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I have a for loop that loops through xml. I then fetch results from the database and look for the id.
What happens is that when an id is found and the break happens, it stops both the while loop and the parent for loop. I just want to stop the while loop. How do I get this to work as intended?
$xml = simplexml_load_file('file/path/here');
$articles = $xml->article;
$total_articles = count($articles);
// Cycle through the list of articles
for($a=0; $a<$total_articles; $a++)
{
// Check if article already exists
// MySQLi select statement goes here
$exists = false;
while($a = $article_result->fetch_assoc())
{
if($a['article_id'] == $id)
{
$exists = true;
break 1;
}
}
}
you're setting $a to $article_result->fetch_assoc().
Here:
...
while($a = $article_result->fetch_assoc())
...
[] < 1 returns false for me, at least for php7.
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Closed 7 years ago.
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I tried to echo out the $rinse variable, I get nothing
But I do get one for the $rang['email'], any clues would be good
I also tried doing $rinse == $rang['email'];
while($rang = mysql_fetch_assoc($results))
{
if ($rang['email'] = $rinse){
echo $rang['email'];
}
$rinse = $rang['email'];
}
my code updated:
echo $rinse;
if ($rang['email'] == $rinse){
echo $rang['email'];
}
$rinse = $rang['email']
This is still not working for me
You need two = in your if statement.
if ($rang['email'] == $rinse){
You should add double ==. This is comparion, a single = means set to
while($rang = mysql_fetch_assoc($results))
{
if ($rang['email'] == $rinse){
echo $rang['email'];
}
$rinse = $rang['email'];
}
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Closed 9 years ago.
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I have a following simple code but it produces syntax error on line this->players[] = 'Tom':
<?php
class club {
var $clubID = 0;
var $players=array();
function __constructor($clubID = '') {
$this->clubID = $clubID;
}
function populatePlayers() {
$this->players[] = 'Tom';
}
}
$myClub = new club(1);
$myClub->populatePlayers();
var_dump($myClub->players);
?>
It should be
$this->players[] = 'Tom';
instead of
$this->$players[] = 'Tom';
You need to add $ before the this keyword and the players variable does not need one.
Demo
try this
function populatePlayers() {
$this->players[] = 'Tom';
}
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I am seeing the following error when executing my status script:
Warning: Cannot use a scalar value as an array in
$result[$array[$i*2]] = $array[$i*2+1];
What am I doing wrong?
I have included the full code below:
<?php
// Set the host and port
$host = "ip_goes_here";
$port = port_goes_here;
// Open the socket connection to the server
$fp = fsockopen("udp://".$host, $port);
// Set the string to send to the server
$string = "\xff\xff\xff\xffgetinfo";
// Set the socket timeout to 2 seconds
socket_set_timeout($fp, 2);
// Actually send the string
fwrite($fp, $string);
// Read the first 18 bytes to get rid of the header and do the error checking here
if(!fread($fp, 18)) {
die("Oh God, the pain!");
}
// Get the status of the socket, to be used for the length left
$status = socket_get_status($fp);
// Read the rest
$info = fread($fp, $status['unread_bytes']);
// Explode the result of the fread into another variable
$array = explode("\\", $info);
// Loop through and create a result array, with the key being even, the result, odd
for($i = 0; $i < count($array)/2; $i++) {
$result[$array[$i*2]] = $array[$i*2+1];
}
// Print the result for error checking
print_r($result);
// Close the file pointer
fclose($fp);
The line I mentioned is causing the errors. I have no idea what I am doing wrong here...
You can try declaring the variable $result, as an array, before using it.
$result = array();
// Loop through and create a result array, with the key being even, the result, odd
for($i = 0; $i < count($array)/2; $i++) {
$result[$array[$i*2]] = $array[$i*2+1];
}
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Closed 9 years ago.
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http://plnkr.co/edit/06lu6r34eGNfRq1fygNy
I want to only display 10 "cards" from my array, how would I do so?
I tried using unset() but it is very inefficient and doesn't even work for multiple cards.
Also how can I make the code display the "cards" horizontally instead of vertically?
If you’d like to use unset, the correct syntax would be unset($cards[1]); unset($cards[2]); unset($cards[3]); ... and so on.
However, for your particular situation, I’ll recommend you to use array_slice:
$cards = array(
"Messi", "Ronaldo", "Ibrahimovic", "Ribery", "Robben", "Neymar", "Rooney", "Casillas",
"Falcao", "Van Persie", "Hazard", "Iniesta", "Xavi", "Schweinsteiger", "Silva", "Fabregas",
"Lahm", "Aguero", "Cavani", "Vidic", "Ozil", "Mata", "Bale", "ThiagoSilva",
"Kompany", "Tevez", "Toure", "Ramos", "Suarez", "Pirlo", "DiMaria", "Neuer",
"Pique", "Buffon", "Lewandowski", "Gomez", "Chiellini", "Cole", "Pedro", "Busquets",
"Cech", "Muller", "Hummels", "Alonso", "Navas", "Modric", "Cazorla", "Gotze",
"Benzema", "Vidal", "Lavezzi"
);
shuffle($cards);
$cards = array_slice($cards, 0, 10);
For the horizontal display, you may simply omit the <br> at the end of every iteration of your loop, but, depending on the resolution of the user’s browser, the images may occupy more than one line. For a strictly horizontal arrangement, use an HTML table with 10 columns:
print("<table><tr>");
foreach($cards as $card){
$img = "http://d2bm3ljpacyxu8.cloudfront.net/fit/105x97/http://clearpkz.webs.com/webstore/".$card.".png";
print("<td><img src=\"".$img."\"/></td>");
}
print("</tr></table>");
The following works too:
for ($i = 0; $i < 10; $i++) {
echo $cards[$i] ." <br>"; // put the name above the card
echo "<img src='http://d2bm3ljpacyxu8.cloudfront.net/fit/105x97/http://clearpkz.webs.com/webstore/$card.png'> <br>";
}
If you want them horizontally, and without names, don't put in the <br>:
for ($i = 0; $i < 10; $i++) {
echo "<img src='http://d2bm3ljpacyxu8.cloudfront.net/fit/105x97/http://clearpkz.webs.com/webstore/$card.png'>";
}