PLease look my php code. I dont want rmeoving zeros.
<?php
$number = '00154';
$next = $number + 1;
echo $next; // returns 155
?>
But I want to return 00155
Use str_pad() in conjunction with strlen(). strlen() gets the number of digits, and then uses that as the pad length for str_pad().
$next = str_pad($next, strlen($number), '0', STR_PAD_LEFT);
If you always want a fixed length, say 5, then this becomes shorter:
$next = sprintf('%05d', $next);
Demo
You can do that with str_pad if your number length is constant. In your case you have 5 length number. You can get length of number first and you can fill up zeros in result;
<?php
$number = '00154';
$length = strlen($number);
$next = $number + 1;
echo str_pad($next, $length, "0", STR_PAD_LEFT);
?>
Here is a working demo: codepad
00155 and 155 is from a maths perspective EQUAL.
echo str_pad($next, 5, '0', STR_PAD_LEFT);
fills left side with zeroes.
This is because your number is a string. Convert it to a number (integer or float) first, the use math function.
Related
I have variables of bitcoin values all rounded to 8 decimal places. eg
1.00645600
I need a way in jQuery or php to get the whole number [1], The decimal values [006456], and trailing zeros [00]. I have already tried php substr but it messed up with the results since im dealing with variables.
Simple and general solution in PHP without involving regular expressions (that is an option also):
$number = '1.00645600';
$flooredNumber = floor($number); // 1
$decimalPart = (string) (floatval($number) - $flooredNumber); // 0.006456
$decimals = str_replace('0.', '', $decimalPart); // 006456
$trailingZeros = str_replace(rtrim($number, '0'), '', $number); // 00
substr
Returns the portion of string specified by the start and length parameters.
http://php.net/manual/en/function.substr.php
If the numbers in your string are always in the same position you can use substr() to get the desired values:
$str = '1.00645600';
echo substr($str, 0, 1)."\r\n";
echo substr($str, 2, 2)."\r\n";
echo substr($str, 2, 6)."\r\n";
Output:
1
00
006456
Perhaps, this way?
<?php
$i = '1.00645600';
echo rtrim(rtrim($i, '0'), '.');
?>
I'm trying to replace some characters from a string using str_pad and I can't get it to work at all and I have no idea why it doesn't work.
Code:
<?php
$t = "abcdefghij";
$t = str_pad($t, 4, "0");
echo $t;
?>
Expected:
abcd000000
Result:
abcdefghij
I also tried:
$t = sprintf("%04x", $t);
Which results in:
0000
If you have a variable length string, you can use the below
$str = "abcdefghijzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz";
$head = substr($str, 0, 4); // construct the first part of your string
$tail = substr($str, 4); // get the second part of the string
print $head . str_repeat('0',strlen($tail));
// or all in one go
$number = 4;
print substr($str, 0, $number) . str_repeat('0',strlen(substr($str, $number)));
//will output
//abcd0000000000000000000000000000000000000
To replace everything except the first x number of characters in your string.
Because your string is longer than four characters so str_pad() will not append anything to it.
If the value of pad_length is negative, less than, or equal to the length of the input string, no padding takes place, and input will be returned.
If you want to always append four zeros just concatenate them onto your string:
<?php
$t = "abcdefghij";
$t = '0000' . $t;
echo $t;
?>
What you are looking for is a mixture of str_pad and substr, using the two like this:
echo str_pad(substr($str, 0, 4), strlen($str), '0', STR_PAD_RIGHT);
Will give you output like this:
abcd000000
You may however, need to tweak the numbers to get your desired results.
Here is a function you can use:
function pad($str, $length, $value= '0', $side = STR_PAD_RIGHT){
return str_pad(substr($str, 0, $length), strlen($str), $value, $side);
}
echo pad('abcdefghij', 4);
You need a different functions. str_pad() adds to the string and you are wanting to replace:
$t = substr_replace($t, str_repeat('0', strlen($t)-4), 4);
I'm trying to add thousand separators to a number using PHP and at the same time keep the leading zeros (It's part of the design of an app that the leading 0s stay so that people can see the number grow towards the set target - a 6 figure number).
My initial attempt was to use str_pad to add the leading zeros if the current number calculated was less than 6 figures long. Then to add the commas I used number_format. The obvious issue is that number_format removes the leading 0s.
$num = 550;
$num_padded = str_pad($num, 6, '0', STR_PAD_LEFT);
echo number_format($num_padded);
So that returns 550 instead of 000,550
Does anyone know of a reliable way to achieve the format I'm looking for?
Thanks!
I have in mind this simple trick:
function padAndFormat($number, $length)
{
if(strlen($number)>=$length)
{
return number_format($number);
}
$number = number_format('1'.str_pad($number, $length-1, '0', STR_PAD_LEFT));
$number[0] = '0';
return $number;
}
//var_dump(padAndFormat('517', 6)); //string(7) "000,517"
another way to do this is to use sprintf
// length can be changed, here is 6
implode(',',str_split(sprintf('%06d', $this->iterator),3));
the result will be :
input
result
4
000,004
400
000,400
23560
023,560
1234567
1,234,567
it can be improved by reading the length, and computing automatically the final length, multiple of 3
I don't need number format but I need that comma! :)
<?php
$zeroes=0;
$num = 550;
$num_padded = str_pad($zeroes, 3, '0', STR_PAD_LEFT);
$num_padded = str_pad($num_padded,strlen($num_padded)+strlen($zeroes), ',', STR_PAD_RIGHT);
$num_padded = str_pad($num_padded,strlen($num_padded)+strlen($num), $num, STR_PAD_RIGHT);
echo $num_padded;
OUTPUT :
000,550
One Liner with PHP string manipulation. Works for any number of digits:
function pad($number, $min_digits){
return strrev(implode(",",str_split(str_pad(strrev($number), $min_digits, "0", STR_PAD_RIGHT),3)));
}
/* Output for 9 digits
0,000,001
0,000,012
0,000,123
0,001,234
0,012,345
0,123,456
1,234,567
12,345,678
123,456,789
/**/
I have a string, its content is "24896". Now I want to add some zeros to the left, so I tried:
$test = str_pad($myString, 4, "0", STR_PAD_LEFT);
The result is "24896" again, no zeros added to the left. Am I missing something here?
Thanks!
The second argument to str_pad() takes the full length of the final string; because you're passing 4 and the length of $myString is 5, nothing will happen.
You should choose a width that's at least one bigger than your example value, e.g.:
str_pad($myString, 9, '0', STR_PAD_LEFT);
// "000024896"
Update
This might be obvious, but if you always want 4 zeros in front of whatever $myString is:
'0000' . $myString;
Because you're padding it to length 4, and your string 24896 is 5 characters long, hence it doesn't need to pad anything as it's already more than 4 characters long.
The second parameter in the str_pad function is the new length of the string.
Try
$myString = "24896" ;
$test = str_pad($myString, strlen($myString) + 4, "0", STR_PAD_LEFT);
echo $test;
Output
000024896
Just make the pad first and attach it, presuming you don't know how long it is. No need to calculate the length of the original string:
$x = 4;
$pad = str_pad('', $x, '0');
$test = $pad.$myString;
Or better
$x = 4;
$test = str_pad('', $x, '0').$myString;
The length you specified in the str_function is less than the input string read documentation properly
try this it will work for you
Your String is 5 character
e.g $myString=24896;
Now you want to add 5 zero to the left
then your length will be you string + 5 the actual is 5+5=10;
Now pass this to the function your function will be like this
$test = str_pad($myString, 10, "0", STR_PAD_LEFT);
echo $test;
OUTPUT:
0000024896
how many no zero you want to add? no zeros added because padding length is smaller than your given $myString length.
Please try this one
$number = 24896;
$number = sprintf('%06d', $number);
echo $number;
or use this one
$number = 24896;
$number = str_pad($number, 6, '0', STR_PAD_LEFT);//here 6 is padding length
echo $number;
output
024896
What would be an elegant way of doing this?
I have this -> "MC0001" This is the input. It always begins with "MC"
The output I'd be aiming with this input is "MC0002".
So I've created a function that's supposed to return "1" after removing "MC000". I'm going to convert this into an integer later on so I could generate "MC0002" which could go up to "MC9999". To do that, I figured I'd need to loop through the string and count the zeros and so on but I think I'd be making a mess that way.
Anybody has a better idea?
This should do the trick:
<?php
$string = 'MC0001';
// extract the part succeeding 'MC':
$number_part = substr($string, 2);
// count the digits for later:
$number_digits = strlen($number_part);
// turn it into a number:
$number = (int) $number_part;
// make the next sequence:
$next = 'MC' . str_pad($number + 1, $number_digits, '0', STR_PAD_LEFT);
using filter_var might be the best solution.
echo filter_var("MC0001", FILTER_SANITIZE_NUMBER_INT)."\n";
echo filter_var("MC9999", FILTER_SANITIZE_NUMBER_INT);
will give you
0001
9999
These can be cast to int or just used as they are, as PHP will auto-convert anyway if you use them as numbers.
just use ltrim to remove any leading chars: http://php.net/manual/en/function.trim.php
$str = ltrim($str, 'MC0');
$num = intval($str);
<php
// original number to integer
sscanf( $your_string, 'MC%d', $your_number );
// pad increment to string later on
sprintf( 'MC%04u', $your_number + 1 );
Not sure if there is a better way of parsing a string as an integer when there are leading zero's.
I'd suggest doing the following:
1. Loop through the string ( beginning at location 2 since you don't need the MC part )
2. If you find a number thats bigger than 0, stop, get the substring using your current location and the length of the string minus your current location. Cast to integer, return value.
You can remove the "MC" par by doing a substring operating on the string.
$a = "MC0001";
$a = substr($a, 2); //Lengths of "MC"
$number = intval($a); //1
return intval(str_replace($input, 'MC', ''), 10);