I have a Description table which contains certain descriptions along with a unique ID. I have another table that contains two foreign keys to this table. So far i have the following query:
SELECT
Description.description AS Description,
Object.objID AS ID,
Description.description AS Location
FROM
Object
INNER JOIN
Description
ON
Object.objDescID=Description.descID
AND
Object.objLocID=Description.descID;
However this is not working, please can someone point me in the right direction?
If I understand right you want to join to the Description table twice for the same object. Give this a shot and see if it gets you what you're after:
SELECT
Object.objID AS ID,
od.description AS Description,
ld.description AS Location
FROM Object
INNER JOIN Description AS od
ON Object.objDescID=od.descID
INNER JOIN Description AS ld
ON Object.objLocID=ld.descID;
Edit: A word of advice, if you allow for null foreign keys you should use a LEFT JOIN instead of an INNER JOIN, that way if one of them is null it doesn't keep the entire record from showing.
Try Running This (might need minor adjustments):
SELECT
Description.description AS Description,
Object.objID AS ID,
Description.description AS Location
FROM
Object
INNER JOIN
Description AS Object.objDescID=Description.descID
INNER JOIN
Description AS Object.objLocID=Description.descID;
Looks like you need two references to the Description table. Each reference will be joined using one of the foreign key columns.
For example:
SELECT o.objID AS `ID`
, d.description AS `Description`
, l.description AS `Location`
FROM Object o
JOIN Description d
ON d.descID = o.objDescID
JOIN Description l
ON l.descID = o.objLocID
We assign the short alias d to the source we get the Description value from.
We assign the short alias l to the source we get the Location value from.
We reference columns from each table using the short alias, rather than the table name.
Essentially, think of the references to the Description table like it's two different tables, even though it's really the same table.
Note that we have to assign an alias to at least one of the references to Description, so that we can distinguish between them. (Otherwise, MySQL won't know which one we're talking about if we just said Description.description.)
Note that if the foreign key column objDescID or objLocID has a NULL value, or a matching value doesn't exist in the referenced table, the query won't return the row from Object.
To ensure you get a row from Object even when the matching values aren't found, you can use an OUTER join operation by including the LEFT keyword.
For example:
SELECT o.objID AS `ID`
, d.description AS `Description`
, l.description AS `Location`
FROM Object o
LEFT
JOIN Description d
ON d.descID = o.objDescID
LEFT
JOIN Description l
ON l.descID = o.objLocID
Note that only one alias is actually required, but I tend to assign short aliases to all row sources in a query. This makes the statement more decipherable, and really helps if I later need to add another reference to a table that is already used, or if I need to replace one of the table names with a different table name or an inline view (or subquery), I can leave the alias the same, and change just the rowsource. The other aliases don't make any difference in the actual execution of the statement, they are just there because I follow the same pattern for simple queries that I follow for more complex queries.
Related
I have several different tables in my database(mySQL).
Here are the relevant coumns for the tables
table_tournaments
tournamentId
tournamnetName
tournamentStatus
table_tournament_results
tournamentId
playerId
playerName
playerRank
tournamnetParticipants
table_players
playerId
playerName
The tournaments table contains the information about the tournament, the tournament results table shows the results from that table
I want to search the tournaments table by name and then with the returned results get the information from the tournament results table.
SELECT * FROM `tournaments` `WHERE` `tournamentName` LIKE "%Query%"
I'm not sure how to go about this, maybe I need to do something via PHP, any and all help is appreciated.
You can get the results you want with a join operation.
This is an example of an outer join, returning all rows from t that have the string 'foo' appearing as part of tournament_name, along with any matching rows from r.
A relationship between rows in the two tables is established by storing a common value in the tournamentId column of the two tables. The predicate in the ON clause specifies the condition that determines if a row "matches".
SELECT t.tournamentId
, t.tournamentName
, t.tournamentStatus
, r.playerId
, r.playerName
, r.playerRank
FROM table_tournaments t
LEFT
JOIN table_tournament_results r
ON r.tournamentId = t.tournamentId
WHERE t.tournament_name LIKE '%foo%'
ORDER
BY t.tournamentId
, r.playerId
The t and r that appear after the table names are table aliases, we can qualify references to the columns in each table by prefacing the column name with the table alias and a dot. This makes the column reference unambiguous. (In the case of tournamentId, MySQL doesn't know if you are referring to the column in t or r, so we qualify it to make it explicit. We follow this same pattern for all column references. Then, someone reading the statement doesn't need to wonder which table contains the column playerId.
Your Query may be like this
SELECT a.*, b.tournamnetName FROM table_tournament_results a
left join table_tournaments on a.tournamentId=b.tournamentId
WHERE b.tournamnetName LIKE "%Query%"
Imagine I have the following SELECT statement which has been oversimplified.
SELECT a.Name, b.Name FROM table a LEFT JOIN table b ON a.ID=b.TID
using php I run the following:
while ($result = mysql_fetch_array($results)) {
echo $result["Name"];
}
this will give me the result of b.Name. I am aware I can use a.Name AS aName, B.Name AS bName however this might sometimes complicate things where you have a long query and you use a.*. I tried using $result["a.Name"] but it does not work. I am aware this works $result[0] but again this is not always possible without complicating things.
Is there any other way I can show a.Name please?
simple answer : no.
long answer : the array index at PHP has to be unique. By this, the last similar name column will get the precedence.
If two or more columns of the result have the same field names, the last column will take precedence. To access the other column(s) of the same name, you must use the numeric index of the column or make an alias for the column. For aliased columns, you cannot access the contents with the original column name.
source
However, you can solve this by using aliases.
SELECT a.Name as aName, b.Name as bName FROM table a LEFT JOIN table b ON a.ID=b.TID
then you can access the names from both tables by using $result["aName"] and $result["bName"]
Based on your requirements, you could consider dividing your query in to two fetch statements. This would allow you to have the duplicate column names.
SELECT a.* FROM table a LEFT JOIN table b ON a.ID=b.TID
SELECT b.* FROM table b LEFT JOIN table a ON a.ID=b.TID
I've been scratching my head at this problem all day and I simple just can't work it out. This is the first time I've attempted to try and use SQL Joining, while we do kinda get taught the basics I'm more into pushing a little more into the advanced stuff.
Basically I'm making my own forum, and I have two tables. f_topics (The threads) and f_groups (The forums, or categories). There is a relationship between topicBase in f_topics and groupID in f_groups, this shows which group each topic belongs to. Each topic has a unique ID called topicID and same for the groups, called groupID.
Basically, I'm trying to get all these columns into a single SELECT statement - The title of the topic, the date the topic was posted, the ID of the group the topic belongs in, and the name of that group. This is what I was trying to use, but the group always comes back as 1, even if the topic is in groupID 2:
$query=mysqli_query($link, "
SELECT `topicName`, `topicDate`, `groupName`, `groupID`
FROM `f_topics`
NATURAL JOIN `f_groups`
WHERE `f_topics`.`topicID`='$tid';
") or die("Failed to get topic detail E: ".mysqli_error());
var_dump(mysqli_fetch_assoc($query));
Sorry if this doesn't make much sense, and if my entire logic is completely wrong, if so could you suggest an alternate method?
Thanks for reading!
To join tables, you need to map the foreign keys. Assuming your groups table has an groupID field, this is how you'd join them:
SELECT `topicName`, `topicDate`, `groupName`, `groupID`
FROM `f_topics`
LEFT JOIN `f_groups`
ON `f_topics`.`groupID` = `f_groups`.`groupID`
WHERE`f_topics`.`topicID`='$tid';
So from what I gather there is a column in f_topics named "topicBase" which references the groupID column from the f_groups table.
Based on that assumption, you can perform either an INNER JOIN or a LEFT JOIN. INNER requires there be an entry in both tables while LEFT requires there only be data in f_topics.
SELECT
f_topics.topicName,
f_topics.topicDate
f_groups.groupName
f_groups.groupID
FROM
f_topics
INNER JOIN
f_groups
ON
f_topics.topicBase = f_groups.groupID
WHERE
f_topics.topicID = '$tid'
I recommend you avoid NATURAL JOIN.
Primarily because a working query can be broken by the addition of a new column in a referenced table, which matches a column name in the other referenced table.
Secondly, for any reader (reviewer) of the SQL, which columns are being matched to which columns is not clear, without a careful review of both tables. (And, if someone has added a column that has broken the query, it makes it even more difficult to figure out what the JOIN criteria used to be, before the column was added.
Instead, I recommend you specify the column names in a predicate in the ON clause.
It's also good practice to qualify all column references by table name, or preferably, a shorter table alias.
For simpler statements, I agree that this may look like unnecessary overhead. But once statements become more complicated, this pattern VASTLY improves the readability of the statement.
Absent the definitions of the two tables, I'm going to have to make assumptions, and I "guess" that there is a groupID column in both of those tables, and that is the only column that is named the same. But you specify that its the topicBase column in f_topics that matches groupID in f_groups. (And the NATURAL JOIN won't get you that.)
I think the resultset you want will be returned by this query:
SELECT t.`topicName`
, t.`topicDate`
, g.`groupName`
, g.`groupID`
FROM `f_topics` t
JOIN `f_groups` g
ON g.`groupID` = t.`topicBase`
WHERE t.`topicID`='$tid';
If its possible for the topicBase column to be NULL or to contain a value that does not match a f_groups.GroupID value, and you want that topic returned, with the columns from f_group returned as NULL (when there is no match), you can get that with an outer join.
To get that behavior, in the query above, add the LEFT keyword immediately before the JOIN keyword.
I'm currently struggling to figure out a solution to a situation I'm in. I'll give you some background on the database structure:
Table 'Entities' has columns Ent_ID (AI, Int), Ent_Type (Enum, 'Locations, Characters, Houses, Armies') and Obj_ID (Int).
The Obj_ID matches the ID from the relevant table. For example the 'Locations' table has columns Obj_ID (AI, Int), Loc_Name (Text) and Loc_Desc (Text).
Characters can be in different locations depending on the date, so I have a 'TimeSensitives' table to store these kind of things. This table has columns TS_ID (AI, Int), Ent_ID (Int), TS_Start (Float), TS_End (Float) and TS_Content (Text). The Ent_ID is which character is being some information (such as location). The Ent_ID of the location goes into TS_Content.
So, as you might imagine, I have many locations each with different characters there at different dates. My problem is that I want to be to search for a location that either has a name LIKE the search filter or has a character there that has a name LIKE the search filter.
Up until now I have looped through each Entity with type 'Locations' and then for each one I have looped through all characters currently there. This is my code:
SELECT *
FROM Entities
INNER JOIN Locations
ON Entities.Obj_ID=Locations.Obj_ID
WHERE Entities.Ent_Type='Locations'
AND Loc_Name LIKE ?
Then for each one:
SELECT *
FROM TimeSensatives
INNER JOIN Entities
ON TimeSensatives.Ent_ID=Entities.Ent_ID
INNER JOIN Characters
ON Entities.Obj_ID=Characters.Obj_ID
WHERE TS_Type='Location'
AND TS_Content=?
AND TS_Start<=?
AND TS_End>=?
So as you might have seen, this currently only takes the search filter into account when selecting places.
I would now like to implement the search filter onto the characters too but it needs to show places that don't necessarily have matching name but do have a character there with a matching name. I hope that makes sense. My current code wont select any locations without a matching name so there's no chance to search for matching character names.
Is there any way to combine this into one sql statement? Or can somebody think of a way to achieve what I'm trying to do?
Any help would be greatly appreciated and if you need any more info then please ask :)
Kallum
SELECT
Entities.*,
Locations.Loc_Name as Loc_Name
FROM
Entities
INNER JOIN Locations ON Entities.Obj_ID=Locations.Obj_ID
WHERE
Entities.Ent_Type='Locations'
AND Loc_Name LIKE ?
UNION
SELECT
LocEnt.*,
Locations.Loc_Name as Loc_Name
FROM
TimeSensatives
INNER JOIN Entities AS CharEnt ON TimeSensatives.Ent_ID=CharEnt.Ent_ID
INNER JOIN Characters ON Entities.Obj_ID=Characters.Obj_ID
INNER JOIN Entities AS LocEnt ON TS_Content.Ent_ID=LocEnt.Ent_ID
INNER JOIN Locations ON LocEnt.Obj_ID=Locations.Obj_ID
WHERE
TS_Type='Location'
AND TS_Start<=?
AND TS_End>=?
AND Char_Name LIKE ?
will give you all needed locations plus their names
What I want to do is to query three separate tables into one row which is identified by a unique reference. I don't really have full understanding of the Join clause as it seems to require some sort of related data from each table.
I know I can go about this the long way round, but can not afford to lose even a little efficiency. Any help would be greatly appreciated.
Table Structure
package_id int(8),
client_id int(8),
unique reference varchar (40)
Each of the tables have essentially the same structure. I just need to know how to query all three, for 1 row.
If you have few tables that are sharing the same or similar definition, you can use union or union all to treat them as one. This query will return rows from each table having requested reference. I've included OriginTable info in case your code will need to refer to original table for update or something else.
select 'TableA' OriginTable,
package_id,
client_id
from TableA
where reference = ?
union all
select 'TableB' OriginTable,
package_id,
client_id
from TableB
where reference = ?
union all
select 'TableC' OriginTable,
package_id,
client_id
from TableC
where reference = ?
You might extend select list with other columns, provided that they have the same data type, or are implicitly convertible to data type from first select.
Let's say you have 3 tables :
table1, table2 and table3 with structure
package_id int(8),
client_id int(8),
unique reference varchar (40)
Let's assume that column reference is unique key.
Then you can use this:
SELECT t1.exists_row ,t2.exists_row ,t3.exists_row FROM
(
(SELECT COUNT(1) as exists_row FROM table1 t1 WHERE
t1.reference = #reference ) t1,
(SELECT COUNT(1) as exists_row FROM table1 t2 WHERE
t2.reference = #reference ) t2,
(SELECT COUNT(1) as exists_row FROM table1 t3 WHERE
t3.reference = #reference ) t3
) a
;
Replace #reference with actual value of unique key
or when you provide output of
SHOW CREATE TABLE
I can rewrite SQL with actual query
It is entirely possible to create a join between tables using a where clause. In fact this is often what I do as I find it leads to clearer information of what you are actually doing, and if you don't get the results you expect you can debug it bit by bit.
That said however a join is certainly a lot quicker to write!
Please bear in mind I'm a bi rusty on SQL so I may have missed remembered, and I'm not going to include any code as you haven't said what DBMS you are using as they all have slightly different code.
The thing to remember is that the join functions on a column with the same data (and type) within it.
It is much easier if each table has the 'joining' field named the same, then it should be a matter of
join on <nameOfField>
However if you wish to use field that have different names in the different tables you will need to list the fully qualified names. ie tableName.FieldName
If you are having trouble with natural, inner and outer, left and right, you need to think of a venn diagram with the natural being the point of commonality between the tables. If you are using only 2 tables inner and outer are equivalent to left and right (with each table being a single circle in the venn diagram) and left and right being the order of the tables in your list in the main part of your select (the first being the left and the second being the right).
When you add a third table this is where you can select any of the cross over section using these keywords.
Again however I have always found it easier to do a primary select and create a temp table, then perform my next join using this temp table (so effectively only need to use natural or left and right again). Again I find this easier to debug.
The best thing is to experiment and see what you get in return. Without a diagram of your tables this is the best I can offer.
in brief...
nested selects where field = (select from table where field = )
and temp tables
are (I think) easier to debug... but do take more writting !
David.
array_of_tables[]; // contain name of each table
foreach(array_of_tables as $val)
{
$query="select * from `$val` where $condition "; // $conditon
$result=mysqli_query($connection,$query);
$result_row[]=mysqli_fetch_assoc($result); // if only one row going to return form each table
//check resulting array ,for your row
}
SELECT * FROM table1 t1 JOIN table2 t2 ON (t2.unique = t1.unique) JOIN table3 t3 ON (t3.unique = t1.unique) WHERE t1.unique = '?';
You could use a JOIN like this, assuming all three tables have the same unique column.