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How to calculate the difference between two dates using PHP?
(34 answers)
PHP: strtotime is returning false for a future date?
(5 answers)
Closed 8 years ago.
I need to calculate age in php.
I use this solution:
$birthdate = '1986-09-16';
$_age = floor( (strtotime(date('Y-m-d')) - strtotime($birthDate)) / 31556926);
from here
Everything works fine, but for example if
$birthday = '1194-01-06' or
$birthday = '1900-01-01'
result is always 44.
if $birthday = '1910-11-09' everything is fine again and result is 103. Why?
Note: I don't want to use diff() function, because of some issues.
EDIT:
Earlier i had problems with diff(), some
Warning range()
showed during processing and after refreshing of website everything was fine again... i could not find solution to fix it and somewhere i read that using of diff() could cause it. So i tried other solution and it worked... until now.
Finally I used this solution:
$birthDate = from database in timestamp format...
$birth = new \DateTime($birthDate);
$now = new \DateTime;
$age = $now->diff($birth)->y;
and I randomly get
Warning
range(): step exceeds the specified range
again.
It's because you're using date that is using timestamp that has a default value of time() that is based on EPOCH that started on January 1 1970 00:00:00 GMT - it's 44 years since 1970.
More on this can be found in the PHP Manual: http://php.net/manual/en/function.date.php
Integer limit issue, either:
Your OS doesn't handle negative timestamps
The maximum integer values for signed integers on a 32 bit system
strtotime()
The valid range of a timestamp is typically from Fri, 13 Dec 1901 20:45:54 UTC to Tue, 19 Jan 2038 03:14:07 UTC. (These are the dates that correspond to the minimum and maximum values for a 32-bit signed integer.)
Additionally, not all platforms support negative timestamps, therefore your date range may be limited to no earlier than the Unix epoch (1 Jan 1970).
Have you read strtotime() manual (https://php.net/manual/en/function.strtotime.php)?
The function expects to be given a string containing an English date format and will try to parse that format into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 UTC), relative to the timestamp given in now, or the current time if now is not supplied.
Related
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Convert one date format into another in PHP
(17 answers)
Closed 4 years ago.
I have a DB that shows when the user made the last login but then it shows 1542575966120. I wanted it to show so 18/11/2018 19:00
I tried using this in php
$intDate = "20". $ infologado ["lastlogin"];
$newDate = date ("d-m-Y", strtotime ($ intDate));
but I could not.
sorry for English
So as #Taha Paksu had mentioned, these numbers are a timestamp (seconds since 1 January 1970). Try this code:
$intDate = 1542575966120;
$newDate = date('d/m/Y H:i', $intDate/1000);
It is in miliseconds, date function accepts seconds, thus the division by 1000. Also no need to put it into strtotime, because this function is meant to convert string dates to... said numeric timestamps.
In your case, you can put $intDate = $infologado['lastlogin']; instead of first line to get the result dynamically from the database.
First of all, you need to learn what a timestamp is. The timestamp is a number which shows the seconds passed (or milliseconds, some include the milliseconds too) since epoch (01/01/1970). A general definition can be found here:
The Unix epoch (or Unix time or POSIX time or Unix timestamp) is the number of seconds that have elapsed since January 1, 1970 (midnight UTC/GMT), not counting leap seconds (in ISO 8601: 1970-01-01T00:00:00Z). Literally speaking the epoch is Unix time 0 (midnight 1/1/1970), but 'epoch' is often used as a synonym for 'Unix time'. Many Unix systems store epoch dates as a signed 32-bit integer, which might cause problems on January 19, 2038 (known as the Year 2038 problem or Y2038).
The converter on this page converts timestamps in seconds, milliseconds and microseconds to readable dates.
Taken from: https://www.epochconverter.com/ a tool which you can convert your dates to/from timestamps or vice versa.
Then to answer your question, the system saved the dates as a timestamp to the database to (probably) bypass the formatting errors on each different system that uses it.
Nevermind, TL;DR:
The number shows Sunday, 18 November 2018 21:19:26.120 when you give it to the timestamp converter I mentioned above. With PHP, you can use:
$unixTimestamp = 1542575966120;
$dt = DateTime::createFromFormat("U.u", $unixTimestamp / 1000);
var_dump($dt);
to convert to PHP DateTime class, then you can use it in your application.
I am trying to find the retirement date from joining date at the age of 58 years in php.
$retire_date = date('Y-m-d', strtotime($joining_date. '+58 years'));
it's showing 1970-01-01 , Up to "+40 years" it's showing correctly.can anyone contribute to find this one
The valid range of a timestamp is typically from Fri, 13 Dec 1901 20:45:54 UTC to Tue, 19 Jan 2038 03:14:07 UTC. (These are the dates that correspond to the minimum and maximum values for a 32-bit signed integer.) Additionally, not all platforms support negative timestamps, therefore your date range may be limited to no earlier than the Unix epoch. This means that e.g. dates prior to Jan 1, 1970 will not work on Windows, some Linux distributions, and a few other operating systems. PHP 5.1.0 and newer versions overcome this limitation though.
For 64-bit versions of PHP, the valid range of a timestamp is effectively infinite, as 64 bits can represent approximately 293 billion years in either direction.
If the number of the year is specified in a two digit format, the values between 00-69 are mapped to 2000-2069 and 70-99 to 1970-1999. See the notes below for possible differences on 32bit systems (possible dates might end on 2038-01-19 03:14:07).
Source
Beside of autista_z's answer,
you can stumple upon this if you use an incorrect date format or something like this
below an example
$joining_date = "1976-14-02";
$timeToAdd = "+ 58 years";
$objDateTime = DateTime::createFromFormat("Y-m-d",$joining_date);
$objDateTime->modify($timeToAdd);
echo "My Retire Date is ".$objDateTime->format("Y-m-d")."<br />";
$retire_date = date('Y-m-d', strtotime($joining_date.$timeToAdd));
echo $retire_date;
die;
This leads with strtotime to a result like 1970-01-01.
This is also the reason why i prefer the Datetime function createFromFormat if you know your format, because the outcome is absolutely predictable.
(in this particulary example you'll see - datetime tries to find a correct value and interprets it as 1977-02-02)
Although it doesn't really explain why +40 years would work, but maybe you tested it with different data.
$retire_date = date('Y-m-d', strtotime('+58 years', strtotime($joining_date)));
Correct answer
I think this will work for you.
$retire_date = date('Y-m-d', strtotime('+58 years', strtotime($joining_date)));
Excel's date format is, I believe, the # of days since December 30, 1899. (Why? Because it's based on 1/1/1900 but they erroneously include a leap day in 1900, and it's one-based. So it's fine for the first couple of months in 1900 but then it goes wrong. 1/1/1901 in Excel is "367".)
So, how can I convert a date or timestamp from PHP (which is typically stored as a Unix timestamp, the # of seconds since 1/1/1970) to Excel?
In PHP 5.1.6?
Yeah, bet you didn't see that one coming. So I don't have any of the DateTime objects, date_create(), date_diff(), etc. functions available to me.
Is it even possible without simply recording the Excel day for 1/1/1970 and working from there? And is there a DST-proof version?
If I'm not mistaken, there are 86400 seconds in a day, and 25569 days between 30 Dec 1899 and 01 Jan 1970. So, to convert a Unix timestamp to an Excel date, the formula
ExcelDate = 25569 + UnixTS / 86400
ought to work. Of course, this formula is only correct for UTC. (Also, it ignores leap seconds.) For other timezones, if you know the offset (in seconds!) from UTC, you can just add it to the timestamp before using the formula above.
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Date to timestamp (PHP)?
How do I get the current time in seconds since 1st january 1970 in php?
does the dateTime object support anything since as
$date1 = new DateTime("01/01/1970");
$return = since($date1, date.now());
The problem I get here is I could just do something like ((minutes=hours *60)*60)
Is there a nicer way?
You can use the time() function:
http://php.net/manual/en/function.time.php
time()
Returns the current time measured in the number of seconds since the Unix Epoch (January 1 1970 00:00:00 GMT).
$_SERVER['REQUEST_TIME']; is a pretty light way to do it, if your server supports it. Otherwise you have the usual time() / strtotime() functions. Also, why is there javascript in your PHP?
In .net, there are the static properties DateTime.MinDate, and DateTime.MaxDate that conveniently return the minimum and maximum valid dates for a DateTime object.
I'm dabbling in web programming right now, using php + mysql + javascript. There doesn't seem to be the same convenient min/max date values in that programming environment? For example, the max value of a date object in mysql is 9999-12-31, but the php function strtotime() doesn't like that value.
I would like a cross-language minimum date (to be used to mean 'not set yet' for example), and a cross-language maximum date (to be used to mean 'good forever'). That means there could be those min dates and max dates stored in a database, which php would retrieve (and it would have to differentiate between 'normal' dates and min/max date), and eventually they would trickle down to some javascript (which, again would have to differentiate between 'normal' dates and min/max date).
So, which date value do you use for min/max dates when working in php + mysql + javascript? And how do you store these constants -- it'd be nice to define them only in one place and have them be available in each of php + mysql + javascript...
Thanks
For the JavaScript side, the range is a lot bigger:
The date is measured in milliseconds since midnight 01 January, 1970 UTC. A day holds 86,400,000 milliseconds. The Date object range is -100,000,000 days to 100,000,000 days relative to 01 January, 1970 UTC.
So you could do this in your JavaScript:
var min_date = new Date(-100000000*86400000);
var max_date = new Date( 100000000*86400000);
I'll just answer the PHP portion of the question. According to the PHP date() documentation:
The valid range of a timestamp is typically from Fri, 13 Dec 1901 20:45:54 GMT to Tue, 19 Jan 2038 03:14:07 GMT. (These are the dates that correspond to the minimum and maximum values for a 32-bit signed integer)
PHP uses 32 bit integer values to represent date/time — that means you can use the PHP_INT_MAX constant to derive the integer values associated with the min/max dates:
echo date('m/d/Y G:i:s', PHP_INT_MAX + 1); // minimum valid date
echo date('m/d/Y G:i:s', PHP_INT_MAX); // maximum valid date
OUTPUT:
12/13/1901 15:45:52
01/18/2038 22:14:07
Not sure why that's off by 2 seconds on the min date they quoted, but you get the general idea.
For the 'not set yet' logical value, maybe a null value is better.