i want to return follower and following numbers for just one user_id from existing two tables which one is users and the other one is follow:
my code is here
SELECT users.id,
users.name,
COUNT(folow.following),
COUNT(folow.follower)
FROM users
JOIN folow ON folow.following = users.id
WHERE users.id = '$other' LIMIT 10
It's probably simplest to use correlated subqueries here:
SELECT id,
name,
(SELECT COUNT(*) FROM folow WHERE following = users.id) followers,
(SELECT COUNT(*) FROM folow WHERE follower = users.id) following
FROM users
WHERE id = ?
Related
I want to show all those users from Users table, whose id is present in table favorite_group_users as user_id for a user whose favorite_groups.id = favorite_group_users.id.
I used below query but it is returning null.
select users.id as user_id, users.first_name as name,
favorite_groups.id as group_id,
favorite_groups_users.user_id as carrier_id
from users
inner join favorite_groups
on users.id = favorite_groups.user_id
inner join favorite_groups_users
on favorite_groups.id = favorite_groups_users.favorite_group_id
where users.id = 38;
You may try nested select
select
favorite_groups.group_id, users_group.user_id
from
favorite_groups_users ,
(select
favorite_groups_users.favorite_group_id,
users.user_id
from
users, favorite_groups_users
where
users.id = 38 and
users.id = favorite_groups.user_id
) users_group
where
users_group.favorite_group_id=favorite_groups.group_id
I have tables:
likes - id, user_id, like_user_id<br>
users - id, name, email ...,<br>
friends - id, user_id, friend_id, status<br>
Is it possible to sort it with one SQL query first to show the friends then the other users.
Any help would be appreciated.
Thank you.
I tried this and it works, but the problem is it give me double results of users:
select *
from `likes`
left join `users` on `users.id` = `likes.user_id`
left join `friends` on `friends.user_id` = `likes.user_id`
or `friends.friend_id` = `likes.user_id`
where `likes.id` = 1
order by `friends.user_id` = 5
or `friends.friend_id` = 5
You need to work with a UNION here to merge the liked users with the befriended users. Upon doing this, you can create an artificial column friend, that you fill with 1 in the friend query and 0 in the like query. Later on you can order by that column.
SELECT
friends.user_id,
1 as friend,
users.*
FROM
friends
JOIN users ON users.id = friends.friend_user_id
UNION SELECT
likes.user_id,
0 as friend,
users_liked.*
FROM
likes
JOIN users as users_liked ON likes.like_user_id = users_liked.id
WHERE
user_id = '$userId'
ORDER BY friend DESC, id ASC
This will return a list of all friends, followed by a list of all liked users.
I have table
answers(aid,user_id,...) - posts table
users (userid,name,...)
followers(user_one,user_two) - where user_one is the follower and user_two is the followed by person.
I need to show posts from people I follow and my posts using php and mysql in my home feed.But currently it is not working as expected.Each posts is showing 7 times.
curent select query
<?php
$my_id = $_SESSION['user_id'];
$sql_query = "SELECT * FROM answers left join users on users.userid = answers.user_id LEFT join followers on followers.user_one = answers.user_id WHERE answers.user_id= '$my_id' ORDER BY answers.date_created DESC";
?>
Didn't see you also want to return your posts. Try below sql:
select * from answers, users, (select user_one user_id from followers where user_two='$my_id' union select '$my_id' user_id) a where answers.user_id=users.user_id and answers.user_id=a.user_id;
There is error in your sql: SELECT * FROM answers left join users on users.userid = answers.user_id LEFT join followers on followers.user_one = answers.user_id WHERE answers.user_id= '$my_id' ORDER BY answers.date_created DESC".
the second left join should be followers.user_two=ansers.user_id, and the where statement should be followers.user_one='$my_id';
One option here is to phrase your query as a union of two queries. The first half of the union below finds all posts given by people you follow. The second half of the union finds all of your posts.
SELECT a.*
FROM answers a
INNER JOIN followers f
ON (a.user_id = f.user_two AND f.user_one = $my_id)
UNION ALL
SELECT a.* FROM answers WHERE user_id = $my_id;
I'm not a PHP person, but hopefully you can easily adapt the above query into your code.
I have 4 tables called shops, users, review and rating.
I want to get all reviews for the corresponding shop with reviewed user details and also overall rating for that shop.
I have done almost with the single query. But the problem is if the shop has same rating for multiple times by same user its consider as single rating. But that rating count was correct.
i.e
from this table user_id 3 was rated shop_id 1 as 4 times. So the count is 4 and total_rating is 17.
My query is
select review.comments, users.username, count(distinct rating.id) as rating_count,
sum(distinct rating.rating) as total_rating from users
left join review on users.id = review.user_id and review.shop_id='1'
left join rating on users.id = rating.user_id and rating.shop_id='1'
where review.shop_id='1' or rating.shop_id='1'
group by users.id, review.user_id, rating.user_id, review.id
When I run this query I got
But I need total_rating 17 for user_id 3..
Check this fiddle
You put DISTINCT IN sum( rating.rating) as total_rating, thats why the result(12=17-5), since it will include 5 only once while computing sum.
select review.comments, review.user_id, count(distinct rating.id) as rating_count,
sum( rating.rating) as total_rating from users
left join review on users.id = review.user_id and review.shop_id='1'
left join rating on users.id = rating.user_id and rating.shop_id='1'
where review.shop_id='1' or rating.shop_id='1'
group by users.id, review.user_id, rating.user_id, review.id
Here is SQLFiddle
Sample Output :
Hope this helps
Try this - Remove the distinct from sum(rating.rating). Since you gave sum(distinct rating.rating), it is ignoring one 5 that user 3 gave to store 1.
select review.comments, users.username, count(distinct rating.id) as rating_count,
sum(rating.rating) as total_rating from users
left join review on users.id = review.user_id and review.shop_id='1'
left join rating on users.id = rating.user_id and rating.shop_id='1'
where review.shop_id='1' or rating.shop_id='1'
group by users.id, review.user_id, rating.user_id, review.id
First of all: It makes no sense to outer-join records from a table and then remove them in the WHERE clause. With left join review ... you say: find a matching record in table review, and if you don't find any, then add nulls, so we keep the users record. Then with where review.shop_id='1' you say: keep only records where you actually found a record in review. So you are dismissing the records that you just took the pain to keep. Your WHERE clause renders your LEFT OUTER JOINS mere INNER JOINS.
As to your actual problem: That stems from joining all tables first and only then trying to get aggregates from the resulting records. Aggregate before joining instead:
select
rev.comments,
usr.username,
coalesce(rat.rating_count, 0) as rating_count,
rat.total_rating
from review rev
join users usr on users.id = review.user_id
left join
(
select user_id, shop_id, count(*) as rating_count, sum(rating) as total_rating
from rating
group by user_id, shop_id
) rat on rat.user_id = usr.id and rat.shop_id = rev.shop_id
where rev.shop_id = 1
group by rev.id;
The following is what I got right now, which does not work properly because it checks one row for two different values.
SELECT users.*
FROM users INNER JOIN roles_users ru ON users.id = ru.user_id
WHERE ru.role_id = 1 AND ru.role_id = 2
I would like to select all users that have two rows in roles_users. The one rows role_id should have one and the second should have role_id two.
So select all users that have two rows in the roles_users where one of them has role_id = 1 and the other has role_id = 2.
The above query selects all users that have one row in roles_users that has first one and then two, that's why I get no results and it does not work. So how can I do this right?
SELECT users.id
FROM users INNER JOIN roles_users ON users.id = roles_users.user_id
WHERE roles_users.role_id IN (1, 2)
GROUP BY users.id
HAVING COUNT(*) = 2
Why not just join in on roles_users twice? Ala:
SELECT users.* FROM users
INNER JOIN roles_users ru1 ON users.id = ru1.role_id AND ru1.role_id = 1
INNER JOIN roles_users ru2 ON users.id = ru2.role_id AND ru2.role_id = 2
You need to get a (distinct) list of the users having the required roles. Try this instead:
SELECT users.{column_list}
FROM users as a
JOIN (SELECT user_id
FROM roles_users
WHERE role_id IN (1, 2)
GROUP BY user_id
HAVING COUNT(DISTINCT role_id) = 2) required_role
ON required_role.user_id = users.id