Message: Undefined property: stdClass in codeigniter - php

Question

I got this error:
A PHP Error was encountered Severity: Notice Message: Undefined property: stdClass::$positionsNum
when i run.
My model:
public function load_job($id){
$Where = array('jobs.id' => $id);
$this->db->select('jobs.id, positionsNum, companyName, contract_type.titleEN as contractType');
$this->db->from('jobs');
$this->db->join('contract_type', 'jobs.contractTypeId = contract_type.id', 'left');
$this->db->where($Where);
$Result = $this->db->get();
return $Result->first_row() ;
}
my view:
<?php if(isset($job) && count($job) > 0){ ?>
<div class="row job-detail-row">
<div class="col-lg-6 job-detail-label"><?php echo lang('contractType'); ?></div>
<div class="col-lg-6"><?php if(isset($job->contractType)) echo $job->contractType; ?></div>
</div>
<div class="row job-detail-row">
<div class="col-lg-6 job-detail-label"><?php echo lang('num_vacancies'); ?> </div>
<div class="col-lg-6"><?php echo $job->positionsNum; ?></div>
</div>
<?php } ?>
my Controller's function:
public function job() {
$job_id = $this->uri->segment(3);
if(isset($job_id) && !empty($job_id))
{
//one job
$job = $this->job_model->load_job($this->GetLang, $job_id);
$data['job'] = $job;
$this->load->view( 'front/singleJob', $data);
}
}
Also, i printed the returned object and it returns this:
stdClass Object(
[id] => 9
[positionsNum] => 2
[companyName] =>
[contractType] => type1
)
But, contractType won't be printed in page even if it is already has a value.
I can't figure out the problem. Any help?

Answer 1

The problem is here.
you have a function with one parameter.
public function load_job($id);
but in controller you are passing two values.
Try to pass correct values.
$job = $this->job_model->load_job($this->GetLang, $job_id);
it should be like this.
$job = $this->job_model->load_job( $job_id);

Answer 2

try like this
public function job() {
$job_id = $this->uri->segment(3);
if(isset($job_id) && !empty($job_id))
{
//one job
$data['job'] = $this->job_model->load_job($this->GetLang, $job_id);
$this->load->view( 'front/singleJob', $data);
}
}

Answer 3

So, it is solved now :)
This problem happened twice in two files:
First is which stated in my question, and I had an error in another query at the same page.
Second problem was in the HTML file. My complete view was like this:
<?php if(isset($service) && count($service) > 0){ ?>
<div class="row job-detail-row">
<div class="col-lg-6 job-detail-label"><?php echo lang('contractType'); ?></div>
<div class="col-lg-6"><?php if(isset($service->contractType)) echo $service->contractType; ?></div>
</div>
<?php } ?>
<ul>
<?php foreach ($similarServices as $service) { ?> <<========= NOTICE: $service here is the same as the above condition
<li>
<div class="title"><?php echo $service->title; ?>
</div>
</li>
<?php }//end foreach similarServices ?>
</ul>
It appeared because i used the same variable name $service, so i changed it and it works now. Hope this helps you.