How to find string position php - php

Question

I want to get the position of 'ja' in each of the words in $string, but its not working. what am i doing wrong?
<?php
$offset = 0;
$find = 'ja';
$find_length = strlen($find);
$string = 'jasim jasmin jassir';
while ($string_position = strpos($string, $find, $offer)) {
echo $find.' found at '.$string_position.'<br>';
$offset = $string_position + $find_length;
}
?>

Answer 1

Change the variable name to $offset
strpos may return 0 and while will treat it as false
So replace your while statement with:
while (($string_position = strpos($string, $find, $offset)) !== false) {

Answer 2

<?php
// stack overflow area
$offset = 0;
$find = 'ja';
$find_length = strlen($find);
$string = 'jasim jasmin jassir';
if (strpos($string, $find) === false) {
echo "not found";
}
else {
while (strpos($string, $find, $offset) !== false) {
$string_position = strpos($string, $find, $offset);
echo $find.' found at '.$string_position.'<br>';
$offset = $string_position + $find_length;
}
}
?>
Little workaround, but it apparently works.
Output:
ja found at 0
ja found at 6
ja found at 13

Answer 3

try changing offest
<?php
$offset = 1;
$find = 'ja';
$find_length = strlen($find);
$string = 'jasim jasmin jassir';
while ($string_position = strpos($string, $find, $offset)) {
echo $find.' found at '.$string_position.'<br>';
$offset = $string_position + $find_length;
}
?>
// output :- ja found at 6
ja found at 13
if you don't want to change offset use
$string = ' jasim jasmin jassir'; (without space not be jasim it's 'jasim )
then it will output 3
ja found at 1
ja found at 7
ja found at 14
OR try to change your condition check
while (($string_position = strpos($string, $find, $offset)) !== false) {

Answer 4

Probably you should code this way to find string positions
$positions = array();
$offset = -1;
while (($pos = strpos($string, $find, $offset+1)) !== false) {
$positions[] = $offset;
}
$result = implode(', ', $positions);
print this result