This is the code provided in an example at: http://www.php.net/manual/en/function.imagecopyresampled.php
test.jpg size: 500x357
phpdotnet_resize.php
This displays test.jpg resized at 200x142
<?php
// The file
$filename = 'test.jpg';
// Set a maximum height and width
$width = 200;
$height = 200;
// Content type
header('Content-Type: image/jpeg');
// Get new dimensions
list($width_orig, $height_orig) = getimagesize($filename);
$ratio_orig = $width_orig/$height_orig;
if ($width/$height > $ratio_orig) {
$width = $height*$ratio_orig;
} else {
$height = $width/$ratio_orig;
}
// Resample
$image_p = imagecreatetruecolor($width, $height);
$image = imagecreatefromjpeg($filename);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $width, $height, $width_orig, $height_orig);
// Output
imagejpeg($image_p, null, 100);
echo "<img src='$filename'>";
?>
However, this displays test.jpg in its original size of 500x357
<?php
include "phpdotnet_resize.php";
echo "<img src='$filename'>";
?>
I am trying to move the resized test.jpg to images/ but it keeps moving the original size image.
upload.php (only relevant snippet showing)
include "phpdotnet_resize.php";
if(move_uploaded_file($file_tmp,"images/".$filename)){
echo "Success";
Related
This is straight out of the PHP manual except the jpg name. I even used the php logo in the php manual. I right clicked and saved image, just to be sure it wasn't my images. I researched other questions in stack overflow, such as GD is enabled. There was also talk of UTF-8 with BOM doesn't work. I use Visual Studio Code with UTF-8 no BOM. Here is the link to page. http://cartrus.com/shops/scale_image.php?
<?php
// The file
$filename = 'php.jpg';
// Set a maximum height and width
$width = 200;
$height = 200;
// Content type
header('Content-Type: image/jpeg');
// Get new dimensions
list($width_orig, $height_orig) = getimagesize($filename);
$ratio_orig = $width_orig/$height_orig;
if ($width/$height > $ratio_orig) {
$width = $height*$ratio_orig;
} else {
$height = $width/$ratio_orig;
}
// Resample
$image_p = imagecreatetruecolor($width, $height);
$image = imagecreatefromjpeg($filename);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $width, $height, $width_orig, $height_orig);
// Output
imagejpeg($image_p, null, 100);
?>
I need to resize image to 150 x 150 px and then upload it to Amazon S3
Following is the code:
$image = $_FILES["userImage"]["name"];
$fileTempName = $_FILES['userImage']['tmp_name'];
$new_width = 150;
$new_height = 150;
$image_p = imagecreatetruecolor($new_width, $new_height);
$image = imagecreatefromstring(file_get_contents($fileTempName));
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $new_width, $new_height, imagesx($image), imagesy($image));
$newFielName = tempnam(sys_get_temp_dir(), "tempfilename");
imagepng($image_p, $newFielName, 9);
$s3 = new S3(awsAccessKey, awsSecretKey);
//move the file
if ($s3->putObjectFile($fileTempName, "urimages", $newFielName, S3::ACL_PUBLIC_READ)) {
$image_link = 'https://s3-us-west-2.amazonaws.com/urimages/' . $newFielName . '';
$this->Product->saveField('image', $image_link);
}
Following is the link which i receive upon uploading : https://s3-us-west-2.amazonaws.com/urimages/C:/Users/LS/AppData/Local/Temp/9102.tmp
Could be you please help me debug the code
i think issue in path. Please create folder on s3 and make a valid
path according to that folder
https://s3-us-west-2.amazonaws.com/urimages/C:/Users/LS/AppData/Local/Temp/9102.tmp
Example :- Resampling an image proportionally
<?php
// The file
$filename = 'test.jpg';
// Set a maximum height and width
$width = 200;
$height = 200;
// Content type
header('Content-Type: image/jpeg');
// Get new dimensions
list($width_orig, $height_orig) = getimagesize($filename);
$ratio_orig = $width_orig/$height_orig;
if ($width/$height > $ratio_orig) {
$width = $height*$ratio_orig;
} else {
$height = $width/$ratio_orig;
}
// Resample
$image_p = imagecreatetruecolor($width, $height);
$image = imagecreatefromjpeg($filename);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $width, $height, $width_orig, $height_orig);
// Output
imagejpeg($image_p, null, 100);
?>
I found the following script from PHP site to half the size of the image. I use the database to fetch the link of the image. Other things are working correctly which means there isn't any kind of error anywhere except this one.
echo "<img src='".// File and new size
$filename = '$row["image"]';
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
imagejpeg($thumb);
"'>"
Error:
The whole page is destroyed and there is a broken link of an image.
Hope you guys will help me!
It works after you drop those lines:
echo "<img src='".// File and new size
"'>"
header does it for you, informs that there is jpg coming, no need to echo image tag.
The other solution is to remove this line:
header('Content-Type: image/jpeg');
And create new file, then use it as a source of an image:
// Output
$new_filename = 'new_image.jpg';
imagejpeg($thumb,$new_filename);//saves new image to a file, instead of outputting it to the screen
echo "<img src='$new_filename'>";
Try this it works
<?php
$filename = '$row["image"]';
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
echo "<img src='".imagejpeg($thumb)."'>";
?>
Index.php
<?php
error_reporting(E_ALL);
// File and new size
//the original image has 800x600
$filename = 'images/lazy1.jpg';
//the resize will be a percent of the original size
$percent = 0.5;
// Content type
header('Content-Type: image/jpg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output and free memory
//the resized image will be 400x300
imagejpeg($thumb, "raj.jpg", 100);
imagedestroy($thumb);
echo "Image Resize Successfully";
?>
I am using imagejpeg() to save file. i want save file in folder but not show on browser. in browser only show this message "Image Resize successfully".
<?php
error_reporting(E_ALL);
// File and new size
//the original image has 800x600
$filename = 'images/lazy1.jpg';
//the resize will be a percent of the original size
$percent = 0.5;
//Removed lines here
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output and free memory
//the resized image will be 400x300
imagejpeg($thumb, "raj.jpg", 100);
imagedestroy($thumb);
echo "Image Resize Successfully";
?>
this script some how showing half of the image not the whole image... i am trying to figure this out what is wrong here
any help please
// The file
$ftimage = $_POST['feature_image'];
// maximum height 150 X width 150
$width = 150;
$height = 150;
// Dimensions Set
list($width_orig, $height_orig) = getimagesize($ftimage);
$ratio_orig = $width_orig/$height_orig;
if ($width/$height > $ratio_orig) {
$width = $height*$ratio_orig;
} else {
$height = $width/$ratio_orig;
}
// Resample
$image_p = imagecreatetruecolor($width, $height);
$image = imagecreatefromjpeg($ftimage);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $width, $height, $width_orig, $height_orig);
// Output
$image = imagejpeg($image_p, null, 100);
var_dump($image);
Try to replace it
$ftimage = $_POST['feature_image'];
with it:
$ftimage = $_POST['feature_image']['tmp_name'];
Or if in your POST request stores a URL of remote image, try something like that:
$image = imagecreatefromstring(file_get_contents($ftimage));