INSERT command is not being executed? [duplicate] - php

Question

This question already has answers here:
Why does this PDO statement silently fail?
(2 answers)
Closed 5 years ago.
Here is a snippet of my code:
$qry = '
INSERT INTO non-existant-table (id, score)
SELECT id, 40
FROM another-non-existant-table
WHERE description LIKE "%:search_string%"
AND available = "yes"
ON DUPLICATE KEY UPDATE score = score + 40
';
$sth = $this->pdo->prepare($qry);
$sth->execute($data);
print_r($this->pdo->errorInfo());
This should give me an error because the tables don't even exist. All I get however is this:
Array ( [0] => 00000 )
How can I get a better description of the error so I can debug the issue?

Answer 1

Try this instead:
print_r($sth->errorInfo());
Add this before your prepare:
$this->pdo->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING );
This will change the PDO error reporting type and cause it to emit a warning whenever there is a PDO error. It should help you track it down, although your errorInfo should have bet set.

Answer 2

Old thread, but maybe my answer will help someone. I resolved by executing the query first, then setting an errors variable, then checking if that errors variable array is empty. see simplified example:
$field1 = 'foo';
$field2 = 'bar';
$insert_QUERY = $db->prepare("INSERT INTO table bogus(field1, field2) VALUES (:field1, :field2)");
$insert_QUERY->bindParam(':field1', $field1);
$insert_QUERY->bindParam(':field2', $field2);
$insert_QUERY->execute();
$databaseErrors = $insert_QUERY->errorInfo();
if( !empty($databaseErrors) ){
$errorInfo = print_r($databaseErrors, true); # true flag returns val rather than print
$errorLogMsg = "error info: $errorInfo"; # do what you wish with this var, write to log file etc...
/*
$errorLogMsg will return something like:
error info:
Array(
[0] => 42000
[1] => 1064
[2] => You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'table bogus(field1, field2) VALUES ('bar', NULL)' at line 1
)
*/
} else {
# no SQL errors.
}

Answer 3

Maybe this post is too old but it may help as a suggestion for someone looking around on this :
Instead of using:
print_r($this->pdo->errorInfo());
Use PHP implode() function:
echo 'Error occurred:'.implode(":",$this->pdo->errorInfo());
This should print the error code, detailed error information etc. that you would usually get if you were using some SQL User interface.
Hope it helps

Answer 4

From the manual:
If the database server successfully
prepares the statement, PDO::prepare()
returns a PDOStatement object. If the
database server cannot successfully
prepare the statement, PDO::prepare()
returns FALSE or emits PDOException
(depending on error handling).
The prepare statement likely caused an error because the db would be unable to prepare the statement. Try testing for an error immediately after you prepare your query and before you execute it.
$qry = '
INSERT INTO non-existant-table (id, score)
SELECT id, 40
FROM another-non-existant-table
WHERE description LIKE "%:search_string%"
AND available = "yes"
ON DUPLICATE KEY UPDATE score = score + 40
';
$sth = $this->pdo->prepare($qry);
print_r($this->pdo->errorInfo());