PHP - Foreach loop only echoing first letter of string - php

Question

I have an array that looks like this:
array(1) {
["brookybear"]=> array(5) {
["id"]=> int(20217894)
["name"]=> string(10) "Brookybear"
["profileIconId"]=> int(603)
["summonerLevel"]=> int(30)
["revisionDate"]=> float(1397388011000)
}
}
when i var_dump(); it. I'm trying to use a foreach loop to take the "name" value out of it. However, when I echo it, I only get "B" as the output, and not the full Brookybear.
Here is my foreach loop:
$url="APIURL";
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL,$url);
$result=curl_exec($ch);
$array = json_decode($result, true);
foreach($array['brookybear'] as $champs)
{
echo $champs['name'];
}

Answer 1

Looks like you're looping on the 'brookybear' item instead of the parent array.
If you want to see all the names of all the $champs:
$array = json_decode($result, true);
foreach($array as $champs)
{
echo $champs['name'];
}
or more clearly:
$champions = json_decode($result, true);
foreach($champions as $champ)
{
echo $champ['name'];
}

Answer 2

Why do you use loop to get the value? If I am doing this, I will simply write：
<?php
if ( isset( $array['brookybear']['name'] ) ) {
echo $array['brookybear']['name'];
}

Answer 3

If first character is only display in string, you know what is the reason i now,
make sure array variable name is not same in your above script
. example
$my_var = "My name is umair";
and below you same use this variable for array
$my_var[0] = "My name is umair";
now if you echo array var it will show only first letter in output is "M"
simply change the array variable than it will be working