Using Selected="Selected" from dynamic list of options - php

I'm posting variables from my form on to another form (a search records form), this will have all the variables that are being posted to the current form and place within INPUT field or SELECT fields. Any fields which are INPUT type I can POST to using the Value="" section of the INPUT. Now for SELECT I have a little problem, any small list that I prepopulate in the code are fine I have used this code below
<label>Fuel</label>
<select tabindex="1" id="propertyfueltype" name="propertyfueltype">
<option value=""></option>
<option value="1" <?php echo ($searchfuel == '1' ? 'selected' : '')?>>Mains gas</option>
<option value="2" <?php echo ($searchfuel == '2' ? 'selected' : '')?>>Wood or coal fire</option>
<option value="3" <?php echo ($searchfuel == '3' ? 'selected' : '')?>>Oil</option>
<option value="4" <?php echo ($searchfuel == '4' ? 'selected' : '')?>>Electric storage heaters</option>
<option value="5" <?php echo ($searchfuel == '5' ? 'selected' : '')?>>LPG or bottled gas</option>
<option value="6" <?php echo ($searchfuel == '6' ? 'selected' : '')?>>No central heating system</option>
</select>
As I said when I run the Sear records form and return the posted variables, this works great. My problem is with big data sets within SELECT which are from the database, this is what I have currently, which is perfect to get data into a SELECT but how can I post a variable to it in a similar way to the previous code?
<label>Fuel Type</label>
<?php $fueltype = db::getInstance()->query('SELECT * FROM lkup_fueltype');
if(!$fueltype->count()) { echo 'Problem'; } else { ?>
<select tabindex="1" id="propertyfueltype" name="propertyfueltype">
<?php foreach ($fueltype->results() as $fueltype) { ?>
<option value="<?php echo $fueltype->PropertyFuelType; ?>"><?php echo $fueltype->PropertyFuelType; ?></option>
<?php } } ?>
</select>

Like this:
<option
value="<?php echo $fueltype->PropertyFuelType; ?>"
<?php echo $fueltype->PropertyFuelType == $searchfuel ? "selected" : ""; ?>
><?php echo $fueltype->PropertyFuelType; ?></option>
Having said that, I would recommend using a PHP templating system; or at least convert this logic into a function.

Related

How to get certain data from database based on primary key from select option? [duplicate]

Is there any way to set the selected item in a drop down box using the following 'type' code?
<select selected="<?php print($row[month]); ?>"><option value="Janurary">January</option><option value="February">February</option><option value="March">March</option><option value="April">April</option></select>
The database holds a month.. and I want to allow on the edit page, them to choose this month.. but it to be pre-filled with their current setting?
You need to set the selected attribute of the correct option tag:
<option value="January" selected="selected">January</option>
Your PHP would look something like this:
<option value="January"<?=$row['month'] == 'January' ? ' selected="selected"' : '';?>>January</option>
I usually find it neater to create an array of values and loop through that to create a dropdown.
You mark the selected item on the <option> tag, not the <select> tag.
So your code should read something like this:
<select>
<option value="January"<?php if ($row[month] == 'January') echo ' selected="selected"'; ?>>January</option>
<option value="February"<?php if ($row[month] == 'February') echo ' selected="selected"'; ?>>February</option>
...
...
<option value="December"<?php if ($row[month] == 'December') echo ' selected="selected"'; ?>>December</option>
</select>
You can make this less repetitive by putting all the month names in an array and using a basic foreach over them.
You can use this method if you use a MySQL database:
include('sql_connect.php');
$result = mysql_query("SELECT * FROM users WHERE `id`!='".$user_id."'");
while ($row = mysql_fetch_array($result))
{
if ($_GET['to'] == $row['id'])
{
$selected = 'selected="selected"';
}
else
{
$selected = '';
}
echo('<option value="'.$row['id'].' '.$selected.'">'.$row['username'].' ('.$row['fname'].' '.substr($row['lname'],0,1).'.)</option>');
}
mysql_close($con);
It will compare if the user in $_GET['to'] is the same as $row['id'] in table, if yes, the $selected will be created. This was for a private messaging system...
Simple and easy to understand example by using ternary operators to set selected value in php
<?php $plan = array('1' => 'Green','2'=>'Red' ); ?>
<select class="form-control" title="Choose Plan">
<?php foreach ($plan as $id=> $value) { ?>
<option value="<?php echo $id;?>" <?php echo ($id== '2') ? ' selected="selected"' : '';?>><?php echo $value;?></option>
<?php } ?>
</select>
Its too old but I have to add my way as well :) because it is generic and useful especially when you are using static dropdown values.
function selectdCheck($value1,$value2)
{
if ($value1 == $value2)
{
echo 'selected="selected"';
} else
{
echo '';
}
return;
}
and in you dropdown options you can use this function like this and you can use this as many as you can because it fits with all of your select boxes/dropdowns
<option <?php selectdCheck($row[month],january); ?> value="january">january</option>
:) I hope this function help others
Simple way
<select class ="dropdownstyle" name="category" selected="<?php print($messageeditdetails[0]['category_id']); ?>">
<option value=""><?php echo "Select"; ?></option>
<?php foreach ($dropdowndetails as $dropdowndetails) { ?>
<option <?php if($messageeditdetails[0]['category_id'] == $dropdowndetails['id']) { ?> selected="<?php echo $dropdowndetails['id']; ?>" <?php } ?> value="<?php echo $dropdowndetails['id']; ?>"><?php echo $dropdowndetails['category_name']; ?></option>
<?php } ?>
</select>
This is the solution that I came up with...
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<select name="select_month">
<?php
if (isset($_POST['select_month'])) {
if($_POST["select_month"] == "January"){
echo '<option value="January" selected="selected">January</option><option value="February">February</option>';
}
elseif($_POST["select_month"] == "February"){
echo '<option value="January">January</option><option value="February" selected="selected">February</option>';
}
}
else{
echo '<option value="January">January</option><option value="February">February</option>';
}
?>
</select>
<input name="submit_button" type="submit" value="Search Month">
</form>
A Simple Solution:
It work's for me
<div class="form-group">
<label for="mcategory">Select Category</label>
<select class="form-control" id="mcategory" name="mcategory" required>
<option value="">Please select category</option>
<?php foreach ($result_cat as $result): ?>
<option value="<?php echo $result['name'];?>"<?php
if($result['name']==$mcategory){
echo 'selected';
} ?>><?php echo $result['name']; ?></option>
}
<?php endforeach; ?>
</select>
</div>
Check this:
<select class="form-control" id="department" name="department" type="text">
<option value="medical-furniture" #if($list->department == "medical-furniture") selected #endif>Medical furniture</option>
<option value="medical-table" #if($list->department == "medical-table") selected #endif>Medical table</option>
<option value="service" #if($list->department == "service") selected #endif>Service</option>
</select>
My suggestion is to leverage the hidden/collapse attribute. Try with this example:
<select>
<option value="echo $row[month]" selected disabled hidden><? echo $row[month] ?></option>
<option value="1">Jan</option>
<option value="2">Feb</option>
<option value="3">Mar</option>
</select>
in case of null for $row[month] the selected item is blank and with data, it would contain less codes for many options and always working for HTML5 and bootstrap etc...
If you have a big drop down. it's much easier to use jQuery with PHP.
This is how to do it:
<script>
$(document).ready(function () {
$('select[name="country"]').val('<?=$data[0]['Country']?>');
});
</script>
The easiest solution for the selected option in dropdown using PHP is following
<select class="form-control" name="currency_selling" required >
<option value="">Select Currency</option>
<option value="pkr" <?=$selected_currency == 'pkr' ? ' selected="selected"' : '';?> >PKR</option>
<option value="dollar" <?=$selected_currency == 'dollar' ? ' selected="selected"' : '';?> >USD</option>
<option value="pounds" <?=$selected_currency == 'pounds' ? ' selected="selected"' : '';?> >POUNDS</option>
<option value="dirham" <?=$selected_currency == 'dirham' ? ' selected="selected"' : '';?> >DRHM</option>
</select>
You can try this after select tag:
<option value="yes" selected>yes</option>
<option value="no">no</option>

Changing HTML <select> Element Using Only HTML/PHP

I'm trying to retrieve data from a SQL DB when the user types a category ID in to search with. It should then autofill (populate) the html form data with the retrieved data from the row's columns (upon pressing the submit button).
Everything is working properly, but I don't know how to change a dropdown menu
For example:
<input name="prodname" type="text" value="<?php echo $pName; ?>"/>
Fills the form value successfully after I press the search(submit) button.
This following code does not change the drop down values at all (<select> vs <input>)
<select name="supplierID" value="<?php $suppID; ?>">
How can I change the drop down values of a while only using HTML/PHP?
Thank you.
To select a option in <select> tag you need to set selected attribute to that option. The following code may help you to understand.
<select name="supplierID">
<option value="1" <?php if($suppID == 1) echo 'selected'; ?> >1</option>
<option value="2" <?php if($suppID == 2) echo 'selected'; ?> >2</option>
<option value="3" <?php if($suppID == 3) echo 'selected'; ?> >3</option>
<option value="4" <?php if($suppID == 4) echo 'selected'; ?> >4</option>
</select>
Hope this helps.
To select the values in drop down, the selected attribute is required. You may check with the code below:
<select name="supplierID">
<option value="1" <?php if($id == 1) echo "selected"; ?>> A </option>
<option value="2" <?php if($id == 2) echo "selected"; ?>> B </option>
<option value="3" <?php if($id == 3) echo "selected"; ?>> C </option>
</select>

Multiple options in select in php form

I have this simple code in my product_form.tpl php file of opencart 2.3:
<select name="type" id="type" class="form-control">
<?php if ($type) { ?>
<option value="1" selected="selected">Flower</option>
<option value="0">Plant</option>
<?php } else { ?>
<option value="1">Flower</option>
<option value="0" selected="selected">Plant</option>
<?php } ?>
</select>
Everything fine and simple, but i need at least 1 more option for this select to add:
<option value="2">Bouquet</option>
Could you please tell me how this should look like in case of 3 options... Thanks in advance!
You chose a bad approach as I wrote in comment under question.
<select name="type" id="type" class="form-control">
<option value="1" <?php echo isset($type) && $type == 1 ? 'selected' : '' ?>>Flower</option>
<option value="0" <?php echo isset($type) && $type == 0 ? 'selected' : '' ?>>Plant</option>
<option value="2" <?php echo isset($type) && $type == 2 ? 'selected' : '' ?>>Bouquet</option>
</select>
Another way is using array and write the dropdown using foreach loop.
isset($type) can be taken above the code, you need to check if variable exists to prevent notice of undefined variable.
There can be something like
$type = isset($type) ? $type : NULL; // or any default value like 0
In options then will be just <?php echo $type == 1 ? 'selected' : ''; ?>.
Sometimes it's easier to just write some structured code..
<?php
$options = array(
"1" => "flower",
"0" => "Plant",
"2" => "Bouquet",
"3" => "Rock"
);
$currentval = 2;
?>
<select name="type" id="type" class="form-control">
<?php
foreach($options as $val => $label):
?>
<option value="<?=$val;?>" <?=$currentval == $val ? 'selected' : ''?>><?=$label;?></option>
<?php
endforeach;
?>
You can use a siwtch case block instead of bunch of if's you can check the documentation here https://www.w3schools.com/PhP/php_switch.asp and you can compare the value of $type more organized ! Good Luck !
If you really want to go this way, then:
<select name="type" id="type" class="form-control">
<?php if ((int)$type === 0) { ?>
<option value="2">Bouquet</option>
<option value="1">Flower</option>
<option value="0" selected="selected">Plant</option>
<?php } elseif ((int)$type === 1) { ?>
<option value="2">Bouquet</option>
<option value="1" selected="selected">Flower</option>
<option value="0">Plant</option>
<?php } elseif ((int)$type === 2) { ?>
<option value="2" selected="selected">Bouquet</option>
<option value="1">Flower</option>
<option value="0">Plant</option>
<?php } ?>
</select>
But I would suggest using the way Jelmer Jellema suggested.

Whats the best way to show selected options on a form when reloaded using PHP

I would like the select option the user selected to be shown when the form is reloaded. I am currently using bootstrap select picker to style the drop down. Right now I am creating an array and echoing out a selected class based on the value stored in the database.
This is not a major problem with a small amount of options like the code provided below, however with a select box with larger amounts of options this obviously amounts to lots of extra code.
There must be a smarter way to do this than the code i'm using below. Can anyone help?
<select class="selectpicker" name="Do_You_Have_A_Job_Spec_You_Can_Email">
<option value="" <?php if ($user_data_array['Do_You_Have_A_Job_Spec_You_Can_Email'] == '') echo "selected='selected'"; ?>>Please Select</option>
<option value="Yes" <?php if ($user_data_array['Do_You_Have_A_Job_Spec_You_Can_Email'] == 'Yes') echo "selected='selected'"; ?>>Yes</option>
<option value="No" <?php if ($user_data_array['Do_You_Have_A_Job_Spec_You_Can_Email'] == 'No') echo "selected='selected'"; ?>>No</option>
</select>
If the option's are static you could use ternary operators, so it will be something like :
<?php $selected_option = $user_data_array['Do_You_Have_A_Job_Spec_You_Can_Email']; ?>
<select class="selectpicker" name="Do_You_Have_A_Job_Spec_You_Can_Email">
<option value="" <?php echo $selected_option==''?'selected':''; ?>>Please Select</option>
<option value="Yes" <?php echo $selected_option=='Yes'?'selected':''; ?>>Yes</option>
<option value="No" <?php echo $selected_option=='No'?'selected':''; ?>>No</option>
</select>
Hope this helps.
<?php
$text = $user_data_array['Do_You_Have_A_Job_Spec_You_Can_Email'];
?>
<select class="selectpicker" name="Do_You_Have_A_Job_Spec_You_Can_Email">
<option value="">Please Select</option>
<option value="Yes" <?php echo $text == 'Yes' ? 'selected' : ''; ?>> Yes </option>
<option value="No" <?php echo $text == 'No' ? 'selected' : ''; ?>> No </option>
</select>
Alternative Way
"..however with a select box with larger amounts of options this
obviously amounts to lots of extra code.".
In this case, when you are having lots of data for dropdown. You can create a table where you can have both option name and option value.
job_specification_table
id option_value option_name
1 Please Select
2 Yes Yes
3 No No
.
.
.
Then, retreive those values and check for user_data and according to it, option will get selected.
<?php
$sql = "SELECT * FROM job_specification_table";
$result = mysqli_query($db_con,$sql);
$text = $user_data_array['Do_You_Have_A_Job_Spec_You_Can_Email'];
?>
<select class="selectpicker" name="Do_You_Have_A_Job_Spec_You_Can_Email">
<?php
while ($row = mysqli_fetch_array($result)){
$option_value = $row['option_value'];
$selected = ($option_value == $text) ? "selected" : "";
?>
<option value="<?=$option_value;?>" <?=$selected;?>>
<?=$row['option_name'];?>
</option>
<?php }?>
</select>
Here is more readable solution:
<select class="selectpicker" name="Do_You_Have_A_Job_Spec_You_Can_Email">
<option value=
<?php
$choise = $user_data_array['Do_You_Have_A_Job_Spec_You_Can_Email'];
switch ($choise) {
case 'Yes':
echo '"Yes" selected="selected" >Yes';
break;
case 'No':
echo '"No" selected="selected" >No';
break;
case '':
echo '"" selected="selected" >Please Select';
break;
}
?>
</option>
</select>

Show current database record

For the 'wachtwoord' input field, the value is the current database record. But how can I show the current record for the 'Jaar' select field? It's currently showing one, but it has to be two.. Anyone know how to solve this?
<label for="password">Wachtwoord</label>
<input type="password" id="password" name="password" value="<?php echo $t['gids_password'] ?>"/>
<br/>
<label for="jaar">Jaar</label>
<select name="jaar" id="jaar">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>
You would need to compare the result from the database with the value of the options. If it matches, you need to echo 'selected'; Like so:
<option value="1" <?php if($t['gids_jaar']==1){ echo 'selected'; } ?> >1</option>
<option value="2" <?php if($t['gids_jaar']==2){ echo 'selected'; } ?> >2</option>
<option value="3" <?php if($t['gids_jaar']==3){ echo 'selected'; } ?> >3</option>
NOTE:
$t['gids_jaar'] would be the value of the database. Dont forget to put space between the closing php tag and the end of the option open tag. So this part has to have a space:
?> >3</option>
there has to be a space between the ?> and >
The answer of Daan works as well but I just wanted to add some additional information.
You need to add a selected to one of your option tags, most easy is with a ternary operator:
<option value="1" <?php echo ($t['myvalfromdb'] == 1) ? 'selected' : ''; ?> >1</option>
<option value="2" <?php echo ($t['myvalfromdb'] == 2) ? 'selected' : ''; ?> >1</option>
<option value="3" <?php echo ($t['myvalfromdb'] == 3) ? 'selected' : ''; ?> >1</option>

Categories