I am trying to POST a div section to a new page using jquery ajax as:
<!DOCTYPE html>
<body>
<div id="edit_content">
<p>This is a test</p>
</div>
Submit
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script>
$( document ).ready(function() {
var htmlData = $('#edit_content').html();
$.post('out.php', {'html': htmlData },function(){
});
});
</script>
</body>
</html>
and in the out.php page I have:
<?php
$content = $_POST['html'];
echo $content;
but when I run the code I am getting this error:
Notice: Undefined index: html in G:\Apps\out.php on line 2
can you please let me know why this is happening and how I can stop it?
Your $.post function has a typo in the data field, try this instead:
$.post('out.php', {html: htmlData }, function(response){
Since you are sending an object, the key does not need quotes.
or better yet, but all your data ouside and juste reference them in your post:
var postData = {html: $('#edit_content').html() }
$.post('out.php', postData, function(response){
Your code works as it is - at least in terms of the post. To illustrate this change it to the following (the only change is to actuallly do something with the response to the ajax request):
<!DOCTYPE html>
<body>
<div id="edit_content">
<p>This is a test</p>
</div>
Submit
<div id="out"></div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script>
$( document ).ready(function() {
var htmlData = $('#edit_content').html();
$.post('out.php', {'html': htmlData }, function(data){
$('#out').html(data);
});
});
</script>
</body>
</html>
I think you need to explain what you are trying to do (or what you are expecting to see). As your code stands you are running the ajax request as soon as the page loads (in document ready) but not doing anything with the response. You then have a link to the out.php (Submit). Are you expecting to see the result in out.php when you click the link? If so then that isn't going to happen. What is happening is that when the page loads it runs a request to out.php with the post data and gets a response (which it then ignores). When you click the link you run a new request to out.php without the post data so you see nothing.
If I have guessed right then you want to replace the link with a form submission triggered by the click of the link (with the data fetched first). Something like
<!DOCTYPE html>
<body>
<div id="edit_content">
<p>This is a test</p>
</div>
Submit
<form action="out.php" method="post" id="out-form" style="display: none;">
<input type="hidden" id="hidden-html" name="html" value="" />
</form>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script>
$( document ).ready(function() {
$('#submit_script').click(function(){
$('#hidden-html').val($('#edit_content').html());
$('#out-form').submit();
return false;
})
});
</script>
</body>
</html>
The 'html' data is not being posted to your php page. Change your php file to this:
<?php
if(isset($_POST['html']))
{
$content = $_POST['html'];
echo $content;
}
?>
This should stop the error and at least point you in the right direction. Without more code, I am not able to tell you why the 'html' data is not being posted.
Related
I am beginner to ajax world and trying to call contents from php page using $.ajax() function and the code couldn't executed. the html page i used:
<!DOCTYPE html>
<html>
<head>
<title>AJAX</title>
</head>
<body>
<div >
<input type="text" name="search" id="search">
<br>
<br>
<h2 id="result"></h2>
</div>
<script src="https://code.jquery.com/jquery-2.2.4.min.js" integrity="sha256-BbhdlvQf/xTY9gja0Dq3HiwQF8LaCRTXxZKRutelT44=" crossorigin="anonymous"></script>
<script src="js/script.js"></script>
</body>
</html>
the JQuery code i used in the script.js:
$(document).ready(function() {
$('#search').keyup(function () {
var search = $('#search').val();
$.ajax({
url:'search.php',
//the page to which the request will go to
data:{search: search},
type: 'POST',
success:function(data) {
if(!data.error){
$('#result').html(data);//the h2 we want to echo it uing the ajax
}
}
});
});
});
the search.php page contain:
$search = $_POST['search'];
echo $search;
the code not executed. What should I do.
I see some issue in your response from PHP code and in ajax side success code.
You are not sending in response JSON format so data.error is meaningless.
so in your success callback code should be like this.
success:function(data) {
$('#result').html(data);//the h2 we want to echo it uing the ajax
}
Follow jQuery Ajax Document :
An alias for method. You should use type if you're using versions of jQuery prior to 1.9.0
type: 'POST'
But you are using 2.0 so i think this will work :
method: 'POST'
jQuery Documents
I have a PHP page included called 'leaguestatus.php'. This page allows the user to post a message/status update and the intent is to have only this part of the div refreshed; however, on submit, the entire page is reloaded.
In the current implementation I'm simply printing all the $_POST variables to the div so I can see what's coming through. The MsgText textarea DOES get posted, however, it's only after the whole page loads. I'm trying to get just the div and that included file to reload.
div id="statusupdates"><? include 'leaguestatus.php'; ?></div>
leaguestatus.php
<form id="statusform" method="POST">
<textarea name=MsgText rows=5 cols=40></textarea><BR>
<input type=submit value=Post id=uhsbutton>
</form>
<BR>
<BR>
<div id='formbox'>
<? print "<pre>POST Variables:<BR>";
print_r ($_POST);
print "</pre>";
$MsgText = $_POST["MsgText"];
?>
</div>
The jQuery I'm running in the header is:
$(document).ready(function() {
$("#statusform").submit(function(e) {
e.preventDefault();
var formData=$(this).serialize();
var pUrl="leaguestatus.php";
submitFormSave(formData, pUrl);
});
function submitFormSave(formData, pUrl) {
$.ajax({
url: pUrl,
type: 'POST',
data:formData,
success: function(response) {
$("#formbox").html(response);
}
}).success(function(){
});
}
});
Here are my includes:
html header
<link rel="stylesheet" href="css/jquery-ui.css">
<script src="js/jquery-1.9.1.js"></script>
<script src="js/jquery-ui.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
Edit: updated code to reflect use of #sazedul's response. Only issue now is on first click page acts as expected (no page refresh). On second click the entire page reloads. On third click we're back to normal.
Use this following code for ajax submit hope it will work.
$("#statusform").submit(function(e) {
e.preventDefault();
var formData=$(this).serialize();
var pUrl="leaguestatus.php";
submitFormSave(formData, pUrl);
});
function submitFormSave(formData, pUrl)
{
$.ajax({
url: pUrl,
type: 'POST',
data:formData,
success: function(response)
{
$("#formbox").html(response);
}
});
}
Made the following changes in your leaguestatus.php remembar to put double quote in the name="MsgText" in text area.
<form id="statusform" method="POST">
<textarea name="MsgText" rows=5 cols=40></textarea><BR>
<input type=submit value=Post id=uhsbutton>
</form>
<BR>
<BR>
<div id='formbox'>
</div>
<?php
if(isset($_POST['MsgText'])){
$message=$_POST['MsgText'];
echo $message;
}
?>
check for .load() like the code below....
$(document).ready(function() {
$("#statusform").submit(function() {
$("div").load();
});
});
You have to preventDefault of submit then other thing
so,you have to use e.preventDefault() to prevent submit.then do what ever you want
$("#statusform").submit(function(e) {
e.preventDefault();
......
I am trying to run this simple Ajax Post example like:
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js">
</script>
<script>
$(document).ready(function(){
$("button").click(function(){
$.post("test.php",
{
name:"Hello Ajax"
},
function(data){
$("p").html(data);
}
);
});
});
</script>
</head>
<body>
<p></p>
</body>
</html>
and PHP (test.php) as:
<?php
$name = $_POST['name'];
echo '<a>'.$name.'</a>';
?>
No error message but not getting any result back! can you please let me know what I am doing wrong?
Just a simple change, added button element in your markup. Click it and it should work:
<body>
<button>Click Me</button>
<p></p>
</body>
Your javascript is looking for the button element on which when clicked, will trigger the ajaxcall in test.php
$("button").click(function(){
By clicking the button, it will display Hello Ajax, the echo from the test.php and the one that you've send.
$.post("test.php",
{
name:"Hello Ajax"
},
Ok, I have this code:
<html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.7.1.min.js"></script>
<script type="text/javascript">
function get() {
$.post('tt.php', { name : $(this).attr('id') }, function(output) {
$('#age').html(output).show();
});
}
</script>
</head>
<body>
<input type="text" id="name"/>
<a id="grabe" href="javascript: get()">haller</a>
<div id="age">See your name</div>
</body>
</html>
Here's what I want: get the id of an anchor tag from the anchor tag that has been clicked by the user via jQuery and then past that to a PHP file. The PHP file will then echo the id name of the anchor tag that was clicked by the user back to the jQuery which will then display the output into the specified element.
Here's the PHP file:
<?
$name=$_POST['name'];
if ($name==NULL)
{
echo "No text";
}
else
{
echo $name;
}
?>
Bind your event like this, since you are using jQuery
$('a').click(function(){
$.post('tt.php', { name : $(this).attr('id') }, function(output) {
$('#age').html(output).show();
});
});
And remove the javascript from the href
<a id="grabe" href="#">haller</a>
<a id="kane" href="#">haller 2</a>
$('#grabe').click(function() {
$('#age').load('yourphp.php', {'name':$(this).prop('id')});
});
You can use $(this) to access almost anything about "what brought you here" in the code. You'll also need a listener for the event. In this way too brief example below, I have it listening for any clicks to <span class="edit_area"> spans.
<script>
$(document).ready(function(){
$('span.edit_area').click( function(){
var fieldname = $(this).attr('id');
...
});
});
I dont know why you want to send an id to a server and then receive that id back again from the ajax call as it is already there in your client script. Anyway this is the code.
This code will does this functionalirty for all a tag with a class called"crazyLink" and show the data received from the server page in a div with id anotherCrazyDiv
HTML
<a class="crazyLink" href="#">I am crazy</a>
<a class="crazyLink" href="#">I am crazy2</a>
<div id="anotherCrazyDiv"></div>
Script
$(function(){
$(".crazyLink").click(function(){
var id=$(this).attr("id");
$.post("data.php", { name : id } ,function(data){
$("#anotherCrazyDiv").html(data);
});
return false; // to prevent normal navigation if there is a valid href value
});
});
Keep in mind that, in your scenario, the value in id variable and value in data variable (after getting response from ajax call ) are same.
you may want to separate your javascript from your html. it makes things easier. it should probably look something like this.
HTML
<html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.7.1.min.js"> </script>
<script type="text/javascript" src="javascript/somescript.js"></script>
</head>
<body>
<input type="text" id="name"/>
<a id="grabe" class="someclass">haller</a>
<div id="age">See your name</div>
</body>
</html>
javascript
$(document).ready(function() {
$('.someclass').click(function() {
$('#age').load(
url: 'tt.php',
data: { name: $(this).attr('id')}
);
});
});
this a simple example in how to submit form using the Jquery form plugins and retrieving data using html format
html Code
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
<script>
// prepare the form when the DOM is ready
$(document).ready(function() {
// bind form using ajaxForm
$('#htmlForm').ajaxForm({
// target identifies the element(s) to update with the server response
target: '#htmlExampleTarget',
// success identifies the function to invoke when the server response
// has been received; here we apply a fade-in effect to the new content
success: function() {
$('#htmlExampleTarget').fadeIn('slow');
}
});
});
</script>
</head>
<body>
<form id="htmlForm" action="post.php" method="post">
Message: <input type="text" name="message" value="Hello HTML" />
<input type="submit" value="Echo as HTML" />
</form>
<div id="htmlExampleTarget"></div>
</body>
</html>
PHP Code
<?php
echo '<div style="background-color:#ffa; padding:20px">' . $_POST['message'] . '</div>';
?>
this just work fine
what i need to know if what if i need to Serialize the form fields so how to pass this option through the JS function
also i want show a loading message while form processed
how should i do that too
thank you
To serailize and post that to a php page, you need only jQuery in your page. no other plugin needed
$("#htmlForm").submit(function(){
var serializedData= $("#htmlForm").serialize();
$.post("post.php", { dat: serializedData}, function(data) {
//do whatever with the response here
});
});
If you want to show a loading message, you can do that before you start the post call.
Assuming you have div with id "divProgress" present in your page
HTML
<div id="divProgress" style="display:none;"></div>
Script
$(function(){
$("#htmlForm").submit(function(){
$("#divProgress").html("Please wait...").fadeIn(400,function(){
var serializedData= $("#htmlForm").serialize();
$.post("post.php", { dat: serializedData},function(data) {
//do whatever with the response here
});
});
});
});
The answer posted by Shyju should work just fine. I think the 'dat' should be given in quotes.
$.post("post.php", { 'dat': serializedData},function(data) {
...
}
OR simply,
$.post("post.php", serializedData, function(data) {
...
}
and access the data using $_POST in PHP.
NOTE: Sorry, I have not tested the code, but it should work.
Phery library does this behind the scenes for you, just create the form with and it will submit your inputs in form automatically. http://phery-php-ajax.net/
<?php
Phery::instance()->set(array(
'remote-function' => function($data){
return PheryResponse::factory('#htmlExampleTarget')->fadeIn('slow');
}
))->process();
?>
<?php echo Phery::form_for('remote-function', 'post.php', array('id' => ''); ?> //outputs <form data-remote="remote-function">
Message: <input type="text" name="message" value="Hello HTML" />
<input type="submit" value="Echo as HTML" />
</form>
<div id="htmlExampleTarget"></div>
</body>
</html>