I want check my array value with in_array my arrays this is:
I use this code but it's not work
if(in_array(167, $array) AND in_array(556, $array) ) {
echo 'ok';
return;
}
now how can check my values?
in_array() does not work for multi-dimensional arrays , you either have to loop it and do the in_array() check or merge the array into a single one and then do single in_array() check.
Way 1:
foreach($array as $k=>$arr)
{
if(in_array(167,$arr))
{
echo "Found";
}
}
Way 2: (Merge)
$merged_arr = call_user_func_array('array_merge', $array);
if(in_array(167,$merged_arr))
{
echo "Found";
}
EDIT :
<?php
$array = array(array(167),array(167),array(556));
$merged_arr = call_user_func_array('array_merge', $array);
$needle_array = array(167,556,223);
foreach($needle_array as $v)
{
if(in_array($v,$merged_arr))
{
echo "Found";
}
}
You can even use array_intersect() on these two arrays to get the matched content , if that is what you are looking for.
You could create a mult-dimensional in_array function:
function inArrayMulti($needle, $haystack, $strict=false) {
foreach( $haystack as $item ) {
if( is_array($item) ) return inArrayMulti($needle, $item);
else {
if( $strict && $needle === $item) ) return true;
else if( $needle == $item ) return true;
}
}
return false;
}
May be useful this
return 0 < count(
array_filter(
$my_array,
function ($a) {
return array_key_exists('id', $a) && $a['id'] == 152;
}
)
);
Or
$lookup_array=array();
foreach($my_array as $arr){
$lookup_array[$arr['id']]=1;
}
Now you can check for an existing id very fast, for example:
echo (isset($lookup_array[152]))?'yes':'no';
Loop through the array
<?php
foreach($array as $ar){
if(in_array(167,$ar) && in_array(556,$ar)){
echo "ok";
}
}
?>
Why all answers use in_array and other difficult construction? We need found only two numbers, easy way for this:
$array = array(array(165), array(167),array(167),array(556));
foreach($array as $key){
foreach($key as $next){
echo 167 == $next || 556 == $next ? '<p>Found<p></br>' : '';
}
}
Related
I have an array, say
$updates = array();
$updates['U1'] = array('F1', 'F2', 'F5');
$updates['U2'] = array('F3');
$updates['U3'] = array('F3', 'F4');
I need search for a value say F5 so it should return the key U1.
And also if there is multiple occurrence of a value, should return the last key.
Eg. searching F3 should return U3 and not U2.
I have searched a lot and can't find a way. I am looking for a solution without using loops.
without using loop:
function findArrVal($arr = [], $param){
static $indx = 0;
if($indx == 0){
krsort($arr);
}
$keys = array_keys($arr);
$values = array_values($arr);
if( count($values) == $indx ){
return false;
} else if( is_array($values[$indx]) && in_array($param, $values[$indx])){
return $keys[$indx];
} else {
++$indx;
return findArrVal($arr, $param);
}
return FALSE;
}
using loop:
function findArrVal($arr = [], $param){
krsort($arr);
foreach($arr as $key => $ar){
if(is_array($ar) && in_array($param, $ar)){
return $key;
}
}
return FALSE;
}
findArrVal($updates,'F3');
krsort - sorts the array in reverse order. ( to find the value at first occurrence )
is_array to check if the child value is an array type.
in_array to find the item on the child array.
Maybe It's helpful for you.
function _getFindArrayKey(array $arr, $key)
{
if (array_key_exists($key, $arr)) {
return true;
}
// check arrays contained in this array
foreach ($arr as $element) {
if (is_array($element)) {
if (_getFindArrayKey($element, $key)) {
return true;
}
}
}
return false;
}
I need a help. I have two arrays. I need to check if the values in first array are present in second or not. The arrays are as:
$maindata=array(array('id'=>3),array('id'=>7),array('id'=>9));
$childata=array(array('id'=>7),array('id'=>11),array('id'=>3),array('id'=>123));
Here, I need to check if each value from first array is present inside second array or not. If yes, then should return true else false at each time.
Here you go, you can use the in_array() for PHP.
$maindata=array( array('id'=>3),array('id'=>7),array('id'=>9) );
$childata=array( array('id'=>7),array('id'=>11),array('id'=>3),array('id'=>123) );
foreach( $maindata as $key => $value )
{
if( in_array( $value, $childata ) )
{
echo true;
}
else
{
echo false;
}
}
You could also remove the whole if else and replace with a single line.
echo ( in_array( $value, $childata ) ? true : false );
Reference -
http://php.net/manual/en/function.in-array.php
https://code.tutsplus.com/tutorials/the-ternary-operator-in-php--cms-24010
To check if an array contains a value:
if (in_array($value, $array)) {
// ... logic here
}
To check if an array contains a certain key:
if (array_key_exists($key, $array)) {
// ... logic here
}
Resources
in_array - PHP Manual
array_key_exists() - PHP Manual
Following code will return true only if all elements of main array exists in second array, false otherwise:
$maindata=array(array('id'=>3),array('id'=>7),array('id'=>9));
$childata=array(array('id'=>3),array('id'=>7),array('id'=>11),array('id'=>123));
$match = 0;
foreach( $maindata as $key => $value ) {
if( in_array( $value, $childata ) ) {
$match++;
}
}
if($match == count($maindata)){
// return true;
} else {
// return false;
}
Use array_intersect
if(!empty(array_intersect($childata, $maindata)))
{
//do something
}
or
$result = count(array_intersect($childata, $maindata)) == count($childata);
Use array_column and array_intersect.
$first = array_column($maindata, 'id');
$second = array_column($childata, 'id');
//If intersect done, means column are common
if (count(array_intersect($first, $second)) > 0) {
echo "Value present from maindata in childata array.";
}
else {
echo "No values are common.";
}
I have this code:
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
if(in_array("backup", $arr)){
echo "Da";
} else { echo "Nu";
}
But is not working because,in_array instruction check the array for the complete string "backup" , which doesnt exist.I need to check for a part of the string,for example,to return true because backup is a part of the "Hello_backup" and "Beautiful_backup" strings
EDIT: I take the advice and i have used stripos like this:
$arr = array("Hello_backup-2014","World!","Beautiful_backup-2014","Day!");
$word='backup';
if(stripos($arr,$word) !== false){
echo "Da";
} else { echo "Nu";}
but now i get an error: "stripos() expects parameter 1 to be string, array given in if(stripos($arr,$word) !== false){"
Use implode to basically concatenate the array values as a string, then use strpos to check for a string within a string.
The first argument you pass to implode is used to separate each value in the array.
$array = array("Hello_backup","World!","Beautiful_backup","Day!");
$r = implode(" ", $array);
if (strpos($r, "backup") !== false) {
echo "found";
}
In this case you need to use stripos(). Example:
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
$needle = 'backup';
function check($haystack, $needle) {
foreach($haystack as $word) {
if(stripos($word, $needle) !== false) {
return 'Da!'; // if found
}
}
return 'Nu'; // if not found
}
var_dump(check($arr, $needle));
Without a function:
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
$found = false;
foreach($arr as $word) {
if(stripos($word, 'backup') !== false) {
$found = true;
break;
}
}
if($found) {
echo 'Da!';
} else {
echo 'Nu';
}
Try with strpos()
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
foreach($arr as $v){
echo (strpos($v,"backup")!== false ? "Da" : "Nu");
}
output :- DaNuDaNu
Here is the one line solution for you.
$arr = array("Hello_backup-2014","World!","Beautiful_backup-2014","Day!");
$returned_a = array_map(function($u){ if(stripos($u,'backup') !== false) return "Da"; else return "Nu";}, $arr);
You can use $returned_a with array as your answer..
Array ( [0] => Da [1] => Nu [2] => Da [3] => Nu )
Use this method. It is little bit simple to use.
$matches = preg_grep('/backup/', $arr);
$keys = array_keys($matches);
print_r($matches);
Look this working example
According to your question
$matches = preg_grep('/backup/', $arr);
$keys = array_keys($matches);
$matches = trim($matches);
if($matches != '')
{echo "Da";
}else { echo "Nu";}
<?php
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
foreach($arr as $arr1) {
if (strpos ($arr1,"backup")) {
echo "Da";
} else {
echo "Nu";
}
}
?>
I'm trying to find a part of a string in a multidimentional array.
foreach ($invitees as $invitee) {
if (in_array($invitee, $result)){
echo 'YES';
} else {
echo 'NO';
}
}
the $invitees array has 2 elements:
and $result is what I get from my Drupal database using db_select()
What I'm trying to do is, if the first part from one of the emails in $invitees is in $result it should echo "YES". (the part before the "#" charather)
For example:
"test.email" is in $result, so => YES
"user.one" is not in $result, so => NO
How do i do this? How can I search for a part of a string in a multidimentional array?
Sidenote: I noticed that the array I get from Drupal ($result) has 2 "Objects" which contain a "String", and not arrays like I would expect.
For example:
$test = array('red', 'green', array('apple', 'banana'));
Difference between $result and $test:
Does this have any effect on how I should search for my string?
Because $result is an array of objects, you'll need to use a method to access the value and compare it. So, for instance you could do:
//1: create new array $results from array of objects in $result
foreach ($result as $r) {
$results[] = get_object_vars($r);
}
//2: expanded, recursive in_array function for use with multidimensional arrays
function in_array_r($needle, $haystack, $strict = false) {
foreach ($haystack as $item) {
if (($strict ? $item === $needle : $item == $needle) || (is_array($item) && in_array_r($needle, $item, $strict))) {
return true;
}
}
return false;
}
//3: check each element of the $invitees array
foreach ($invitees as $invitee) {
echo in_array_r($invitee, $results) ? "Yes" : "No";
}
Also, for some illumination, check out this answer.
You can search through the array using preg_grep, and use a wildcard for anything before and after it. If it returns a value (or values), use key to get the index of the first one. Then do a check if its greater than or equal to 0, which means it found a match :)
<?php
$array = array('test1#gdfgfdg.com', 'test2#dgdgfdg.com', 'test3#dfgfdgdfg');
$invitee = 'test2';
$result = key(preg_grep('/^.*'.$invitee.'.*/', $array));
if ($result >= 0) {
echo 'YES';
} else {
echo 'NO';
}
?>
Accepted larsAnders's answer since he pointed me in to direction of recursive functions.
This is what I ended up using (bases on his answer):
function Array_search($array, $string) {
foreach ($array as $key => $value) {
if (is_array($value)) {
Array_search($array[$key], $string);
} else {
if ($value->data == $string) {
return TRUE;
}
}
}
return FALSE;
}
I have this kind of simple array:
$puctures=array('1_noname.jpg','2_new.jpg','1_ok.jpg','3_lets.jpg','1_stack.jpg','1_predlog.jpg','3_loli.jpg');
I want to make new array that i will only have elements thats starts with 1_
Example
$new=array('1_noname.jpg','1_ok.jpg','1_stack.jpg','1_predlog.jpg');
Something like array_pop but how?
See array_filter():
$new = array_filter(
$puctures,
function($a) {return substr($a, 0, 2) == '1_'; }
);
A simple loop will do.
foreach ($pictures as $picture) {
if (substr($picture, 0, 2) == "1_") {
$new[] = $picture;
}
}
Use array_filter() to get your array:
$new = array_filter($puctures, function($item)
{
//here strpos() may be a better option:
return preg_match('/^1_/', $item);
});
This examples uses array_push() & strpos()
$FirstPictures = array();
foreach( $pictures as $pic => $value ) {
if ( strpos( $value, '1_' ) !== 0 ) {
array_push( $FirstPictures, $pic );
}
}
$puctures=array('1_noname.jpg','2_new.jpg','1_ok.jpg','3_lets.jpg','1_stack.jpg','1_predlog.jpg','3_loli.jpg');
$new=array();
foreach($puctures as $value)
{
if(strchr($value,'1'))
$new[]=$value;
}
echo "<pre>"; print_r($new);