JSON PHP decode not working - php

Question

I have seen many examples, but for whatever reason, none seem to work for me.
I have the following sent from a app, via ajax, to a php file. This is how it looks when its sent:
obj:{"ClientData":
[{
"firstName":"Master",
"lastName":"Tester",
"email":"me#me.com",
"dob":"1973-01-22",
"age":"51",
}],
"HealthData":
[
"condition : Prone to Fainting / Dizziness",
"condition : Allergic Response to Plasters",
],
"someData":
[{
"firstName":"Male",
"lastName":"checking",
}]
}
Code as is:
{"ClientData":[{"firstName":"Master","lastName":"Tester","email":"me#me.com","dob":"1973-01-22","age":"51","pierceType":"Vici","street":"number of house","city":"here","county":"there","postcode":"everywhere"}],"HealthData":[["condtion : Prone to Fainting / Dizziness","condtion : Allergic Response to Plasters","condtion : Prone to Fainting / Dizziness"]],"PiercerData":[{"firstName":"Male","lastName":"checking","pierceDate":"2013-02-25","jewelleryType":"Vici","jewelleryDesign":"Vidi","jewellerySize":"Vici","idChecked":null,"medicalChecked":null,"notes":"This is for more info"}]}
This comes in one long line into a php file, here is the code:
<?php
header('Content-Type: application/json');
header("Access-Control-Allow-Origin: *");
//var_dump($_POST['obj']);
$Ojb = json_decode($_POST['obj'],true);
$clientData = $Ojb['ClientData'];
$healthData = $Ojb->HealthData;
$someData = $Ojb->someData;
print_r($clientData['firstName']);
?>
No matter what I have tried, I am unable to see any of the information, I don't even get an error, just blank! Please can someone point me in the right direction.
Thank you :)
UPDATE
Here is the code that creates the object:
ClientObject = {
ClientData : [
{
firstName : localStorage.getItem('cfn'),
lastName : localStorage.getItem('cln'),
email : localStorage.getItem('cem'),
dob : localStorage.getItem('cdo'),
age : localStorage.getItem('cag'),
pierceType : localStorage.getItem('cpt'),
street : localStorage.getItem('cst'),
city : localStorage.getItem('cci'),
county : localStorage.getItem('cco'),
postcode : localStorage.getItem('cpc')
}
],
HealthData : health,
PiercerData : [
{
firstName : localStorage.getItem('pfn'),
lastName : localStorage.getItem('pln'),
pierceDate : localStorage.getItem('pda'),
jewelleryType : localStorage.getItem('pjt'),
jewelleryDesign : localStorage.getItem('pjd'),
jewellerySize : localStorage.getItem('pjs'),
idChecked: localStorage.getItem('pid'),
medicalChecked: localStorage.getItem('pmh'),
notes: localStorage.getItem('poi')
}
]
};
And here is how its sent:
function senddata() {
$.ajax({
url: 'http://domain.com/app.php',
type: 'POST',
crossDomain: true,
contentType: "application/json; charset=utf-8",
dataType: 'jsonp',
data: 'obj='+JSON.stringify(ClientObject),
success : function(res) {
console.log(res);
},
error: function(err) {
}
});
}

Answer 1

There are a few things that will cause problems:
why dataType: 'jsonp'? If you don't intend to utilize jsonp, don't instruct jQuery to do this. See the docs: https://api.jquery.com/jQuery.ajax/
"jsonp": Loads in a JSON block using JSONP. Adds an extra
"?callback=?" to the end of your URL to specify the callback. Disables
caching by appending a query string parameter, "_=[TIMESTAMP]", to the
URL unless the cache option is set to true.
'obj='+JSON.stringify(ClientObject), this will guarantee invalid json.
For reference, have a look at this question: jQuery ajax, how to send JSON instead of QueryString on how to send json with jquery.
That said, try the following:
function senddata() {
$.ajax({
url: 'app.php',
type: 'POST',
crossDomain: true,
contentType: 'application/json; charset=utf-8"',
data: JSON.stringify(ClientObject),
success : function(res) {
console.log(res);
},
error: function(err) {
}
});
}
And in app.php use
$input = json_decode(file_get_contents('php://input'));
to get the data. Use it like:
var_dump($input->ClientData[0]->firstName); // => string(6) "Master"

Answer 2

$Ojb = json_decode($_POST['obj'],true);
makes it array so u need to get them using array index instead of object
UPDATE1
With your update here how it could be done
$str ='{"ClientData":[{"firstName":"Master","lastName":"Tester","email":"me#me.com","‌​dob":"1973-01-22","age":"51","pierceType":"Vici","street":"number of house","city":"here","county":"there","postcode":"everywhere"}],"HealthData":[["‌​condtion : Prone to Fainting / Dizziness","condtion : Allergic Response to Plasters","condtion : Prone to Fainting / Dizziness"]],"PiercerData":[{"firstName":"Male","lastName":"checking","pierceDat‌​e":"2013-02-25","jewelleryType":"Vici","jewelleryDesign":"Vidi","jewellerySize":"‌​Vici","idChecked":null,"medicalChecked":null,"notes":"This is for more info"}]}' ;
$obj = json_decode($str,true);
echo $obj["ClientData"][0]["firstName"];
You can get other elements as above
UPDATE2
You are sending the data as JSONP and this will make the request as
?callback=jQuery17108448240196903967_1396448041102&{"ClientData"
Now you are also adding data: 'obj=' which is not correct.
You can simply send as json not jsonp
and on the php file you can do as
$Ojb = json_decode(file_get_contents('php://input'),true);