Add multiple arrays in single table - php

Question

<table border="2">
<?php
foreach($array1 as $value)
{
echo '<tr><td>';
echo $value;
echo '</td></tr>';
}
?>
</table>
I have more array: array2,array3.
The above code only executes values of array1 but I want all the values of all array in the same table in separate columns!
array1 | array2 | array3
------------------------
| |
| |
| |
| |
I want something like this...
I tried modifying the code but no idea how to do it correctly.
$data = mysql_query(" SELECT * FROM user_pokemon_db WHERE user_id = '".$id."' ");
while($rows = mysql_fetch_assoc($data)) {
$db_id = $rows['id'];
$array[] = $db_id;
$level = $rows['level'];
$array1[] = $level;
$exp = $rows['exp'];
$array2[] = $exp;
$pkmn_id = $rows['pkmn_id'];
$data1 = mysql_query(" SELECT * FROM pokemons WHERE pk_id = '".$pkmn_id."' ");
while($rows = mysql_fetch_assoc($data1)) {
$poke = $rows['path']; $array3[] = $poke;
}
}
The above code fetches data from database and adds it to different arrays!

Answer 1

When you create your array, you don't specify keys, so they are generated automaticaly. So you can work on keys for your for loop instead of using a foreach in values:
We can see in your code that $array3 is longuer than the others. So we will base on it:
foreach($array3 as $key => $value)
{
if (isset($array1[$key])){
echo '<tr><td>'.$array1[$key].'</td>';
}else{
echo '<tr><td></td>';
}
if (isset($array2[$key])){
echo '<td>'.$array2[$key].'</td>';
}else{
echo '<td></td>';
}
echo '<td>'.$array3[$key].'</td></tr>';
}
It should work

Answer 2

try making a function that calls itself in the end. not sure if I got the syntax right here, but this should work.
$i = 0;
function test($i){
if($i < ar1.lenght && $i < ar2.lenght && $i< ar3.lenght){
echo "<tr><td>";
echo ar1[$i];
echo "</td><td>";
echo ar2[$i];
echo "</td><td>";
echo ar3[$i];
echo "</td></tr>";
$i++;
//calls itself with an incremented $i
test($i);
}//else do nothing.
}
--edit forgot some tags