PHP: Get result from arrays. - php

Question

Sorry for the title. its little difficult for me to explain. I've spent almost few hours to figure this out, but failed. So I'm posting it here.
I have following array
Array
(
[0] => Array
(
[0] => a
[1] => b
[2] => c
)
[1] => Array
(
[0] => p
[1] => q
[2] => r
)
[2] => Array
(
[0] => w
[1] => x
[2] => y
[3] => z
)
)
The array could have any number of elements.
What i need to do is create another array based on above array.
Array
(
[0] => Array
(
[0] => a
[1] => p
[2] => w
)
[1] => Array
(
[0] => b
[1] => q
[2] => x
)
[2] => Array
(
[0] => c
[1] => r
[2] => y
)
[3] => Array
(
[0] => Z
)
)
Any hints will be appreciated.
Thanks

Answer 1

If PHP < 5.5 or you don't want to use array_column-solution
$newArray = array();
foreach($array as $row)
foreach($row as $key => $value){
if (!isset($newArray[$key]))
$newArray[$key] = array();
$newArray[$key][] = $value;
}

Answer 2

Upgrade to PHP 5.5 if you aren't already on it, then use array_column

Answer 3

Just try with array_walk_recursive:
$input = [
['a', 'b', 'c'],
['p', 'q', 'r'],
['w', 'x', 'y', 'z'],
];
$output = [];
array_walk_recursive($input, function($value, $index) use (&$output) {
if (!isset($output[$index])) {
$output[$index] = [];
}
$output[$index][] = $value;
});
Output:
array (size=4)
0 =>
array (size=3)
0 => string 'a' (length=1)
1 => string 'p' (length=1)
2 => string 'w' (length=1)
1 =>
array (size=3)
0 => string 'b' (length=1)
1 => string 'q' (length=1)
2 => string 'x' (length=1)
2 =>
array (size=3)
0 => string 'c' (length=1)
1 => string 'r' (length=1)
2 => string 'y' (length=1)
3 =>
array (size=1)
0 => string 'z' (length=1)