I'm running a second database search using mysql inside a for loop but I can't get it show the correct amount of rows:
Original search:
$topicemailsql = "select se.id as id, se.users as users, se.topic as topic, se.body as body, se.postID as postID, DATE_FORMAT(se.sent, '%d.%m.%Y %H:%i:%s' ) as sent, (SELECT u.email from users u where u.users_id in (se.users)) as emails from sentEmail se LEFT OUTER JOIN topics t on (t.ID = se.theader_) where t.ID = '$topicID'";
$topicemailsqlquery = mysql_query($topicemailsql)or die(mysql_error());
$numrows = mysql_num_rows($topicemailsqlquery);
php for loop:
for ($i=0; $i < $numrows ; $i++){
$sqlarray = mysql_fetch_array($topicemailsqlquery);
$users = $sqlarray['users'];
$sqlemail = ('select email from users where users_id in ("'.$users.'")');
//echo $sqlemail;
$emailsqlquery = mysql_query($sqlemail)or die(mysql_error());
$amountofusers = mysql_num_rows($emailsqlquery);
$sqlarrayemail = mysql_fetch_array($emailsqlquery);
echo $amountofusers;
//echo $sqlarrayemail['email'];
for ($a=0; $a < $amountofusers ; $a++){
if($a == 0){
$email = $sqlarrayemail['email'];
}
else if($a < $amountofusers){
$email = $sqlarrayemail['email'].','.$sqlarrayemail['email'];
}
}
}
So based on this the $amountofusers should return more than 1 row but now it always return only one row.
When I echo the $sqlemail it should return 2 rows because it looks like this:
select email from users where users_id in ("4,82") --> this should return 2 rows and a count of 2 but it only returns one row.
Where does it go wrong?
Br,
Toby
I think, it's a very bad idea to store multiple values in one field. Furthermore I wouldn't fire up queries in a loop, if I can avoid it. Better fetch the data in one go and let PHP do the rest. If you try your query i.e. with PHPAdmin you would use
SELECT email
FROM users
WHERE users_id IN (4, 82)
The IN operator needs a comma separated list of arguments. You give one single value
"4,82"
That's a huge difference. MySQL would accept ("4","82") too (other DBMS are not as tolerant) and handle the not needed conversion for you.
Related
I have 2 queries that I want to compare and display
Compare the 2 queries for matching
if match show image, if not show placeholder image
$variable1 = " SELECT * FROM
(
SELECT img, ID from tbl1
UNION DISTINCT
SELECT img, ID from tbl2
) as everything";
while($a = mysqli_fetch_array...){
$row1 = $a['img'];
$rowA = $a['ID'];
}
Compare with
$variable2 = "SELECT img, ID FROM tbl3";
while($b = mysqli_fetch_array...){
$row2 = $b['img'];
$rowB = $b['ID'];
}
I tried the foreach looping through each row to compare
foreach($rowB as $rowC){
if($rowC == $rowA)...
echo'<table>'.$row1.'</table>';
}else{
echo'<table>'.$row2.'</table>';
}
Seems like the entire result is repeated by the number of matches. I tried nesting one query into the other along with a host of other trials. Could use some guidance.
I have a code in PHP where I want to display multiple times values, and so, even if these values are the same between them. My code is simple :
$sql = "SELECT photo from table WHERE username IN ('1','2','2') ORDER BY id DESC ";
$res = array();
$result = mysqli_query($con,$sql);
while($row = mysqli_fetch_array($result)){
array_push($res, $row['photo']);
}
echo json_encode($res);
But this code only display (in json) an array of two values (because the values of photo of the username 2 are the same).
What I want to achieve is to make an array with the exact same number of values of the number of username I defined WHERE username IN ('1','2','2') (so here, 3 values).
I hope you understood me, thanks for helping me !
I think what you're after is to list even the duplicates in the end result. As your SQL will only retrieve the unique items, the idea would be to include the username in the SQL result set. Then use the original list of user names ($userNames) and add in the photo for each of them.
I've used mysqli_fetch_all() to simplify the process of fetching all of the data, then used array_column() to make the username the key for the photos.
$userNames = array(1,2,2);
$sql = "SELECT username, photo
from table
WHERE username IN ('".implode("','", $userNames)."')
ORDER BY id DESC ";
$res = array();
$result = mysqli_query($con,$sql);
$photos = mysqli_fetch_all($result, MYSQLI_ASSOC);
$photos = array_column($photos, "photo", "username");
foreach ( $userNames as $user ) {
if ( isset($photos[$user])) {
$res[] = $photos[$user];
}
else {
$res[] = '';
}
}
echo json_encode($res);
You would use left join:
select t.photo
from (select '1' as username union all select '2' union all select '3'
) u left join
table t
on t.username = u.username
order by t.id desc;
Note this will return rows, even when the user name does not exist. If you want to filter those rows, remove the left so you are doing an inner join.
I am trying to get single rank for a user for each stat "column" in the table. I am trying to do this as more efficiently because i know you can.
So I have a table called userstats. in that table i have 3 columns user_id, stat_1, stat_2, and stat_3. I want to me able to get the rank for each stat for the associated user_id. with my current code below i would have to duplicate the code 3x and change the column names to get my result. please look at the examples below. Thanks!
this is how i currently get the rank for the users
$rankstat1 = getUserRank($userid);
<code>
function getUserRank($userid){
$sql = "SELECT * FROM ".DB_USERSTATS." ORDER BY stat_1 DESC";
$result = mysql_query($sql);
$rows = '';
$data = array();
if (!empty($result))
$rows = mysql_num_rows($result);
else
$rows = '';
if (!empty($rows)){
while ($rows = mysql_fetch_assoc($result)){
$data[] = $rows;
}
}
$rank = 1;
foreach($data as $item){
if ($item['user_id'] == $userid){
return $rank;
}
++$rank;
}
return 1;
}
</code>
I believe there is a way for me to get what i need with something like this but i cant get it to work.
$rankstat1 = getUserRank($userid, 'stat_1'); $rankstat2 =
getUserRank($userid, 'stat_2'); $rankstat3 = getUserRank($userid,
'stat_3');
You can get all the stat ranks using one query without doing all the PHP looping and checking.
I have used PDO in this example because the value of the $userid variable needs to be used in the query, and the deprecated mysql database extension does not support prepared statements, which should be used to reduce the risk of SQL injection.
The function could be adapted to use the same query with mysqli, or even mysql if you must use it.
function getUserRanks($userid, $pdo) {
$sql = "SELECT
COUNT(DISTINCT s1.user_id) + 1 AS stat_1_rank,
COUNT(DISTINCT s2.user_id) + 1 AS stat_2_rank,
COUNT(DISTINCT s3.user_id) + 1 AS stat_3_rank
FROM user_stats f
LEFT JOIN user_stats s1 ON f.stat_1 < s1.stat_1
LEFT JOIN user_stats s2 ON f.stat_2 < s2.stat_2
LEFT JOIN user_stats s3 ON f.stat_3 < s3.stat_3
WHERE f.user_id = ?"
$stmt = $pdo->prepare($sql);
$stmt->bindValue(1, $userid);
$stmt->execute();
$ranks = $stmt->fetchObject();
return $ranks;
}
This should return an object with properties containing the ranks of the given user for each stat. An example of using this function:
$pdo = new PDO($dsn, $user, $pw);
$ranks = getUserRanks(3, $pdo); // get the stat ranks for user 3
echo $ranks->stat_2_rank; // show user 3's rank for stat 2
$sql = "SELECT user_id, stat_1, stat_2, stat_3 FROM ".DB_USERSTATS." ORDER BY stat_1 DESC";
Also, unless there is a reason you need ALL users results, limit your query with a WHERE clause so you're only getting the results you actually need.
Assuming you limit your sql query to just one user, this will get that user's stats.
foreach($data as $item){
$stat_1 = $item['stat_1'];
$stat_2 = $item['stat_2'];
$stat_3 = $item['stat_3'];
}
If you get more than one user's stats with your sql query, consider passing your $data array back to the calling function and loop through the array to match the users stats to particular user id's.
Hello I would like to query multiple identical tables in my db which has different prefixes and than display the results randomly but somehow I need to track the origin of the item and I couldn't figure out how
I do the query like this because I don't have access to information_schema
$query = "SHOW TABLES FROM mydb WHERE RIGHT( tables_in_mydb, 5 ) = 'table'";
$res = mysql_query($query);
$num = mysql_num_rows($res);
while($row = mysql_fetch_row($res)) {
$numbers = explode('_', $row[0]);
if($num > 0) {
$q = "SELECT `this`, `that`, `something` FROM ".$numbers[0]."_idetinticaltables"; // :)
$r = mysql_query($q);
while($c = mysql_fetch_array($r)) {
/*display the results randomly with an identifier where the come from*/
}
}
}
You could use ORDER BY RAND() to randomly sort it
The following might work:
Get the list of the tables you're interested in. You already do that.
Create a UNION of multiple SELECT statements. Each SELECT statement differs for the table being selected from and you add a column set to the name of the table (so you can identify it later):
(SELECT *, TABLENAME = 'first_name_of_table' FROM first_name_of_table ...)
UNION
(SELECT *, TABLENAME = 'second_name_of_table' FROM second_name_of_table ...)
UNION
...
ORDER BY RAND() LIMIT 10;
Because it is a UNION you can randomize the whole order then. See How can i optimize MySQL's ORDER BY RAND() function? because it is not that trivial to do well, the example above is only to have an ORDER BY and LIMIT clause placed there. With many entries in your tables, it will kill your server.
$aa=array()
while($c = mysql_fetch_array($r))
{
/*display the results randomly with an identifier where the come from*/
$aa[]=$c;
}
echo $aa; // print "Array"
Trying to search through a column in a db, and pull out the total number of males, and total number of females.
This data is stored in the db as f and m in the whatsex column.
$query = "SELECT whatsex, COUNT(*) FROM soberdata GROUP BY whatsex";
$result = mysqli_query($connection,$query) or die(mysql_error());
$sexdb = mysqli_fetch_array($result);
$totalmale = $sexdb['m'];
$totalfemale = $sexdb['f'];
echo $totalfemale." & ".$totalmale;
This code outputs nothing. What am I doing wrong?
$sexdb have only "whatsex" and "COUNT(*)" columns. You should use one of them
try
print_r($sexdb);
and look if some of results meet your needs
Your query is going to return a whatsex value, and a COUNT(*) value, not m or f. Doing a var_dump($sexdb) would show you what's in the array.
You are treating a multi-dimensional array as flat. You could do this to flatten it
$query = "SELECT whatsex, COUNT(*) as total FROM soberdata GROUP BY whatsex";
while ($row = mysqli_fetch_array($result)) {
$$row['whatsex'] = $row['total']; // this makes a variable ($m or $f) using the value of the row
}
$totalmale = !empty($m) ? $m : 0;
$totalfemale = !empty($f) ? $f : 0;
You should empty check the results of the db in case there is no male or female entries to avoid errors.