In PHP i have array variable from another function like this
$v->params:
(
[{"username":"myusername","email":"myemail#gmail_com","phone":"0123456789","password":"abc123","fullname":"myfullname","register_ip":"127_0_0_1","country":"Qu\u1ed1c_Gia","birthday":"N\u0103m_sinh","gender":"male","bank_code":"Ng\u00e2n_h\u00e0ng","ip":"127_0_0_1","os":"Windows_10","device":"Computer","browser":"Mozilla_Firefox_77_0"}] =>
)
Now i want to access to it item, how can i code to access item value like this:
$password = $v->params->password; //myemail#gmail_com
I new with PHP thank you all
The data seems the wrong way round as it's the key of the array rather than a value.
So using array_keys()[0] to get the first key and then json_decode this...
$data = json_decode(array_keys($v->params)[0]);
you can then use the $data object to get at the values...
echo $data->username;
I am trying to make a php page tp print json data for this i m using one paraeter for which i needed to fetch json from another url.I used the code given in other stackoverflow ans but it always giving 0.I tried everything but it always giving 0.My php code is:
<?php
if(isset($_POST['add']))
{
require_once('loginConnect.php');
$bookname=$_POST['bookname'];
$url = "http://example/star_avg.php?bookName=$bookname";
$json = file_get_contents($url);
$json_data = json_decode($json,TRUE);
echo 'data' + $json_data->results[0]->{'num'};
?>
My json data from other url is:
{"result":[{"avg":"3.9","num":"3"}]}
You see 0 printed because you're performing an addition + between the string data and a non-existent property. In PHP, to concatenate strings, do not use +; instead, use the dot . operator
In addition, because you're using true as the 2nd parameter to json_decode, what you get back is an array of arrays. Use the array notation [] rather than the object notation -> to access members.
$json_data = json_decode($json,TRUE);
$num = $json_data['result'][0]['num']; //<- array notation
echo 'data: '.$num; //prints data: 3
Live demo
{"coord":{"lon":73.69,"lat":17.8},"sys":{"message":0.109,"country":"IN","sunrise":1393032482,"sunset":1393074559},"weather":[{"id":800,"main":"Clear","description":"Sky is Clear","icon":"01n"}],"base":"cmc stations","main":{"temp":293.999,"temp_min":293.999,"temp_max":293.999,"pressure":962.38,"sea_level":1025.86,"grnd_level":962.38,"humidity":78},"wind":{"speed":1.15,"deg":275.503},"clouds":{"all":0},"dt":1393077388,"id":1264491,"name":"Mahabaleshwar","cod":200}
I am trying to fetch description from the weather from the json above but getting errors in php. I have tried the below php code:
$jsonDecode = json_decode($contents, true);
$result=array();
foreach($jsonDecode as $data)
{
foreach($data{'weather'} as $data2)
{
echo $data2{'description'};
}
}
Any help is appreciated. I am new in using json.
You have to use square brackets ([]) for accessing array elements, not curly ones ({}).
Thus, your code should be changed to reflect these changes:
foreach($data['weather'] as $data2)
{
echo $data2['description'];
}
Also, your outer foreach loop will cause your code to do something completely different than you intend, you should just do this:
foreach($jsonDecode['weather'] as $data2)
{
echo $data2['description'];
}
Your $jsonDecode seems to be an array, so this should work-
foreach($jsonDecode['weather'] as $data)
{
echo $data['description'];
}
You can access data directly with scopes
$json = '{"coord":{"lon":73.69,"lat":17.8},"sys":{"message":0.109,"country":"IN","sunrise":1393032482,"sunset":1393074559},"weather":[{"id":800,"main":"Clear","description":"Sky is Clear","icon":"01n"}],"base":"cmc stations","main":{"temp":293.999,"temp_min":293.999,"temp_max":293.999,"pressure":962.38,"sea_level":1025.86,"grnd_level":962.38,"humidity":78},"wind":{"speed":1.15,"deg":275.503},"clouds":{"all":0},"dt":1393077388,"id":1264491,"name":"Mahabaleshwar","cod":200}';
$jsonDecode = json_decode($json, true);
echo $jsonDecode['weather'][0]['description'];
//output Sky is Clear
As you can see wheater` is surrounded with scopes so that means it is another array. You can loop throw that array if you have more than one result
foreach($jsonDecode['weather'] as $weather)
{
echo $weather['description'];
}
Live demo
If the result of decode is an array, use:
$data['weather']
If the result is an object, use:
$data->weather
you have to access "weather" with "[]" operator
like this,
$data["weather"]
There is several things worth answering in your question:
Q: What's the difference between json_decode($data) and json_decode($data, true)?
A: The former converts JSON object to a PHP object, the latter creates an associative array: http://uk1.php.net/json_decode
In either case, there is no point on iterating over the result. You probably want to access just the 'weather' field:
$o = json_decode($data) => use $weather = $o->weather
$a = json_decode($data, true) => use $weather = $a['weather']
Once you have the 'weather' field, look carefully what it is:
"weather":[{"id":800,"main":"Clear","description":"Sky is Clear","icon":"01n"}]
It's an array, containing a single object. That means you will either need to iterate over it, or use $clearSky = $weather[0]. In this case, it does not matter which approach of json_decode did you choose => JSON array is always decoded to a PHP (numeric indexed) array.
But, once you get $clearSky, you are accessing the object and it again matters, which approach you chose - use arrow or brackets, similarly to the first step.
So, the correct way to get for exaple the weather description would be either of these:
json_decode($data)->weather[0]->description
json_decode($data, true)['weather'][0]['description']
Note: In the latter case, dereferencing result of the function call is supported only in PHP 5.4 or newer. In PHP 5.3 or older, you have to create a variable.
Note: I also encourage you to always check if the expected fields are actually set in the result, using isset. Otherwise you will try to access undefined field, which raises an error.
I'm trying to decode the following JSON using php json_decode function.
[{"total_count":17}]
I think the square brackets in output is preventing it. How do I get around that? I can't control the output because it is coming from Facebook FQL query:
https://api.facebook.com/method/fql.query?format=json&query=SELECT%20total_count%20FROM%20link_stat%20WHERE%20url=%22http://www.apple.com%22
PHP's json_decode returns an instance of stdClass by default.
For you, it's probably easier to deal with array. You can force PHP to return arrays, as a second parameter to json_decode:
$var = json_decode('[{"total_count":17}]', true);
After that, you can access the variable as $result[0]['total_count']
See this JS fiddle for an example of how to read it:
http://jsfiddle.net/8V4qP/1
It's basically the same code for PHP, except you need to pass true as your second argument to json_decode to tell php you want to use it as associative arrays instead of actual objects:
<?php
$result = json_decode('[{"total_count":17}]', true);
print $result[0]['total_count'];
?>
if you don't pass true, you would have to access it like this: $result[0]->total_count because it is an array containing an object, not an array containing an array.
$json = "[{\"total_count\":17}]";
$arr = Jason_decode($json);
foreach ($arr as $obj) {
echo $obj->total_count . "<br>";
}
Or use json_decode($json, true) if you want associative arrays instead of objects.
I'm trying to output the value of the email value of an array, but have problems doing so.
The array is based on json_decode()
This is the error I receive
Fatal error: Cannot use object of type stdClass as array in /home/.... line 57
JSON (value of: $this->bck_content)
{"email":"test#email.com","membership_id":"0","fname":"Kenneth","lname":"Poulsen","userlevel":"1","created":"2012-04-23 10:57:45","lastlogin":"2012-04-23 10:58:52","active":"y"}
My code
# Display requested user details
$details_array = json_decode($this->bck_content);
$value = $details_array['email'];
print $value;
You need to use the second argument to json_decode to force array structures on JS objects.
json_decode($this->bck_content, true);
This will make sure all JS objects in the json are decoded as associative arrays instead of PHP StdObjects.
Of course that is assuming you want to use array notation to access them. If you're fine with using object notation then you can just use:
$value = $details_array->email;
try this one
$value = $details_array->email;
or
json_decode($json, true);
or
$details_array = (array)json_decode($json);
what have you done wrong is writen in error description