MySQL query fails silently in php - php

Question

This is my PHP code written for website. When I executed this, the query doesn't execute and doesn't show any error. I also checked data types of values that are to be inserted.
The database username and password and all credentials are correct. What could be the problem?
<?php
$password ='abcdef';
$host="localhost"; // Host name
$username="futureti_dsatya"; // Mysql username
$password="D2e3e4v1i"; // Mysql password
$db_name="futureti_db"; // Database name
$tbl_name="users"; // Table name
// Connect to server and select databse.
$con = mysqli_connect($host, $username, $password,$db_name);
if(!$con)
{
die('Could not connect: '. mysql_error());
}
else
{
$res = mysqli_query($con,"insert into users values(55555623,'saran1','satya_saran',$password)");
if($res){
print("i am ok");
}
else{
print("bad");
}
}
?>

Answer 1

Wrap $pass in quotes (55555623,'saran1','satya_saran','$pass') as shown below with an explanation about "$password", and change mysql_error()); to mysqli_error()); those two functions don't mix and that is why you did not get the proper error messages to show up.
As already stated, you're using $password twice; change one of the variables to something else.
What you're presently doing is overwriting your $password variable.
I am assuming you want to enter abcdef into your DB. If so, then do this instead:
<?php
$pass ='abcdef';
$host = "localhost"; // Host name
$username = "futureti_dsatya"; // Mysql username
$password = "D2e3e4v1i"; // Mysql password
$db_name = "futureti_db"; // Database name
$tbl_name = "users"; // Table name
// Connect to server and select databse.
$con = mysqli_connect($host, $username, $password,$db_name);
if ( !$con ) {
die('Could not connect: '. mysqli_error());
} else {
$res = mysqli_query($con, "insert into users values (55555623,'saran1','satya_saran','$pass' )");
if( $res ) {
print("i am ok");
} else {
print("bad");
}
}
?>
Also, inserting data into a table without telling it which columns to use is not a recommended method.
Use something to the effect of:
($con, "insert into users (column1, column2, column3, column4) values (55555623,'saran1','satya_saran','$pass' )
Sidenote: If the column for your first value isn't an (int) you will need to wrap that in quotes as well.
Also, if your first column is an AUTO_INCREMENT, you will need to remove the AUTO_INCREMENT from the column's type.

Answer 2

you dont get any error because you are making using mysql. not mysqli.
your code is wroking just wrap password . i guess the connection is not connecting.
replace this:
die('Could not connect: '. mysql_error());
to
die('Could not connect: '. mysqli_error()); //to see the error