I am trying to do this sql query on codeigniter
SELECT* FROM person WHERE type = 'staff' AND description LIKE 'university%'
I am not sure if it is correct...
$this->db->get_where('person' , array('type'=>'staff'))
->like('description','university%')
->result_array();
does anyone have an idea about my case? thanks in advance ...
Using Active Record you can do so
$query = $this->db->select('*')
->from('person')
->where('type','staff')
->like('description','university','after')
->get();
$result = $query->result_array();
Make sure you pass after as a third parameter in like() function so active record will add the wild card i.e % after university so it will look like LIKE 'university%'
The docs has this explained very well, but their API is very simple. To produce the query you need the relevant code which looks like this:
$this->db->select('*')
->from('person');
->where('type', 'staff')
->like('description','university');
$query = $this->db->get();
$result = $query->result_array();
I never used chaining(even though i know it's possible), but breaking down your question should be easy ;
$this->db->from('person');
$this->db->where('type','staff');
$this->db->where('description', 'university%');
$query = $this->db->get();
$result = $query->result_array();
return $result;
Related
I want to get data from two tables, the second table is for rating so i want to get rating of products simultaneosly. Below code is not working for me if i change
$this->db->select('dg_products.',', AVG(dg_rating.rating) As
averageRating');
to
$this->db->select('*');
then it is working.
Please help to sort out my issue.
public function get_rating()
{
$this->db->select('dg_products.*','*, AVG(`dg_rating.rating`) As averageRating');
$this->db->from('dg_products');
$this->db->join('dg_rating', 'dg_products.id = dg_rating.product_id','left');
$this->db->where('dg_products.is_featured_prod','1');
$this->db->group_by("dg_products.id");
$query = $this->db->get();
$result = $query->result();
return $result;
}
Try it like this :
$this->db->select('dg_products.*, AVG(`dg_rating.rating`) As averageRating');
you just have an unneeded quotes in there.
I make a join between two tables using codeigniter framework and this is my query:
public function SearchDataUnderCondition($firsttable,$secondtable,$data)
{
$this->db->select("atm.* , tender.status as tenderstatus");
$this->db->from($firsttable);
$this->db->join($secondtable,'atm.id_tender=tender.id');
$this->db->where('tenderstatus','1');
$this->db->like('serial', $data);
$sql = $this->db->get();
return $sql->result();
}
I am using database model when is remove
$this->db->where('tenderstatus','1');
from my code operation done and i get result but I want to make search under this condition. what is my problem?
Try this
public function SearchDataUnderCondition($data)
{
$this->db->select('atm.* , tender.status');
$this->db->from('atm');
$this->db->join('tender','atm.id_tender=tender.id');
$this->db->where('tender.status','1');
$this->db->like('serial', $data);
$sql = $this->db->get();
return $sql->result();
}
Try this
$this->db->where('tender.status','1');
I think, we can not aliases in where clause
Using aliases (and also making sure you want and WHERE AND LIKE clause):
$fist_table = 'atm';
$second_table = 'tender';
$this->db->select('aliasone.* , aliastwo.status as "tenderstatus"');
$this->db->from("$first_table as aliasone");
$this->db->join("$second_table as aliastwo", "aliastwo.id = aliasone.tender_id");
$this->db->where('aliastwo.status','1');
$this->db->like('serial', $data);
return $this->db->get();
In my Model, I wrote this function with MySQL raw query
function get_question_result($lr_id)
{
$raw_query = 'SELECT question_record.qr_id, LEFT(question.question, 50) as question,
question.correct_answer
FROM question_record
INNER JOIN question ON question.q_id = question_record.q_id
WHERE question_record.lr_id = '.$lr_id.' ';
$query = $this->db->query($raw_query);
$questionresult = $query->result_array();
return $questionresult;
}
It worked fine. It gave me the array I want. I continued my project.
Then suddenly I was curious to try it in CI Active Record Class.
function get_question_result($lr_id)
{
$this->db->select('question_record.qr_id, LEFT(question.question, 50) as question, question.correct_answer');
$this->db->from('question_record');
$this->db->join('question', 'question.q_id = question_record.q_id', 'inner');
$this->db->where('question_record.lr_id', $lr_id);
$result = $this->db->get()->result_array();
return $result;
}
It didn't work. It gave me this error
PHP Fatal error: Call to a member function result_array() on a non-object
Just out of curiosity, where did I do wrong?
Was it me writing it wrong or the result data structure with Active Record is just different?
'cause when I tried it again in Active Record without selecting this field
LEFT(question.question, 50) as question
It worked but it didn't give the field I want. Do you guys know why?
In your $this->db->select() call you need pass FALSE as second parameter so that active record will not try to add backticks ` for your columns in select statement
function get_question_result($lr_id)
{
$this->db->select('question_record.qr_id, LEFT(question.question, 50) as question, question.correct_answer',FALSE);
$this->db->from('question_record');
$this->db->join('question', 'question.q_id = question_record.q_id', 'inner');
$this->db->where('question_record.lr_id', $lr_id);
$result = $this->db->get()->result_array();
return $result;
}
According to docs
$this->db->select() accepts an optional second parameter. If you set
it to FALSE, CodeIgniter will not try to protect your field or table
names with backticks. This is useful if you need a compound select
statement.
$this->db->select();
I am working in codeigniter.. I want to count the no. of rows having the same order_no.. below is my code.
public function get_my_orders() {
$user_data = $this->session->all_userdata();
$email = $user_data['user_email'];
$this->db->select('*');
$this->db->from('order_details');
$this->db->where('email', $email);
$this->db->group_by('order_no');
$this->db->order_by('order_no', 'DESC');
$query = $this->db->get();
return $query->result();
}
Pls help..
You can use $this->db->count_all_results()
public function get_my_orders() {
$user_data = $this->session->all_userdata();
$email = $user_data['user_email'];
//$this->db->select('*');// no need select as you only want counts
$this->db->from('order_details');
$this->db->where('email', $email);
//$this->db->group_by('order_no');//no need group_by as you only want counts
//$this->db->order_by('order_no', 'DESC');//no need order_by as you only want counts
return $this->db->count_all_results();;
}
Try changing your select line to look like this:
$this->db->select('COUNT(*) as count');
Rather than having all fields accessible like they currently are, you will instead only have access to one variable called count. To keep all variables accessible and add the count in as well, use this instead:
$this->db->select('*, COUNT(*) as count');
Feel free to change the lowercase name for count, I'm just using that as an example.
Check Codeigniter Manual
$query = $this->db->get();
return $query->num_rows(); //Return total no. of rows here
$query->num_rows(); will count the total active record return by your query.
This is a search function I made, it gets the search term and displays fine. HM_Jobs has 3 options for JobStatus: Open, Accepted or Complete.
However the search is also pulling results from the Accepted and Complete rows when I run it, why isn't the WHERE statement stopping this from happening?
function search_jobs($search) //This function checks a search term against the job title and description.
{
$this->db->select('*');
$this->db->from('HM_Jobs');
$this->db->like('JobTitle',$search);
$this->db->or_like('JobDescription',$search);
$this->db->where('JobStatus','Open');
$query = $this->db->get();
return $query->result();
}
Try this
$this->db->select('*');
$this->db->from('HM_Jobs');
$this->db->where("(JobTitle LIKE '$search' OR JobDescription LIKE '$search')" );
$this->db->where('JobStatus','Open');
$query = $this->db->get();
You can see your query executed by using echo $this->db->last_query()
Your query creates like
where JobTitle like 'search' or JobDescription like 'search' and JobStatus='Open'
But the query you need require something like
where (JobTitle like 'search' or JobDescription like 'search') and JobStatus='Open'
Try using the following query
function search_jobs($search)
{
$query = $this->db->select('*')
->from('HM_Jobs')
->where('JobStatus','Open')
->where("(`JobTitle` LIKE '%$search%' OR
`JobDescription` LIKE '%$search%')",null,false)
->get();
return $query->result();
}