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i want to add 30 days from the date $first and the result in $sec to take the data between these days from MySQL
$first=05/02/2014
result as in
$sec= 06/02/2014 in m/d/y format
thank you
try
echo $sec=date('m/d/y',strtotime('+30 days', time($first))); //06/04/14
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How can I convert integer to time in minutes e.g. 5 would give 30mins. I've tried
<?php
$toMin = 5;
echo date('i', ($toMin*60)).'mins';
?>
But it only returns 05mins
so something like:
$time='7.5'; //, 8.3, 2.2.
$x=explode('.',$time);
$min=60*($x[1]/10);
echo $x[0] .'hours and '.$min.'mins';
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Say:
The start day is January 5 and the end is January 10 and the current date is January 7. I want to output the remaining days which is 3.
I think the easiest method is like this.
$date1 = new DateTime("2015-01-01");
$date2 = new DateTime("2010-02-05");
$diff = $date2->diff($date1)->format("%a");
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Please help me to find the current date in the following formate yyyy-mm-ddThh:mm:ss:ss.sssz
<?php
$t = microtime(true);
$micro = sprintf("%03d",($t - floor($t)) * 1000);
$utc = gmdate('Y-m-d\TH:i:s.', $t).$micro.'Z';
echo $utc;
?>
DEMO
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I tried to get events from google calendar. So I have trouble in time output.
$date = DateTime::createFromFormat("Y-m-d\TH:m:sP", "2013-02-12T21:00:00-05:00");
echo $date->format('H:m');
Output is 21:12, but it should be 21:00. How it can be fixed?
m is months. You're looking for minutes which is i:
$date = DateTime::createFromFormat("Y-m-d\TH:i:sP", "2013-02-12T21:00:00-05:00");
echo $date->format('H:i');
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i have time in a format of an integer example:(454 seconds) and i need to convert it to a time format example:(00:07:34) any function can help me to do this??
You can do it using Zend_Date:
$time = new Zend_Date();
$time->setTime('00:00:00');
$time->addSecond(454);
echo $time->toString('HH:mm:ss'); // result 00:07:34