I have two associative array.
$Array1 = array(
'abc'=> 'abc',
'def'=> 'def'
);
$Array2 = array(
'123'=> '123',
'456'=> '456'
);
I am merging them using array_merge.
$Array3 = array_merge($Array1, $Array2);
Now value of $Array3 is like this.
Array
(
[abc] => abc
[def] => def
[0] => 123
[1] => 456
)
It looks really odd until I read php manual which says Values in the input array with numeric keys will be renumbered with incrementing keys starting from zero in the result array. array_merge manual
My questing How can I merge both array without loosing their associative keys.
Both array can have common KEYS and I don't want to loose my information also. :(
By +:
$Array1 = array(
'abc'=> 'abc',
'def'=> 'def'
);
$Array2 = array(
'123'=> '123',
'456'=> '456'
);
var_dump($Array1 + $Array2);
This will preserve the index, but note this will not overwrite the value of the first array if same key exists in first array.
And if you want the overwrite working, then there is array_replace function for this:
var_dump(array_replace($Array1, $Array2));
Try this code :) it will work
function my_merge($array1,$array2)
{
foreach($array2 as $key => $value)
{
$array1[$key] = $value;
}
return $array1;
}
$Array1 = array(
'abc'=> 'abc',
'def'=> 'def'
);
$Array2 = array(
'123'=> '123',
'456'=> '456'
);
$Array3 = my_merge($Array1, $Array2);
For associative arrays, use
$result = $Array1 + $Array2;
-but note, that for numeric keys this will also re-index:
$Array1 = array(
'abc',
'def'=> 'def'
);
$Array2 = array(
'123',
'456'
);
var_dump($Array1 + $Array2);
//array(3) { [0]=> string(3) "abc" ["def"]=> string(3) "def" [1]=> string(3) "456" }
If you have same keys in your arrays, you can use:
$result = array_reduce(array_keys($Array1), function($c, $x) use ($Array1)
{
$c[$x] = isset($c[$x])
?array_merge((array)$c[$x], [$Array1[$x]])
:$Array1[$x];
return $c;
}, $Array2);
Related
I have an array containing rows of associative data.
$array1 = array(
array('ITEM' => 1),
array('ITEM' => 2),
array('ITEM' => 3),
);
I have a second array, also containing rows of associative data, that I would like to filter using the first array.
$array2 = array(
array('ITEM' => 2),
array('ITEM' => 3),
array('ITEM' => 1),
array('ITEM' => 4),
);
This feels like a job for array_diff(), but how can I compare the rows exclusively on the deeper ITEM values?
How can I filter the second array and get the following result?
array(3 => array('ITEM' => 4))
You can define a custom comparison function using array_udiff().
function udiffCompare($a, $b)
{
return $a['ITEM'] - $b['ITEM'];
}
$arrdiff = array_udiff($arr2, $arr1, 'udiffCompare');
print_r($arrdiff);
Output:
Array
(
[3] => Array
(
[ITEM] => 4
)
)
This uses and preserves the arrays' existing structure, which I assume you want.
I would probably iterate through the original arrays and make them 1-dimensional... something like
foreach($array1 as $aV){
$aTmp1[] = $aV['ITEM'];
}
foreach($array2 as $aV){
$aTmp2[] = $aV['ITEM'];
}
$new_array = array_diff($aTmp1,$aTmp2);
Another fun approach with a json_encode trick (can be usefull if you need to "raw" compare some complex values in the first level array) :
// Compare all values by a json_encode
$diff = array_diff(array_map('json_encode', $array1), array_map('json_encode', $array2));
// Json decode the result
$diff = array_map('json_decode', $diff);
A couple of solutions using array_filter that are less performant than the array_udiff solution for large arrays, but which are a little more straightforward and more flexible:
$array1 = [
['ITEM' => 1],
['ITEM' => 2],
['ITEM' => 3],
];
$array2 = [
['ITEM' => 2],
['ITEM' => 3],
['ITEM' => 1],
['ITEM' => 4],
];
$arrayDiff = array_filter($array2, function ($element) use ($array1) {
return !in_array($element, $array1);
});
// OR
$arrayDiff = array_filter($array2, function ($array2Element) use ($array1) {
foreach ($array1 as $array1Element) {
if ($array1Element['ITEM'] == $array2Element['ITEM']) {
return false;
}
}
return true;
});
As always with array_filter, note that array_filter preserves the keys of the original array, so if you want $arrayDiff to be zero-indexed, do $arrayDiff = array_values($arrayDiff); after the array_filter call.
you can use below code to get difference
$a1 = Array(
[0] => Array(
[ITEM] => 1
)
[1] => Array(
[ITEM] => 2
)
[2] => Array(
[ITEM] => 3
)
);
$a2 = Array(
[0] => Array(
[ITEM] => 2
)
[1] => Array(
[ITEM] => 3
)
[2] => Array(
[ITEM] => 1
)
[3] => Array(
[ITEM] => 4
));
array_diff(array_column($a1, 'ITEM'), array_column($a2, 'ITEM'));
Having the same problem but my multidimensional array has various keys unlike your "ITEM" consistently in every array.
Solved it with: $result = array_diff_assoc($array2, $array1);
Reference: PHP: array_diff_assoc
Another solution
if( json_encode($array1) == json_encode($array2) ){
...
}
Trust that the maintainers of PHP have optimized array_udiff() to outperform all other techniques which could do the same.
With respect to your scenario, you are seeking a filtering array_diff() that evaluates data within the first level's "value" (the row of data). Within the custom function, the specific column must be isolated for comparison. For a list of all native array_diff() function variations, see this answer.
To use the first array to filter the second array (and output the retained data from the second array), you must write $array2 as the first parameter and $array1 as the second parameter.
array_diff() and array_intersect() functions that leverage (contain u in their function name) expect an integer as their return value. That value is used to preliminary sort the data before actually performing the evaluations -- this is a performance optimization. There may be scenarios where if you only return 0 or 1 (not a three-way comparison), then the results may be unexpected. To ensure a stable result, always provide a comparison function that can return a negative, a positive, and a zero integer.
When comparing integer values, subtraction ($a - $b) will give reliable return values. For greater utility when comparing float values or non-numeric data, you can use the spaceship operator when your PHP version makes it available.
Codes: (Demo)
PHP7.4+ (arrow functions)
var_export(
array_udiff($array2, $array1, fn($a, $b) => $a['ITEM'] <=> $b['ITEM'])
);
PHP7+ (spaceship operator)
var_export(
array_udiff(
$array2,
$array1,
function($a, $b) {
return $a['ITEM'] <=> $b['ITEM'];
}
)
);
PHP5.3+ (anonymous functions)
var_export(
array_udiff(
$array2,
$array1,
function($a, $b) {
return $a['ITEM'] === $b['ITEM']
? 0
: ($a['ITEM'] > $b['ITEM'] ? 1 : -1);
}
)
);
Output for all version above:
array (
3 =>
array (
'ITEM' => 4,
),
)
When working with object arrays, the technique is the same; only the syntax to access a property is different from accessing an array element ($a['ITEM'] would be $a->ITEM).
For scenarios where the element being isolated from one array does not exist in the other array, you will need to coalesce both $a and $b data to the opposite fallback column because the data from the first array and the second arrays will be represented in both arguments of the callback.
Code: (Demo)
$array1 = array(
array('ITEM' => 1),
array('ITEM' => 2),
array('ITEM' => 3),
);
$array2 = array(
array('ITEMID' => 2),
array('ITEMID' => 3),
array('ITEMID' => 1),
array('ITEMID' => 4),
);
// PHP7.4+ (arrow functions)
var_export(
array_udiff(
$array2,
$array1,
fn($a, $b) => ($a['ITEM'] ?? $a['ITEMID']) <=> ($b['ITEM'] ?? $b['ITEMID'])
)
);
Compares array1 against one or more other arrays and returns the values in array1 that are not present in any of the other arrays.
//Enter your code here, enjoy!
$array1 = array("a" => "green", "red", "blue");
$array2 = array("b" => "green", "yellow", "red");
$result = array_diff($array1, $array2);
print_r($result);
Let say we have 2 flowing arrays
$arr1= array('a' => "XL");
$arr2= array('a' => "XLd",'b'=>"CDW");
i need to assign $arr1 to $arr2 and make other keys empty whith a builtin function not foreach.
It should looks as bellow:
array(2) { ['a']=> string(2) "XL" ['b']=> string(0) ""}
thanks
This seems fun enough :)
<?php
$arr1= array('a' => "XL");
$arr2= array('a' => "XLd",'b'=>"CDW");
array_walk(
$arr2,
function (&$val ,$key) use ($arr1){
if (isset($arr1[$key])) {
$val = $arr1[$key];
} else {
$val = '';
}
}
);
print_r($arr2);
//Array
//(
//[a] => XL
//[b] =>
//)
See it here: https://3v4l.org/B7G5p
If I understand your question correctly, this should do:
$out = array_merge(
$arr2,
array_fill_keys(array_keys($arr2), ''),
$arr1
);
Another oneliner solution:
$arr2 = array_replace(array_map(function($n){return "";}, $arr2), $arr1);
https://3v4l.org/cgBB1
I want to go from these arrays:
$array1 = ["x", "y", "z"];
$array2 = ["a","b"];
$array3 = ["1","2","3","4","5","6"];
To this array:
$arrayResult =
array(
array("x" => array("a" => array(1,2,3,4,5,6),
"b" => array(1,2,3,4,5,6)),
"y" => array("a" => array(1,2,3,4,5,6),
"b" => array(1,2,3,4,5,6)),
"z" => array("a" => array(1,2,3,4,5,6),
"b" => array(1,2,3,4,5,6)))
);
I tried to make this combined array with cartesian product approaches, but no satisfying result so far.
Here is another solution without using any loop:
$array1 = ["x", "y", "z"];
$array2 = ["a","b"];
$array3 = ["1","2","3","4","5","6"];
$result = array_combine(
$array1,
array_fill(
0,
count($array1),
array_combine(
$array2,
array_fill(0, count($array2), $array3)
)
)
);
print_r($result);
Here is the demo
use array_fill_keys twice to get the result
$result = array_fill_keys(
$array1,
array_fill_keys($array2, $array3)
);
Demo on eval.in
Following Below are two arrays which i wanna compare and remove the same values something like array_diff() Function and i want to store the result in third array
$array1 = Array([0] => Array([a] => XYZ,[b] => ABC))
$array2 = Array([0] => Array([a] => XYZ,[b] => ABC),[1] => Array([a] => PQR,[b] => XYZ))
$array3 = array_diff($array1,$array2);
//$array3 value must return this value Array([1] => Array[a]=> PQR,[b] => XYZ)
I don't know what i am doing wrong but i am getting error that array cannot be converted into string. Can anyone help me with this?
Thanks in advance
If you are sure that your $array2 will always contain more elements than $array1 then here is your solution:
$array1 = array(array('a' => 'XYZ','b' => 'ABC'));
$array2 = array(array('a' => 'XYZ','b' => 'ABC'),array('a' => 'PQR','b' => 'XYZ'));
$limit = count($array2);
$array3 = array();
for($i=0;$i<$limit;$i++){
if(empty($array1[$i]))
$array3[] = $array2[$i];
$array3[] = array_diff($array1[$i],$array2[$i]);
}
foreach($array3 as $k=>$a3){
if(empty($a3)||($a3===NULL))
continue;
$result[$k] = $a3;
}
var_dump($result); //array(1) { [1]=> array(2) { ["a"]=> string(3) "PQR" ["b"]=> string(3) "XYZ" } }
Please note that array_diff works on 1D array and you was providing 2D arrays as parameter and that's why it wasn't working.
Also your way of defining $array1 and $array2 is wrong, please check this solution for right syntax.
I hope it helps
There is function array_values in PHP such that
$array2 = array_values($array1);
$array2 has the same values as $array1 but keys are from
0 to sizeof($array1) - 1. Is it possible to get mapping from old keys to new keys?
EDIT. I will explain on an example:
$array1 = array( 'a' => 'val1', 'b' => 'val1');
$array2 = array_values( $array1 );
so now array2 has next values
$array2[0] = 'val1'
$array2[1] = 'val2'
How get array3 such that:
$array3['a'] = 0
$array3['b'] = 1
To produce a key map you need to first get the keys into a regular array and then flip the keys and values:
$array1_keymap = array_flip(array_keys($array1));
For example:
$array1 = array(
'a' => 123,
'b' => 567,
);
$array1_values = array_values($array1);
$array1_keymap = array_flip(array_keys($array1));
Value of $array1_values:
array(
0 => 123,
1 => 567,
);
Value of $array1_keymap:
array(
'a' => 0,
'b' => 1,
);
So:
$array1['a'] == $array1_values[$array1_keymap['a']];
$array1['b'] == $array1_values[$array1_keymap['b']];
Yes, as simple as
$array2 = $array1;
In this case you would get both values and keys like they are in the original array.
$keyMapping = array_combine(array_keys($array1), array_keys($array2));
This the keys of $array1 and maps them to the keys of $array2 like so
<?php
$array1 = array(
'a' => '1',
'b' => '2',
);
$array2 = array_values($array1);
print_r(array_combine(array_keys($array1), array_keys($array2)));
Array
(
[a] => 0
[b] => 1
)
You can use:
$array3 = array_keys($array1);
Now $array3[$n] is the key of the value in $array2[$n] for any 0 <= $n < count($array1). You can use this to determine which keys were in which places.
If you want to keep the same value of array1 but change the key to index numbers, try this:
$array2 = array();
foreach ($array1 as $key => $value){
$array2[] = $value;
// or array_push($array2, $value);
}
var_dump($array2);