I need to get the number of rows of a studentID and then echo if the count is over 10.
This is what I wrote so far. But doesn't seem to work.
$findID = ID1231275;
$gipct = mysql_query("SELECT COUNT(studentID) FROM classFees WHERE studentID = '".$findID."'");
if ($gipct>10) {
echo ("$gipct");
}
$searchID = 'ID1231275';
$gipct = mysql_query("SELECT COUNT(studentID) as students FROM classFees WHERE studentID = '$searchID'");
$row = mysql_fetch_object($gipct);
if ($row->students >10) {
echo $row->students;
}
Btw, mysql_ functions are deprecated and can/will be removed in future versions of php, I recommend you to look at PDO statements or mysqli_ functions
$gipct is a mysql resource. So you have to use the function mysql_num_rows to get all rows that are selected.
Thats in your case not working because you have a COUNT in your query so you get only one row.
In your case you have to fetch the data first.
$gipct = mysql_query("SELECT COUNT(studentID) AS countout FROM classFees WHERE....");
$row = mysql_fetch_object($gpict);
if ($row->countout > 10) {
echo ("$gipct");
}
Or the method with the mysql_num_rows
$gipct = mysql_query("SELECT * FROM classFees WHERE student...");
if (mysql_num_rows($row) > 10) {
echo ("$gipct");
}
But here you select all records which can be much slower as the first solution.
If you are using php > 5 then you must use mysqli instead of mysql class. Then try this:
$db = new mysqli('localhost','user','pass','database');
$searchID = 'ID1231275';
$stmt = $db->prepare("SELECT COUNT(studentID) FROM classFees WHERE studentID =? ");
$stmt->bind_param('s', $searchID);
$stmt->execute();
$stmt->bind_result($gipct);
$stmt->fetch();
if ($gipct > 10) {
echo ($gipct);
}
Related
I want to check {if row exist} first and then fetch the results. here is my code:
$id = 102;
// connecting to database here
$sth = $dbh->prepare('SELECT * FROM users WHERE id = ?');
$sth->execute(array($id));
$num_rows = $sth->fetchColumn();
// if exist
if($num_rows){
// then fetch
while($end = $sth->fetch())
{
echo $end['id'];
}
}
But the output is blank, Why ?
It should be noted that the row with id = 102 is exist in the database.
As I understood, you have only one row with this ID. You can use fetch():
$id = 102;
// connecting to database here
$sth = $dbh->prepare('SELECT * FROM users WHERE id = ?');
$sth->execute(array($id));
$row = $sth->fetch();
// if record exist
if ($row) {
var_dump($row);
die();
}
PDO also have similar method rowCount but that would return effected rows in some cases.
Quoting from PHP Manual
For most databases, PDOStatement::rowCount() does not return the
number of rows affected by a SELECT statement. Instead, use
PDO::query() to issue a SELECT COUNT(*) statement with the same
predicates as your intended SELECT statement, then use
PDOStatement::fetchColumn() to retrieve the number of rows that will
be returned. Your application can then perform the correct action.
As suggested, you can query, count and proceed
$id = 102;
// connecting to database here
$sth = $dbh->prepare('SELECT COUNT(*) FROM users WHERE id = ?');
$sth->execute(array($id));
$num_rows = $sth->fetchColumn();
// if exist
if($num_rows > 0){
$sth = $dbh->prepare('SELECT * FROM users WHERE id = ?');
$sth->execute(array($id));
// then fetch
while($end = $sth->fetch())
{
echo $end['id'];
}
}
I'm in the process of updating my old mysql database techniques to prepared pdo statements. I'm all good with while loops while($row = $result->fetch()) however how would I do the following with PDO prepared statements?
$sql = "SELECT * FROM table WHERE id=".$id;
$result = mysql_query($sql) or die(mysql_error());
$loop_count = mysql_num_rows($result);
for($row=0;$row<7 && $loop_count-->0;$row++)
{
// Get next row
$loop_row = mysql_fetch_array($result);
echo $loop_row['field'];
}
I've tried this but with no joy:
$result = $conn->prepare("SELECT * FROM table WHERE id= ?");
$result->execute(array($id));
$loop_count = $result->rowCount();
for($row=0;$row<7 && $loop_count-->0;$row++)
{
// Get next row
$loop_row = $result->fetch();
echo $loop_row['field'];
}
Thanks!
UPDATE: The reason for using a for loop instead of a while loop is the ability to paginate the results, otherwise I would just put LIMIT 7 on the end of the SQL query.
To properly count rows with PDO you have to do this -
$result = $conn->prepare("SELECT * FROM table WHERE id= ?");
$result->execute(array($id));
$rows = $result->fetch(PDO::FETCH_NUM);
echo $rows[0];
But you would be better off using LIMIT in your query if all you want to do is get a static number of results.
In addition you're making your loop overly complex, there is no need to test for a range in the for condition just set the static number unless you're doing something weird, like possibly pagination.
You can try it this way:
$result = $conn->prepare("SELECT * FROM table WHERE id= ?");
$result->execute(array($id));
$loop_rows = $result->fetchAll();
$loop_count = count($loop_rows);
for($row=0;$row<7 && $loop_count-->0;$row++)
{
// Get next row
echo $loop_rows[$row]['field'];
}
As requested by the OP, here's an example of PDO prepared statements using LIMIT and OFFSET for pagination purposes. Please note i prefer to use bindValue() rather than passing parameters to execute(), but this is personal preference.
$pagesize = 7; //put this into a configuration file
$pagenumber = 3; // NOTE: ZERO BASED. First page is nr. 0.
//You get this from the $_REQUEST (aka: GET or POST)
$result = $conn->prepare("SELECT *
FROM table
WHERE id= :id
LIMIT :pagesize
OFFSET :offset");
$result->bindValue(':id', $id);
$result->bindValue(':pagesize', $pagesize);
$result->bindValue(':offset', $pagesize * $pagenumber);
$result->execute();
$rows = $result->fetchAll(PDO::FETCH_ASSOC);
This gives you the complete resultset of rows, limited to your required page. You need another query to calculate the total number of rows, of course.
What you could try is:
//Get your page number for example 2
$pagenum = 2;
//Calculate the offset
$offset = 7 * $pagenum;
//Create array
$data = array();
$result = $conn->prepare("SELECT * FROM table WHERE id= ? LIMIT 7 OFFSET ?");
$result->bind_param("ii", $id,$offset);
$result->execute();
$resultSet = $result->get_result();
while ($item = $resultSet->fetch_assoc())
{
$data[] = $item;
}
$result->close();
//echo resultSet you want
var_dump($data);
I have a table in my database named visitor_table . Within table i have a column named visitor_affiliate. I want to get the count of the rows when visitor_affiliate = "someurer" .
I want to get the count as number. I already have this code but i don't know how to get the count only for the rows containing the string. I currently get the number of all rows,
$result = mysql_query("SELECT * FROM visitor_table");
$num_rows = mysql_num_rows($result);
echo "$num_rows Rows\n";
You can ask MySQL to return the count:
SELECT COUNT(*) FROM visitor_table WHERE visitor_affiliate = 'someurer'
You shouldn't be using the ancient (deprecated as of PHP v5.5.0, soon to be removed entirely) MySQL extension for writing new code—use instead the improved MySQLi extension or the PDO abstraction layer, both of which enable you to pass variables to the database in a safe, parameterised, fashion that ensures they are not evaluated for SQL (and therefore prevents SQL injection attacks):
$dbh = new PDO("mysql:dbname=$dbname", $username, $password);
$dbh->setAttribute(PDO::ATTR_EMULATE_PREPARES, FALSE);
$qry = $dbh->prepare('
SELECT COUNT(*) FROM visitor_table WHERE visitor_affiliate = ?
');
$qry->execute(['someurer']);
echo $qry->fetchColumn(), ' rows';
$result = mysql_query("SELECT * FROM visitor_table WHERE `visitor_affiliate` = 'someurer'");
$num_rows = mysql_num_rows($result);
echo $num_rows . " Rows\n";
With what little information you have given just try this-
$result = mysql_query("SELECT * FROM visitor_table Where visitor_affiliate like '%someurer%'");
$num_rows = mysql_num_rows($result);
echo "$num_rows Rows\n";
The deprecated MySQL:
$res = mysql_query('SELECT * FROM visitor_table');
echo 'Number of rows:'.mysql_num_rows($res);
Procedural MySQLi:
$tu = mysqli_prepare($DBH,'SELECT * FROM visitor_table');
mysqli_execute($tu);
$num_rows = mysqli_num_rows($tu);
echo $num_rows.' rows\n';
mysql has been deprecated. Please use mysqli.
Using MySQLi bind_param to get your result:
$someuser = 'Dave';
$DBH = mysqli_connect('localhost','user','pass','database');
$query = mysqli_prepare($DBH,'SELECT * FROM visitor_table WHERE user = ?');
mysqli_bind_param($query,'s',$someuser);
mysqli_execute($query);
mysqli_bind_result($id,$user,$tabCol1,$tabCol2);
while(mysqli_fetch_result){
$row = $row +1;
echo $user.': was found in the record with ID of: '.$id;
}
echo 'total records found:'.$row;
That's one way of doing it as I'm not completely 100% sure about using a mysqli_num_row() with the query above.
This question already has an answer here:
Closed 10 years ago.
Possible Duplicate:
How do i “echo” a “Resource id #6” from a MySql response in PHP?
I am looking for the result out of a query, but it keeps giving me resource id #3.
The following is my code.
$type = "SELECT `sellingid` FROM `ticket` WHERE `ticketid` = $_GET[ticketid]";
$typeResult = mysql_query($type);
print_r($typeResult);
What step am I missing here?
You need to fetch the result. All you're doing is sending the query.
Be aware that if you are writing new code, you should use mysqli_ or PDO functions as your query is vulnerable to SQL injection and mysql_ functions are being deprecated. Hesitantly, below is a sample for mysql_fetch_assoc.
<?php
$sql = "SELECT `sellingid` FROM `ticket` WHERE `ticketid` = $_GET[ticketid]";
$result = mysql_query($sql);
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
// then create $userid, $fullname, and $userstatus
while ($row = mysql_fetch_assoc($result)) {
echo $row[sellingid];
}
mysql_free_result($result);
?>
Reference
$type = "SELECT `sellingid` FROM `ticket` WHERE `ticketid` = $_GET[ticketid]";
$typeResult = mysql_query($type);
$row = mysql_fetch_array($typeResult);
print_r($row);
More clear hint - use MySQLi class/functions, read this:
http://lt1.php.net/manual/en/mysqli-result.fetch-assoc.php
or if you like OOP approach more then
http://lt1.php.net/manual/en/mysqli-result.fetch-object.php
You are not actually fetching the results of your query. Below are two examples that use WHILE loops to fetch the results as rows. You can then grab the column values and work with them.
Incorrect and depreciated method, but working:
$type = "SELECT `sellingid` FROM `ticket` WHERE `ticketid` = $_GET[ticketid]";
$typeResult = mysql_query($type);
// for each row
while ($row = mysql_fetch_array($typeResult)) {
// grab the columns
$value = $row['column_name'];
}
I would recommend using MySQLi or PDO like to following (MySQLi):
$mysqli_connection = new mysqli("hostname", "username", "password", "database");
$type = "SELECT `sellingid` FROM `ticket` WHERE `ticketid` = $_GET[ticketid]";
$res = $mysqli_connection->query($type);
while($row = $res->fetch_array(MYSQLI_ASSOC)) {
$value = $row['column_name'];
}
$res->free();
$mysqli_connection->close();
I am trying to get pagination working on my website. Everything should be working but this only displays one product, however that should be 8 products. Anybody know what's wrong?
Thanks in advance.
else {
$query = "SELECT COUNT(*) FROM products";
$result = mysql_query($query) or die(mysql_error());
$num_rows = mysql_fetch_row($result);
$pages = new Paginator;
$pages->items_total = $num_rows[0];
$pages->mid_range = 9;
$pages->paginate();
$query = "SELECT serial, name, description, price, picture FROM products WHERE serial != '' ORDER BY serial ASC $pages->limit";
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_row($result);
{
echo '<div style="margin-bottom:10px;display:inline-block;background-color:#E3E3E3;width:190px;height:200px;"><img style="padding-top:10px;padding-left:25px;width:150px;height:150px;" src="'.htmlspecialchars($row[4]).'"><br><div align="center"><b>'.htmlspecialchars($row[1]).'</b><br><h6>€'.htmlspecialchars($row[3]).'</h6></div></div>';
};
echo ' ';
echo '<br><br><div style="margin-left:330px;">';
echo $pages->display_pages();
echo '</div>';
}
?>
mysql_fetch_row() only fetches one row at a time. You need to call it repeatedly to display all rows, like this:
while ($row = mysql_fetch_row($result)) {
// handle single row
}
I suggest you consider using mysql_fetch_array() instead. Then you will not have to rely on the order of the columns anymore and your code becomes more legible:
$row[0] becomes $row["serial"] etc.
Try reading the articles that #Kush linked. See here for a PHP-specific discussion.
You do not seem to be using mysql_fetch_row() properly
The following code is vulnerable to SQL injection because $page->limit does not appear to be sanitized
$query = "SELECT serial, name, description, price, picture FROM products WHERE serial != '' ORDER BY serial ASC $pages->limit";
Stop using mysql_* functions as they're deprecated. Use PHP database objects (PDO) instead because PDO allows parameter binding which protects you from sql injection.
You can read up on using PDO here
because of this line
$row = mysql_fetch_row($result);
should be
while($row = mysql_fetch_row($result)){...
Change the line
$row = mysql_fetch_row($result);
to
while ($row = mysql_fetch_row($result))