PHP Variables - same var, different values ok? - php

Basic PHP Question...
Is it okay to use the same variable name ($image) over and over again in the same php file, if you keep changing it's value? Or do you need to do $image1, $image2 and so on...?
It's working to do it with the same variable/different values, but I'm not sure if it's a bad practice? (I'm still learning, obviously.)
Here's a simplified example:
$image = get_field('image_3');
echo $image
...
$image = get_field('image_5');
echo $image
Also, I'm referring to what I assume are global variables. The variable is not set within an individual function. Do I need to unset the variable each time if I do it this way? Or is this ok?
Thanks!

Of course it's a bad practice, because it's hard to understand what is it currently inside the $image when reading the source code.
However, it's perfectly valid PHP code, variables in imperative languages like the Algol family of languages are meant to be changed.
By the way, you almost never need to unset() the value of a variable, only in clever tricks or when working with really large datasets.

You may use var_dump() for the best practice and also you may use unset() when it remains unhelpful

As PHP is not a typed language, you may do this.
Typed (Java):
float i = 3.563
string s = "3.563"
Non-Typed (PHP):
e.g on Line 10: i = 3.563;
Then, further down: i = "3.563";
In a non-typed programming language, it is up to you, to not having a chaos with your var-names. My advice is:
Basically, it is allowed, but...
If suddenly, you'll put a boolean or a float in previously stringed variable, I'd say, that's not clean programming.
You may encounter problems in bigger applications. Here's why:
For you as a programmer, it's cleaner to create another variable for other values, than e.g.
$image = get_field('image_3');
and further down you say: $image = true;
Will you remember on line 10'000 (or as commented: on line 42) what kind of value you had in the $image var?
But if you have an $image var and a $someThingIstrue var, you'll see by the name of the variable, what it's for.

Related

Can you Force Type Casting in PHP?

I have been doing some research online and it appears that the answer to my question is no, but I realize there are times when I might miss something or search for something incorrectly. I know in languages like C++, when a variable is declared it can be declared as int or string. Is it possible to force this in PHP?
For Example:
<?php
(int)$var = 5;
?>
will be validated and not cause an error in PHP, but:
<?php
$var = 5;
?>
will cause an error because it was not cast as a type string, int, object, etc...
I know PHP is loosely typed so this may not be an option, however I would like to use it that way I ensure that I sanitize data appropriately and improve readability by letting others know exactly what is going on with the code. I am hoping there is a way to enforce this in the php.ini file or to load it in a script that will always be executed by my program.
Thank you for any help you can offer!
PHP is loosely typed and does not require you to declare a variable type when declaring a variable. You can’t change that behavior with a magic php.ini directive.
The benefit of having “loose typing” is that it allows for flexibility. It allows you to create dynamic applications without having to worry about the type of the variable – PHP makes this possible by not enforcing variable types.
However, if you must convert a variable into a particular format, just cast it:
$int = (int) $foo;
$str = (string) $foo;
$bool = (bool) $foo;
$float = (float) $foo;
...
There are functions to do the same, e.g. intval(), strval(), boolval() – all of them do the same task, but a function is very useful when you want to use it as a callback to another function.

What will load faster. Converted Variables or $_POST variables?

I'm fairly new to PHP and still don't know some of the most basic basics of PHP so bear with me.
When writing a script; IE: (Plz ignore syntax errors)
if isset($_POST['name']) {$Name = $_POST['nsme'];}
When using this name in the page, which way is better and loads faster??
A:) echo $Name. ' went to the river';
B:) echo $_POST['name']. 'went to the river';
Obviously this is a fictional example, I'm just wondering which way is better whether it be an echo or any other function and if anyone wouldn't mind chiming in on this, I'd be most appreciative and I thank you all once again.
Obviously
echo $_POST['name'].' went to the river';
would be faster, as you are skipping one step of assigning the post variable to a php variable.
echo $_POST['name'].' went to the river';
Will be faster as you are skipping one step.
However if you need to use $_POST['name'] multiple times, second approach will be better.
If you care about speed don't worry you can use any of them ,deference significantly low but creating variable which is used only once is not a good idea
However if you are doing
$Name = $_POST['nsme'];
and using $name variable i am sure you want to read about Singleton variable
and if you are using $name at other place too its perfectly
A direct variable access is always faster. At least the zend lexer has not recognize for dimensions...
At least for multiple uses...
(use always an isset()-check at least else you'll have notices.)
If you have var $foo and make:
$bar = $foo;
It doesn't create another copy of $foo in memory until you change $foo or $bar so you will have almost same var for both.
You will have same speed, but $bar will look better than $_POST['bar'] and with it easier to work.

Easiest and most efficient way to get data from URL using php?

Solution?
Apparently there isn't a faster way, I'm okay with that.
I am just learning php and I am trying to figure out some good tips and tricks so I don't get into a bad habit and waste time.
I am passing in values into a php script. I am using $_GET so the URL looks like this:
/poll_results.php?Sports=tennis&cat=Sports&question=Pick+your+favorite+sports
Now I know how to accept those values and place them into variables like so:
$sports = $_GET['Sports'];
$cat = $_GET['cat'];
$question = $_GET['question'];
Super simple yet if I am passing 5 - 6 things it can get bothersome and I don't like typing things out for every single variable, that's the only reason. I know there is a better way of doing this. I have tried list($var, $var, $var) = $_GET but that doesn't work with an associative array just indexed ones (i think).
I also tried variable variables like so:
foreach($_GET as $value) {
$$values = $value;
echo $$values;
}
But that gave me a Notice: Undefined variable: values in poll_results.php on line 14. Line 14 is the $$values = $value. I don't know if that's a big deal or not... but I'm not turning off error reporting as I am still in the process of building the script. It does do what I want it to do though...
Any answers will be copied and pasted into my question so the next person knows :D
Thanks guys!
Your second bit of code is wrong. It ought to be like
foreach ($_GET as $key => $value) {
$$key = $value;
}
if i understand your intent. However, you're basically reinventing register_globals, which....eh. That'll get ya hacked.
If you have certain variables you want to get, you could do like
foreach (array('Sports', 'cat', 'question') as $key)
{
$$key = $_GET[$key];
}
which is less likely to overwrite some important variable (whether by accident or because someone was messing around with URLs).
Use parse_url() to extract the query string from a URL you've got in a string, then parse_str() to extract the individual arguments of the query string.
If you want to pollute your script with the contents of the superglobals, then you can use extract(). however, be aware that this is basically replicating the hideous monstrosity known as "register_globals", and opens all kinds of security vulnerabilities.
For instant, what if one of the original query arguments was _GET=haha. You've now trashed the $_GET superglobal by overwriting it via extract().
I am just learning php and I am trying to figure out some good tips and tricks so I don't get into a bad habit and waste time.
If I am passing 5 - 6 things it can get bothersome and I don't like typing things out for every single variable, that's the only reason.
What you are trying to do will, unless curbed, become a bad habit and even before then is a waste of time.
Type out the variables: your digits like exercise and your brain can take it easy when it doesn't have to figure out which variables are available (or not, or maybe; which would be the case when you use variable variables).
You can use
foreach($_GET as $key => $value)
To preserve the key and value associativity.
Variable variables (the $$value) are a bad idea. With your loop above say you had a variable named $password that is already defined from some other source. Now I can send $_GET['password'] and overwrite your variable! All sorts of nastiness can result from this. It's the same reason why PHP abandoned register_globals which essentially does the same thing.
My advice: use $_POST when possible. It keeps your URLs much cleaner for one thing. Secondly there's no real reason to assign the array to variables anyway, just use them where you need them in the program.
One good reason for this, especially in a large program, is that you'll instantly know where they came from, and that their data should not be trusted.

$var instead of $_GET['var'] in PHP?

Ok I cannot remember the details on this but on some servers you can use
$var instead of $_GET['var'] to access a variable in the URL, I know this is BAD but I can't remember why it is bad?
I think you mean Register Globals.
You shouldn’t use them because you cannot distinguish the source of that variable values since they can come from any source of the EGPCS variables (Environment, GET, POST, Cookie, Server).
So if you have a the $var, you cannot say if the value is either from $_ENV['var'], $_GET['var'], $_POST['var'], $_COOKIE['var'] or $_SERVER['var'].
The feature is called Register Globals and it allows people to inject variables into your code. See the documentation for examples; here's one:
<?php
// define $authorized = true only if user is authenticated
if (authenticated_user()) {
$authorized = true;
}
// Because we didn't first initialize $authorized as false, this might be
// defined through register_globals, like from GET auth.php?authorized=1
// So, anyone can be seen as authenticated!
if ($authorized) {
include "/highly/sensitive/data.php";
}
?>
You can use that if your server has register_globals set to 1 (or true) on the php.ini file.
At some point, this started to be off by default, and applications started to break, which is a reason why this is a bad practice.
You can see a list of php.ini variables here.
It's also bad because you can confuse yourself with the way that PHP will scope your variables. You may wind up overwriting data if you aren't careful. Also, using $_GET is much clearer as to what you are attempting to accomplish.
Because letting people inject values into arbitrary variables is a very bad thing. You could be storing anything there and they could overwrite some value that compromises your security. Remember to use isset to check that a value has been set before trying to use it.
It's bad because if you're not careful to initialize every variable before you use it (something that PHP won't force you to do), people can easily cause your code to do Very Bad Things with a request as simple as /myapp/index.php?admin_privileges=1.
The setting is called REGISTER_GLOBALS and it was discussed here:
Why is REGISTER_GLOBALS so bad?
If you can do that, then "register_globals" is turned on. This is bad because you won't know where a variable came from, and it mixes your variables with the ones any user can inject via the URL. Read more here: http://www.php.net/manual/en/security.globals.php
Once you get used to using $_POST, $_GET, etc your code's purpose will be easier to read and much, much easier to maintain.
Register globals would work but it's going to go away in a future version of PHP. Not to mention that it really is wrong to have it enabled.
You can use extract() for a more controlled behavior. It will extract the keys from an array (in this case, $_GET) into the local context as variables. You can give them a common prefix so that they don't collide with your existing variables. And you can filter the array beforehand to make sure you're only getting the expected variables.
int extract( $var_array [, $type = EXTR_OVERWRITE [, $prefix ]] )
Import variables from an array into the current symbol table.

What is the point of this line of code?

I found this line of code in the Virtuemart plugin for Joomla on line 2136 in administrator/components/com_virtuemart/classes/ps_product.php
eval ("\$text_including_tax = \"$text_including_tax\";");
Scrap my previous answer.
The reason this eval() is here is shown in the php eval docs
This is what's happening:
$text_including_tax = '$tax ...';
...
$tax = 10;
...
eval ("\$text_including_tax = \"$text_including_tax\";");
At the end of this $text_including_tax is equal to:
"10 ..."
The single quotes prevents $tax being included in the original definition of the string. By using eval() it forces it to re-evaluate the string and include the value for $tax in the string.
I'm not a fan of this particular method, but it is correct. An alternative could be to use sprintf()
This code seems to be a bad way of forcing $text_including_tax to be a string.
The reason it is bad is because if $text_including_tax can contain data entered by a user it is possible for them to execute arbitrary code.
For example if $text_include_tax was set to equal:
"\"; readfile('/etc/passwd'); $_dummy = \"";
The eval would become:
eval("$text_include_tax = \"\"; readfile('/etc/passwd'); $_dummy =\"\";");
Giving the malicious user a dump of the passwd file.
A more correct method for doing this would be to cast the variable to string:
$text_include_tax = (string) $text_include_tax;
or even just:
$text_include_tax = "$text_include_tax";
If the data $text_include_tax is only an internal variable or contains already validated content there isn't a security risk. But it's still a bad way to convert a variable to a string because there are more obvious and safer ways to do it.
I'm guessing that it's a funky way of forcing $text_including_tax to be a string and not a number.
Perhaps it's an attempt to cast the variable as a string? Just a guess.
You will need the eval to get the tax rate into the output. Just moved this to a new server and for some reason this line caused a server error. As a quick fix, I changed it to:
//eval ("\$text_including_tax = \"$text_including_tax\";");
$text_including_tax = str_replace('$tax', $tax, $text_including_tax);
It is evaluating the string as PHP code.
But it seems to be making a variable equal itself? Weird.
As others have pointed out, it's code written by someone who doesn't know what on earth they're doing.
I also had a quick browse of the code to find a total lack of text escaping when putting HTML/URIs/etc. together. There are probably many injection holes to be found here in addition to the eval issues, if you can be bothered to audit it properly.
I would not want this code running on my server.
I've looked through that codebase before. It's some of the worst PHP I have seen.
I imagine you'd do that kind of thing to cover up mistakes you made somewhere else.
No, it's doing this:
Say $text_including_tax = "flat". This code evaluates the line:
$flat = "flat";
It isn't necessarily good, but I did use a technique like this once to suck all the MySQL variables in an array like this:
while ($row = mysql_fetch_assoc($result)) {
$var = $row["Variable_name"];
$$var = $row["Value"];
}

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