How to convert PDO query to Yii query? - php

Question

Can someone help me convert the following code to Yii query? I would liek it to return array of type models with derived column
$sql = 'UPDATE jobs
RIGHT JOIN (
SELECT jobs.JOBNO,
round(details' . $type['type'] . '.' . $type['km'] . ' * sum(PRICE),2) AS JOBSVALUE
FROM jobs
JOIN projects ON jobs.PROJID = projects.PROJID
JOIN biditems ON projects.id = biditems.project_id
JOIN details' . $type['type'] . ' on jobs.JOBNO = details' . $type['type'] . '.JOBNO
WHERE jobs.PROJID = :pid
GROUP BY jobs.JOBNO
) AS temp ON jobs.JOBNO = temp.JOBNO
SET jobs.VALUE = JOBSVALUE';
$command=$connection->createCommand($sql);
$command->bindValue(":pid", $model->PROJID,PDO::PARAM_INT);
$command->execute();
$sql = "UPDATE jobs j
JOIN (
SELECT j.JOBNO, COUNT(l.JOBNO) AS numlis
FROM lineitems l
RIGHT JOIN jobs j ON j.JOBNO = l.JOBNO
WHERE j.PROJID = :pid
GROUP BY j.JOBNO
) t ON j.JOBNO = t.JOBNO
SET `VALUE` = 0, `EARNED` = 0
WHERE PROJID = :pid AND t.numlis = 0;";
$command=$connection->createCommand($sql);
$command->bindValue(":pid", $model->PROJID,PDO::PARAM_INT);
$command->execute();
1st attempt
$sql = "select jobs.JOBNO, round(details".$type['type'].".".$type['km']." * sum(PRICE),2) AS JOBSVALUE
from jobs
join projects on jobs.PROJID = projects.PROJID
join biditems on projects.id = biditems.project_id
join details".$type['type']." on jobs.JOBNO = details".$type['type'].".JOBNO
where jobs.PROJID = :pid
GROUP BY jobs.JOBNO";
$command=$connection->createCommand($sql);
$command->bindValue(":pid",$model->PROJID,PDO::PARAM_INT);
$result = $command->queryAll();
foreach ($result as $value) {
$job = Jobs::model()->findByPk($value['JOBNO']);
$job->VALUE = $value['JOBSVALUE'];
$job->save();
}
$sql = "SELECT j.JOBNO, COUNT(l.JOBNO) AS numlis
FROM lineitems l
RIGHT JOIN jobs j ON j.JOBNO = l.JOBNO
WHERE j.PROJID = :pid
GROUP BY j.JOBNO";
$command=$connection->createCommand($sql);
$command->bindValue(":pid",$model->PROJID,PDO::PARAM_INT);
$result = $command->queryAll();
foreach ($result as $value) {
if($value['numlis'] == 0){
$job = Jobs::model()->findByPk($value['JOBNO']);
$job->VALUE = 0;
$job->EARNED = 0;
$job->save();
}
}

Answer 1

Just literally following their documentation:
$job = Yii:app()->db
->createCommand()
->select(
'jobs.JOBNO, round(details'.$type['type'].'.'.$type['km'].' * sum(PRICE), 2)'
)
->join('projects', 'jobs.PROJID = projects.PROJID')
->join('biditems', 'projects.id = biditems.project_id')
->join('details'.$type['type'], 'jobs.JOBNO = details'.$type['type'].'.JOBNO')
->where('jobs.PROJID=:pid', array(':pid' = $model->PROJID))
->group('jobs.JOBNO')
->queryRow();