this is my 3rd post, I just wanted to thank everybody for being patient and helping me out.
So here's my issue, i'm trying to have this form submit to itself and pass the data to the DB on submit.
I'm not seeing any records added to the DB on the submit.
<!DOCTYPE html>
<?php
$con=mysqli_connect("localhost","root","","project1");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// check variables set
if (isset($_POST['submit']))
{
$site_code = $_POST['site_code'];
$site_name = $_POST['site_name'];
$site_address = $_POST['site_address'];
$site_city = $_POST['site_city'];
$site_postalcode = $_POST['site_postalcode'];
$province = $_POST['province'];
$country = $_POST['country'];
}
// Query from Countries table
$query_countries = "select * from countries";
$country_results = mysqli_query($con,$query_countries);
$number_of_returns_country = mysqli_num_rows($country_results);
// Query from Provinces Table
$query_provinces = "select * from provinces";
$provinces_results = mysqli_query($con,$query_provinces);
$number_of_returns_province = mysqli_num_rows($provinces_results);
//insert form values into sites table
$sql_site="INSERT INTO sites (site_code, site_name, site_address, site_city, site_postalcode, id_province, id_county)
VALUES
('$_POST[site_code]','$_POST[site_name]','$_POST[site_address]','$_POST[site_city]','$_POST[site_postalcode]','$_POST[province]','$_POST[country]')";
mysqli_query($con,$sql_site);
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="site.css">
</head>
<body>
<h1>Insert Site into DB</h1>
<h2 class="button"><a href=/index.html>Home</a></h2>
<h2 class="button"><a href=/insert.php>add site</a></h2>
<h2 class="button"><a href=/delete.html>delete site</a></h2>
<h2 class="button"><a href=/search.html>search site</a></h2>
<form class="insert" action="insert.php" method="post">
<h3>Site Info</h3>
Site code: <input type="text" name="site_code"><br>
Site name: <input type="text" name="site_name"><br>
Address: <input type="text" name="site_address"><br>
City: <input type="text" name="site_city"><br>
Postal code: <input type="text" name="site_postalcode"><br>
Province: <select name="province">
<?php while($row = mysqli_fetch_assoc($provinces_results)){ ?>
<option value="<?php echo $row['id'];?>"><?php echo $row['province'];?></option>
<?php } ?>
</select><br>
Country: <select name="country">
<?php while($row = mysqli_fetch_assoc($country_results)){ ?>
<option value="<?php echo $row['id'];?>"><?php echo $row['country'];?></option>
<?php } ?>
</select><br>
<h3>Site Contact Info</h3>
Site contact name: <input type="text" name="site_contact_name"><br>
Phone number 1: <input type="number" name="site_contact_number1"><br>
Phone number 2: <input type="number" name="site_contact_number2"><br>
Email address: <input type="email" name="site_contact_email"><br>
<input type="submit">
</form>
</body>
</html>
What you have is $sql_site storing a mySQL command. The mySQL command in $sql_site needs to be run with the mysqli_query function
//insert values into sites table
$sql_site="INSERT INTO sites (site_code, site_name, site_address, site_city, site_postalcode)
VALUES
('$_POST[site_code]','$_POST[site_name]','$_POST[site_address]','$_POST[site_city]','$_POST[site_postalcode]')";
mysqli_query($con,$sql_site);
?>
Try This,
First Of all you have change the form action
<form class="insert" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
and move the insert query inside the
if (isset($_POST['submit']))
{
// insert query
}
Add this line after declaring $sql_site
mysqli_query($con,$sql_site);
Related
I am struggling to get values from an HTML form into PHP variables using POST. It used to work but now no matter what I do it isn't working. Here is the php file:
<?php
include "DBConn.php";
session_start();
?>
<html>
<head>
<title>Register</title>
<link rel="stylesheet" href="Register.css" type = "text/css">
</head>
<body>
<div id="container">
<form action="register.php" method = "post">
<label for="name">Name:</label>
<input type="text" id="name" name="txtName" value = <?php if(isset($_POST['txtName'])) echo $_POST['txtName'];?>>
<label for="surname">Surname:</label>
<input type="text" id="surname" name="txtSurname" value = <?php if(isset($_POST['txtSurname'])) echo $_POST['txtSurname'];?>>
<label for="address">Address:</label>
<input type="text" id="address" name="txtAddress" value = <?php if(isset($_POST['txtAddress'])) echo $_POST['txtAddress'];?>>
<label for="email">Email:</label>
<input type="email" id="email" name="txtEmail" value = <?php if(isset($_POST['txtEmail'])) echo $_POST['txtEmail'];?>>
<label for="password">Password:</label>
<input type="password" id="password" name="txtPassword" value = <?php if(isset($_POST['txtPassword'])) echo $_POST['txtPassword'];?>>
<label for="password2">Re-enter Password:</label>
<input type="password" id="password2" name="txtPassword2" value = <?php if(isset($_POST['txtPassword2'])) echo $_POST['txtPassword2'];?>>
<div id="lower">
<input type="submit" value="Register" name = "btnRegister">
</div><!--/ lower-->
</form>
</div>
</body>
</html>
<?php
//Runs if btnRegister is clicked. Registers a user.
if (isset($_POST['btnRegister'])) {
//Assigns form data to variables
$_SESSION["Name"] = $_POST['txtName'];
$_SESSION["Surname"] = $_POST['txtSurname'];
$_SESSION["Email"] = $_POST['txtEmail'];
$_SESSION["Password"] = $_POST['txtPassword'];
$_SESSION["Password2"] = $_POST['txtPassword2'];
$_SESSION["Address"] = $_POST['txtAddress'];
$sqlSelect =
"SELECT *
FROM tbl_Customer
WHERE Email = '{$_SESSION["Email"]}'";
//Runs select query
$result = $conn->query($sqlSelect);
$md5pass = md5($_SESSION["Password"]);
//Checks to see if user exists based on query
if ($result->num_rows == 0) {
//Checks to see if passwords match
if ($_SESSION["Password"] == $_SESSION["Password2"]) {
//Passwords match
echo '<script>alert("Passwords match")</script>';
//Insert statement to insert user into table
$sqlInsert = "INSERT INTO tbl_Customer (Name, Surname, Email, Password, Address)
VALUES ('{$_SESSION["Name"]}','{$_SESSION["Surname"]}','{$_SESSION["Email"]}','$md5pass','{$_SESSION["Address"]}');";
if ($conn->query($sqlInsert) === TRUE) {
echo '<script>alert("Registered successfully")</script>';
}
else {
echo '<script>alert("Registration error: " . $sql . "<br>" . $conn->error)</script>';
}
}
else {
echo '<script>alert("Passwords do not match")</script>';
}
}
else {
//User exists
echo '<script>alert("User already exists, choose a different email.")</script>';
}
header('Location: login.php');
exit();
}
?>
None of the alerts are working indicating that they echos are not working. Also, the second I click the register button I am taken to the login page which means the register button must be working. It doesn't give me any errors or messages.
Remove action="register.php" from <form> tag if your PHP code is on the same page as HTML code. The action attribute specifies where to send the form-data when a form is submitted, since your PHP code is on the same page you should remove action and the form-data will be submitted on that same page.
Or
create a register.php and put PHP code there.
I am facing issues with id='$id'
SELECT Query is working fine but update query is not working
if I put any id number instead of $id it updates the data but when I use $id it just does nothing.
<?php
$db = mysqli_connect("localhost", "root", "", "aashir");
$id = $_GET['id'];
$query = "SELECT * FROM students WHERE id='$id' ";
$result = mysqli_query($db, $query);
while ($row = mysqli_fetch_array($result)) {
$key = $row['id'];
$name = $row['student_name'];
$fname = $row['father_name'];
$program = $row['student_program'];
}
if (isset($_POST['submit'])) {
$s_name = $_POST['s_name'];
$s_fname = $_POST['s_fname'];
$s_program = $_POST['s_program'];
$query2 = "UPDATE students SET student_name = '$s_name', father_name = '$s_fname', student_program = '$s_program' WHERE id='$id' ";
mysqli_query($db, $query2);
header("Location:show.php");
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Edit Student</title>
<link rel="stylesheet" type="text/css" href="css/bootstrap.css">
</head>
<body>
<div class="container mt-5">
<form method="POST" action="edit.php" class="col-lg-6 offset-lg-3">
<h2 class="text-center">Edit a Student</h2>
<div class="form-group">
<input type="text" name="s_name" class="form-control" value="<?php echo $name; ?>">
</div>
<div class="form-group">
<input type="text" name="s_fname" class="form-control" value="<?php echo $fname; ?>">
</div>
<div class="form-group">
<input type="text" name="s_program" class="form-control" value="<?php echo $program; ?>">
</div>
<div class="form-group">
<input type="submit" name="submit" class="btn btn-success" value="Update">
</div>
</form>
</div>
</body>
</html>
you have two options to fix your issue (without talking about SQL injection, already quoted in the comments and to be addressed since it is a huge security risk for your application)
Change the form action to pass the id to the page while processing the form:
action="edit.php?id=<?php echo $id; ?>"
or better add an hidden input with the id:
<input type="hidden" name="id" value="<?php echo $id; ?>">
and then:
if (isset($_POST['submit'])) {
$s_name = $_POST['s_name'];
$s_fname = $_POST['s_fname'];
$s_program = $_POST['s_program'];
$id = $_POST['id'];
in this case the action can remain the same.
Posting the form you are reloading the page and not passing the id anymore via url as at the first load
You're performing the UPDATE using a POST request, yet you're looking for $id as a GET parameter. This way, $id will always be undefined, and thus the query fails.
You can try overloading the form action URL, like so:
<form method="POST" action="edit.php?id=<?php echo $_GET['id']; ?>" class="col-lg-6 offset-lg-3">
Hi for some reason my update statement is not working, most probably because of the id=%d, its not getting the id for the statement i think but its finding the id because it is listed in the url (shown Below). What is the problem please ?
This works when i Insert a number for the id, example : id=77, so most probably the problem is the %d how can i get it to find the id with the %d ?
http://localhost/test/edit.php?id=77
<?php
ob_start();
session_start();
include_once 'logindb.php';
$conn = new mysqli($hn, $un, $pw, $db);
if ($conn->connect_error) die($conn->connect_error);
if((isset($_POST['submit']))){
if((!isset($_POST['title'])) || (!isset($_POST['times'])) ){
echo "All values must be set";
}
else{
$title = $_POST['title'];
$times = $_POST['times'];
$film_id = $_GET['id'];
$upfile = 'Uploads/posters/'.$_FILES['userfile']['name'];
if(move_uploaded_file($_FILES['userfile']['tmp_name'],$upfile)){
echo "File moved into folder";
header( "Location: index.php" ) ;
}
else{
echo "Problem: could not move image file to destination directory";
}
$upfile2 = 'Uploads/trailers/'.$_FILES['userfile2']['name'];
$format1 = "UPDATE films SET titles = '$title', ftimes = '$times', poster = '$upfile', trailer = '$upfile2' WHERE id = %d";
$query = sprintf($format1, $film_id );
$result = mysqli_query($conn, $query)
or die("Error in query: ". mysqli_error($conn));
}
}
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="Empire.css"/>
<script type="text/javascript" src="script.js"> </script>
<title>Movie Form</title>
</head>
<body class="formola">
<div class="form-style-5">
<p class="top"> List Movies </p>
<form method = "post" action="edit.php" enctype="multipart/form-data">
<fieldset>
<legend><span class="number">1</span> Details </legend>
<input type="text" name="title" placeholder="Movie Title">
<input type="text" name="times" placeholder="Times">
</fieldset>
<fieldset>
<legend><span class="number">2</span> Attachments </legend>
<div class="form-group ">
<label> Film Poster <br> </label>
<input type="hidden" class="form-control" name="MAX_FILE_SIZE" value="100000000">
Upload this Film Poster: <br> <input name="userfile" id="userfile" type="file"> <br>
<input type="hidden" class="form-control" name="MAX_FILE_SIZE" value="10000000">
Upload this Trailer: <br> <input name="userfile2" id="userfile2" value="10000000" type="file"> <br>
</div>
</fieldset>
<input type="submit" name = "submit" value="Upload" />
</form>
</div>
</body>
</html>
Hi all I am new to mysqli and php (currently studying and trying to work on a test database- I have not used security measures at this wont be available public) and trying to get the information I have just submitted in the form to display in a new form which will then receive further user input then submitted to database. Here is an example of what I have done so far:
Form 1 (customer table - cust id =primary key)
Customer Details ie name address telephone etc
dynamic drop down box - consists of 4 options.( would like whatever option is selected here to return a particular form)
The form is currently submitting correctly in the database, but I would like once it has submitted to the database to return the customer info (including the customer id as that is the relationship in the new table) and on the form2(service table - service id is primary key) so the user can input further data to the form and submit.
Hope this makes sense, any help would be appreciated.
Thanks
Response 1
Thank you for my response I probably havent made myself very clear.
Form 1 where dynamic dropdown list is - when user submits forms I would like it to return form 2 with the customer info we inserted in form 1
Form 1
<!doctype html>
<html>
<head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<title>test</title>
</head>
<body>
<form action="newbookingcode.php" method="post">
<p>First Name: <input type="text" name="firstname"/>
Last Name: <input type="text" name="lastname"/></p>
<p>Business Name: <input type="text" name="businessname"/></p>
<p>Contact Number: <input type="text" name="number"/>
Alt Number: <input type="text" name="altno"></p>
<p>Email Address:<input type="text" name="email"></p>
<p>Street No:<input tyep="text" name="streetno">
Street Name:<input type="text" name="street"></p>
<p>Suburb:<input type="text" name="suburb">
Postal Code:<input type="text" name="postalcode">
State: <input type="text" name="state"></p>
**<p>Type of Service Required: <select id="category" name="category" >
<option value="nill">---Select Service---</option**
<?php
$servername = "";
$username = "";
$password = "";
$dbname = "";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM serviceType";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo '<option value= "'.$row['jobType'].'" >' . $row['jobType'] . '</option>';
}
} else {
echo "0 results";
}
$conn->close();
?>
</p>
</select>
<p>
<input type="submit"/>
</p>
</form>
</body>
</html>
Query in separate file
$fname=$_POST['firstname'];
$lname=$_POST['lastname'];
$bname=$_POST['businessname'];
$phone=$_POST['number'];
$altphone=$_POST['altno'];
$email=$_POST['email'];
$streetno=$_POST['streetno'];
$street=$_POST['street'];
$suburb=$_POST['suburb'];
$postcode=$_POST['postalcode'];
$state=$_POST['state'];
$service=$_POST['category'];
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO customer (contactFirstName,contactLastName,businessName,contactNumber,altNumber,email,streetNo,streetName,suburb,postalCode,state,serviceType)
VALUES ('$fname','$lname','$bname','$phone','$altphone','$email','$streetno','$street','$suburb','$postcode','$state','$service')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
Check this code and let me know if you have any questions:
<?php
$servername = "";
$username = "";
$password = "";
$dbname = "";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM serviceType";
$result = $conn->query($sql);
/************** IMPORTANT *************/
$whichForm = 1;//to know which form to show
$last_customer_id = 0;//to store last customer id
//to store your customer information
$fname=$lname=$bname=$phone=$altphone=$email=$streetno=$street=$suburb=$postcode=$state=$service='';
//To handle post operations after clicking on post.
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
$whichForm = 2; // to show second form
//if it is first form
if($_POST['action'] == 'firstForm')
{
$fname=$_POST['firstname'];
$lname=$_POST['lastname'];
$bname=$_POST['businessname'];
$phone=$_POST['number'];
$altphone=$_POST['altno'];
$email=$_POST['email'];
$streetno=$_POST['streetno'];
$street=$_POST['street'];
$suburb=$_POST['suburb'];
$postcode=$_POST['postalcode'];
$state=$_POST['state'];
$service=$_POST['category'];
//Preparing your insert query
$sql = "INSERT INTO customer (contactFirstName,contactLastName,businessName,contactNumber,altNumber,email,streetNo,streetName,suburb,postalCode,state,serviceType) VALUES ('$fname','$lname','$bname','$phone','$altphone','$email','$streetno','$street','$suburb','$postcode','$state','$service')";
$conn->query($sql); //insert into db
//get last insert customer id and you already have your customer information
//in the variables above $fname, $lname.....etc
$last_customer_id = $conn->insert_id;
}
else{//do something with your second form
//get last customer info
$sql = "SELECT * FROM serviceType where id = ".$POST_['last_customer_id']."";
$result = $conn->query($sql);
$res = $result->fetch_assoc();
//you can access customer information like res['contactFirstName']
}
}
$conn->close(); //close your connection
?>
<!doctype html>
<html>
<head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<title>test</title>
</head>
<body>
<?php
if($whichForm == 1){ //if it is first form
?>
<form id="1" action="test2.php" method="post">
<!-- This input is needed to identify which form -->
<input type="hidden" name="action" value="firstForm" />
<p>First Name: <input type="text" name="firstname" value="<?php echo $fname; ?>"/>
Last Name: <input type="text" name="lastname" value="<?php echo $lname; ?>" /></p>
<p>Business Name: <input type="text" name="businessname" value="<?php echo $bname; ?>"/></p>
<p>Contact Number: <input type="text" name="number" value="<?php echo $phone; ?>"/>
Alt Number: <input type="text" name="altno" value="<?php echo $altphone; ?>"></p>
<p>Email Address:<input type="text" name="email" value="<?php echo $email; ?>"></p>
<p>Street No:<input tyep="text" name="streetno" value="<?php echo $streetno; ?>">
Street Name:<input type="text" name="street" value="<?php echo $street; ?>"></p>
<p>Suburb:<input type="text" name="suburb" value="<?php echo $suburb; ?>">
Postal Code:<input type="text" name="postalcode" value="<?php echo $postcode; ?>">
State: <input type="text" name="state" value="<?php echo $state; ?>"></p>
**<p>Type of Service Required: <select id="category" name="category" >
<option value="nill">---Select Service---</option>
<?php
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
//this if to save the value of the selected category
if($row['jobType'] == $service)
{
echo '<option value= "'.$row['jobType'].'" SELECTED>' . $row['jobType'] . '</option>';
}
else
{
echo '<option value= "'.$row['jobType'].'">' . $row['jobType'] . '</option>';
}
}
}
?>
</select></p>
<button type="submit">Submit</button>
</form>
<?php
}//ending bracket for if($whichForm == 1)
else if($whichForm == 2){ // or just else will do fine
?>
<form id="2" action="test2.php" method="post">
<!-- This input is needed to identify which form -->
<input type="hidden" name="action" value="secondForm" />
<!-- This input is needed to store the last customer id -->
<input type="hidden" name="last_customer_id" value="<?php echo $last_customer_id; ?>" />
<!-- here you put your second form -->
<button type="submit">Submit</button>
</form>
<?php
}//ending bracket for else if($whichForm == 2)
?>
</body>
</html>
Assuming you are using a database object like mysqli to do DB interactions.
Say form1 generate insert query $insertQyery.
And you are executing this query (insert statement) like
$mysqli->query($insertQyery);
After the execution of this insert statement you can use
$customerId = $mysqli->insert_id
Now using this $customerId you can show records details on form2 or use this $customerId as reference on form2.
After customer submit FORM #1
on the next page
let's get the last customer details :-
<?php
//after mysqli connection
$contactFirstName = '';
$contactLastName = '';
$businessName = '';
$sql_get_data = "SELECT * FROM customer ORDER BY customerID DESC limit 1 ";
$query_get_data = mysqli_query($conn, $sql_get_data);
while ($row = mysqli_fetch_array($query_get_data, MYSQLI_ASSOC)) {
//specify which data you want to get from "customer" table
$contactFirstName = $row['contactFirstName'];
$contactLastName = $row['contactLastName'];
$businessName = $row['businessName'];
}
?>
HTML Form#2 :-
<form id="form2" method="post">
<input type="text" value="<?php echo 'contactFirstName'; ?>"
<input type="text" value="<?php echo 'contactLastName'; ?>"
<input type="text" value="<?php echo 'businessName'; ?>"
</form>
Hope this answer will help you.
Going to try to keep it short. I have a while loop in grid.php file to fill up a table as such...
<?php while($product = $products->fetch_assoc()) { ?>
<tr>
<td><?php echo $product['cd_id']?></td>
<td><?php echo $product['cd_title']?></td>
<td><?php echo $product['cd_musician_fname']?></td>
<td><?php echo $product['cd_musician_lname']?></td>
<td><?php echo $product['cd_price']?></td>
<td>Edit</td>
<td>Delete</td>
</tr>
<?php } ?>
If I click the first anchor tag takes me to a edit.php file and here is the head code for that file.
<?php include '_includes/db.php';
$cd_id = trim($_GET['id']);
$message = '';
include '_includes/connection.php';
if($db->connect_error){
$message = $db->connect_error;
}else{
$sql = "SELECT * FROM CD WHERE cd_id = $cd_id";
$result = $db->query($sql);
$row = $result->fetch_assoc();
if($db->error){
$message = $db->error;
}
}
?>
Now I will show the html of edit.php
<!-- Product Musician last name-->
<fieldset class="form-group">
<label for="cd_musician_lname">Musician's lirst name</label>
<input type="text" class="form-control" id="cd_musician_lname" name="cd_musician_lname" value="<?php echo $row['cd_musician_lname'];?>">
</fieldset>
<!-- End of Musician last name-->
<!-- Product price-->
<fieldset class="form-group">
<label for="cd_price">Product price</label>
<input type="text" class="form-control" id="cd_price" name="cd_price" value="<?php echo $row['cd_price'];?>">
</fieldset>
<!-- End of Product price-->
<!-- Form submit button-->
Update Record
<a class="btn btn-primary" href="index.php" role="button">Go Back Home</a>
I have the edit.php page working just fine but if I make changes in the fields and click the submit anchor tag I get all the fields of the row empty but the PK. Here is the code for the final edit_confirm.php file
<?php
include '_includes/db.php';
$cd_id = trim($_GET['id']);
$cd_title = $_POST['cd_title'];
$cd_musician_fname = $_POST['cd_musician_fname'];
$cd_musician_lname = $_POST['cd_musician_lname'];
$cd_price = $_POST['cd_price'];
$message = '';
include '_includes/connection.php';
if($db->connect_error){
die("Connection failed: ".$db->connect_error);
} else {
$sql = "UPDATE CD SET cd_title='".$cd_title."', cd_musician_fname='".
$cd_musician_fname."', cd_musician_lname='".
$cd_musician_lname."', cd_price='".$cd_price."' WHERE cd_id = $cd_id ";
$db->query($sql);
var_dump($sql);
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<?php include '_includes/main-head.php';?>
</head>
<body>
<?php include '_includes/main-navbar.php';?>
<div class="container">
<hr>
<?php
if($db->query($sql) === TRUE){ ?>
<h1>Record updated successfully.</h1>
<?php echo $cd_title; ?>
<?php echo $record->affected_rows ?>
<p> record was updated in the database.</p></br>
<?php } else { ?>
<p>Error updating the record: </p> <?php $db->error; ?>
<?php }; ?>
<hr>
<a class="btn btn-primary" href="index.php" role="button">Go Back Home</a>
</div>
<?php include '_includes/main-script.php';?>
</body>
</html>
If you notice in the edit_confirm.php I did a var_dump to see what are the values in the variables and it shows empty.
I need help with this.
Thank you in advance.
Man the better way to do this is make it simple to test if the record is updating or not
formsample.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<?php
include("connection.php");
$id = $_GET['id'];
$query= "select * from clients where id = '$id'";
$sql = mysqli_query($connect, $query);
$result = mysqli_fetch_assoc($sql);
?>
<form action="process.php" method="post">
<input type="text" name="name" id="name" value="<?php echo $result['name'] ?>" />
<input type="text" name="email" id="email" value="<?php echo $result['email'] ?>" />
<input type="hidden" name="id" id="id" value="<?php echo $id?>" />
<input type="submit" />
</form>
</body>
</html>
process.php
<?php
include("connection.php");
$id = $_POST['id'];
$name = $_POST['name'];
$email= $_POST['email'];
$query = "UPDATE clients set name= '$name', email ='$email' where id = '$id'";
$sql = mysqli_query($connect, $query);
?>
Update Record
This is not the proper way to submit a form - it won't work at all.
You need to have a form opening and closing tag, the target address is in the action attribute of the form element, and the method is on there too and should be post for this form (method="POST"). In your code you have a link where you should have a submit input so it won't submit the data, it will just redirect you to that URL. You should have something like this:
<input type="submit" value="Update Record" />
http://www.w3schools.com/html/html_forms.asp