Pagination with multiple GET values doesn't work as expected - php

Question

I have the url to my blog page:
www.something.com/index.php?menuid=6 or just www.something.com/?menuid=6
I would like to add a GET variable (the page number, because there are too much posts to display them on one page) to the current url, like this:
www.something.com/index.php?id=6&page=12 or www.something.com/?id=6&page=12
What should i write in the <a href> of the pagination if I don't know the www.something.com and the value of the menuid?
I tried this:
$pagination = "<p>";
$pagination.= ($page <= 1) ? "First | " : "First | ";
$pagination.= ($page <= 1) ? "Previous | " : "Previous | ";
for ($i=1; $i<=$pages; $i++) {
$pagination.= ($page == $i) ? "{$i} | " : "{$i} | ";
}
$pagination.= ($page >= $pages) ? "Next | " : "Next | ";
$pagination.= ($page >= $pages) ? "Last" : "Last";
$pagination.= "</p>\n";
but when i clicked on the 2nd page and then the 3rd page, the result was this:
index.php?menuid=6&page=2&page=3
My other question is, that how to show just the previous two and the next two page numbers like in this one?
This is the php code for the pagination:
$query = mysql_query("SELECT * FROM posts");
$howmuch = 5;
$total = mysql_num_rows($query);
$page = (isset($_GET['page'])) ? $_GET['page'] : 1;
$pages = ceil($total/$howmuch);
$where = ($page-1)*$howmuch;
$active="(SELECT s_id FROM status WHERE s_name='active')";
$sql = "SELECT post_id, post_title, post_content, post_date
FROM posts
WHERE post_s_id=".$active."
ORDER BY post_id DESC
LIMIT {$where}, {$howmuch}";
$result = mysql_query($sql);
$output="";
while ($row = mysql_fetch_assoc($result)) {
$output.="Here are the posts";
}
return $output.$pagination;
!!!UPDATE!!!
I'm sorry, but I forgot to mention, that the posts.php is included in the index.php, and the above code is in the posts.php.
The menu_id is in the code of the index.php, not in the posts.php, but the url is the same.

Answer 1

$_SERVER['REQUEST_URI'] will get everything in the URL, thats why it's adding up all your page vars.
Use
$_SERVER['HTTP_HOST'].$_SERVER['SCRIPT_NAME'].'?menuid='.$_GET['menuid'].'&page='.$page

Answer 2

Quick function to generate this regardless of the parameters in the url
function getPageUri($page) {
$_GET['page'] = $page;
foreach($_GET as $key => $value ) {
$query_string[] = "$key=$value";
}
return $_SERVER['PHP_SELF'] . '?' . implode('&', $query_string);
}