I'm struggling to calculate time difference between two 24 hour format. The data extracted from my database is like this:
$timein = "09:00";
$timeout = "17:00";
$timediff = $timein - $timeout
As above, how do I get the $timediff = 8?
$timediff = date("H",strtotime($timein) - strtotime($timeout));
You can also change to format of the result,
check: http://php.net/manual/en/function.date.php
If you first set them to full dates:
$timein = "09:00";
$timeout = "17:00";
$datein = strtotime(date("Y-m-d ".$timein);
$dateout = strtotime(date("Y-m-d ".$timeout);
So, in fact the date you are using (todays date) can be any other date given since it's all about the time between the hours. Then you can create the php date function:
$hourIn = date("G", $datein); // = 9
$hourOut = date("G", $dateout); // = 17
Followed by simple math:
$diff = $hourOut - $hourIn; // = 8
You can use strtotime() for time calculation.
$timein = strtotime('09:00');
$timeout = strtotime('17:00');
$timediff = $timein - $timeout;
echo 'Time: '.date('H:i:s', $timediff);
Break the problem down into two steps.
Convert each time into a number of seconds since midnight.
Calculate the difference between two times.
This breaks the larger problem down into basic problems which can be solved more easily. It is a very valuable tool in the programmer's belt.
For the second part, be sure to handle midnight the way you need to for your data. Perhaps if the timeout is before the timein, then you'll need to add 24 hours to the total? That's just a guess, because I do not know your data.
Related
I'm trying to calculate the number of hours a person has worked on a given day. To do so, I need to get the difference between two DateTime objects in Hours, Minutes, and Seconds. So far I can successfully do so like this
$timeIn = new DateTime($time['timeIn']);
$timeOut = new DateTime($time['timeOut']);
$time['hours'] = date_diff($timeIn, $timeOut) -> format("%H:%i:%s");
This seems to work fine, until I put in a test case where the employee forgot to clock out. Now, let's say that
$timeIn = '2016-09-28 14:26:17'
$timeOut = '2016-09-30 09:53:53'
In that case, the difference SHOULD be 43:27:36 (Because there is over a day in between the timeIn and timeOut). Instead, I get 19:27:36 (as if it's just truncating the days off and returning the rest). How can I add that day onto the hours instead of truncating it? (I'm looking to get 43:27:36, NOT 1day, 19 hours, ect ect. So I'm trying to get the answer in HH:MM:SS)
As Scott suggested but with a tweak, we'll need to format this ourselves, but we have nifty sprintf to help:
$start = new \DateTime("2016-09-28 14:26:17");
$end = new \DateTime("2016-09-30 09:53:53");
$interval = $end->diff($start);
$time = sprintf(
'%d:%02d:%02d',
($interval->d * 24) + $interval->h,
$interval->i,
$interval->s
);
I prefer using the \DateTime objects - although there shouldn't be much of a difference in the end date_diff is just an alias of \DateTime::diff.
You want to check the number of days in the DateInterval object;
$start = new \DateTime("2016-09-28 14:26:17");
$end = new \DateTime("2016-09-30 09:53:53");
$interval = $end->diff($start);
$days = $interval->d;
if ($days > 0) {
echo $interval->format("%a %h:%i:%s\n");
} else {
echo $interval->format("%h:%i:%s\n");
}
date_diff() returns a DateInterval instance. Look at DateInterval::format method or DateInterval::days field. Hour, minute and second values refer to the remainder in the last day (if more than one). You are looking for a the total number of days.
$timeIn = new DateTime($time['timeIn']);
$timeOut = new DateTime($time['timeOut']);
$diff = date_diff($timeIn, $timeOut) -> format("%H:%i:%s");
$days = $diff->days;
$time['hours'] = // calculate based on days + remainder...
Hello I try to take the difference between two dates and display it.
My problem is that the time difference I get is not the correct one.
This is my code:
$time1 = strtotime('2014-03-28 15:20:00');
$time2 = strtotime('2014-03-28 15:15:00');
$diffTime = $time1 - $time2;
echo date('H:i', $diffTime);
The result I get is:
02:05
The currect time should be this:
00:05
My guess that the date somehow takes timezone or something like this but Im not sure.
Thanks.
/****************************************
$start_date = new DateTime('23:58:40'); *These two still give
$end_date = new DateTime('00:00:00'); *a wrong answer
*****************************************/
$start_date = new DateTime('23:58:40');
$end_date = new DateTime('00:11:36');
$dd = date_diff($end_date, $start_date);
//Giving a wrong answer: Hours = 23, Minutes = 47, Seconds = 4
echo "Hours = $dd->h, Minutes = $dd->i, Seconds = $dd->s";
So what you're actually doing here is generating two UNIX timestamps (numbers) and then subtracting them. then you're passing the resulting number as if it were still a timestamp to date().
essentially $diffTime is the number of seconds between your two times. you could divide by 60 to get minutes, and so on and so forth, but PHPs DateTime objects are much better.
From the PHP docs:
http://pl1.php.net/strtotime
Note:
Using this function for mathematical operations is not advisable. It is better to use DateTime::add() and DateTime::sub() in PHP 5.3 and later, or DateTime::modify() in PHP 5.2.
try this
<?php
$time1 = strtotime('2014-03-28 15:20:00');
$time2 = strtotime('2014-03-28 15:15:00');
echo round(abs($time1 - $time2) / 60,2). " minute"
?>
Below is the solution of date time in years,days.hours,minutes and seconds.
$time1 = strtotime('2014-03-28 15:20:00');
$time2 = strtotime('2014-03-28 15:15:00');
$diffTime = $time1 - $time2;
$y = ($diffTime/(60*60*24*365));
$d = ($diffTime/(60*60*24))%365;
$h = ($diffTime/(60*60))%24;
$m = ($diffTime/60)%60;
$s = ($diffTime)%60;
echo "Minutes - " .$m;
echo "<br/>";
i tried most of what is available on stack overflow but none seem to work.
any way i am trying to compare two (date and time formats). and calculate whether their difference is within 5 seconds of each other
the first date is the current date:
$today = date("Y-m-d H:i:s");
the second date is taken from mysql database:
$result = mysql_query("SELECT * FROM BUS_DATA where BusRegID = 'bus'") or die(mysql_error());
$row = mysql_fetch_array($result);
$update_date = $row["update_date"];
the answer should be segmented into years , month , days , hours , minutes ,and seconds portions.
I am running PHP Version 5.3.3
Edit: most answers give result in time frame only , I want to check whether the date matches , then compare if the time of the day is within 5 seconds , than you guys in advance :)
Try this
function getTimes($t1, $t2)
{
$timeFirst = strtotime($t1);
$timeSecond = strtotime($t2);
$differenceInSeconds = $timeSecond - $timeFirst;
$h=0;
$m = floor($differenceInSeconds / 60);
$s = $differenceInSeconds % 60;
if ($m>=60)
{
$h = floor($m / 60);
$m = $m % 60;
}
$tim = $h.':'.$m.':'.$s;
return $tim;
}
it will return difference time in hours:min:sec
use strtotime, it's understands almost any date formats:
$timeDiff = abs(strtotime($today) - strtotime($update_date));
this gives you the difference between dates in seconds.
If you want to know whether it's within 5 seconds then use Timestamps, makes it into a simple int calculation.
$now = time();
$test = strtotime($update_date);
if($now - $test > 5) {
//NOT WITHIN 5 SECONDS
}
I have been looking for an answer for a few hours now, but I can't find one.
I'm writing a simple script. The user sets their work start and end time. So, for example, somebody is working from 8:00 to 16:00.
How can I subtract this time to see how long the person has been working?
I was experimenting with strtotime(); but without success...
A bit nicer is the following:
$a = new DateTime('08:00');
$b = new DateTime('16:00');
$interval = $a->diff($b);
echo $interval->format("%H");
That will give you the difference in hours.
If you get valid date strings, you can use this:
$workingHours = (strtotime($end) - strtotime($start)) / 3600;
This will give you the hours a person has been working.
Another solution would be to go through the Unix-timestamp integer value difference (in seconds).
<?php
$start = strtotime('10-09-2019 12:01:00');
$end = strtotime('12-09-2019 13:16:00');
$hours = intval(($end - $start)/3600);
echo $hours.' hours'; //in hours
//If you want it in minutes, you can divide the difference by 60 instead
$mins = (int)(($end - $start) / 60);
echo $mins.' minutues'.'<br>';
?>
This solution would be a better one if your original dates are stored in Unix-timestamp format.
My friend and I are working on a fairly basic uptime script for an IRC Bot.
Here's our code:
function Uptime()
{
global $uptimeStart;
$currentTime = time();
$uptime = $currentTime - $uptimeStart;
$this->sendIRC("PRIVMSG {$this->ircChannel} :Uptime: ".date("z",$uptime)." Day(s) - ".date("H:i:s",$uptime));
}
$uptimeStart is set immediately when the script runs, as time();
for some reason when I execute this function, it starts at 364 days and 19 hours. I can't figure out why.
Your $uptime is not a timestamp as should be used in date(), but a difference in time. You have an amount of seconds there, not a timestamp (that corresponds with an actual date.
just use something like this to cacluate (quick one, put some extra brain in for things like 1 day, 2 hours etc) ;)
$minutes = $uptime / 60;
$hours = $minuts/60 ;
$days = $hours / 24
etc
If you have 5.3 or above, use the DateTime and DateInterval classes:
$uptimeStart = new DateTime(); //at the beginning of your script
function Uptime() {
global $uptimeStart;
$end = new DateTime();
$diff = $uptimeStart->diff($end);
return $diff->format("%a days %H:%i:%s");
}
You won't get anything meaninful by calling date() on that time difference. You should take that time difference and progressively divide with years, months, days, hours, all measured in seconds. That way you'll get what the time difference in those terms.
$daySeconds = 86400 ;
$monthSeconds = 86400 * 30 ;
$yearSeconds = 86400 * 365 ;
$years = $uptime / $yearSeconds ;
$yearsRemaining = $uptime % $yearSeconds ;
$months = $yearsRemaining / $monthSeconds ;
$monthsRemaining = $yearsRemaining % $monthSeconds ;
$days = $monthsRemaining / $daySeconds ;
.. etc to get hours and minutes.
date() function with second argument set to 0 will actually return you (zero-date + (your time zone)), where "zero-date" is "00:00:00 1970-01-01". Looks like your timezone is UTC-5, so you get (365 days 24 hours) - (5 hours) = (364 days 19 hours)
Also, date() function is not the best way to show the difference between two dates. See other answers - there are are already posted good ways to calculate difference between years