PHP Foreach loop only displaying last result - php

Question

I am having a bit of trouble with some code where in an array I have a list of 2 and the function is only displaying the last in the list.
Here is the code:
<?php
function getKeywordPosition($theurl,$thekeywords) {
$theurl = $theurl;
$thekeywords = $thekeywords;
$found = false;
$x = 0;
for($x; $x < 64 && $found == false;)
{
$url = "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&"
. "q=".stripslashes(str_replace(' ', '%20', $thekeywords)).'&start='.$x;
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_REFERER, 'http://www.boo.com');
$body = curl_exec($ch);
curl_close($ch);
$json = json_decode($body);
$x4 = $x + 4;
$old_x = $x;
for($x; $x < $x4 && $found == false; $x = $x + 1)
{
if (strpos($json->responseData->results[$x-$old_x]->unescapedUrl, strtolower($theurl)) !== false)
{
$found = true;
}
}
// now have some fun with the results...
}
if($found)
{
echo '<strong>'.$theurl.'</strong> is located as the <strong>'.$x.'</strong> result when searching for <strong>'.stripslashes($thekeywords).'</strong>';
echo '<br>';
}
}
$list = array('php.com'=>'php', 'php.com'=>'php');
foreach($list as $key => $value){
getKeywordPosition($key,$value);
}
?>
Why is this not working properly?

Answer 1

Unless this is a badly contrived example, then th issue is you have duplicate keys in your array:
$list = array('php.com'=>'php', 'php.com'=>'php');
This array has a single entry
You coud refactor like so:
$list = array(
array('url'=>'php.net', 'keyword'=>'php'),
array('url'=>'php.net', 'keyword'=>'arrays'),
array('url'=>'php.net', 'keyword'=>'anotherkeyword')
);
foreach($list as $entry){
getKeywordPosition($entry['url'], $entry['keyword']);
}