Why won't my JSON array query work? - php

Can anyone see what the problem with my code is / where im going wrong?
I know i have the correct host,database,user and password.
This is the code in the php file, it should get all the details available on the players from my sql database, however if i go on the page it just gives me a white page. Im using go daddy as a host and my database is also on there.
Any ideas? thanks
<?php
$host = "abc12345"; //Your database host server
$db = "abc12345"; //Your database name
$user = "abc12345"; //Your database user
$pass = "abc12345"; //Your password
$connection = mysql_connect($host, $user, $pass);
//Check to see if we can connect to the server
if (!$connection) {
die("Database server connection failed.");
} else {
//Attempt to select the database
$dbconnect = mysql_select_db($db, $connection);
//Check to see if we could select the database
if (!$dbconnect) {
die("Unable to connect to the specified database!");
} else {
$query = "SELECT * FROM Player";
$resultset = mysql_query($query);
$records = array();
//Loop through all our records and add them to our array
while ($r = mysql_fetch_assoc($resultset)) {
$records[] = $r;
}
//Output the data as JSON
echo json_encode($records);
}
}
?>

The script is all right, I checked it with a different query.
Assuming that the table Player is not empty, the error can be either with your raw sql query (as pointed by #Sharikov in comments), otherwise the error is with the way you have configured your godaddy server.
For debugging that, I would suggest inserting dummy print_r or echo statements before you execute the query, and going through your apache logs at /var/log/apache2/access.log.
Also make sure that you don't have any core php package missing on your server (like php5-mysql if you use mysql).

Related

Failed to query database [duplicate]

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How do I get PHP errors to display?
(27 answers)
Closed 5 years ago.
<?php
//Get Value
$username = $_POST['user'];
$password = $_POST['pass'];
//Connet To The Server And Select Database
mysqli_connect("192.168.xxx.xxx", "xxx", "xxxxxxxxxxxxx");
mysqli_select_db("xxxxx");
//Query The Database For User
$result = mysqli_query("select * from user where username = '$username' and password = '$password'")
or die("Failed to query database ".mysqli_connect_error());
$row = mysqli_fetch_array($result);
if (empty($username)) {
header('Location: fa.html');
} elseif (empty($password)) {
header('Location: fa.html');
} elseif ($row['username'] == $username && $row['password'] == $password){
header('Location: su.html');
} else{
header('Location: fa.html');
}
?>
I have no experience to code PHP so i have no idea what's wrong is my code.
I have replace "mysql" into "mysqli" but it is still not working correctly.
It's work fine when running "mysql_*" and using my local Window web server.
But when i put it into Linux server it occur error message "Failed to query database ".
Add the fourth parameter here as database name like
mysqli_connect("192.168.xxx.xxx", "xxx", "xxxxxxxxxxxxx", "database_name");
and remove
mysqli_select_db("xxxxx");
A sample way of writing php code would be
$link = mysqli_connect("server_name","username","password","database_name");
if(mysqli_connect_error()) {
die("There was an error connecting to the database");
}
$query = 'yourQuery';
$result=mysqli_query($link,$query);
if ( false==$result ) {
printf("error: %s\n", mysqli_error($link));
}
This will work
Hope it helps
You need to trap for more errors to see where it's failing. Right now all you know is that it's failing at-least by the mysqli_query() line where you do trap for errors.
First you have to ensure that you can actually connect to the database server.
Change:
mysqli_connect("192.168.xxx.xxx", "xxx", "xxxxxxxxxxxxx");
to
if(!mysqli_connect("192.168.xxx.xxx", "xxx", "xxxxxxxxxx"))
{
die("Could not connect");
}
then you should also trap for errors on selecting the database. Change:
mysqli_select_db("xxxxx");
to
if(!mysqli_select_db("xxxx"))
{
die("Could not select database");
}
Edit: Also you really didn't need to blank-out your IP. 192.168.1.* is a class C private address - meaning it is not accessible from outside your local network.
You need to learn more, because these are really just the basics. The reason why your code works locally and doesn't on the remote server is probably caused by your DB access - it obviously isn't the same. You need to change your credentials and your db IP to match your remote server if you want to deploy your code there.

moving my sql database localhost to live server

i want to move my sql database and i have exported and imported mysql.sql file from localhost to live server and now i m not getting the files and content from that database. what i do ? i did make sure connection to database if fine and successful
here's my page http://shooop23.byethost7.com
<?php
$db = mysqli_connect('','','','');
if(mysqli_connect_errno()){
echo'Database Connection Failed with following errors: '. mysqli_connect_errno();
die();
}
?>
Once you have successfully established a connection to MySQL, you need to perform a query specifying what you want to retrieve and then subsequently retrieve it.
The following example uses mysqli_fetch_row
You should explore the documentation to learn the basics.
$db = mysqli_connect('localhost', 'my_user', 'my_password', 'my_db');
if(mysqli_connect_errno()){
echo'Database connection failed with the following error: '.mysqli_connect_errno();
exit;
}
if ($result = mysqli_query($db, "SELECT MyCol1,MyCol2 FROM MyTable")) {
while ($row = mysqli_fetch_row($result)) {
echo"{$row[0]} - {$row[1]}<br>");
}
mysqli_free_result($result);
}
mysqli_close($db);
$db = mysqli_connect('localhost', 'my_user', 'my_password', 'my_db');
$sql="SELECT * FROM login";
here i connected and stored my database and set a sql command (which is now a string) into these two veriables.
if(mysqli_connect_errno()){
echo'Database connection failed with the following error: '.mysqli_connect_errno();
exit;
}
this is to check if the database is correctly connected, if not then it will show some errors.
$result = mysqli_query($db,$sql);
here i put the database and the sql command to run my query.
while($row = mysqli_fetch_array($result)){
echo $row['username'];
}
here finally outputting the usernames(username is one of the column in my table in this case) which matched with that query
i will suggest This Sql site to get a better understanding on sql queries and try to improve the secuirty because this is the basic point where hackers try to inject their attact most offenly.
Note : If your table's in the database are empty then it will not able to fetch anything

Connection is made to the database with php script but no values are returned

I have a successful connection to the database through this php script but it is not returning any values even though it is connected. I am checking for the results on my web browser and it just returns a blank screen. I have used the same script (different queries) to access two other tables in the database and they are both working fine. Here is my code:
<?php
$username = "xx";
$password = "xxx";
$host = "xxxxx";
$database="xxxxx";
$server = mysql_connect($host, $username, $password);
$connection = mysql_select_db($database, $server);
$myquery = "SELECT `AUTHOR`, `In_order` from `authors`";
$query = mysql_query($myquery);
if ( ! $query ) {
echo mysql_error();
die;
}
$data = array();
for ($x = 0; $x < mysql_num_rows($query); $x++) {
$data[] = mysql_fetch_assoc($query);
}
echo json_encode($data);
mysql_close($server);
?>
It is probably some silly mistake that I have over looked but I have been stuck on it for longer than I should! thanks in advance for any feedback
Tried you code locally on some data and it returns everything ok.
I needed to change the select to match my data
So I am 95% sure the problem is in your query / db settings.
I would first check if your columns in database is really called AUTHOR and 'In_order' with the exact capital letters.
MySql names can be case sensitive depending on your db server settings, and this could be the problem
Sidenote: if you can research mysqli and pdo for connecting to DB instead of mysql that is deprecated.
Try this:
$myquery = "SELECT `AUTHOR`, `In_order` from `authors`";
$query = mysql_query($myquery);
$num = mysql_num_rows($query);
var_dump($query);
var_dump($num);
echo mysql_error();
and tell us what it all says.
Edit: okay, so it's 231 rows in your table, as the var_dump($num) says. Now let's try and get them at last, but in a slightly more efficient way:
while ($row = mysql_fetch_assoc($query)) {
$data[] = $row;
}
echo json_encode($data);
I have a feeling that your "for" loop and mysql_fetch_assoc() inside is what plays tricks with you, because both of them use different internal counters.

My php script is not using given username/pass/host rather using root#localhost (password: NO)

Got a problem! Though I found almost similar threads but none helped :(
I've written a php script to fetch the number of registered users from my MySQL database. The script is working great in my localhost; it is using the given username,pass and host name which are "root", "root", and "localhost" respectively, but the script is not using the given username/pass/host rather using root#localhost (password: NO) in Live server.
In the Live server I created a MySQL user, set an different password, and hostname there is of course not localhost. I updated the script with my newly created mysql users data. BUT, whenever I run the script, I see that the script is still using "root", "root", and "localhost"!!
take a look at the script:
//database connection
$conn = mysql_connect( "mysql.examplehost.com", "myusername", "mypass" );
$db = mysql_select_db ("regdb",$conn); //Oops, actually it was written this way in the script. I misstyped it previously. now edited as it is in the script.
//Query to fetch data
$query = mysql_query("SELECT * FROM regd ");
while ($row = mysql_fetch_array($query)):
$total_regd = $row['total_regd'];
endwhile;
echo $total_regd;
-- Some says to change the default username and pass in the config.ini.php file located in phpMyAdmin directory. Would this help?? I didn't try this because either my hosting provider didn't give me privilege to access that directory (because I am using free hosting for testing scripts) or I simply didn't find it :(
Please help....
Foreword: The MySQL extension is marked as deprecated, better use mysqli or PDO
Though you store the connection resource in $conn you're not using it in your call to mysql_query() and you're not checking the return value of mysql_connect(), i.e. if the connection fails for some reason mysql_query() "is free" to establish a new default connection.
<?php
//database connection
$conn = mysql_connect( "mysql.examplehost.com", "myusername", "mypass" );
if ( !$conn ) {
die(mysql_error()); // or a more sophisticated error handling....
}
$db = mysql_select_db ("regdb", $conn);
if ( !$db ) {
die(mysql_error($conn)); // or a more sophisticated error handling....
}
//Query to fetch data
$query = mysql_query("SELECT * FROM regd ", $conn);
if (!$query) {
die(mysql_error($conn)); // or a more sophisticated error handling....
}
while ( false!=($row=mysql_fetch_array($query)) ):
$total_regd = $row['total_regd'];
endwhile;
echo $total_regd;
edit: It looks like you're processing only one row.
Either move the echo line into the while-loop or (if you really only want one record) better say so in the sql statement and get rid of the loop, e.g.
// Query to fetch data
// make it "easier" for the MySQL server by limiting the result set to one record
$query = mysql_query("SELECT * FROM regd LIMIT 1", $conn);
if (!$query) {
die(mysql_error($conn)); // or a more sophisticated error handling....
}
// fetch data and output
$row=mysql_fetch_array($query);
if ( !$row ) {
echo 'no record found';
}
else {
echo htmlspecialchars($row['total_regd']);
}
First of all:
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Not connected : ' . mysql_error());
}
// make foo the current db
$db_selected = mysql_select_db('foo', $link);
if (!$db_selected) {
die ('Can\'t use foo : ' . mysql_error());
}
What is your mysql_error()? :)

How does one implement a MySQL database into a webpage?

I am a complete database newbie. So far, I know that I can connect to MySQL using PHP's mysql_connect() command, but apart from that, I really don't see how to take that data and put it onto a web page.
a) are there ways other than mysql_connect()
b) lets say I had a table of data in mysql and all I wanted was for that table (for example: list of names and telephone numbers) to now appear on my web page. I can't for the life of me find a tutorial for this.
<?
$database_name = "dbname";
$mysql_host = "localhost"; //almost always 'localhost'
$database_user = "dbuser";
$database_pwd = "dbpass";
$dbc = mysql_connect($mysql_host, $database_user, $database_pwd);
if(!$dbc)
{
die("We are currently experiencing very heavy traffic to our site, please be patient and try again shortly.");
}
$db = mysql_select_db($database_name);
if(!$db)
{
die("Failed to connect to database - check your database name.");
}
$sql = "SELECT * FROM `table` WHERE `field`= 'value'";
$res = mysql_query($sql);
while($row = mysql_fetch_assoc($res)) {
// code here
// access variables like the following:
echo $row['field'].'<br />';
echo $row['field2'];
}
?>
Check out mysql_fetch_assoc mysql_fetch_array and mysql_fetch_object
This is the very basics, you will want to search for tutorials. There are many about.

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