Inserting user tweets into mysql table - php

Question

I am getting user tweets and mentions and inserting into table. Once this process completes, I redirect to next page.
For few users it correctly stores and display tweets and redirect to next page. But for few user, it stuck on the first page where I get tweets and store into table. I am trying since last few days to overcome this.
Can any one tell me what problem can cause this? Does it is due to it unable to store the data (tweet text) into table?
There are two function in which I perform insert operation:
function lookup($tweetid,$connection,$userid)
{
$tweets5 = $connection->get("https://api.twitter.com/1.1/statuses/retweets/".$tweetid.".json?count=1");
//var_dump($tweets5);
$json = json_encode($tweets5);
foreach($tweets5 as $item)
{
$text = $item->text;
$text_id = $item->id;
// $user_id = $item->user->id;
$name = $item->user->name;
$constant = 'retweet';
$time = $item->created_at;
$dt = \DateTime::createFromFormat('D M d H:i:s e Y', $time);
// $dt = new \DateTime($time);
$tweet_time = $dt->format('H:m:s');
$tweet_dtm = $dt->format('Y:m:d');
$year = $dt->format('Y');
$month = $dt->format('m');
echo $text."-".$text_id."-".$name."-".$time."-".$tweet_time.$tweet_dtm.$year.$month.$rt_count.$follower.$friend."<br>";
echo "<br>";
$inreplyto = $item->in_reply_to_screen_name;
$follower = $item->user->followers_count;
$rt_count = $item->retweet_count;
$friend = $item->user->friends_count;
$con = mysqli_connect('127.0.0.1', 'root', 'karim', 'karim');
$text = mysql_real_escape_string($text);
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
return;
}
$insertQuery1 = "INSERT INTO twitter_retweet(`username`,`userid`,`tweet_text`,`text_id`,`time`,`month`,`year`,`date`,`user_follower_count`,`rt_count`,`constant`,`in_reply_to`) VALUES ('".$name."','".$userid."','".$text."','".$text_id."','".$tweet_time."','".$month."','".$year."','".$tweet_dtm."','".$follower."','".$rt_count."','".$constant."','".$inreplyto."')";
if (!mysqli_query($con,$insertQuery1))
{
die('Error: ' . mysqli_error($con));
// echo "error";
}
// echo "Text : $text <br> ID : $user_id <br> Name : $name <br> Follower : $follower <br> Friends : $friend <br> ---";
}
}
Is there anything wrong in this code? I am not sure whether it stuck here during insertion or what.
2nd function, this prints the data, but it does not store $text into database. why?:
foreach ($tweets1 as $item)
{
$text = $item->text;
//echo $userid.$text;
$text_id = $item->id;
$constant = 'mention';
$time = $item->created_at;
//echo $time;
//$dt = new DateTime('#' . strtotime($time));
$dt = \DateTime::createFromFormat('D M d H:i:s e Y', $time);
//var_dump($dt);
$tweet_time = $dt->format('H:m:s');
$tweet_dtm = $dt->format('Y:m:d');
$year = $dt->format('Y');
$month = $dt->format('m');
$user_name = $item->user->name;
// echo $year.$month.$user_name;
$inreplyto = $item->in_reply_to_screen_name;
$rt_count = $item->retweet_count;
$follower_count = $item->user->followers_count;
echo $text."-".$text_id."-".$time."-".$tweet_time.$tweet_dtm.$year.$month.$user_name.$rt_count.$follower_count."<br>";
echo "<br>";
$con = mysqli_connect('127.0.0.1', 'root', 'karim', 'karim');
//$text = mysqli_real_escape_string($text);
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
return;
}
$insertQuery1 = "INSERT INTO twitter_mention(`username`,`userid`,`tweet_text`,`text_id`,`time`,`month`,`year`,`date`,`user_follower_count`,`rt_count`,`constant`,`in_reply_to`) VALUES ('".$twitteruser."','".$userid."','".$text."','".$text_id."','".$tweet_time."','".$month."','".$year."','".$tweet_dtm."','".$follower_count."','".$rt_count."','".$constant."','".$inreplyto."')";
if (!mysqli_query($con,$insertQuery1))
{
die('Error: ' . mysqli_error($con));
// echo "error";
}
}
This is the code at the end to redirect to next page:
echo '<form name="myForm" id="myForm" action="start.php" method="POST">
<input style="display:none" name="userid" value="'.$userid.'" />
</form>
<script>
function submitform()
{
document.getElementById("myForm").submit();
}
window.onload = submitform;
</script>
';