I have a problem.
I have a certain date/time (A), which is put in a variable. Lets say its May 06 2014 14:26.
I want to compare this date/time with file's modification date/time (B), and if it is the same, I put the file's modification date/time (B) in variable too.
The thing is, I cant get exactly the same date on file (B). So, I want that it would add 5 minutes difference. For example, if file (B) has modification date May 06 2014 14:28, it will be put in a variable. Or if it has modification date May 06 2014 14:22, it will be put in a variable too.
If it helps, I am using date("F d Y H:i",$file['filetime']) command to get the modification date of the file.
Any possibility to do this? Thanks in advance.
If something is unclear, just tell me. I'm new here, so might be hard to explain things correctly.
Maybe, it helps:
$datetimeA = strtotime($file1['filetime']);
$datetimeB = strtotime($file2['filetime']);
$interval = abs($datetimeA - $datetimeB);
$minutes = round($interval / 60);
if ($minutes > 5) {
//do some magic here
}
If $file['filetime'] is a timestamp already, then You can use it without calling strtotime().
With the DateTime class, it is done in a few lines :
$datetime1 = new DateTime('2009-10-13 10:00:00');
$datetime2 = new DateTime('2009-10-13 10:20:00');
$interval = $datetime1->diff($datetime2);
$yourIntervalle = $interval->format('%i minutes'));
i'd either directly use unix-timestamps or convert A and B to Unix Timestamps (e.g. using strtotime) and compare them based on your requirements.
if you have access to the file directly you could even use filemtime to directly get the last modified time as an unix timestamp.
Guess this is what you're looking for, if your problem is just to add 5 minutes:
$dateB = new DateTime('2014-05-06 14:26:00');
$interval = new DateInterval('PT5M');
$dateB->add($interval);
print_r($dateB);
PHPSandbox: http://sandbox.onlinephpfunctions.com/code/9f9a2ee40f09f953c796c9c2dd7e15ad62b45772
Also, look at DateInterval to understand a little more:
http://www.php.net/manual/en/dateinterval.construct.php
you can do like. if you want to minus 5 minutes from the date
$given_date = 'May 06 2014 14:28';
$date = new DateTime($given_date);
//subtract 5 minutes from the date
$new_date = $date->sub(new DateInterval('PT' . '5' . 'M'));
echo $new_date->format('F d Y H:i');
if you want to add 5 minutes then change
//add 5 minutes to the date
$new_date = $date->add(new DateInterval('PT' . '5' . 'M'));
First of all, i think you need to compare the two date/time by the method strtotime. With that you can compare the two date.
Then, you just need to make one or two insert in your database if i understand correctly with a If/Else method.
Hope it helps!
Related
I have these two functions:
function time_is_older_than($timestamp, $time_string)
{
if (strtotime($timestamp) < strtotime('-' . $time_string))
return true;
return false;
}
function time_is_younger_than($timestamp, $time_string)
{
if (strtotime($timestamp) > strtotime('-' . $time_string))
return true;
return false;
}
They enable me to do neat things like:
if (time_is_older_than($last_time_some_action_happened, '5 minutes'))
do_it_again();
They normally work, except for during one hour every six months, when my timezone switches over to "summer time" or "winter time". This means that the clocks are increased or put back one hour at midnight (according to this timezone).
The PHP manual states this for strtotime:
The Unix timestamp that this function returns does not contain information about time zones. In order to do calculations with date/time information, you should use the more capable DateTimeImmutable.
However, if I provide the exact same date/time string, with "+08:00" added in the end versus "+00:00", for example, I get different numbers of seconds returned. So strtotime() does understand timezones when it parses the provided time, even if the returned integer obviously doesn't contain this information. (Nor is it expected or required to by me.)
I've spent countless hours trying to debug this, testing countless things, and just sitting here thinking, but I can't figure out what exactly would make the code I have fail, specifically for one hour. And especially what about it I need to change. Setting the second parameter for strtotime() seems likely, but I just couldn't make it work correctly.
My hottest "lead" for quite some time was that the strtotime('-' . $time_string) part is ending up using a different timezone than the timestamp strings provided, but I do provide timezone data to it most of the time! An example of $last_time_some_action_happened might be something like 2020-10-28 02:22:41.123456+01.
I set the timezone with date_default_timezone_set().
I suspect that I only need to make some very minor change, but I've been experimenting so much and so long now, even taking rests in between, that my brain can no longer see this clearly. I bet the solution is something awfully simple.
Please don't tell me to use DateTimeImmutable. This would fundamentally change my entire structure and require me to do things very differently. Perhaps I should, and even will, at some point, but for now, I just wish to fix this rare but still very annoying bug in my existing code. (If it's possible at all, which I very much believe is the case.)
I'm able to reproduce the issue you are having:
date_default_timezone_set('Pacific/Auckland');
// Daylight saving time 2020 in New Zealand began at 2:00am on Sunday, 27 September
$current = strtotime('2020-09-27 02:04:00');
$d1 = strtotime('2020-09-27 02:05:00', $current);
$d2 = strtotime('-5 minutes', $current);
var_dump($d1 > $d2); // false
var_dump(date('Y-m-d H:i:s', $d1)); // 2020-09-27 03:05:00
var_dump(date('Y-m-d H:i:s', $d2)); // 2020-09-27 03:59:00
This person looks to be having the same issue as you and may appear to be a bug.
DateTime::modify and DST switch
The solution is to convert the dates to UTC then compare:
// Convert to UTC and compare
$d1 = new \DateTime('2020-09-27 02:05:00', new \DateTimeZone('Pacific/Auckland'));
$d2 = new \DateTime('2020-09-27 02:04:00', new \DateTimeZone('Pacific/Auckland'));
$d2->setTimezone(new \DateTimeZone('UTC'));
$d2->modify('-5 minutes');
$d2->setTimezone(new \DateTimeZone('Pacific/Auckland'));
var_dump($d1 > $d2); // true
var_dump($d1->format(\DateTimeInterface::RFC3339_EXTENDED)); // 2020-09-27T03:05:00.000+13:00
var_dump($d2->format(\DateTimeInterface::RFC3339_EXTENDED)); // 2020-09-27T01:59:00.000+12:00
I've updated your functions:
function time_is_older_than($datetime, $time_string)
{
$d1 = new \DateTime($datetime);
$d1->setTimezone(new \DateTimeZone('UTC'));
$d2 = new \DateTime();
$d2->setTimezone(new \DateTimeZone('UTC'));
$d2->modify('-' . $time_string);
return $d1 < $d2;
}
function time_is_younger_than($datetime, $time_string)
{
$d1 = new \DateTime($datetime);
$d1->setTimezone(new \DateTimeZone('UTC'));
$d2 = new \DateTime();
$d2->setTimezone(new \DateTimeZone('UTC'));
$d2->modify('-' . $time_string);
return $d1 > $d2;
}
Could you consider a solution:
In the timestamp string（like Thu, 21 Dec 2000 16:01:07 +0200）, add a timezone tag which specify timezone without difference of daylight saving time.
Im trying to get the difference between 2 differente dates in minutes, but is not outputting correctly.
Ex:
$then = "2017-01-23 18:21:24";
//Convert it into a timestamp.
$then = strtotime($then);
//Get the current timestamp.
$now = time();
//Calculate the difference.
$difference = $now - $then;
//Convert seconds into minutes.
$minutes = floor($difference / 60);
echo $minutes;
Is outputting 611 minutes, and is wrong since from "2017-01-23 18:21:24" to "2017-01-24 12:36:24" it past much more than 611 minutes. Is my code incorrect?
Try to set your default timezone
date_default_timezone_set('Europe/Copenhagen');
Ofc change Europe/Copenhagen for the one that suits your needs.
If you are using or able to use PHP 5.3.x or later, you can use its DateTime object functionality:
$date_a = new DateTime('2010-10-20 08:10:00');
$date_b = new DateTime('2008-12-13 10:42:00');
$interval = date_diff($date_a,$date_b);
echo $interval->format('%h:%i:%s');
You can play with the format in a variety of ways, and once you have dates in DateTime objects, you can take advantage of a lot of different functionality, for example comparison via normal operators. See the manual for more: http://us3.php.net/manual/en/datetime.diff.php
I've checked your code it works perfectly So if have any doubt see your result
But you got wrong, so to ignore this set your timezone.
I want to add an x number of week days (e.g. 48 weekday hours) to the current timestamp. I am trying to do this using the following
echo (strtotime('2 weekdays');
However, this doesn't seem to take me an exact 48 hours ahead in time. For example, inputting the current server time of Tuesday 18/03/2014 10:47 returns Thursday 20/03/2014 00:00. using the following function:
echo (strtotime('2 weekdays')-mktime())/86400;
It can tell that it's returning only 1.3 weekdays from now.
Why is it doing this? Are there any existing functions which allow an exact amount of weekday hours?
Given you want to preserve the weekdays functionality and not loose the hours, minutes and seconds, you could do this:
$now = new DateTime();
$hms = new DateInterval(
'PT'.$now->format('H').'H'.
$now->format('i').'M'.
$now->format('s').'S'.
);
$date = new DateTime('2 weekdays');
$date->add($hms);//add hours here again
The reason why weekday doesn't add the hours is because, if you add 1 weekday at any point in time on a monday, the next weekday has to be tuesday.
The hour simply does not matter. Say your date is 2014-01-02 12:12:12, and you want the next weekday, that day starts at 2014-01-03 00:00:00, so that's what you get.
My last solution works though, and here's how: I use the $now instance of DateTime, and its format method to construct a DateInterval format string, to be passed to the constructor. An interval format is quite easy: it starts with P, for period, then a digit and a char to indicate what that digit represents: 1Y for 1 Year, and 2D for 2 Days.
However, we're only interested in hours, minutes and seconds. Actual time, which is indicated using a T in the interval format string, hence we start the string with PT (Period Time).
Using the format specifiers H, i and s, we construct an interval format that in the case of 12:12:12 looks like this:
$hms = new DateInterval(
'PT12H12M12S'
);
Then, it's a simple matter of calling the DateTime::add method to add the hours, minutes and seconds to our date + weekdays:
$weekdays = new DateTime('6 weekdays');
$weekdays->add($hms);
echo $weekdays->format('Y-m-d H:i:s'), PHP_EOL;
And you're there.
Alternatively, you could just use the basic same trick to compute the actual day-difference between your initial date, and that date + x weekdays, and then add that diff to your initial date. It's the same basic principle, but instead of having to create a format like PTXHXMXS, a simple PXD will do.
Working example here
I'd urge you to use the DateInterface classes, as it is more flexible, allows for type-hinting to be used and makes dealing with dates just a whole lot easier for all of us. Besides, it's not too different from your current code:
$today = new DateTime;
$tomorrow = new DateTime('tomorrow');
$dayAfter = new DateTime('2 days');
In fact, it's a lot easier if you want to do frequent date manipulations on a single date:
$date = new DateTime();//or DateTime::createFromFormat('Y-m-d H:i:s', $dateString);
$diff = new DateInterval('P2D');//2 days
$date->add($diff);
echo $date->format('Y-m-d H:i:s'), PHP_EOL, 'is the date + 2 days', PHP_EOL;
$date->sub($diff);
echo $date->format('Y-m-d H:i:s'), PHP_EOL, 'was the original date, now restored';
Easy, once you've spent some time browsing through the docs
I think I have found a solution. It's primitive but after some quick testing it seems to work.
The function calculates the time passed since midnight of the current day, and adds it onto the date returned by strtotime. Since this could fall into a weekend day, I've checked and added an extra day or two accordingly.
function weekDays($days) {
$tstamp = (strtotime($days.' weekdays') + (time() - strtotime("today")));
if(date('D',$tstamp) == 'Sat') {
$tstamp = $tstamp + 86400*2;
}
elseif(date('D',$tstamp) == 'Sun') {
$tstamp = $tstamp + 86400;
}
return $tstamp;
}
Function strtotime('2 weekdays') seems to add 2 weekdays to the current date without the time.
If you want to add 48 hours why not adding 2*24*60*60 to mktime()?
echo(date('Y-m-d', mktime()+2*24*60*60));
The currently accepted solution works, but it will fail when you want to add weekdays to a timestamp that is not now. Here's a simpler snippet that will work for any given point in time:
$start = new DateTime('2021-09-29 15:12:10');
$start->add(date_interval_create_from_date_string('+ 3 weekdays'));
echo $start->format('Y-m-d H:i:s'); // 2021-10-04 15:12:10
Note that this will also work for a negative amount of weekdays:
$start = new DateTime('2021-09-29 15:12:10');
$start->add(date_interval_create_from_date_string('- 3 weekdays'));
echo $start->format('Y-m-d H:i:s'); // 2021-09-24 15:12:10
I have a form that receives a time value:
$selectedTime = $_REQUEST['time'];
The time is in this format - 9:15:00 - which is 9:15am. I then need to add 15 minutes to this and store that in a separate variable but I'm stumped.
I'm trying to use strtotime without success, e.g.:
$endTime = strtotime("+15 minutes",strtotime($selectedTime)));
but that won't parse.
Your code doesn't work (parse) because you have an extra ) at the end that causes a Parse Error. Count, you have 2 ( and 3 ). It would work fine if you fix that, but strtotime() returns a timestamp, so to get a human readable time use date().
$selectedTime = "9:15:00";
$endTime = strtotime("+15 minutes", strtotime($selectedTime));
echo date('h:i:s', $endTime);
Get an editor that will syntax highlight and show unmatched parentheses, braces, etc.
To just do straight time without any TZ or DST and add 15 minutes (read zerkms comment):
$endTime = strtotime($selectedTime) + 900; //900 = 15 min X 60 sec
Still, the ) is the main issue here.
Though you can do this through PHP's time functions, let me introduce you to PHP's DateTime class, which along with it's related classes, really should be in any PHP developer's toolkit.
// note this will set to today's current date since you are not specifying it in your passed parameter. This probably doesn't matter if you are just going to add time to it.
$datetime = DateTime::createFromFormat('g:i:s', $selectedTime);
$datetime->modify('+15 minutes');
echo $datetime->format('g:i:s');
Note that if what you are looking to do is basically provide a 12 or 24 hours clock functionality to which you can add/subtract time and don't actually care about the date, so you want to eliminate possible problems around daylights saving times changes an such I would recommend one of the following formats:
!g:i:s 12-hour format without leading zeroes on hour
!G:i:s 12-hour format with leading zeroes
Note the ! item in format. This would set date component to first day in Linux epoch (1-1-1970)
strtotime returns the current timestamp and date is to format timestamp
$date=strtotime(date("h:i:sa"))+900;//15*60=900 seconds
$date=date("h:i:sa",$date);
This will add 15 mins to the current time
To expand on previous answers, a function to do this could work like this (changing the time and interval formats however you like them according to this for function.date, and this for DateInterval):
(I've also written an alternate form of the below function here.)
// Return adjusted time.
function addMinutesToTime( $time, $plusMinutes ) {
$time = DateTime::createFromFormat( 'g:i:s', $time );
$time->add( new DateInterval( 'PT' . ( (integer) $plusMinutes ) . 'M' ) );
$newTime = $time->format( 'g:i:s' );
return $newTime;
}
$adjustedTime = addMinutesToTime( '9:15:00', 15 );
echo '<h1>Adjusted Time: ' . $adjustedTime . '</h1>' . PHP_EOL . PHP_EOL;
get After 20min time and date
function add_time($time,$plusMinutes){
$endTime = strtotime("+{$plusMinutes} minutes", strtotime($time));
return date('h:i:s', $endTime);
}
20 min ago Date and time
date_default_timezone_set("Asia/Kolkata");
echo add_time(date("Y-m-d h:i:sa"),20);
In one line
$date = date('h:i:s',strtotime("+10 minutes"));
You can use below code also.It quite simple.
$selectedTime = "9:15:00";
echo date('h:i:s',strtotime($selectedTime . ' +15 minutes'));
Current date and time
$current_date_time = date('Y-m-d H:i:s');
15 min ago Date and time
$newTime = date("Y-m-d H:i:s",strtotime("+15 minutes", strtotime($current_date)));
Quite easy
$timestring = '09:15:00';
echo date('h:i:s', strtotime($timestring) + (15 * 60));
I'm using a PHP script to grab data from Active Directory using LDAP..
When I get the user values for 'lastlogon' I get a number like 129937382382715990
I've tried to figure out how to get the date/time from this but have no idea, can anybody help?
Read this comment on the PHP: LDAP Functions page.
All of them are using "Interval" date/time format with a value that represents the number of 100-nanosecond intervals since January 1, 1601 (UTC, and a value of 0 or 0x7FFFFFFFFFFFFFFF, 9223372036854775807, indicates that the account never expires): https://msdn.microsoft.com/en-us/library/ms675098(v=vs.85).aspx
So if you need to translate it from/to UNIX timestamp you can easily calculate the difference with:
<?php
$datetime1 = new DateTime('1601-01-01');
$datetime2 = new DateTime('1970-01-01');
$interval = $datetime1->diff($datetime2);
echo ($interval->days * 24 * 60 * 60) . " seconds\n";
?>
The difference between both dates is 11644473600 seconds. Don't rely on floating point calculations nor other numbers that probably were calculated badly (including time zone or something similar).
Now you can convert from LDAP field:
<?php
$lastlogon = $info[$i]['lastlogon'][0];
// divide by 10.000.000 to get seconds from 100-nanosecond intervals
$winInterval = round($lastlogon / 10000000);
// substract seconds from 1601-01-01 -> 1970-01-01
$unixTimestamp = ($winInterval - 11644473600);
// show date/time in local time zone
echo date("Y-m-d H:i:s", $unixTimestamp) ."\n";
?>
This is the number 100-nanosecond ticks since 1 January 1601 00:00:00 UT.
System time article in Wikipedia can give you more details.
What about this:
$timeStamp = 129937382382715990;
echo date('Y-m-d H:i:s', $timeStamp);
EDIT ------
I just tried the following and noticed that this method wont work unless the clock on your machine is set 10 years in the future. Below is the code I used to prove the above pretty much useless unless you do more processing maybe..
$time = time();
echo date('Y-m-d H:i:s', $time);
echo "<br />";
$timeStamp = 129937382382715990;
echo date('Y-m-d H:i:s', $timeStamp);
In my case I'm using Pentaho. With a Modified Javascript value you can convert the values, lastLogon is the column I wanna convert from data stream:
calendar = java.util.Calendar.getInstance();
calendar.setTime(new Date("1/1/1601"));
base_1601_time = calendar.getTimeInMillis();
calendar.setTime(new Date("1/1/1970"));
base_1970_time = calendar.getTimeInMillis();
ms_offset = base_1970_time - base_1601_time;
calendar.setTimeInMillis( lastLogon / 10000 - ms_offset); //lastLogon is a column from stream
var converted_AD_time = calendar.getTime(); // now just add this variable 'converted_AD_time' to the 'Fields' as a show in the image below