Testing class who extends another class(PHPUNIT) - php

i'm having problems testing in phpUnit , i have "class class_A extends Class_B"
and i don't know how to test that , i tried to mock class b like this
$this-> mock = $this-> getmock('class_A',array('Class_B'));
but when i run the test ,the test fail and return this
Missing argument 1 for class_b::__construct(),
anyone have an idea of how i can do it?
(sorry if my English sucks!!)

I think this is what you are looking for:
assertInstanceOf
(seen in: https://stackoverflow.com/a/7680164/3454966)
Edit: use any valid arguments in the constructor, if you only want to test the inheritance.

You can disable the constructor as explained in the docs:
$stub = $this->getMockBuilder('Class_A')
->disableOriginalConstructor()
->getMock();

I test that the class inherited properly, and that parent functions are there.
protected $TestObject;
protected function setUp()
{
$this->TestObject = new MyLib\Class_B; // Namespaces being used?
}
public function testClassInstance()
{
$this->assertInstanceOf('MyLib\Class_A', $this->TestObject);
$this->assertInstanceOf('MyLib\Class_B', $this->TestObject);
}
// For Instance: These are from the Class A that was extended
public function testClassAWorks()
{
$this->assertEquals('String', $this->TestObject->GetString(), 'Ensure the Class_A inherited function is returning String');
$this->assertFalse($this->TestObject->IsFalseFunction());
}
// These are from the Class B
public function testClassBWorks()
{
$this->assertEquals('Number', $this->TestObject->GetString2(), 'Ensure the Class_B function is returning Number');
$this->assertTrue($this->TestObject->IsTrueFunction());
}

Related

PHPUnit: Is it possible to mock a php function to return a mocked object in replacement of the normal object?

I have a constructor in the class someClass that calls a function (initObjectFunc), which its only purpose is to return a newly created instance of Thing class, and places its that object into a property (thingObject) in the constructor.
class someClass {
public function __construct() {
$this->thingObject = $this->initObjectFunc();
}
function initObjectFunc() {
return new Thing();
}
}
class Thing {
public function __construct() {}
function funcB() {
... funcB normal implementation ...
return value;
}
}
I also have a separate function (funcA), also in the someClass class, that uses thingObject to call its inner function (funcB).
.
.
.
function funcA() {
$data = $this->thingObject->funcB();
... other stuff ....
}
In a PHPUnit test class, I had mocked the Thing class and its funcB to return mocked data ('test test test test') when it gets called through the execution of funcA. To connect all the pieces together, I mocked the initObjectFunc to return that mocked Thing class object.
class unitTest extends PHPUnit_Framework_TestCase {
$mockThing = $this->getMockBuilder('Thing')
->setMethods(array('funcB'))
->getMock()
->expects($this->any())
->method('funcB')
->will($this->returnValue('test test test test'));
$mockSomeClass = $this->getMockBuilder('someClass')
->setMethods(array('initObjectFunc'))
->getMock()
->expects($this->any())
->method('initObjectFunc')
->will($this->returnValue($mockThing));
}
This setup was created with this execution flow in mind:
$mockSomeClass calls-> funcA() calls-> *mocked*funcB through *mocked*Thing class
Use the $mockSomeClass to call funcA (which, in PHPUnit, should not have been stubbed and should have full functionality), which would call the funcB. However, since I mocked Thing class and its funcB, it should be calling the mocked funcB to return 'test test test test'.
This is not the case when I try to run the tests. It breaks without any errors. Not even the line that says how many tests, assertions, skips, & fails have occurred.
I had also tried this variation, but to no avail:
class someClass {
public function __construct() {}
function initObjectFunc() {
return new Thing();
}
function funcA() {
$thingObject = initObjectFunc();
$data = $thingObject->funcB();
... other stuff ....
}
}
This variation tries to take the functionality from the constructor and move it into funcA so that the initObjectFunc() gets called and should return a mocked Thing instance before using it to call funcB. This was done under the thought that maybe the someClass constructor gets called before any of the mocks can be made.
I don't know why or how these components are not connecting. Has anyone tried unit testing with this structure and achieved success? I know that a simple refactor of code to become "dependency injection"-friendly would solve this issue, but this is a question just to find out if this path to unit testing works.

Tell phpunit to call public instead of private

My Question is. I have a class i want to test (myClass). In myClass there is a function wich calls a private function thats also in the myClass.
I know i can't test private functions. Is it possible to tell phpunit to call another function instead of the private?
Example
$this->testclass is now the class i want to test
$this->testclass = new \stdClass();
$this->testclass->mock = $this->getMockBuilder('myClass')->getMock();
Outside my testcase i have created a fake class.
$this->mockextended = new \stdClass();
$this->mockextended->mock = new MOCKEXTENDEDCLASSES();
in the $this->mockextended i have a public function.
the function i want to test
public function TestMe(){
$this->somePrivateFunctioniHate(); <==== this is the pain in my ass
}
and the private function
private function somePrivateFunctioniHate(){
//come code
}
What i want to do is. the function TestMe is calling a private function.
Is it possible to tell phpunit to override the private function and call another function thats inside $this->mockextended;
I have tried it like this.
$this->testclass->somePrivateFunctioniHate() = $this->mockextended->theWholeNewPrivateFunction()
only this gives me a nice error. I did this before and it worked. Called it like this
EDIT
For people who don't understand my question.
I have another function that calls another class. I din't want to have another class in my test so i created a fake Class outside my testcase. Inserted the same functions as the class the function wants to include. Did it like this
$this->testclass->chunks = new \stdClass();
//MOCKchunckTpl is the fake class outside my testcase
$this->testclass->chunks->config = new MOCKchunkTpl();
This works. Whenever a function wants to call $this->testclass->chunks->config->Somefunction(); it will be redirected to my fake class.
BUT when i try to do the same with a function thats calling a private function. Like $this->testclass->somePrivateFunctioniHate() = $this->mockextended->theWholeNewPrivateFunction() it gives a nice error
Fatal error: Can't use method return value in write context in
Short answer: No, there isn't. There is no way for PHPUnit to manipulate private methods.
Mocks are for faking the behavior of classes, which depend on the class you want to test. If you need to overwrite a private method, there is something wrong in your architecture. Private methods should be tested by simple testing the public methods in which they are used. If you need to test it separately, declare it public.
EDIT: Here is an example how you'd test a simple code using a private method or putting this private method in another class:
1. Private method
class MyClass {
public function myMethod() {
return $this->myPrivateMethod();
}
private function myPrivateMethod() {
return 2;
}
}
And the test class:
class MyClassTest extends \PHPUnit_Framework_TestCase {
public function testMyMethod() {
$myClass = new MyClass();
// don't mind the private method, just test if the public method is working
$this->assertEquals(2, $myClass->myMethod());
}
}
1. Second class
class MyClass {
public $dependentClass;
public function myMethod() {
return $this->dependentClass->dependentMethod();
}
}
And the dependent class:
class DependentClass {
public function dependentMethod() {
return 38943;
}
}
Testing MyClass with the DependentClass:
class MyClassTest extends \PHPUnit_Framework_TestCase {
public function testMyMethod() {
$dependentMock = $this->getMockBuilder("DependentClass")->getMock();
$dependentMock->expects($this->any())
->method("dependentMethod")
->willReturn($this->returnValue(2));
$myClass = new MyClass();
$myClass->dependentClass = $dependentMock;
$this->assertEquals(2, $myClass->myMethod());
}
Although we defined a whole other return in DependentClass, the test will still pass, because we mocked it and are able to define every behavior we'd expect DependentClass to have.
But to cleanly test the project, we need to define another test for DependentClass as well to test, if this class is working. This test should fail if it is not working anymore, not the test for MyClass.

Unable to test static method using Mock class in PHPUnit

I'm trying to test a static method on a class, but it relies on a static array property that doesn't get reset between tests, so I though I could create a mock class & test against that.
The only problem is that the mock class static method is not returning the value as the original static method does.
Here's my class...
class Thing {
static public function doThing() {
return 'yeah!';
}
}
... and here's be test class...
class ThingTest {
public function testDoSomething() {
$mock_class = $this->getMockClass('Thing');
$this->assertEqual('yeah!', $mock_class::doThing())
}
}
This test fails with the message "Failed asserting that null matches expected 'yeah!'."
What am I missing here? I thought not specifying the methods on the getMock() call meant that the original methods carried over, but clearly not. :o(
Any pointers would be great. Thanks.
Edit
I typed this up from memory, rather than from copying code, as I'd made further change to try to resolve this. After writing more tests for mock objects I realised that if you pass array() as the second parameter ($methods) to getMock[Class] then it stubbed out all the methods, & I believe this is what I had actually done. I was doing this, as I also wanted to pass the constructor parameter in the 3rd argument. The code probably looked more like this...
class ThingTest {
public function testDoSomething() {
$mock_class = $this->getMockClass(
'Thing',
array(),
array( 'something' )
);
$this->assertEqual('yeah!', $mock_class::doThing())
}
}
Maybe $mock_class is an object, not a string class name? Try to use next:
class ThingTest {
public function testDoSomething() {
$mock_class = $this->getMockClass('Thing');
$this->assertEqual('yeah!', Thing::doThing())
}
}
Is this work?
You forgot extending by PHPUnit_Framework_TestCase.
class ThingTest extends PHPUnit_Framework_TestCase {
public function testDoSomething() {
$mock_class = $this->getMockClass('Thing');
$this->assertEqual('yeah!', $mock_class::doThing())
}
}
You shouldn't mock the class containing the method you want to test. If you mock the class, you can't call any method either before you haven't defined it via
-> expects('methodName')
-> with($this->equalTo($parameter),[$this->equalTo($parameter2),...])
-> will($this->returnValue($value))
. Mocking is used to reduce complexity of a test. Let's say you want to test a function that looks like this:
class test{
private $someClass;
public function __construct(SomeInterface $someClass){
$this -> someClass = $someClass;
}
public function test(){
$someVariable = $this -> someClass -> doSomething();
changeSomething($someVariable);
return $someVariable;
}
}
If you don't mock someClass, you'd have to test the whole code of someClass -> doSomething. But that is not what you want to do. You just want to use the return of the function doSomething. That is the point where you need a mock. It reduces the complexity of your test and offers REAL UNIT tests instead of testing the whole app.
So what you need to do is:
class ThingTest {
public function testDoSomething() {
$class = new Thing();
$this->assertEquals('yeah!', $class::doThing());
}
}
There is no need for a mock.

getMock - multiple instances of the same class

If I have a class A that interacts with class B then in my tests I want to mock class B so that I can test class A in isolation.
This is easy to do in PHPUnit with "getMock('classname')".
My problem currently is: If class A uses multiple instances of class B I can't simulate this with "getMock('B')" because it appears that "getMock" will not return multiple instances if called multiple times but always the same mock of class B.
Following Example:
<?php
class A()
{
private class_b_1;
private class_b_2;
public function setClassB1(B $class_b)
{
$this->class_b_1 = $class_b;
}
public function setClassB2(B $class_b)
{
$this->class_b_2 = $class_b;
}
}
And in my tests:
$mock_one_of_class_b = $this -> getMock('B');
$mock_two_of_class_b = $this -> getMock('B');
Then $mock_one_of_class_b is the same object as $mock_two_of_class_b.
How can I mock multiple instances of a class with PHPUnit?
Thanks in advance!
Actually the getMock method creates different instances of mocked class. Take a look on this example:
class Foo
{
protected $value;
public function setValue($value)
{
$this->value = $value;
}
public function getValue()
{
return $this->value;
}
}
Now we create test for it:
class FooTest extends \PHPUnit_Framework_TestCase
{
public function testFoo()
{
$a = $this->getMock('Foo', array('someNonExistingMethod'));
$b = $this->getMock('Foo', array('someNonExistingMethod'));
$a->setValue(1);
$b->setValue(234);
$this->assertEquals(1, $a->getValue(), 'This test will fail if "a" and "b" objects are the same');
}
}
Pay attention on the second argument in getMock method. In that argument you tell phpunit which methods will be mocked. If you don't pass any argument at all - then phpunit assume you want mock all methods from the object. So, if you pass array('someNonExistingMethod') then there won't be any mocked method (and "real" methods will be called on invocations).

PHPUnit Mock Objects and Static Methods

I am looking for the best way to go about testing the following static method (specifically using a Doctrine Model):
class Model_User extends Doctrine_Record
{
public static function create($userData)
{
$newUser = new self();
$newUser->fromArray($userData);
$newUser->save();
}
}
Ideally, I would use a mock object to ensure that fromArray (with the supplied user data) and save were called, but that's not possible as the method is static.
Any suggestions?
Sebastian Bergmann, the author of PHPUnit, recently had a blog post about Stubbing and Mocking Static Methods. With PHPUnit 3.5 and PHP 5.3 as well as consistent use of late static binding, you can do
$class::staticExpects($this->any())
->method('helper')
->will($this->returnValue('bar'));
Update: staticExpects is deprecated as of PHPUnit 3.8 and will be removed completely with later versions.
There is now the AspectMock library to help with this:
https://github.com/Codeception/AspectMock
$this->assertEquals('users', UserModel::tableName());
$userModel = test::double('UserModel', ['tableName' => 'my_users']);
$this->assertEquals('my_users', UserModel::tableName());
$userModel->verifyInvoked('tableName');
I would make a new class in the unit test namespace that extends the Model_User and test that. Here's an example:
Original class:
class Model_User extends Doctrine_Record
{
public static function create($userData)
{
$newUser = new self();
$newUser->fromArray($userData);
$newUser->save();
}
}
Mock Class to call in unit test(s):
use \Model_User
class Mock_Model_User extends Model_User
{
/** \PHPUnit\Framework\TestCase */
public static $test;
// This class inherits all the original classes functions.
// However, you can override the methods and use the $test property
// to perform some assertions.
}
In your unit test:
use Module_User;
use PHPUnit\Framework\TestCase;
class Model_UserTest extends TestCase
{
function testCanInitialize()
{
$userDataFixture = []; // Made an assumption user data would be an array.
$sut = new Mock_Model_User::create($userDataFixture); // calls the parent ::create method, so the real thing.
$sut::test = $this; // This is just here to show possibilities.
$this->assertInstanceOf(Model_User::class, $sut);
}
}
Found the working solution, would to share it despite the topic is old.
class_alias can substitute classes which are not autoloaded yet (works only if you use autoloading, not include/require files directly).
For example, our code:
class MyClass
{
public function someAction() {
StaticHelper::staticAction();
}
}
Our test:
class MyClassTest
{
public function __construct() {
// works only if StaticHelper is not autoloaded yet!
class_alias(StaticHelperMock::class, StaticHelper::class);
}
public function test_some_action() {
$sut = new MyClass();
$myClass->someAction();
}
}
Our mock:
class StaticHelperMock
{
public static function staticAction() {
// here implement the mock logic, e.g return some pre-defined value, etc
}
}
This simple solution doesn't need any special libs or extensions.
Mockery's Alias functionality can be used to mock public static methods
http://docs.mockery.io/en/latest/reference/creating_test_doubles.html#creating-test-doubles-aliasing
Another possible approach is with the Moka library:
$modelClass = Moka::mockClass('Model_User', [
'fromArray' => null,
'save' => null
]);
$modelClass::create('DATA');
$this->assertEquals(['DATA'], $modelClass::$moka->report('fromArray')[0]);
$this->assertEquals(1, sizeof($modelClass::$moka->report('save')));
One more approach:
class Experiment
{
public static function getVariant($userId, $experimentName)
{
$experiment = self::loadExperimentJson($experimentName):
return $userId % 10 > 5; // some sort of bucketing
}
protected static function loadExperimentJson($experimentName)
{
// ... do something
}
}
In my ExperimentTest.php
class ExperimentTest extends \Experiment
{
public static function loadExperimentJson($experimentName)
{
return "{
"name": "TestExperiment",
"variants": ["a", "b"],
... etc
}"
}
}
And then I would use it like so:
public function test_Experiment_getVariantForExperiment()
{
$variant = ExperimentTest::getVariant(123, 'blah');
$this->assertEquals($variant, 'a');
$variant = ExperimentTest::getVariant(124, 'blah');
$this->assertEquals($variant, 'b');
}
Testing static methods is generally considered as a bit hard (as you probably already noticed), especially before PHP 5.3.
Could you not modify your code to not use static a method ? I don't really see why you're using a static method here, in fact ; this could probably be re-written to some non-static code, could it not ?
For instance, could something like this not do the trick :
class Model_User extends Doctrine_Record
{
public function saveFromArray($userData)
{
$this->fromArray($userData);
$this->save();
}
}
Not sure what you'll be testing ; but, at least, no static method anymore...

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