How do i integrate a form with a table? - php

Question

Here is my current TABLE:
print "<table cellpadding=12px>";
print "<th>Name</ th>";
print "<th>Price</ th>";
print "<th>Image</ th>";
if ($cat == 'Clothes'){
$query = "SELECT * FROM Products WHERE Type = 'Clothes' ORDER BY ProductPrice";
$result = mysqli_query($connection, $query);
while ($row = mysqli_fetch_assoc($result))
{
echo " <tr>";
echo "<td>" . $row['ProductName'] . "</td>";
echo "<td>" . '&pound'. $row['ProductPrice'] . "</td>";
echo "<td>" . '<img width=200px height=200px src="./ProductsPic/' . $row['ProductPic'] . '" />' . "</td>";
echo "<td> Add to Cart</td>";
echo "</tr>";
}
print "</table>";
However, when i click on the "add to cart" link, it only sends the ID of the product to the cart. I somehow need to send the price and name of that product (possibly hidden data?). So would it be easy to integrate a form into my table, or would there be another way i can add the name and price of the product into my cart array?

Answer 1

If the ID field is the unique key that represents the product, then you can simply fetch its other details from the database. Otherwise you can do the following:
You could add more parameters to the query string.
echo "<td> Add to Cart</td>";
You could create a form with hidden values, and convert the Add to Cart link to a submit button.
echo '
<form action="cart.php">
<input type="hidden" name="price" value="'.$row['ProductPrice'].'">
<input type="hidden" name="name" value="'.$row['ProductName'].'">
<input type="hidden" name="id" value="'.$row['ID'].'">
<button type="submit">Add to cart</button>
</form>
';