Getting time left - php

Question

I have a time left function that I am using to get the time left based on a sent parameter. My issue is I am having difficulty calculating if there is a day, a year, or a month left.
Function:
function get_time_difference_php_left($created_time)
{
$str = strtotime($created_time);
$today = strtotime(date('Y-m-d H:i:s'));
// It returns the time difference in Seconds...
$time_differnce = $today-$str;
// To Calculate the time difference in Years...
$years = 60*60*24*365;
// To Calculate the time difference in Months...
$months = 60*60*24*30;
// To Calculate the time difference in Days...
$days = 60*60*24;
// To Calculate the time difference in Hours...
$hours = 60*60;
// To Calculate the time difference in Minutes...
$minutes = 60;
if(intval($time_differnce/$years) > 1)
{
return " - ". intval($time_differnce/$years)." years left";
}else if(intval($time_differnce/$years) > 0)
{
return " - ".intval($time_differnce/$years)." year left";
}else if(intval($time_differnce/$months) > 1)
{
return " - ".intval($time_differnce/$months)." months left";
}else if(intval(($time_differnce/$months)) > 0)
{
return " - ".intval(($time_differnce/$months))." month left";
}else if(intval(($time_differnce/$days)) > 1)
{
return " - ".intval(($time_differnce/$days))." days left";
}else if (intval(($time_differnce/$days)) > 0)
{
return " - ".intval(($time_differnce/$days))." day left";
}else if (intval(($time_differnce/$hours)) > 1)
{
return " - ".intval(($time_differnce/$hours))." hours left";
}else if (intval(($time_differnce/$hours)) > 0)
{
return " - ".intval(($time_differnce/$hours))." hour left";
}else if (intval(($time_differnce/$minutes)) > 1)
{
return " - ".intval(($time_differnce/$minutes))." minutes left";
}else if (intval(($time_differnce/$minutes)) > 0)
{
return " - ".intval(($time_differnce/$minutes))." minute left";
}else if (intval(($time_differnce)) > 1)
{
return " - ".intval(($time_differnce))." seconds left";
}else
{
return " - few seconds left";
}
}
If I run this based on the now time and a date time of: 2014-04-17 03:27:26 it will tell me 88 years.
Suggestions, thoughts?

Answer 1

You had March initially. You are doing the calculation backwards then. Your code should show expiration date, not creation date. If you are trying to use an expiration date, then your code should use:
$time_differnce = $str - $today;
You can use the modulus (remainder) operator in each if to show the next value as well. For example if you have 3.7 days, you use 3 days and then .7*$hours.

Answer 2

Change all else if statements to if's
Change from:
if(intval($time_differnce/$years) > 1) {
return " - ". intval($time_differnce/$years)." years left";
} else if (intval($time_differnce/$years) > 0) {
to
if(intval($time_differnce/$years) > 1) {
return " - ". intval($time_differnce/$years)." years left";
}
if (intval($time_differnce/$years) > 0) {