Skipping blank rows with fopen(); - php

Question

I currently have some code like this:
$handle = fopen($_FILES['file']['tmp_name'], "r");
$i = 0;
while (($data = fgetcsv($handle, 1000, ",")) !== false) {
if($i > 0) {
$sql = "
insert into TABLE(A, B, C, D)
values ('$data[0]', '$data[1]', '$data[2]', '$data[3]')
";
$stmt = $dbh -> prepare($sql);
$stmt->execute();
}
$i++;
}
fclose($handle);
This allows me to write to a certain table the contents of a CSV file, excluding the first row where all the names are. I want to be able to extract only the filled rows. How would I use so using this code?

Answer 1

fgetcsv returns an array consisting of a single null if the rows are empty
http://www.php.net/manual/en/function.fgetcsv.php
so you should be able to do a check based on that.
if ($data[0]===null)
{
continue;
}
or something like that

Answer 2

fgetcsv() returns an array with null for blank lines so you can do something like below.
$handle = fopen($_FILES['file']['tmp_name'], "r");
$i = 0;
while (($data = fgetcsv($handle, 1000, ",")) !== false) {
if (array(null) === $data) { // ignore blank lines
continue;
}
if($i > 0) {
$sql = "
insert into TABLE(A, B, C, D)
values ('$data[0]', '$data[1]', '$data[2]', '$data[3]')
";
$stmt = $dbh -> prepare($sql);
$stmt->execute();
}
$i++;
}
fclose($handle);

Answer 3

Based on the documentation, fgetcsv will return an array consisting of a single null value for empty rows, so you should be able to test the return value against that and skip blank lines that way.
The following example code will skip processing blank lines. Note that I have changed the file and removed some other logic to make it more easily testable.
<?php
$handle = fopen("LocalInput.txt", "r");
$i = 0;
while (($data = fgetcsv($handle, 1000, ",")) !== false) {
if($data== array(null)) continue;
var_dump($data);
$i++;
}
fclose($handle);
?>