convert php sql Result from Vertical to Horizontal - php

The following code generate the result(one record) in a vertical table is there any way to convert to horizontal like with a nice styling.. in addition if possible to get certain column in a popup window using the parameter in the query, using jquery or CSS
<html>
<head>
<link rel="stylesheet" href="style.css" type="text/css" />
</head>
<body>
<?
$table = $_GET["table"];
$lon = $_GET["lon"];
$lat = $_GET["lat"];
$sql = "select
st_geometrytype(geom) as geometrytype,
st_area(geom) as area, *
from $table
where
st_contains(
geom,
st_transform(
st_setsrid(
st_makepoint($lon, $lat),
4326),
2276))";
$db = pg_connect("dbname=db user=user password=pass");
$result = pg_query($db, $sql);
while( $row = pg_fetch_assoc($result) )
{
print "<table>";
foreach ( array_keys($row) as $column_name )
{
if ( $column_name <> "geom" )
{
print "<tr>";
print "<th>" . $column_name . "</th>";
print "<td>" . $row[$column_name] . "</td>";
print "</tr>";
}
}
print "</table>";
}
?>
</body>
</html>
so far I am using this CSS to style my table.
th
{
text-align:right;
padding-right:0.5em;
}
td
{
text-align:center;
}
many thanks..

Your are printing the tr at the same time the loop runs, so it will make trs and obviously it will be vertical, to make it horizontal , your loop will be like this;
while( $row = pg_fetch_assoc($result) )
{
print "<table>";
print "<tr>";
foreach ( array_keys($row) as $column )
{
if ( $column_name <> "geom" )
{
print "<th>" . $column . "</th>";
}
}
print "</tr>";
print "<tr>"; <-- this one here opening tag
foreach ( array_keys($row) as $column_name )
{
if ( $column_name <> "geom" )
{
print "<td>" . $row[$column_name] . "</td>";
}
}
print "</tr>"; <-- this one here closing tag
print "</table>";
}

code for display 8 elements horizontally.
<table>
<?if($c==8){echo "<tr >";$c=0; }<td> ?>
// your elements
<? echo "</td>";
$c++;?>
</tr>
</table>

Related

Extracting columns from sql table with php

My query selects all columns from my table
$spool = $wpdb->get_results('SELECT * FROM `tablename`');
then I display the results in a table. I need to display all columns. This is the way I do it.
echo "<table>";
if ( !empty( $spool ) ) {
echo "<tr><th> header </th></tr>";
foreach ( $spool as $a ) {
echo "<tr><th>" . $a->columnname1 . "</th><th>" .$a->columnnameN . "</th></tr>";
}
}
echo "</table>";
Now since I have around 40 columns, I'd like to ask if there is a more intelligent and less tedious way of displaying them.
probably you need nested loops, you are getting result probably like this
array(
0:{column1:test,column2:test . . . },
1:{column1:test,column2:test . . . }
)
so you can try this way
echo "<table>";
if ( !empty( $spool ) ) {
echo "<tr><th> header </th></tr>";
foreach ( $spool as $key => $value ) {
echo '<tr>';
foreach ( $value as $a ) {
echo "<th>" . $a. "</th>";
}
echo '</tr>';
}
}
echo "</table>";
As you have objects you could cast them to arrays and use implode.
(But attribute order could be different from what you want.)
<?php
class A
{
public $foo = 'bing';
public $bar = 'bang';
public $baz = 'bong';
}
$spool = [new A, new A];
echo '<table>';
foreach($spool as $a) {
echo '<tr>';
echo '<td>' . implode('</td><td>', (array) $a) . '</td>';
echo '</tr>';
}
echo '</table>';
Output:
<table><tr><td>bing</td><td>bang</td><td>bong</td></tr><tr><td>bing</td><td>bang</td><td>bong</td></tr></table>

Display sql tables in separate html table columns

I'm trying to display data from different mysql tables in an html table. The problem I have is that it currently displays both in the same column. I'd like to have two separate columns in the table one for each of the sql data.
This is my code:
global $wpdb;
$centr = $wpdb->get_results('SELECT meta_value FROM `wp__frm_item_metas` WHERE `item_id` = 2');
$namelist = $wpdb->get_results('SELECT name FROM `wp__frm_fields` WHERE form_id = 2');
echo "<table>";
if ( !empty( $centr ) ) {
foreach ($namelist as $key) {
# code...
echo "<tr><td>" . $key->name . "</tr></td>";
}
foreach ( $centr as $r ) {
echo"<tr><td>" . $r->meta_value . "</tr></td>";
}
}
echo "</table>";
I'd like the second echo to start in a new column, instead of displaying more rows in the same one.
I guess this is what you want
echo "<table>";
if ( !empty( $centr ) ) {
echo "<tr><td>";
foreach ($namelist as $key) {
echo "<table><tr><td>" . $key->name . "</td></tr></table>";
}
echo "</td><td>";
foreach ( $centr as $r ) {
echo"<table><tr><td>" . $r->meta_value . "</td></tr></table>";
}
echo "</td></tr>";
}
echo "</table>";

mysqli_fetch_array using a foreach loop

Ive got a pretty basic table named 'customers' with four columns:
ID (primary Auto Increment)
businessName
contactName
contactEmail
I call it with:
$result = mysqli_query($con, "SELECT * FROM customers");
and was using mysqli_fetch_array to display it on the page with a foreach loop:
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
echo "<tr>";
foreach ($row as $value) {
echo "<td>" . $value . "</td>";
}
echo "<td><a href='updateform.php?id=" . $row['id'] . "'>Edit</a></td>";
echo "</tr>";
}
Which gives you an array like:
Array ( [id] => 1 [businessName] => Microsoft [contactName] => Bill Gates [contactEmail] => bill#microsoft.com ) Array ( [id] => 2 [businessName] => Amazon [contactName] => Jeff Bezos [contactEmail] => jeff#amazon.com )
Is it possible to display results differently based on which column (technically now position in the array) they are in? I would like to make a
a href="mailto:bill#microsoft.com"
link when it gets to contactEmail.
What if I wanted to display just one key or value instead of using foreach?
It doesn't seem possible to call
$row['contactEmail']
in the foreach loop
which confuses me since below that I am able to create a link to
$row['id']
If anyone has any ideas how to do this, or if there is a better way to be displaying this information, I'm open to suggestions, as I'm not very good at programming, especially PHP.
Yes! you can just add like this:
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
echo "<tr>";
foreach ($row as $key => $value) {
if($key == "contactEmail"){
$mailUrl = "mailto:".$value;
echo "<td>".$value."";
}
else{
echo "<td>" . $value . "</td>";
}
}
echo "<td><a href='updateform.php?id=" . $row['id'] . "'>Edit</a></td>";
echo "</tr>";
}
Yes, You can able to mysqli_fetch_array retrieve data directly using foreach loop. like bellow :
<?php
$result = mysqli_query($con, "SELECT * FROM customers");
?>
<table>
<tr>
<td>Business Name</td>
<td>Contact Name</td>
<td>#</td>
</tr>
<?php
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
echo "<tr>";
echo "<td>".$row['businessName']."</td>";
foreach ($row as $key => $value) {
$newValue = $key == "contactEmail" ? ''.$value.'' : $value;
echo "<td>" . $newValue . "</td>";
}
echo "<td><a href='updateform.php?id=" . $row['id'] . "'>Edit</a></td>";
echo "</tr>";
}
?>
</table>

how to take foreach result in a table format

I want to take the result of foreach in a table format and that whole table in a variable.
Here is my model:
public function cron_job_seller(){
$this->db->select('*');
$this->db->from('wc_seller_products');
$query = $this->db->get();
$result = array();
foreach ($query->result() as $row){
$result[] = $row;
}
return $result;
}
and my controller is
public function cron_job(){
$this->load->model('home/Home_model');
$buyer = $this->Home_model->cron_job_buyer();
$this->load->library('email', array('mailtype'=>'html'));
$seller = $this->Home_model->cron_job_seller();
echo "<table>";
foreach($seller as $key=>$row) {
echo "<tr>";
foreach($row as $key2=>$row2){
echo "<td>" . $row2 . "</td>";
}
echo "</tr>";
}
echo "</table>";
gives o/p like this in table format
19 102 Rolex 65 Good 0000-00-00 fh ghf fgh ghf ghf gfh ghf ghf 56 56 download14.jpg 11/6/2016 19:03 2016-07-15 12:13:35 1 0
when i print $seller variable it gives
Array ( [0] => stdClass Object ( [id] => 19 [seller_id] => 102 [brand_name] => Rolex [model_no] => 65 [condition] => Good [date_purchase] => 0000-00-00 [case_size] => fh [case_shape] => ghf [case_material] => fgh [strap_type] => ghf [dial_colour] => ghf [water_resistance] => gfh [local_overseas] => ghf [warranty_period] => ghf [min_price] => 56 [sale_price] => 56 [photo] => download14.jpg [date] => 11/6/2016 19:03 [time] => 2016-07-15 12:13:35 [status] => 1 [login] => 0 [verified] => )
now i want 2 things in this:
1. that whole table in a single variable.
2. array keys like id, seller_id,brand_name as table heading
i really got confused what to do now and how to do...please help
public function cron_job() {
$this->load->model('home/Home_model');
$buyer = $this->Home_model->cron_job_buyer();
$this->load->library('email', array('mailtype'=>'html'));
$seller = $this->Home_model->cron_job_seller();
$theader = '';
$tbody = "<tbody>";
foreach($seller as $key => $row) {
$tbody .= "<tr>";
foreach($row as $key2 => $row2){
if (!$theader) {
$theader = array_keys($row2);
}
$tbody .= "<td>" . $row2 . "</td>";
}
$tbody .= "</tr>";
}
$tbody .= "</tbody>";
if (!empty($theader)) {
$theader = '<thead><th>' . implode('</th><th>', $theader) . '</th></thead>';
}
$table = '<table>'.$theader.$tbody.'</table>';
}
you don't need to worry much about it... It could be a solution. Just do like this in your controller:
$seller = $this->Home_model->cron_job_seller();
$table = "<table border='1'>";
$i=1;
foreach($seller as $key=>$row) { //you don't need to loop twice
if($i == 1){
$table.="<tr>";
$table .= "<th>".$key."</th>";
$table.="</tr>";
$i=0; //change value of $i so for next iteration the header will not print
}
$table .= "<tr>";
$table .= "<td>" . $row . "</td>";
$table.= "</tr>";
}
$table .= "</table>";
and also you need to return $query->result() from your model.
and now try print $table
using echo $table; it will print result as you want and now it is also set in a single variable so you can, and you set to $data['table'] = $table and end it to view, if you need.
You can just loop through the Array of Data from the DB and since each row is an array of Standard PHP Object (which contains the column names as keys), you can then extract the Column Names from the first row and then use it to construct the Table Header. Afterwards, you can just continue building Rows containing the actual Data you want. The Code below illustrates how:
<?php
function cron_job() {
$strOutput = "<table class='cron-tbl'>";
$this->load->model('home/Home_model');
$buyer = $this->Home_model->cron_job_buyer();
$this->load->library('email', array('mailtype' => 'html'));
$seller = $this->Home_model->cron_job_seller();
$cue = 0;
foreach ($seller as $key => $row) {
if($cue == 0){
// CREATE THE HEADER ROW:
$strOutput .= "<tr class='cron-head-row'>" . PHP_EOL;
foreach($row as $rowName=>$rowVal){
$strOutput .= "<th class='cron-head-cell'>{$rowName}</th>" . PHP_EOL;
}
$strOutput .= "</tr>" . PHP_EOL;
$strOutput .= "<tbody class='cron-body'>" . PHP_EOL;
}
// CREATE THE TABLE-BODY CELL
$strOutput .= "</tr>" . PHP_EOL;
foreach ($row as $rowKey => $data) {
$strOutput .= "<td class='cron-data-cell'>{$data}</td>" . PHP_EOL;
}
$strOutput .= "</tr>" . PHP_EOL;
$cue++;
}
$strOutput .= "</tbody>" . PHP_EOL;
$strOutput .= "</table>" . PHP_EOL;;
return $strOutput;
}
echo (cron_job());
Cheers & Good Luck...
Test it out yourself HERE.
You are doing correct but need some modifications
What you need to do is in you second foreach() loop you need to convert your object to array and take out the array keys array_keys($array) in a variable and print this keys to variable. As shown bellow.
$table = "<table border='1'>";
foreach($seller as $key=>$row) { //you don't need to loop twice
$table .="<tr>";
// creating a table heading
if($key === 0 ){
$cols = array_keys((array)$row); // Convert the object to array and take out all keys of array and assign to $cols variable
$table .="<th>".implode("</th><th>", $cols);
$table .="</th></tr><tr>";
}
// table heading end
$table .= '<td>'. implode('</td><td>', (array)$row). '</td>';
$table .= "</tr>";
}
$table .="</table>";
echo $table;
Try this way.
I guess html tag, body tag are missing. That's why didnot display table the way you want.
My suggestion is that for html part, it is better if put in view.
I have create view page cron_job_seller.php with bootstrap.
// Model - Change to this
public function cron_job_seller()
{
$this->db->select('*');
$this->db->from('wc_seller_products');
return $this->db->get();
}
// Controller
public function cron_job() {
$this->load->model('home/Home_model');
$this->load->library('email', array('mailtype'=>'html'));
$buyer = $this->Home_model->cron_job_buyer();
$seller = $this->Home_model->cron_job_seller();
$data['seller'] = $seller // Send data to View
// Create cron_job_seller.php file in Views Folder.
$this->load->view('cron_job_seller', $data);
}
// View cron_job_seller.php
<!DOCTYPE html>
<html lang="en">
<head>
<title>Sample Table</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap-theme.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script>
<script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
</head>
<body>
<div class="container">
<table class="table table-bordered">
<?php foreach($seller->result() as $row) { ?>
<tr>
<td><?php echo $row->colname_1; ?></td>
<td><?php echo $row->colname_2; ?></td>
<td><?php echo $row->colname_3; ?></td>
<td><?php echo $row->colname_4; ?></td>
</tr>
<?php } ?>
</table>
</div>
</body>
</html>

New line after multiple columns

Hi all i'm not very experienced with programming so this is probably easy to achieve.
I am pulling data from a mysql table using php i want to display the output like so:
$row[1] $row[2] Line break
$row[3] $row[4] Line break
$row[5] $row[6] Line break
And so on
Any help would be appreciated thanks
$user_table = select_table( "users", "user_name ASC" );
$rows = array( );
while( $row = mysqli_fetch_assoc( $user_table ) ) {
$rows[] = $row;
}
$user_groups = array_chunk( $rows, 2 );
foreach ( $user_groups as $user_group ) {
echo "<tr>";
foreach( $user_group as $row ) {
echo "<td class=\"user-box\">{$row["user_name"]}</td>";
}
echo "</tr>";
}
This is my working code. Thanks Tim
Loop through your results and start counting again after 2.
here's an example using a simple array and a table so you can see how it works
<?php
$results = array('one','two','three','four');
echo '<table border="1">';
foreach(array_chunk($results,2) as $row) {
echo '<tr>';
foreach($row as $value) {
echo '<td>'.$value.'</td>';
}
echo '</tr>';
}
echo '</table>';

Categories