MySQL UPDATE statement is not updating database data through web form - php

Scenario: I have a web form where the user can manually enter data (see below). The user will submit the form and the data will be automatically added to the database.
date, order_ref, first_name, last_name, postcode, country, quantity, scott_packing, packing_price, courier_price, dispatch_type, job_status
On another page, the user will be able to only view all the jobs that are currently being (this data is taken from the database) processed and add the tracking number and edit the packing_price,courier_price and job_status and submit the new data.
http://i754.photobucket.com/albums/xx182/rache_R/Screenshot2014-04-23at104045_zps2a628d50.png
Issue: When the user clicks the 'submit all' button, the user is supposed to be redirected to the thank you page which simply notifies the user that their entry has been successful however at the moment, the user is only directed to a blank page which contains the navigation menu. I have checked the database to see if the data has been updated but nothing has changed. How do i get my update statement to work so that the user can update the existing jobs?
This is the code for the page that displays all the jobs:
<?
session_start();
if(!session_is_registered(myusername))
{
header("location:../index.php");
}
include("../template/header.php");
include("../controllers/cn.php");
$sql = "SELECT * FROM Jobs";
$qry = mysql_query($sql);
echo "<div class='content'>";
echo "<form class='form_edit' method='post' action='updatejob.php'>";
echo "<table id='job_list' cellpadding='0' cellspacing='0'>
<tr>
<th>Job No</th>
<th>Date</th>
<th>Qty</th>
<th>Postcode</th>
<th>Country</th>
<th>Packed by Scott</th>
<th>Packing Price</th>
<th>Courier Price</th>
<th>Tracking No</th>
<th>Dispatch Type</th>
<th>Job Status</th>
</tr>";
while($row = mysql_fetch_array($qry))
{
echo "<tr>";
echo "<td width='80' style='text-align: center;'>" . $row['order_ref'] . "</td>";
echo "<td width='100' style='text-align: center;'>" . $row['date'] . "</td>";
echo "<td width='100' style='text-align: center;'>" . $row['quantity'] . "</td>";
echo "<td width='100' style='text-align: center;'>" . $row['postcode'] . "</td>";
echo "<td width='100' style='text-align: center;'>" . $row['country'] . "</td>";
echo "<td width='100' style='text-align: center;'><input type='CHECKBOX' id='scott_packing' name='scott_packing' value='". $row['scott_packing'] . "'></td>";
echo "<td width='100' style='text-align: center;'><input type='text' id='packing_price' name='packing_price' value='". $row['packing_price'] . "'/></td>";
echo "<td width='100' style='text-align: center;'><input type='text' id='courier_price' name='courier_price' value='". $row['courier_price']."'/></td>";
echo "<td width='100' style='text-align: center;'><input type='text' id='tracking_number' name='tracking_number' value='". $row['tracking_number'] . "'/></td>";
echo "<td width='100' style='text-align: center;'>" . $row['dispatch_type'] . "</td>";
echo "<td width='100' style='text-align: center;'><select name='job_status' id='job_status'>
<option value='". $row['job_status'] ."'>". $row['job_status']. " <option value='dispatched'>Dispatched</td>";
//echo "<td width='100' style='text-align: center;'><a href='editjob.php'>edit</td>";
echo "</tr>";
}
echo "</table>";
echo "<input type='submit' name='submit' value='submit all'/>";
echo "</form>";
mysql_close();
?>
And here is the code that is supposed to update the data:
<?
session_start();
if(!session_is_registered(myusername)){
header("location:../index.php");
}
include("../template/header.php");
include("../controllers/cn.php");
if (isset($_POST['submit']))
{
$order_ref = $_POST['order_ref'];
$packing_price = $_POST['packing_price'];
$courier_price = $_POST['courier_price'];
$tracking_number = $_POST['tracking_number'];
$job_status = $_POST['job_status'];
$sql_qry = "UPDATE Jobs SET '$packing_price, $courier_price, $tracking_number, $job_status' WHERE order_ref = '$order_ref'";
$query = mysql_query($sql_query);
if(!$query)
{
die('Could not update data' .mysql_error());
} else
{
header("location: updatesuccess.php");
exit;
}
mysql_close();
}
?>

Your update query is wrong. The query of update should be like
UPDATE table_name SET field1=new-value1, field2=new-value2
[WHERE Clause]
In this case it will be something like
UPDATE Jobs SET packing_price='$packing_price',courier_price='$courier_price',tracking_number='$tracking_number',job_status='job_status' WHERE order_ref = '$order_ref'";
and also you missed out the name property for input fields. If you don't specify it you can't access it like $_POST['packing_price'] where packing_price is be the name of the input field.
Also add method="post" to the form like
echo "<form class='form_edit' action='updatejob.php' method='post'>";

Try with this query
$sql_qry = "UPDATE Jobs SET column1 = '$packing_price', column2 ='$courier_price', .... WHERE order_ref = '$order_ref'";
And like Roland Jansen stated you are missing the name attributes on your input tags

Related

Multiple delete through checkout

I am stuck in one of my application module. I have to set multiple delete options in my application.
I have used the below code. The designing is perfectly fine. All what I want to add multiple delete options in it.
Below is the code which I have tried out:
<html>
<head>
<title>Strad Hosting Limited -Web Hosting</title>
<script language="javascript">
function validate()
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var chks = document.getElementsByName('checkbox[]');
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if (chks[i].checked)
{
hasChecked = true;
break;
}
}
if (hasChecked == false)
{
alert("Please select at least one.");
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}
return true;
}
</script>
</head>
<body >
<?php
$con=mysqli_connect("localhost","stradsol","D#v,b5TnQ!D!","stradsol_sales");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<form name='form1' method='post' action='' onSubmit='return validate();'>";
echo "<table border='1' style='
background-color: white;'>
<tr>
<th></th>
<th>id</th>
<th style='padding-left: 11px;'>Lead Generated Date </th>
<th>name</th>
<th>email</th>
<th>contacts</th>
<th>requirement</th>
<th style='display:none;'>Company name</th>
<th style='display:none;'>Address</th>
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<th>Final_Details</th>
<th style='display:none;'>Status</th>
<th style='padding-left: 12px; display:none;'>Lead Closed Date</th>
<th>EDIT</th>
<th>Follow-up History</th>
<th>Add Follow-up</th>
<th>Delete Record</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td><input name='checkbox[]' type='checkbox' id='checkbox[]' value='".$rows['id']."'></td>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td><a href='config_info.php?id=" . $row['id'] . "'>".$row['name']."</a></td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['contacts'] . "</td>";
echo "<td>" . $row['requirement'] . "</td>";
echo "<td style='display:none;'>" . $row['company_name'] . "</td>";
echo "<td style='display:none;'>" . $row['address'] . "</td>";
echo "<td>" . $row['startdate'] . "</td>";
echo "<td>" . $row['final_details'] . "</td>";
echo "<td style='display:none;'>" . $row['status'] . "</td>";
echo "<td style='display:none;'>" . $row['lead_close'] . "</td>";
echo "<td><a href='edit_eg1.php?id=" . $row['id'] . "'>Edit</a></td>";
echo "<td><a href='Follow_history.php?id=" . $row['id'] . "'>Follow_history</a></td>";
echo "<td><a href='add_follow.php?id=" . $row['id'] . "'>Followup</a></td>";
echo "<td><a href='delete.php?id=" . $row['id'] . "'>Delete</a></td>";
echo "</tr>";
}
echo "<tr><td><input name='delete' type='submit' id='delete' value='Delete'></td></tr>";
$count=mysqli_num_rows($result);
if(isset($_POST['delete'])){
for($i=0;$i<count($_POST['checkbox']);$i++){
$del_id=$_POST['checkbox'][$i];
$sql = "DELETE FROM Persons WHERE id='$del_id'";
echo $sql;
$result2 = mysqli_query($con,$sql);
}
// if successful redirect to delete_multiple.php
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echo "<meta http-equiv=\"refresh\" content=\"0;URL=edit_table_del.php\">";
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}
mysqli_close($con);
echo "</table>";
echo "</form>";
?>
<br><br>
[ Back To Home ]
</body>
</html>
I am stuck, the query is not working I think. I don't know what I am missing.
Try replacing
$sql = "DELETE FROM Persons WHERE id='$del_id'";
With
$sql = "DELETE FROM Persons WHERE id=$del_id";
I'm assuming the ID is a number so the single quotes aren't needed.

trying to retrieve name from current data selected

t
I have data shown about a band that matches a id selected, im then using the band_id and getting it to use it else where.
I would like to do the same with Name field but I am having a few problems, its just getting the word array in to the var $name.
code
<?php
require 'core/init.php';
$Band_id = $_GET['id'];
$name = ['Name']; // trying to get the band name
$result = mysql_query("SELECT * FROM bands WHERE Band_id = $Band_id");
echo "<table border = '1'>
<tr>
<th>Band Name</th>
<th>Venue</th>
<th>Category</th>
<th>Stock</th>
<th>Buy Ticket</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr><form name=\"myform\" action=\" order.php\" method=\"post\">";
echo " <input name=\"band\" type=\"hidden\" value=\"". $Band_id."\" >";
echo " <input name=\"bandn\" type=\"hidden\" value=\"". $name."\" >";
echo "<td>" .$row['Name']. "</td>";
echo "<td>" .$row['Venue']. "</td>";
echo "<td>" .$row['Category']. "</td>";
echo "<td>" .$row['Stock']. "</td>";
echo "<td><button>Buy Ticket</button></td>";
echo "</tr> </form>";
}
echo "</table>";
?>
$name = ['Name'] wont work above the query, and generally wont work at all as its invalid syntax for what you're trying to do. Where you have used $name use $row['Name']

Pulling in data from MySQL and breaking it up between pages

I have working code that brings in data from my database as follows:
require("database.php");
$result = mysqli_query($con,"SELECT * FROM menuitem");
echo "<table width='1024' border='0' cellpadding='10' cellspacing='5' align='center'>
<tr>
<th></th>
<th>Menu Items</th>
<th>Description</th>
<th>Price</th>
<th>Add to Order</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td align='center'><img src=\"" . $row['picturepath'] . "\" /></td>";
echo "<td align='center'>" . $row['name'] . "</td> <td align='center'> <input type='button' value='More Info'; onclick=\"window.location='more_info.php?';\"> </td>";
echo "<td align='center'>" . $row['price'] . "</td> <td align='center'> <input type='button' value='Add to Order' onclick=''> </td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
However, the columns that I am calling have over 20 items. I want to limit the amount of items the page displays to 4 items per page, and then create multiple pages listing the remaining items in the database.
So far I have tried adding in the if then statement, but that didn't work very well. I'm not sure if that is even the correct way to go about it.
SELECT * FROM menuitem LIMIT $startPositionVariable,$howManyItemsPerPageVariable
a separate query should determine how many total entries there are to begin with and determine how many pages accordingly.

show checkbox data mysql

I am having some minor errors and was wondering if anyone could help!
I am creating a attendance system for a college.
This Scenario:
Student logs in successfully and then wants to view his/her attendance for a particular course.
Problem: I want it to show me both checked and uncheked data from mysql, it currently shows an empty checkbox (when its meant to be checked) also at the moment it is showing numerous duplicated data, is it possible i could limit that, say for example show one record per week , it shows all data and duplicates it.
<?php
$q3= "SELECT attendance.week_number_id, attendance.week_number, courses.course_id, students.student_id, course_attendance.present, course_attendance.notes
FROM courses, course_attendance, attendance, students
WHERE course_attendance.student_id= ".$_SESSION['student_id']." AND course_attendance.course_id= courses.course_id AND course_attendance.week_id= attendance.week_number_id AND courses.course_id='101'
";
$result = mysql_query($q3) or die(mysql_error());
echo "<table border='1' align='center'><tr> <th><strong>Week Number</strong></th> <th><strong>Present</strong></th> <th><strong>Notes</strong></th> </tr> ";
while($row = mysql_fetch_assoc($result))
{
extract($row);
echo
"</td><td width='200' align='center'>" .$row['week_number'].
"</td><td width='400' align='center'><input type='checkbox' name='present'" .$row['present'].
"</td><td width='400' align='center'>" .$row['notes'].
"</td><tr>";
}
echo "</table>";
?>
Note: I am connected successfully to database, mysql is up and running, i am using sessions, currently it does show data for the student but does not show the existing checked or uncheked value, the checkbox is empty.
Can anyone help
In your code, you're not properly defining the checkbox to be checked. Make a code that adds checked="true" if the 'present' field is 1.
<?php
$q3 = " SELECT attendance.week_number_id, attendance.week_number, courses.course_id, students.student_id, course_attendance.present, course_attendance.notes
FROM courses, course_attendance, attendance, students
WHERE course_attendance.student_id= ".$_SESSION['student_id']." AND course_attendance.course_id= courses.course_id AND course_attendance.week_id= attendance.week_number_id AND courses.course_id='101'";
$result = mysql_query($q3) or die(mysql_error());
echo "
<table border='1' align='center'>
<tr>
<th><strong>Week Number</strong></th>
<th><strong>Present</strong></th>
<th><strong>Notes</strong></th>
</tr>
";
while($row = mysql_fetch_assoc($result)) {
$checked = '';
if($row['present'] == 1) {
$checked = ' checked="true"';
}
echo "
<tr>
<td width='200' align='center'>" . $row['week_number'] . "</td>
<td width='400' align='center'>
<input type='checkbox' name='present'" .$checked . "/>
</td>
<td width='400' align='center'>" . $row['notes'] . "</td>
</tr>
";
}
echo "</table>";
?>
Your
echo
"</td><td width='200' align='center'>" .$row['week_number'].
"</td><td width='400' align='center'><input type='checkbox' name='present'" .$row['present'].
"</td><td width='400' align='center'>" .$row['notes'].
"</td><tr>";
statement should be
$present = "";
if(.$row['present']==1)
{
$present = "checked =checked/>";
}
else
{
$present = "/>";
}
echo
"" .$row['week_number'].
"" .$row['notes'].
"";
Hope this helps you. Thanks
$checked = '';
if($present == 1) {
$checked = 'checked="checked"';
}
echo "</td><td width='200' align='center'>" .$row['week_number'].
"</td><td width='400' align='center'><input type='checkbox' name='present'" .$checked . "/>" .
"</td><td width='400' align='center'>" .$row['notes'].
"</td><tr>";
}
echo "</table>";
Try.

Posting from a form in a table

I am trying to retrieve records from db and put them into a table. I want to have an update button which can do some processing. Here is the code. It outputs properly. However the update button (image) doesn't work. Please help
<?php
echo "</br>";
echo "<table border='1'>
<tr>
<th>Order ID</th>
<th>Customer Number</th>
<th>Order Items</th>
<th>Transaction Time</th>
<th>Amount</th>
</tr>";
$con = mysql_connect('localhost', 'root', '');
if (!$con)
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die('Could not connect: ' . mysql_error());
}
mysql_select_db("kaka", $con);
$sql="SELECT * FROM orders WHERE status = 'NRDY'";
$result2 = mysql_query($sql);
while($row1 = mysql_fetch_array($result2))
{
echo "<div class=\"update\"><form method='post' action=\"test.php\">\n";
echo "<tr>";
echo "<td><input type='hidden' name='order_id' value='".$row1['order_id']."'>" .$row1['order_id']. "</td>";
echo "<td><input type='hidden' name='cust_num' value='".$row1['cust_num']."'>" .$row1['cust_num']. "</td>";
echo "<td><input type='hidden' name='items' value='".$row1['items']."'>" .$row1['items']. "</td>";
echo "<td><input type='hidden' name='order_time' value='".$row1['order_time']."'>" .$row1['order_time']. "</td>";
echo "<td><input type='hidden' name='order_id' value='".$row1['amount']."'>" .$row1['amount']. "</td>";
//echo "<td>" . $row1['order_id'] . "</td>";
//echo "<td>" . $row1['cust_num'] . "</td>";
//echo "<td>" . $row1['items'] . "</td>";
//echo "<td>" . $row1['order_time'] . "</td>";
//echo "<td>" . $row1['amount'] . "</td>";
echo "<td>" . "<input type=\"image\" src=\"images/update.png\" alt=\"Update Row\" class=\"update\" title=\"Update Row\">\n" . "</td>";
echo "</tr>";
echo "</form></div>";
}
echo "</table>";
?>
Here is test.php
<?php
echo $_POST['order_id'];
?>
Use a validator. You aren't allowed to wrap divs or forms around table rows. Some browsers recover from this error by moving the div/form so it is outside the table (leaving the content behind). Your inputs are therefore not inside a form so shouldn't be expected to do anything.

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