I want to execute a command on a remote machine and store the out of that command in a variable using php
Here is what i tried
$command = 'exec("whoami")';
$connection = ssh2_connect($ip,$port);
ssh2_auth_password($connection,$user,$pass);
$test = ssh2_shell($connection,$command);
echo $test;
According to me $test should output root
However nothing is return , I am sure i am missing something.....
php-pecl-ssh2 is already installed and no error is returned
I guess your command is incorrect :
$command = 'whoami';
And you should also add this 2 lines to the end to get your output :
if ( $connection = ssh2_connect($ip,$port) ) {
echo 'Error occured while connecting to server via ssh';
}
if (!ssh2_auth_password($connection,$user,$pass)) {
echo 'Error occured while authenticating via ssh';
}
if(!$test = ssh2_shell($connection,$command)){
echo 'Error occured while executing remote command via ssh';
} else {
stream_set_blocking($test, true);
echo stream_get_contents($test);
}
Related
So I have question which in my head should seem very simple to solve.
I want to ssh to a server, which I have done a ton of times, and then make a shell execute which I have done a ton of times as well, but it is not working.
The code i am using
<?php
$ip = '1.2.3.4';
$cmd = "ssh user#".$ip;
$result = shell_exec($cmd." 'sudo /bin/systemctl stop wildfly.service'");
echo "<pre>output: $result</pre>";
echo "<div class='alert alert-success'><strong>SUCCESS</strong><br>Wildfly node has now restarted</div>";
?>
Running the command directly from the terminal
ssh user#1.2.3.4 sudo /bin/systemctl stop wildfly.service
It works, but running it within php gives me nothing, and it not doing anything.
Can someone maybe guide me to what I am doing wrong with my shell_exec?
Thanks in advance!
function execPrint($command) {
try {
$result = array();
exec($command.' 2>&1', $result);
foreach ($result as $line) {
print($line . "\n");
}
echo '------------------------' . "\n" . "\n";
} catch (\Exception $e) {
print($e);
}
http_response_code(200);
}
i made this function to get result
add 2>&1 in last of the CMD
use print with every line
use try and catch to catch any error
The user attempting to execute those shell commands from php is likely _www and not you. Try this code in your php to gain insight:
$shellscript = 'whoami';
$sr = shell_exec($shellscript);
echo '['.$sr.']';
Make sure the shell_exec function is not disabled. It usually is disabled by default in CPanel accounts PHP.ini and PHP-FPM .ini files.
You can check it using this validation
if (is_callable('shell_exec') && (false === stripos(ini_get('disable_functions'), 'shell_exec'))) {
echo "shell_exec enabled";
} else {
echo "shell_exec disabled";
}
It's the most common reason i've found for shell_exec to return always empty
You can also execute a quick command for testing purpouses
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
echo "Command: shell_exec('ls -lart')";
try {
$output = shell_exec('ls -lart');
echo "<pre>$output</pre>";
} catch (Exception $e) {
echo $e->getMessage();
}
I'm creating a button on my web page.I want that when someone presses this button an execution of a process of Linux commands on my first server (like "cd file" "./file_to_execute"..) when these commandes are done and finished i want to connect on another server by ssh and to execute another commands.
the probleme is how can i know that the commands before are already finished to proceed to the second part which is to connect on another server .
to resume :
first step connect on the first server , execute some commands
=> when these commands are done ( the part i dont know how to do it )
second step : to connect on another server and execute some others commands.
I'm searching for a way that will allows me to add some pop up to inform the user of my web page that he finished the first step and he started the second.
<?php
$hostname = '192.177.0.252';
$username = 'pepe';
$password = '*****';
$commande = 'cd file && ./file_one.sh';
if (false === $connection_first = ssh2_connect($hostname, 22)) {
echo 'failed<br />';
exit();
}
else {
echo 'Connected<br />';
}
if (false === ssh2_auth_password($connection_first, $username, $password)) {
echo 'failed<br />';
exit();
}
else {
echo 'done !<br />';
}
if (false === $stream = ssh2_exec($connection_first, $commande)) {
echo "error<br />";
}
?>
Thanks
PS: sorry for my English, I'm from Barcelone
To handle events where an exception occurs i would recommend using a try/catch statement, like the one below:
try {
echo inverse(5) . "\n";
echo inverse(0) . "\n";
} catch (Exception $e) {
echo 'Caught exception: ', $e->getMessage(), "\n";
}
When you're trying to handle events and need to know when they finish, there are a few ways to achieve this. You can either set a boolean to true after the command has been executed (like what you are already doing). OR you can return output from the command by printing the output to a txt file and then echoing out the returns of this file. See code below:
exec ('/usr/bin/flush-cache-mage > /tmp/.tmp-mxadmin');
$out = nl2br(file_get_contents('/tmp/.tmp-mxadmin'));
echo $out;
At this point you can create conditions based off of what is returned in the $out variable.
My first time to deploy matlab exec in php and i need ur help.
I have a matlab script compiled as sampleExe.exe (standalone app) with a single argument 'IdNo' to processes images. When i call it thru command line using sampleExe 2014000, the program runs and gives the desired output. However, I am having trouble when deploying/calling sampleExe.exe file from php as it gives me no output at all. :(
Here's the code i tried based on this: Call matlab exe from php is not working well
<?php
define("EVAL_IMAGE","sampleExe.exe");
$target=isset($_REQUEST['IdNo'])?trim($_REQUEST['IdNo']):"";
if($target==""){
echo "No folder name is passed";
exit();
}
passthru(EVAL_IMAGE." ".$target);
?>
Any help is very much appreciated. Btw, I tried running it in a localhost and sampleExe.exe is also save in c:/wamp/www
<?php
try {
define("EVAL_IMAGE","mainProg1.exe");
$target=isset($_REQUEST['IdNo'])?trim($_REQUEST['IdNo']):"";
if($target==""){
echo "No folder name is passed";
exit();
}
set_time_limit(300);
$return = exec(EVAL_IMAGE." ".$target);
echo "return = " .$return;
}catch (Exception $e) {
echo 'Message: ' .$e->getMessage();
}
exit(0); ?>
How can you mimic a command line run of a script with arguements inside a PHP script? Or is that not possible?
In other words, let's say you have the following script:
#!/usr/bin/php
<?php
require "../src/php/whatsprot.class.php";
function fgets_u($pStdn) {
$pArr = array($pStdn);
if (false === ($num_changed_streams = stream_select($pArr, $write = NULL, $except = NULL, 0))) {
print("\$ 001 Socket Error : UNABLE TO WATCH STDIN.\n");
return FALSE;
} elseif ($num_changed_streams > 0) {
return trim(fgets($pStdn, 1024));
}
}
$nickname = "WhatsAPI Test";
$sender = ""; // Mobile number with country code (but without + or 00)
$imei = ""; // MAC Address for iOS IMEI for other platform (Android/etc)
$countrycode = substr($sender, 0, 2);
$phonenumber=substr($sender, 2);
if ($argc < 2) {
echo "USAGE: ".$_SERVER['argv'][0]." [-l] [-s <phone> <message>] [-i <phone>]\n";
echo "\tphone: full number including country code, without '+' or '00'\n";
echo "\t-s: send message\n";
echo "\t-l: listen for new messages\n";
echo "\t-i: interactive conversation with <phone>\n";
exit(1);
}
$dst=$_SERVER['argv'][2];
$msg = "";
for ($i=3; $i<$argc; $i++) {
$msg .= $_SERVER['argv'][$i]." ";
}
echo "[] Logging in as '$nickname' ($sender)\n";
$wa = new WhatsProt($sender, $imei, $nickname, true);
$url = "https://r.whatsapp.net/v1/exist.php?cc=".$countrycode."&in=".$phonenumber."&udid=".$wa->encryptPassword();
$content = file_get_contents($url);
if(stristr($content,'status="ok"') === false){
echo "Wrong Password\n";
exit(0);
}
$wa->Connect();
$wa->Login();
if ($_SERVER['argv'][1] == "-i") {
echo "\n[] Interactive conversation with $dst:\n";
stream_set_timeout(STDIN,1);
while(TRUE) {
$wa->PollMessages();
$buff = $wa->GetMessages();
if(!empty($buff)){
print_r($buff);
}
$line = fgets_u(STDIN);
if ($line != "") {
if (strrchr($line, " ")) {
// needs PHP >= 5.3.0
$command = trim(strstr($line, ' ', TRUE));
} else {
$command = $line;
}
switch ($command) {
case "/query":
$dst = trim(strstr($line, ' ', FALSE));
echo "[] Interactive conversation with $dst:\n";
break;
case "/accountinfo":
echo "[] Account Info: ";
$wa->accountInfo();
break;
case "/lastseen":
echo "[] Request last seen $dst: ";
$wa->RequestLastSeen("$dst");
break;
default:
echo "[] Send message to $dst: $line\n";
$wa->Message(time()."-1", $dst , $line);
break;
}
}
}
exit(0);
}
if ($_SERVER['argv'][1] == "-l") {
echo "\n[] Listen mode:\n";
while (TRUE) {
$wa->PollMessages();
$data = $wa->GetMessages();
if(!empty($data)) print_r($data);
sleep(1);
}
exit(0);
}
echo "\n[] Request last seen $dst: ";
$wa->RequestLastSeen($dst);
echo "\n[] Send message to $dst: $msg\n";
$wa->Message(time()."-1", $dst , $msg);
echo "\n";
?>
To run this script, you are meant to go to the Command Line, down to the directory the file is in, and then type in something like php -s "whatsapp.php" "Number" "Message".
But what if I wanted to bypass the Command Line altogether and do that directly inside the script so that I can run it at any time from my Web Server, how would I do that?
First off, you should be using getopt.
In PHP it supports both short and long formats.
Usage demos are documented at the page I've linked to. In your case, I suspect you'll have difficulty detecting whether a <message> was included as your -s tag's second parameter. It will probably be easier to make the message a parameter for its own option.
$options = getopt("ls:m:i:");
if (isset($options["s"] && !isset($options["m"])) {
die("-s needs -m");
}
As for running things from a web server ... well, you pass variables to a command line PHP script using getopt() and $argv, but you pass variables from a web server using $_GET and $_POST. If you can figure out a sensible way to map $_GET variables your command line options, you should be good to go.
Note that a variety of other considerations exist when taking a command line script and running it through a web server. Permission and security go hand in hand, usually as inverse functions of each other. That is, if you open up permissions so that it's allowed to do what it needs, you may expose or even create vulnerabilities on your server. I don't recommend you do this unless you'll more experienced, or you don't mind if things break or get attacked by script kiddies out to 0wn your server.
You're looking for backticks, see
http://php.net/manual/en/language.operators.execution.php
Or you can use shell_exec()
http://www.php.net/manual/en/function.shell-exec.php
When I try the following PHP code:
exec('/usr/bin/latex ...')
I'll get an 127-exit code. What can I do to stop this?
Regards,
Kevin
127 error code indicates the command was not found by bash. You sure that latex is installed?
Why do not use ssh2 ?
something like this:
//Connect first
if (!($con = #ssh2_connect('192.168.0.1', 22))) {
echo "[FAILED_CONNECT]\n";
exit(1);
}
if (!#ssh2_auth_password($con, "your_user", "your_password")) {
echo "[FAILED_AUTH_DENIED]\n";
exit(1);
}
echo "[OK]\n CONNECTED!";
// the command line
$stdout_stream = ssh2_exec($con, "/usr/bin/latex ...");
// close connection
fclose($stdout_stream);