
https://3v4l.org/r6OKl
$lot_num = strtoupper('e1,1,2,3,4,5,7,8,9,10,11,12,13,14,15,16,17,18,e18');
$ecount = substr_count($lot_num, 'E');
$totcount = count(explode(",", $lot_num));
echo 'END UNIT: '.$ecount;
Echo "\ntotal count: ". $totcount;
Echo "\nother count: ". Intval($totcount-$ecount);
No loops and no regex makes it a simple and quick solution.
You could always turn it into an array and use a loop:
$lot_num = explode(',',strtoupper('e1,1,2,3,4,5,7,8,9,10,11,12,13,14,15,16,17,18,e18');
$count = 0;
for ($i=0;$i<count($lot_num);$i++) {
if (is_int($lot_num[$i])) { //detects all numbers
$count++;
}
}
echo $count;
$lot_num = strtoupper('e1,1,2,3,4,5,7,8,9,10,11,12,13,14,15,16,17,18,e18');
$array = explode(',', $lot_num);
$data=array();
foreach($array as $k=>$val){
if(is_numeric($val )){
$data['number'][] = $val;
}else{
$data['string'][] = $val;
}
}
echo count($data['number']);
echo count($data['string']);
you can use is_numeric() and
if (!preg_match("/^[a-zA-Z]$/", $param)) {
// throw an Exception...
}
inside a loop
Id use preg_match
preg_match('/\b([0-9]+)\b/', $lot_num, $matches );
And matches would be like this.
$mathes[1][1,2,3,4,5,7,8,9,10,11,12,13,14,15,16,17,18]
So you would
$lot_num = strtoupper('e1,1,2,3,4,5,7,8,9,10,11,12,13,14,15,16,17,18,e18');
$total = 0;
if( preg_match('/\b([0-9]+)\b/', $lot_num, $matches )){
$total = count( $mathes[1] );
}
You can see how the Regx works here https://regex101.com/r/17psAQ/1
1,first u have to seperate the string and stored into array
2,then u can easily count the value of integers
<?php
$lot_num =explode(',',strtoupper('e1,1,2,3,4,5,7,8,9,10,11,12,13,14,15,16,17,18,e18'));//seperate string by ","
$arr_count=count($lot_num);
for($i=0;$i<$arr_count;$i++)
{
$get_num[]=$lot_num[$i];//saving seperated string value into array
}
$count=0;
for($j=0;$j<count($get_num);$j++)
{
if(is_numeric($get_num[$j]))//chect whether the value is integer or not
{
$count++;
}
}
echo $count;
I want to echo one element of the array like sum1. But I only get one letter like s. Please solve this problem.
$nums = array("sum1", 100, 200);
foreach ($nums as $value) {
echo $value[0];
echo $value[1];
}
If you want to just echo 1 item from that array, you should to it like this:
echo $nums[0];
If you want to loop through all of them, and show each, do it like so:
$nums = array("sum1", 100, 200);
foreach ($nums as $value) {
echo $value."<br>";
}
What you did wrong
You had already looped through the array, so you had a string. You can select the first letter from a string like in this example:
$string = "A string";
echo $string[0];
Will return A, as it's the first index of that string. That is essentially what you did in your loop.
You made your String an array, and it showed the index's you selected to be shown. You can read this where the questions asks how to do this. I hope this gives some more clearity.
If you want every element of array,
then,
For your array,
$nums = array("sum1", 100, 200);
$nums[0] will be sum1
$nums[1] will be 100
$nums[2] will be 200,
Now your loop,
foreach ($nums as $value) {
// here echo $value values are like 'sum1', 100, 200 will be printed.
// by default string will be considered as array,
// if you print $value[0], $value[1], $value[2], $value[3] for sum1, it will return, s, u, m, 1 respectively.
// and integers will be considered as pure value, which you will get in $value only, not in $value[0], ....
}
I hope I explained your concern.
Thanks.
How do you echo only the first line of print print_r?
More info:
I have this PHP code:
preg_match_all('/MbrDtlMain.php\?([^ ]+)>/i', $string, $matches);
foreach(end($matches) as $key=> $value){
print print_r($value, 1).'<br>';
}
That results in:
12567682
12764252
12493678
14739908
(or other numbers depending on user input)
I tried:
preg_match_all('/MbrDtlMain.php\?([^ ]+)>/i', $string, $matches);
foreach(end($matches) as $key=> $value){
$id = print_r($value, 1).'<br>';
}
echo $id
But it results in 1 random number from the list. In other words, the result only shows when using print like ' print print_r($value, 1).'<br>';'. The problem is that I only want the first, inorder, result to be shown. As if:
$firstlineofnumbers = '12567682';
echo $firstlineofnumbers;
Hope this makes sense. Thanks (:
If I understood what you're trying to do, just adding a break; statement after outputting the first value should be enough:
foreach(end($matches) as $key=> $value){
print print_r($value, true).'<br>'; // print_r() expects true, not 1
break;
}
If the keys in $matches are always numeric keys, this code should be enough:
echo $matches[0];
Otherwise, try this code:
$keys = array_keys($matches);
echo $matches[array_shift($keys)];
$keys will contain all keys of $matches.
array_shift will return the first value of $keys (the first key).
So the last line will display the corresponding value.
There is no need to loop through the entire array if you only need to display the first element.
preg_match_all('/MbrDtlMain.php\?([^ ]+)>/i', $string, $matches);
$i=0;
foreach(end($matches) as $key=> $value){
$i++;
if ($i == 1) {
echo $value."<br />";
}
}
This starts with the variable $i which increases by 1 for each match. If $i == 1, then it will echo the $value.
I want to get the count of characters from the following words in the string. For example, if my input is I am John then the output must be like this:
9 // count of 'I am John'
4 // count of 'I am'
1 // count of 'I'
I use the code like this in PHP for this process:
$string = 'I am John';
$words = explode(' ',$string);
$count_words = count($words);
$i =0;
while ($i<$count_words){
if($i==0) {
$words_length[$i] = strlen($words[$i]);
} else {
$words_length[$i] = strlen($words[$i])+1+$words_length[$i-1];
}
echo $words_length[$i]."<br>";
$i++;
}
But it return the output like this:
1
4
9
Why ? Where is my error ? How can I change the ordering ? What does my code must be like ?
Thanks in advance!
If you simply want to have the output in reverse order use array_reverse:
print_r(array_reverse($words_length));
Your problem is that you're looping through the words left to right. You can't output the full length right to left, because each one depends on the words to it's left.
You could take the echo out of the loop, and print the values after all have been calculated.
$string = 'I am John';
$words = explode(' ',$string);
$count_words = count($words);
$i =0;
while ($i<$count_words){
if($i==0) {
$words_length[$i] = strlen($words[$i]);
} else {
$words_length[$i] = strlen($words[$i])+1+$words_length[$i-1];
}
$i++;
}
print implode('<br />', array_reverse($words_length));
The quickest fix is to add print_r(array_reverse($words_length)); after the loop
You may use foreach and array_reverse to get the array values:
foreach(array_reverse($words_length) as $val){
echo $val;
}