I'm working on a php code that connects to mysql database using beans.
I have written this code for inserting record into the database using a form.
However, the recode cannot be added to the database, and I dont know why.
the same problem happens with the update..
Please anybody can check the code and tell me where is the problem.
<?php
if(isset($_POST['submitted'])) {
$dbhost='localhost:8888';
$dbuser='root';
$dbpass='root';
$dbname='clients';
$conn=mysql_connect($dbhost,$dbuser,$dbpass,$dbname);
$cardnum = $_POST['cardnum'];
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$idnum = $_POST['idnum'];
$mobnum = $_POST['mobnum'];
$visit = $_POST['visit'];
$sqlinsert = "INSERT INTO clients (cardnum, fname, lname, idnum, mobnum, visit)
VALUES ('$cardnum', '$fname', '$lname', '$idnum', '$mobnum', '$visit')";
if(!mysqli_query($conn, $sqlinsert)) {
die("Error inserting new record");
}
$newrecord = "One record added successfuly";
}
?>
<html>
<head>
<title>
<b>Add New Client</b>
</title>
</head>
<body bgcolor="#F0FFFF">
<br/> <br/> <br/>
<font size="4" face="WildWest" color="#4EE2EC"><b>Insert Data for the Client</b></font>
<br/>
<form method="post" action="Add.php">
<input type="hidden" name="submitted" value="true"/>
<fieldset>
<lable><font color="#48CCCD"> Card Number: </font><input type="text" name="cardnum" size="30"/> </lable><br/>
<lable><font color="#48CCCD"> First Name: </font><input type="text" name="fname" size="30"/> </lable><br/>
<lable><font color="#48CCCD"> Last Name: </font><input type="text" name="lname" size="30"/> </lable><br/>
<lable><font color="#48CCCD">ID Number: </font><input type="text" name="idnum" size="30"/> </lable><br/>
<lable><font color="#48CCCD"> Mobile Number: </font><input type="text" name="mobnum" size="30"/> </lable><br/>
<lable><font color="#48CCCD"> Visits:</font><input type="text" name="visit" size="30"/> </lable><br/>
</fieldset>
<br/>
<input type="submit" value="Add" aligh="right"/>
<?php
echo $newrecord
?>
</form>
</body>
</html>
Related
I am trying to make my first php based website and have ran into a problem. The website is very basic and is intended to allow users to enter student information into a database. I built this website following a tutorial by Derek Banas which can be found here:
https://www.youtube.com/watch?v=mpQts3ezPVg&t=25s.
Whenever I try to open my getStudentInfo.php file in my browser, I receive the following error:
Warning: require_once(C:\xampp\htdocs\practiceWebDev): failed to open stream: Permission denied in C:\xampp\htdocs\practiceWebDev\practicePHPmySQL\getStudentInfo.php on line 3
Fatal error: require_once(): Failed opening required '../../practiceWebDev' (include_path='C:\xampp\php\PEAR') in C:\xampp\htdocs\practiceWebDev\practicePHPmySQL\getStudentInfo.php on line 3
Does this error mean I have something wrong with my code? Or do I need to change the php.ini or httpd.conf files associated with XAMPP? Below are the files I have dealing with connections if they are of any use. Thank you very much for any feedback you all can give. Also, I make use of mysql for my database.
mysqli_connect.php:
<?php
//IMPORTANT! This file must be saved outside of where the rest of my files related to our website are saved so that no one may access them.
DEFINE ('DB_USER' 'studentweb');
DEFINE ('DB_PASSWORD' 'turtledove');
DEFINE ('DB_HOST' 'localhost');
DEFINE ('DB_NAME' 'studentdatabase');
$databaseConnection = #mysqli_connect(DB_USER, DB_PASSWORD, DB_HOST, DB_NAME)
//using the above # symbol before mysqli_connect makes it so errors will not appear in the browser.
//# is known as the 'error control operator', and makes PHP suppress error messages associated with the expression.
OR die('Could not connect to MySql lol' . mysqli_connect_error());
//mysqli_connect_error() is a function defined in the php synthax.
?>
getStudentInfo.php:
<?php
//now we require the file outside of the current directory called mysqli_connect.php
require_once('../../practiceWebDev');
//the query below will display the information from each student in the form of a table.
$query = "SELECT first_name, last_name, email, street, province,
postal_code, phone_num, birth_date, sex, date_entered,
lunch_cost, student_id, FROM students";
//the response below is all the info that we've gotten that we want to show in our table.
$response = #mysqli_query($databseConnection, $query);
//below we will see if the query executed properly.
if($response)
{
echo '<table align="left" cellspacing="5" cellpadding="8">
<tr><td align="left"><b>First Name</b></td>
<td align="left"><b>Last Name</b></td>
<td align="left"><b>Email</b></td>
<td align="left"><b>Street</b></td>
<td align="left"><b>City</b></td>
<td align="left"><b>State</b></td>
<td align="left"><b>Zip</b></td>
<td align="left"><b>Phone</b></td>
<td align="left"><b>Birth Day</b></td></tr>';
while($row = mysqli_fetch_array($response)){
echo '<tr>';
echo '<td align=left">'.$row['first_name'].'</td><td align="left">'.$row['last_name'].'</td><td align="left">'.$row['email'].'</td>';
echo '<td align="left">'.$row['street'].'</td><td align="left">'.$row['city'].'</td><td align="left">'.$row['state'].'</td>';
echo '<td align="left">'.$row['zip'].'</td><td align="left">'.$row['phone'].'</td><td align="left">'.$row['birth_date'].'</td>';
echo '</tr>';
}
echo '</table>';
}
else
{
echo "Couldn't issue database query";
echo mysqli_error($databseConnection);
}
mysqli_close($databseConnection);
?>
studentadded.php
<html>
<head>
<title>Add Student</title>
</head>
<body>
<!--First, we need to check if this page was actually reached when the form was submitted--->
<?php
//Below we check that a POST operation was completed by the button I have named "submitButton"
if(isset($_POST['submitButton']))
{
$data_missing = array();
/*If there is an empty field when a POST operation is completed, that field's name will be
added to the data_missing array so that we may visually see which fields are not being sent*/
if(empty($_POST['first_name']))
{
$data_missing[] = 'First Name';
}
else
{
$f_name = trim($POST['first_name']);
}
if(empty($_POST['lastName']))
{
$data_missing[] = 'Last Name';
}
else
{
$l_name = trim($POST['lastName']);
}
if(empty($_POST['email']))
{
$data_missing[] = 'email';
}
else
{
$email = trim($POST['email']);
}
if(empty($_POST['street']))
{
$data_missing[] = 'street';
}
else
{
$street = trim($POST['street']);
}
if(empty($_POST['province']))
{
$data_missing[] = 'province';
}
else
{
$province = trim($POST['province']);
}
if(empty($_POST['postal_code']))
{
$data_missing[] = 'postal_code';
}
else
{
$postal_code = trim($POST['postal_code']);
}
if(empty($_POST['phone_num']))
{
$data_missing[] = 'phone_num';
}
else
{
$phone_num = trim($POST['phone_num']);
}
if(empty($_POST['birth_date']))
{
$data_missing[] = 'birth_date';
}
else
{
$birth_date = trim($POST['birth_date']);
}
if(empty($_POST['sex']))
{
$sex[] = 'sex';
}
else
{
$sex = trim($POST['sex']);
}
if(empty($_POST['lunch_cost']))
{
$data_missing[] = 'lunch_cost';
}
else
{
$lunch_cost = trim($POST['lunch_cost']);
}
if(empty($_POST['student_id']))
{
$data_missing[] = 'student_id';
}
else
{
$student_id = trim($POST['student_id']);
}
//Now lets check
if(empty($data_missing))
{
require_once('../mysqli_connect.php');
$myQuery = "INSERT INTO students (first_name, last_name, email, street, province,
postal_code, phone_num, birth_date, sex, date_entered, lunch_cost,
student_id) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, NOW(), ?, NULL)";
$statement = mysqli_prepare($databaseConnection, $myQuery);
//We have to represent the data type for each of the value that will be passed into our database.
/*i Integers
d Doubles
b Blobs
s Everything Else*/
//Now lets bind variables to the '?'s passed in with the myQuery query.
mysqli_stmt_bind_param($statement, "sssssssisssd", $f_name, $l_name, $email, $street, $province,
$postal_code, $phone_num, $birth_date, $sex, $lunch_cost, $student_id);
mysqli_statement_execute($statement);
$affected_rows = mysqli_stmt_addected_rows($statement);
if($affected_rows == 1)
{
echo 'Went through properly! Student entered correctly!';
mysqli_stmt_close($statement);
mysqli_close($databaseConnection);
}
else
{
echo 'Error occurred :(';
echo '<br />';
echo mysqli_error();
mysqli_stmt_close($statement);
mysqli_close($databaseConnection);
}
}
else
{
echo 'You need to enter the following data my dude: <br />';
foreach($data_missing as $missingData)
{
echo "$missingData<br />";
}
}
}
?>
<form action="http://localhost/studentadded.php" method="post">
<b>Add a New Student</b>
<p>First Name: <input type="text" name="first_name" size="30" value="" /></p>
<p>Last Name: <input type="text" name="lastName" size="30" value="" /></p>
<p>Email: <input type="text" name="email" size="60" value="" /></p>
<p>Street: <input type="text" name="street" size="50" value="" /></p>
<p>Province: <input type="text" name="province" size="3" value="" /></p>
<p>Postal Code: <input type="text" name="postal_code" size="6" value="" /></p>
<p>Phone Number: <input type="text" name="phone_num" size="20" value="" /></p>
<p>Birth Date (YYYY-MM-DD): <input type="text" name="birth_date" size="20" value="" /></p>
<p>Sex: <input type="text" name="sexField1" size="5" maxlength="1" value="" />
<!---<p>Sex: <input type="radio" name="sexField" value="M" />
<br>
<input type="radio" name="sexField" value="F" checked /></p>--->
<!--<p>Date Entered: <input type="" name="" size="" value="" /></p>--->
<p>Lunch Cost: <input type="text" name="lunch_cost" size="5" value="" /></p>
<p>Student ID: <input type="text" name="student_id" size="10" value="" /></p>
<input type="submit" name="submitButton" value="submitValue">
<!-- type="submit" is a predefined term in html--->
</form>
</body>
</html>
addStudent.php
<html>
<head>
<title>Add Student</title>
</head>
<body>
<form action="http://localhost/studentadded.php" method="post">
<b>Add a New Student</b>
<p>First Name: <input type="text" name="first_name" size="30" value="" /></p>
<p>Last Name: <input type="text" name="lastName" size="30" value="" /></p>
<p>Email: <input type="text" name="email" size="60" value="" /></p>
<p>Street: <input type="text" name="street" size="50" value="" /></p>
<p>Province: <input type="text" name="province" size="3" value="" /></p>
<p>Postal Code: <input type="text" name="postal_code" size="6" value="" /></p>
<p>Phone Number: <input type="text" name="phone_num" size="20" value="" /></p>
<p>Birth Date (YYYY-MM-DD): <input type="text" name="birth_date" size="20" value="" /></p>
<p>Sex: <input type="text" name="sexField1" size="5" maxlength="1" value="" />
<!---<p>Sex: <input type="radio" name="sexField" value="M" />
<br>
<input type="radio" name="sexField" value="F" checked /></p>--->
<!--<p>Date Entered: <input type="" name="" size="" value="" /></p>--->
<p>Lunch Cost: <input type="text" name="lunch_cost" size="5" value="" /></p>
<p>Student ID: <input type="text" name="student_id" size="10" value="" /></p>
<input type="submit" name="submitButton" value="submitValue">
<!-- type="submit" is a predefined term in html--->
</form>
</body>
</html>
From what I can see in the tutorial files at this address:
http://www.newthinktank.com/2014/09/php-mysql-tutorial/
In the file getstudentinfo.php at the beginning of the file
You should have require_once('../mysqli_connect.php');
But you have require_once('../../practiceWebDev');
(there is no filename in this line of your code!)
So I think just changing this line of code and using correct path + the filename should solve your error
Update:
Again from what I can see in your code, in studentadded.php file you have this line of code:
require_once('../mysqli_connect.php');
So if your studentadded.php file is working without errors, then just change the line which is generating the error in getstudentinfo.php file with this line.
This is the code for saving the information into mysql database from a FORM.
In the HTML section the form is being handled i.e. retrieving required data from user.
In the PHP section storing data has been handled.
But the problem is it doesn't store data.
I'm using XAMPP server.
<html>
<head>
<title>signup</title>
<link rel="stylesheet" href="css/insert.css" />
</head>
<body>
<div class="maindiv">
<!--HTML form -->
<div class="form_div">
<div class="title"><h2>Insert Data In Database Using PHP.</h2> </div>
<form action="signup.php" method="post"> <!-- method can be set POST for hiding values in URL-->
<h2>Form</h2>
<label>Name:</label>
<br />
<input class="input" type="text" name="name" value="" />
<br />
<label>Email:</label><br />
<input class="input" type="text" name="mail" value="" />
<br />
<label>Phone:</label><br />
<input class="input" type="text" name="phone" value="" />
<br />
<label>Password:</label><br />
<input class="input" type="text" name="pass" value="" />
<br />
<label>Address:</label><br />
<textarea rows="5" cols="25" name="add"></textarea>
<br />
<input class="submit" type="submit" name="submit" value="Insert" />
<?php
//Establishing Connection with Server
$connection = mysql_connect("localhost", "root", "buet2010");
//Selecting Database from Server
$db = mysql_select_db("tanni", $connection);
if(isset($_POST['submit'])){
//Fetching variables of the form which travels in URL
$name = $_POST['name'];
$mail = $_POST['mail'];
$phone = $_POST['phone'];
$pass = $_POST['pass'];
$add = $_POST['add'];
if($name !=''||$email !=''){
//Insert Query of SQL
$query = mysql_query($db, "INSERT INTO user (name, mail, phone, pass, add)VALUES('$name', '$mail', '$phone', '$pass', '$add')");
echo "<br/><br/><span>Data Inserted successfully...!!</span>";
}
else{
echo "<p>Insertion Failed <br/> Some Fields are Blank....!!</p>";
}
}
//Closing Connection with Server
mysql_close($connection);
?>
</form>
</div>
</div>
</body>
I don't understand what can be the problem.
Thanks all. I got the problem.
Actually the sequence of the column in my database was not matching with the query in php code.
I have solved this by changing the variable sequence in the query which is maintained in the database.
$query = mysql_query("INSERT INTO user (`name`, `mail`, `pass`, `address`, `phone`)VALUES('".$name."', '".$mail."', '".$pass."', '".$address."', '".$phone."')");
Here is the code and it will work for your..
I have passed connection link in your mysql_query. and used PHP_SELF for current page.
<html>
<head>
<title>signup</title>
<link rel="stylesheet" href="css/insert.css" />
</head>
<body>
<div class="maindiv">
<!--HTML form -->
<div class="form_div">
<div class="title"><h2>Insert Data In Database Using PHP.</h2> </div>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <!-- method can be set POST for hiding values in URL-->
<h2>Form</h2>
<label>Name:</label>
<br />
<input class="input" type="text" name="name" value="" />
<br />
<label>Email:</label><br />
<input class="input" type="text" name="mail" value="" />
<br />
<label>Phone:</label><br />
<input class="input" type="text" name="phone" value="" />
<br />
<label>Password:</label><br />
<input class="input" type="text" name="pass" value="" />
<br />
<label>Address:</label><br />
<textarea rows="5" cols="25" name="add"></textarea>
<br />
<input class="submit" type="submit" name="submit" value="Insert" />
<?php
//Establishing Connection with Server
$connection = mysql_connect("localhost", "root", "buet2010");
//Selecting Database from Server
$db = mysql_select_db("tanni", $connection);
if(isset($_POST['submit'])){
//Fetching variables of the form which travels in URL
$name = $_POST['name'];
$mail = $_POST['mail'];
$phone = $_POST['phone'];
$pass = $_POST['pass'];
$add = $_POST['add'];
if($name !=''||$email !=''){
//Insert Query of SQL
$query = mysql_query($db, "INSERT INTO user (name, mail, phone, pass, add)VALUES('$name', '$mail', '$phone', '$pass', '$add')",$connection);
echo "<br/><br/><span>Data Inserted successfully...!!</span>";
}
else{
echo "<p>Insertion Failed <br/> Some Fields are Blank....!!</p>";
}
}
//Closing Connection with Server
mysql_close($connection);
?>
</form>
</div>
</div>
</body>
I'm trying to use both $_GET and $_POST in an sql query. The following is my code:
<?php
$assignment = mysql_real_escape_string($_GET['name']);
echo "$assignment <br>";
if (isset($_POST['add'])) {
$user = $_POST['username'];
$text = $_POST['comment'];
$query = "INSERT INTO comments (user, text, assignment) VALUES ('$user', '$text', '$assignment')";
mysql_query($query) or die('Error, comment failed to post');
}
?>
<h1>Add Comment</h1>
<form action="log_entry.php" method="post">
Name:<br/>
<input type="text" name="username" value="" />
<br /><br />
Comment:<br />
<textarea style="height:200px;" type="text" name="comment" value="" ></textarea>
<br /><br />
<input type="submit" name="add" value="Add Comment" />
</form>
However, the $assignment variable does not work in the query. It is echoed properly before the query is made but its value inside the table after the INSERT is completed is empty. What exactly is causing this?
Instead of trying to combine GET and POST, use a hidden input field:
<?php
$assignment = mysql_real_escape_string($_POST['name']); // Name is now in POST data, so swap this
echo "$assignment <br>";
if (isset($_POST['add'])) {
$user = $_POST['username'];
$text = $_POST['comment'];
$query = "INSERT INTO comments (user, text, assignment) VALUES ('$user', '$text', '$assignment')";
mysql_query($query) or die('Error, comment failed to post');
}
?>
<h1>Add Comment</h1>
<form action="log_entry.php" method="post">
<!-- Add hidden input to carry the name -->
<input type="hidden" name="name" value="<?php echo $_GET['name']; ?>"/>
<!-- Rest of the form is the same -->
Name:<br/>
<input type="text" name="username" value="" />
<br /><br />
Comment:<br />
<textarea style="height:200px;" type="text" name="comment" value="" ></textarea>
<br /><br />
<input type="submit" name="add" value="Add Comment" />
</form>
I am trying to insert data into a database mysql phpAdmin.
My webhost is 000webhost.
My connection to mysql database code:
<?PHP
$mysql_host = "mysql2.000webhost.com";
$mysql_database = "*********";
$mysql_user = "********";
$mysql_password = "**********";
$dbcon = mysql_connect($mysql_host,$mysql_user,$mysql_password,$mysql_database);
if (!$dbcon) {
die('error connecting to database');
}
echo ('You have connected successfully');
?>
My insert data code:
<?PHP
if (isset($_POST['submitted'])) {
include('connect_mysql.php');
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$sqlinsert = "INSERT INTO people (firstname, lastname) VALUES ('$fname', '$lname')";
if (!mysql_query($dbcon, $sqlinsert)) {
die('error inserting new record');
} // end of nested if statement
$newrecord = "1 record added to the database";
}
?>
<html>
<head>
<title>Insert Data into DB</title>
</head>
<body>
<h1>Insert Data into DB</h1>
<form method="post" action="insert-data.php">
<input type="hidden" name="submitted" value="true" />
<fieldset>
<legend>New People</legend>
<label>First Name: <input type="text" name="fname" /></label>
<label>Last Name: <input type="text" name="lname" /></label>
</fieldset>
<br />
<input type="submit" value="add new person" />
</form>
<?PHP
echo $newrecord
?>
</body>
</html>
Instead of letting me put it into the database it brings me to this page
http://error404.000webhost.com/?
try change
<label>First Name: <input type="text name="fname" /></label>
<label>Last Name: <input type="text name="lname" /></label>
to
<label>First Name: <input type="text" name="fname" /></label>
<label>Last Name: <input type="text" name="lname" /></label>
and also insert query and connection to
$dbcon = mysql_connect($mysql_host,$mysql_user,$mysql_password,$mysql_database);
$sqlinsert = "INSERT INTO people (firstname, lastname) VALUES ('$fname', '$lname')";
First change below code:
$dbcon = mysqli_connect($mysql_host,$mysql_user,$mysql_password,$mysql_database);
To :
$dbcon = mysql_connect($mysql_host,$mysql_user,$mysql_password,$mysql_database);
Then change below code:
$sqlinsert = "INSERT INTO people (firstname, lastname) VALUES ('fname', 'lname')";
To:
$sqlinsert = "INSERT INTO people (firstname, lastname) VALUES ('$fname', '$lname')";
can u please change this line?
<fieldset>
<legend>New People</legend>
<label>First Name: <input type="text name="fname" /></label>
<label>Last Name: <input type="text name="lname" /></label>
</fieldset>
to
<fieldset>
<legend>New People</legend>
<label>First Name: <input type="text" name="fname" /></label>
<label>Last Name: <input type="text" name="lname" /></label>
</fieldset>
you are setting wrong attributes so its not getting the values..
after that, u have to update your sql query:
$sqlinsert = "INSERT INTO people (firstname, lastname) VALUES ('$fname', '$lname')";
It DID have to be mysqli
my problem was the - had to be changed to an _ on <form method="post" action="insert-data.php">
working code:
<?PHP
if (isset($_POST['submitted'])) {
include('connect_mysql.php');
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$sqlinsert = "INSERT INTO people (firstname, lastname) VALUES ('$fname', '$lname')";
if (!mysqli_query($dbcon, $sqlinsert)) {
die('error inserting new record');
}
$newrecord = "1 new record added to the database";
}
?>
<html>
<head>
<title>Insert Data into DB</title>
</head>
<body>
<h1>Insert Data into DB</h1>
<form method="post" action="insert_data.php">
<input type="hidden" name="submitted" value="true" />
<fieldset>
<legend>New People</legend>
<label>First Name: <input type="text" name="fname" /></label>
<label>Last Name: <input type="text" name="lname" /></label>
</fieldset>
<br />
<input type="submit" value="add new person" />
</form>
<?PHP
echo $newrecord
?>
</body>
</html>
I have an HTML form for submitting and retrieves data from MySQL database with two buttons, "Save/Submit" and "New/Reset"
It fetch data correctly from MySQL database but when I click on New/Reset button for new contact entry it couldn't clear forms text fields. My HTML and PHP codes are as under:
<?php
//Database Connection file.
include'connect.php';
$sql = mysql_query("SELECT * FROM contact_list WHERE id='1'");
While($result = mysql_fetch_assoc($sql)){
$fname = $result['fname'];
$lname = $result['lname'];
$email = $result['email'];
$contact = $result['contact'];
}
if(isset($_POST['fname'])&&isset($_POST['lname'])&&isset($_POST['email'])&&
isset($_POST['contact'])){
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$email = $_POST['email'];
$contact = $_POST['contact'];
if($sql = mysql_query("INSERT INTO contact_list VALUES ('', '$fname', '$lname',
'$email', '$contact')")){
echo'Contact Save Successfully.';
}else{
echo'Contact not save.';
}
}
?>
<html>
<form action="sample.php" method="POST">
First Name:<input type="text" name="fname" value="<?php if(isset($fname))
{echo $fname;}?>">
Last Name:<input type="text" name="lname" value="<?php if(isset($lname))
{echo $lname;}?>">
Email:<input type="text" name="email" value="<?php if(isset($email))
{echo $email;}?>">
Contact:<input type="text" name="contact" value="<?php if(isset($contact))
{echo $contact;}?>">
//Clean all fields of forms for new entry.
<input type="reset" value="New">
//Save or submit form data into mysql database
<input type="submit" value="Save">
</form>
</html>
You can do this easily by using jQuery
<html>
<head>
<script type="text/javascript">
$(document).ready(function() {
$("#btnReset").click(function(){
$("#fname").val("");
$("#lname").val("");
$("#email").val("");
$("#contact").val("");
});
});
</script>
</head>
<form action="sample.php" method="POST">
First Name:<input type="text" name="fname" value="<?php if(isset($fname))
{echo $fname;}?>" id="fname">
Last Name:<input type="text" name="lname" value="<?php if(isset($lname))
{echo $lname;}?>" id="lname">
Email:<input type="text" name="email" value="<?php if(isset($email))
{echo $email;}?>" id="email">
Contact:<input type="text" name="contact" value="<?php if(isset($contact))
{echo $contact;}?>" id="contact">
//Clean all fields of forms for new entry.
<input type="reset" value="New" id="btnReset">
//Save or submit form data into mysql database
<input type="submit" value="Save" id="btnSave">
</form>
</html>