codeigniter unix timestamp validate - php

I have unix timestamp input value. I have to validate whether input is correct timestamp format or not. Currently I'm using this:
$currenttime = $_POST['unixdate']; //input unix timestamp
if( $currenttime==strtotime( date('Y-m-d H:m:s',$currenttime) ) ){
echo "Correct";
} else {
echo "incorrect format";
}
I check this with several test cases, but its fail. Is that correct or is there any other way to check input is unix timestamp format or not?

I timestamp is just an integer that represents the number of seconds passed since the epoch. So the best validation you can do is something like
$currenttime = $_POST['unixdate']; //input unix timestamp
if((int)$currenttime == $currenttime && is_numeric($currenttime)) {
If you know what date you are expecting you could check to see if the timestamp falls between two dates or something like that
$startDate = '2014-10-04';
$endDate = '2013-10-04';
if((strtotime($currentDate) > strtotime($startDate)) && (strtotime($currentDate) < strtotime($endDate))) {
//Is valid
}

Your validation is incorrect because you compare with another date where you've replaced minutes with months:
'Y-m-d H:m:s'
^ ^
Other than that, it's quite a pointless validation. A Unix timestamp is nothing but a number (an integer if you want to be strict). Something like this should be enough:
$currenttime = filter_input(INT_POST, 'unixdate', FILTER_VALIDATE_INT);
if($currenttime===false){
// Invalid
}
Your method is like validating an age by trying to calculate the date of birth ;-)

Related

php strtotime() values not working as expected

this code keeps telling me that $lasUpdate is always greater than $yesterday no matter the change i make to $yesterday result is (12/31/14 is greater than 01/19/15 no update needed). i feel like i'm missing something simple thank you in advance it is greatly appreciated.
$result['MAX(Date)']='12/31/14';
$lastUpdate = date('m/d/y', strtotime($result['MAX(Date)']));
$yesterday = date('m/d/y', strtotime('-1 day'));
if($lastUpdate<$yesterday){echo $lastUpdate.'is less '.$yesterday.'<br>'.'update needed';}
if($lastUpdate>=$yesterday){echo $lastUpdate.'is greater than '.$yesterday.'<br>'.'no update needed';
You have fallen victim to PHP type juggling with strings. A date function has a return value of a string. You cannot compare dates in their string format since PHP will juggle strings into integers in the context of a comparison. The only exception is if the string is a valid number. In essence, you are doing:
if ('12/31/14' < '01/19/15') { ... }
if ('12/31/14' >= '01/19/15') { ... }
Which PHP type juggles to:
if (12 < 1) { ... }
if (12 >= 1) { ... }
And returns false on the first instance, and true on the second instance.
Your solution is to not wrap date around the strtotime functions, and just use the returned timestamps from the strtotime functions themselves to compare UNIX timestamps directly:
$lastUpdate = strtotime($result['MAX(Date)']);
$yesterday = strtotime('-1 day');
You will however want to use date when you do the echo back to the user so they have a meaningful date string to work with.
Try something like this:
$lastUpdate = strtotime($result['MAX(Date)']);
$yesterday = strtotime('-1 day');
if ($lastUpdate < $yesterday) { /* do Something */ }
12/31/14 is greater than 01/19/15
Because 1 is greater than 0. If you want to compare dates that way you will need to store them in a different format (from most to least significant digit), for example Ymd.
Or store the timestamps you are making in the different variables and compare them.

How to check whether the date coming in $_POST array is not greater than today's date in PHP?

The date to be checked is as follows :
$submission_date = 12-25-2014; //The date in mm-dd-yyyy format that is to be tested against today's date
Now I want to echo the error message since the date contained in a variable $submission_date is a future date.
How should I do this efficiently and effectively using PHP?
Thanks in advance.
Many ways to do this (use DateTime::createFromFormat() to control exact format of input dates, for example) but perhaps the simplest that suits the example is:
$isFuture = (strtotime($submission_date) > strtotime($_POST['current_date']))
Note that OP changed the question. If desired date to test against is not in $_POST array, just replace strtotime($_POST['current_date']) with time() to use current system time.
To compare against current date, disregarding time of day, use:
$today = new DateTime(date("Y-m-d"));
// $today = new DateTime("today"); // better solution courtesy of Glavić
// see http://php.net/manual/en/datetime.formats.relative.php for more info
$today_timestamp = $today->getTimestamp();
If posted format is in m-d-Y, then you cannot convert it to unix timestamp directly with strtotime() function, because it will return false.
If you need to use strtotime() then change the input format to m/d/Y by simple str_replace().
On the other hand, you could use DateTime class, where you can directly compare objects:
$submission_date = DateTime::createFromFormat('!m-d-Y', $submission_date);
$today_date = new DateTime('today');
if ($submission_date > $today_date) {
echo "submission_date is in the future\n";
}
demo
With PHP DateTime you can check whether the input date is future or old w.r.to the todate.
$submission_date = DateTime::createFromFormat('m-d-Y', $submission_date);
$submission_date = $submission_date->format('Y-m-d');
$current_date = new DateTime('today');
$current_date = $current_date->format('Y-m-d');
if ($submission_date > $current_date)
{
echo "Future date";
}
else
{
echo "Old date";
}

Adding leading zeroes to a string date in PHP

I have a string "date" which can be DD.MM.YYYY or D.M.YYYY (with or without leading zeros), it depends what a user types.
Then I use it in a condition to send another email when the day is today.
if($_POST["date"]== date("d.m.Y")){
$headers.="Bcc: another#mail.cz\r\n";
}
The problem is that the mail is send when the date format DD.MM.YYYY (with leading zeros) only.
My proposed solution
As I'm not very good in PHP, I only know the solution theoretically but not how to write the code - I would spend a week trying to figure it out on my own.
What's in my mind is dividing the date into three parts (day, month, year), then checking the first two parts if there's just one digit and adding leading zeros if it's the case. I don't know how to implement that to the condition above, though. I have read a few topics about how to do this, but they were a bit more different than my case is.
You should equalize to same format d.m.Y and you can do this with strtotime and date function:
$post_date = date("d.m.Y", strtotime($_POST["date"]));
if($post_date == date("d.m.Y")){
$headers.="Bcc: another#mail.cz\r\n";
}
I changed date to $post_date for more clear. I'll try to explain difference with outputs
echo $_POST["date"]; // lets say: 8.7.2013
echo date("d.m.Y"); // 09.09.2013 > it's current day
strtotime($_POST["date"]); // 1373230800 > it's given date with unix time
$post_date = date("d.m.Y", strtotime($_POST["date"])); // 08.07.2013 > it's given date as right format
If you use date function without param, it returns as current date.
Otherwise if you use with param like date('d.m.Y', strtotime('given_date'));, it returns as given date.
$post_date = date("d.m.Y", strtotime($_POST["date"]));
At first, we converted your date string to unix with strtotime then equalized and converted format that you used in if clause.
first set date format with leading Zero
$postdate = strtotime('DD.MM.YY', $_POST['date']);
and also matching date will be in same format
$matching_date = date('DD.MM.YY', strtotime('whatever the date'));
then
if ( $postdate === $matching_date )
{
// send mail
}
Why don't you just check the length of the _POST (it can be either 8 or 10)
if (strlen($_POST["date"]) == 10) {
$headers.="Bcc: another#mail.cz\r\n";
}

Comparing a date to current server date using PHP

I am using the following code to attempt to compare the current date with a date entry in a mySql database. It's code that I have found online and adapted as all the examples I have found hard-code the date to compare the current date with.
The trouble is even dates in the future are being marked as expired and I can't understand why this would be.
I am afraid that I am still new to PHP, so I may be making a schoolboy error!
$exp_date = KT_formatDate($row_issue_whatson1['dateToShow']);
$todays_date = date("d-m-Y");
$today = strtotime($todays_date);
$expiration_date = strtotime($exp_date);
if ($expiration_date > $today) { echo "Not expired"; } else { echo "expired"; }
Any help would be most appreciated.
I should add that the date time format used in the database entries is dd/mm/yyyy
Instead of making a string then converting it to a timestamp, simply use mktime:
<?php
$today = mktime(
0, // hour
0, // minute
0 // seconds
);
?>
The rest of the values will be filled according to today's date. If this still gives problems, put in some echo's for the values of $exp_date and $expiration_date.
Edit
Since this solved the problem, the discrepancy you were seeing was because you were doing the opposite with date('d-m-Y'). You were asking for the current date and the time values are then filled in with the current time. The expiration date in the database is likely set at midnight. With both dates being equal, and it being say 11am now, you are comparing if (00:00:00 > 11:00:00) which fails.
$exp_date = 14/05/2011 // todays date, int
$server_date = server.date() // servers date, int
// check exp_date against server date
if ( $server > $exp_date)
{ echo "Sorry your 'service' has expired"; }
else
{ echo "Welcome 'members_name' to StackOverflow"; }
Try that. However you need the right date format, as server.date() is probably different in PHP.
If problem still persists I would check whether your dates are strings or integers or both. That could possibly be the issue.
Hope that helps.
DL.
Your function does not seem to be valid.
function KT_formatDate( $exp_date){
$exp_date = strtotime($exp_date);
$now = time();
if ($now > $exp_date)
return 'expired';
else
return ' Not expired';
}
$response = KT_formatDate($row_issue_whatson1['dateToShow']);

PHP Compare datetime values

In my PHP application I'm trying to compare date time values like the following:
if($datetime_from_db < date('Y-m-d H:i:s'))
{
// then do something
}
Both values are in the same format. What I can't figure out is why it only compares the date and ignores the time. Both the date and the time values are important for me but I don't know how to make it work.
Comparing a string like "2011-02-14 15:46:00" to another string doesn't actually compare dates, it compares two strings according string parsing numeric rules. You will need to compare actual numeric timestamps:
strtotime($datetime_from_db) < time()
If you want this to work with dates past 2038, you can't use strtotime() or time().
See this question for the explanation.
A better approach:
new DateTime($datetime_from_db) < new DateTime();
This may help you.
$today = date("m-d-Y H:i:s");
$thisMonth =date("m");
$thisYear = date("y");
$expectedDate = $thisMonth."-08-$thisYear 23:58:00";
//pr($today);
//pr($expectedDate);
if (strtotime($expectedDate) > strtotime($today)) {
echo "Expected date is greater then current date";
return ;
} else
{
echo "Expected date is lesser then current date";
}
Here is a solution where we use strtotime. I give two examples.
First one comparing the whole timestamp. Second one is just compare the date.
<?php
$date = "2022-10-06 17:49:10"; // string. can set any current timestamp
#example 1 - compare the date and time Y-m-d H:i:s
if(date("Y-m-d H:i:s" , strtotime($date)) >= date("Y-m-d H:i:s")){
echo "the date checked is bigger than today";
}else{
echo "the date checked is smaller than today";
}
#example 2 - compare the date only Y-m-d
if(date("Y-m-d" , strtotime($date)) == date("Y-m-d")){
echo "same day is true";
}else{
echo "same day is false";
}

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