How to pass the php variables from dynamically created HTML page to next php file.
For Example. I have the following php code
<?php
session_start();
$uid=$_SESSION['uid'];
$doc=new DOMDocument('1.0');
$doc->loadHTML("
<html>
<head>
</head>
<body>
<a href='comments.php?id=`$uid`'> comments</a>
</body>
</html>
");
echo 'wrote:'. $doc->savedHTMLFile("/home/user/project1/test1.html"). 'bytes';
?>
Now when I see dynamically created HTML page, it just shows me the following code with .html extension; so how can I pass the php variable from this page to next file:
<html>
<head>
</head>
<body>
<a href='comments.php?id=`$uid`'> comments</a>
</body>
</html>
try to replace
<a href='comments.php?id=`$uid`'>
to
<a href='comments.php?id=$uid'>
try this... Your mistake is here 'comments.php?id=$uid' is string no php code use correct like this 'comments.php?id=".$uid."'.
<?php
session_start();
$uid = $_SESSION['uid'];
$doc = new DOMDocument('1.0');
$doc->loadHTML("
<html>
<head>
</head>
<body>
<a href='comments.php?id=".$uid."'> comments</a>
</body>
</html>
");
echo 'wrote:' . $doc->savedHTMLFile("/home/user/project1/test1.html") . 'bytes';
?>
Basically, you can use $_GET[''] method to do it. You just insert it into the URL, but I think, this will make the site vulnerable to SQL Injection.
remove back ticks(`) around $uid or use this code
<?php
session_start();
$uid=$_SESSION['uid'];
$doc=new DOMDocument('1.0');
$doc->loadHTML("
<html>
<head>
</head>
<body>
comments
</body>
</html>
");
echo 'wrote:'. $doc->savedHTMLFile("/home/user/project1/test1.html"). 'bytes';
?>
Related
Guys, I have a problem. Is there a way to add html inside a tag without using javascript using only php anyway ?. Thank you very much for your help in advance.
For example, there is this code:
<?php
// This part is required here, because she comes another function.
// It's generate from php server, I need to show inside tag body, for example.
$code = "<h1 style='display:none' id='title'>My String</h1>";
echo $code;
?>
<!DOCTYPE html>
<html lang="en">
<head>
<title>Document</title>
</head>
<body>
<div id="my-div"></div>
<script src='https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.0/jquery.min.js'
integrity='sha512-b6lGn9+1aD2DgwZXuSY4BhhdrDURVzu7f/PASu4H1i5+CRpEalOOz/HNhgmxZTK9lObM1Q7ZG9jONPYz8klIMg=='
crossorigin='anonymous'></script>
<script>
$('#my-div').html($('#titulo').html());
</script>
</body>
</html>
The output is this in the source code:
In the browser, the output is this My String:
But, this manipulation is the gift, which uses javascript for this. I don't want it that way. This will not do, because the code will be shown at the top, before the <! DOCTYPE html> tag. Is it possible, on the server, to insert <h1 style ='display:none' id='title'> My String </h1> inside the boby tag, for example?
How I would like it to look:
Example 2
For example, I have this file with code:
file2.php
<?php
include "file2.php";
?>
<!DOCTYPE html>
<html lang="en">
<head>
<title>Document</title>
</head>
<body>
<div id="my-div">
I want to show "<h1>My String</h1>" here.
</div>
</body>
</html>
Yes you can do it as simple as this:
<!DOCTYPE html>
<html lang="en">
<head>
<title>Document</title>
</head>
<body>
<div id="my-div">
<?php
$code = "<h1 style='display:none' id='title'>My String</h1>";
echo $code;
?>
</div>
<script src='https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.0/jquery.min.js'
integrity='sha512-b6lGn9+1aD2DgwZXuSY4BhhdrDURVzu7f/PASu4H1i5+CRpEalOOz/HNhgmxZTK9lObM1Q7ZG9jONPYz8klIMg=='
crossorigin='anonymous'></script>
</body>
</html>
PHP is a server side scripting language and will only parse PHP code on the server side.
Yes, you can place HTML code inside PHP variables like you have done, but that will get rendered into the client (your browser).
What you can do is place $code variable inside the target div, like this:
<div id="my-div"><?php echo $code; ?></div>
Give it a try
I'd like to select an included html element with jQuery. How can I achive this?
index.php
<?php
<html>
<head>
...
</head>
<body>
include('file.php');
</body>
<html>
?>
file.php
<?php
echo '<div class="test">test</div>';
?>
select.js
let a = $('.test');
console.log(a); // returns undefined
Try executing your script after the page has fully loaded.
$(window).on("load", function() {
let test = $('.test');
console.log(test);
});
Code should be organized as follows: <?php Php.Code.Goes.Here ?>. This can be surrounded by HTML, for instance, <b><?php print("HELLO!"); ?></b>. This will display: HELLO!
So...you see the problem then, with...
<?php
<html>
<head>
...
</head>
<body>
include('file.php');
</body>
<html>
?>
The HTML is IN the PHP. You want this:
<html>
<head>
...
</head>
<body>
<?php include('file.php'); ?>
</body>
<html>
This code, of course, shouldn't have executed at all, since <?php <html> isn't really valid PHP syntax.
tried to ask this question earlier but made a total mess of it. so thought i'd try it again but clearer this time.
how can you get php variables to display in loaded content using JQuery?
index.php:
<!doctype html>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
<script>
$(document).ready(function(){
$('#clickMe').click(function(){
$('#parent').load('loaded.php #child', {},function(){
});
});
});
</script>
</head>
<?php
session_start();
$test = "this should display php string";
$_SESSION['another'] = "Session variable String";
echo ' tests to see if they work below <br>';
echo $test."<br>";
echo $_SESSION['another']."<br><br>";
?>
<button name="clickMe" id="clickMe" class="clickMe">Click me</button>
<div class="parent" name="parent" id="parent" style="background-color:yellow; height:200px; width:200px;">
</div>
<body>
</body>
</html>
loaded.php:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>
<body>
<div name="child" id="child" class="child">
<p1> html loads fine..</p1><br>
<?php echo $test ?><br>
<?php echo $_SESSION['another'] ?>
</div>
</body>
</html>
As stated by #Fred -ii- in the comments, you only have to fetch the session in your index.php file to do this.
If you want to get a part of another web page inside index.php :
Your index.php should contain this call :
$(document).ready(function(){
$('#clickMe').click(function(){
$('#parent').load('loaded.php'); // No need for additional parameters
});
});
You don't need to select a part of the HTML, return just what you need :
loaded.php :
<?php session_start() ?>
<p>Example text</p>
<?php echo $_SESSION['another'] ?>
So, Im creating a library for other uses, but how can I make content from a file specificly go within the <head> or <body> html tag attribute etc...
for example, this is what im trying to make.
<html>
<head>
<?php include('content/starter/library.php'); ?>
<!-- From that included file, theres a script that put content in the head.-->
</head>
<body>
<!-- From that included file, theres a script that put content in the body -->
</body>
</html>
Im just trying to find another way instead of making multiple files for specific sections and do
<html>
<head>
<?php include('content/starter/library_head.php'); ?>
</head>
<body>
<?php include('content/starter/library_body.php'); ?>
</body>
</html>
Which I don't really want to do. Im not very good with javascript so, There no hope of me trying to figure out how to do this with javascript. Thanks for the answers in the future.
If you want to use one file (as your questions suggests) then one method is to create variables or functions in your library.php file and then echo them in your template
// contents of the library.php file...
<?php
$head_content = "put your <head> content here";
$body_content = "put your <body> content here";
?>
// your HTML file...
<?php include('content/starter/library.php'); ?>
<html>
<head>
<?php echo $head_content ?>
</head>
<body>
<?php echo $body_content ?>
</body>
</html>
UPDATE
To answer the question in your comment, here's an example using a function. You can put all of your code in a function and then just echo that anywhere in your document.
<?php
// contents of library.php...
function head() {
$return = '<link href="file.css" rel="stylesheet">';
$return .= '<link href="another_file.css" rel="stylesheet">';
return $return;
}
// your HTML file...
<html>
<head>
<?php echo head(); ?>
</head>
PHP functions explained: http://www.w3schools.com/php/php_functions.asp
can you please let me know what I am missing:
<html>
<head><title>page</title></head>
<body>
<h2><center>Welcome to the mainpage</center></h2><br />
Home page
</body>
</html>
php code is :
<?PHP
$currpage=$_GET['currpage'];
echo "Hello world $currpage";
?>
when I click the homepage I want the sample4.php script to be executed and that output which is a html page to be displayed.
But when I click the homage page : I get a file window download.
I have the php script in the same location I have the html?
Does:
<html>
<head>
<title>My Page</title>
</head>
<body>
<p>Home page<p>
</body>
</html>
Do what you want? Otherwise, you'll need to show us the PHP code, in case it's making it a download from within the PHP.
For a hello world program, try this:
<html>
<head>
<title>My Page</title>
</head>
<body>
<?php
$currpage = isset($_REQUEST['currpage']) && is_int($_REQUEST['currpage'])?(int)$_REQUEST['currpage']:1;
echo "<p>Current page is $currpage</p>\n";
?>
</body>
</html>
You may also need to make sure that PHP is installed and running on your machine/server...
<html>
<head>
<title>My Page</title>
</head>
<body>
<?php
phpinfo();
?>
</body>
</html>