How can i add a £ symbol before echoing price [closed] - php

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I am trying to echo my price field but I need a £ symbol before it, I have tried adding it to this line of code but i keep getting errors, help please!
echo "<td>" . $row['price'] . "</td>";


Try this"
echo "<td>" . $row['price'] . "£</td>";
Or instead of £ with HTML output you can always write
£
like this:
echo "<td>£". $row['price'] . "</td>";


echo "<td> £" . $row['price'] . "</td>";
You could add as well to get a standard amount with a comma seperating thousands
"<td> £" . number_format( $row['price']) . "</td>";


echo "<td> £" . $row['price'] . "</td>";

Related

syntax error, unexpected 'preg_replace' (T_STRING) [closed]

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all I want to know what's the syntax error in this code.
echo "<p id='hide_text_$heading->id' >"preg_replace($rx, "<b>$0</b>", $heading->shortHeadline)"</p>";

Use . to concatenate strings. Change your code to
echo "<p id='hide_text_$heading->id' >" . preg_replace($rx, "<b>$0</b>", $heading->shortHeadline) . "</p>";
to concatenate the three parts or separate each statement:
echo "<p id='hide_text_$heading->id' >";
echo preg_replace($rx, "<b>$0</b>", $heading->shortHeadline);
echo "</p>";
More on String Operators

you forget concatination sympol => .
Also there is syntax error in $0 if you mean by that variable name.
variable name could not start with numbers
only _ and string characters as i remember.
echo "<p id='hide_text_".$heading->id."' >" . preg_replace($rx, "<b>.$0.</b>", $heading->shortHeadline) . "</p>";
You can read more about Concatenation

Paragraph does not work (var_dump) [closed]

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this is my first post and I am new to this community. I'm currently learning php, but facing an issue with paragraphs:
<?php
$name = "Erik Mustermann";
echo $name . "<br />";
echo strlen($name) . "<br />";
var_dump($name) . "<br />";
echo "Heyho" . "<br />";
var_dump($name) . "<br />";
?>
output:
Erik Mustermann
15
string(15) "Erik Mustermann" Heyho
string(15) "Erik Mustermann"
Why is the string "Heyho" in the same line like var_dump even I created a paragraph?

To be honest I'm surprised this code compiles.
With the code var_dump($name) . "<br />"; the second part . "<br />"; is not passed to var_dump and so it isn't output. What you want is:
var_dump($name . "<br />");
echo is not a function but a language construct which is why it doesn't required the braces.
As a side note, <br/> doesn't create a new paragraph, it creates a new line.

PHP Format Number With Dollar Sign And Comma And ROUND()

I have been using this syntax
print "<td>" . "$" . round($res->DollarValue) . "</td>";
Which will output something like this: $8812 I want the format to be $8,812 so I tried this
print "<td>" . "$" . round(number_format($res->AveragePrice)) . "</td>";
but that did not do the trick either.
What I am after is rounding with a dollar sign and comma, but no decimals.
Further Examples
1000.78 -> $1,001
1000.23 -> $1,000
What is the php synatx for this?

Concatenating strings having dot(period) in php [duplicate]

This question already has answers here:
How can I combine two strings together in PHP?
(19 answers)
Closed 7 years ago.
Googled but couldn't find an answer.
I have
echo "<input type = 'text' value = ".$value." name = ".$input_id."/>";
$value or $input_id contains a dot which is conflicting with the dot used for concatenation. How do I escape it?
Thanks!

If the variables contains eg. space, they has to be in quotes. Concat operators cause no problem.
echo "<input type='text' value='" . $value . "' name='" . $input_id . "'/>";

Use this
echo "<input type='text' value='" . $value . "' name='" . $input_id . "'/>";

PHP, While Loop a Table to show results from a database

I am having a problem trying to get a row to create everytime I enter a new database entry.
My code so far is:
<table align="center">
<th>MH/s</th><th>Contact Length</th><th>Date Bought</th><th>Payment</th>
<?php while ($row_cnt > 0) {
echo "<tr><td>" . $row['mhbought'] . "</td><td>" . $row['length'] . "</td><td>" . date(d-m-Y, $row['datebought'] . "</ td><td>" . $row['payment'] . "</td></tr>";
}
?>
</table>
The error I receive however states PHP Parse error: syntax error, unexpected ';' (which is the echo line) Am I doing something completely dumb here, can this even be done?
Thank you for any help you may provide.

Looking at the code, the problematic line is this:
date(d-m-Y, $row['datebought']
^^ missing quotes ^ missing closing parenthesis
Change it to:
date('d-m-Y', $row['datebought'])

You haven't close date() right bracket and there is quotation missing for date format. Your echo should look like:
echo "<tr><td>" . $row['mhbought'] . "</td><td>" . $row['length'] . "</td><td>" . date('d-m-Y', $row['datebought']) . "</td><td>" . $row['payment'] . "</td></tr>";

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