Submit form after form load is blank - php

I make index.php like this:
<script src="js/jquery-1.9.1.js"></script>
<script>
$(document).ready(function(){
$("#sload").load('save1.php',function(forma){
$(".csave").click(function(){
$.ajax({
type: 'POST',
url: $('#form1').attr('action'),
data: $('#form1').serialize(),
success: function(data) {
alert(data);
}
})
return false;
});
});
});
</script>
SAVE
<div id="sload"></div>
save1.php like this :
<table>
<form method="post" name="form1" id="form1" action="input1.php">
<tr>
<td>Date</td><td>:</td><td><input name="date" id="date"/></td>
</tr>
<tr>
<td>Location</td><td>:</td><td><input name="location" id="location" /></td>
</tr>
</form>
and input1.php
<? session_start();
include "db.php";
$date=$_POST['date'];
$location=$_POST['location'];
mysql_query("insert into hal (date,location) values ('$date','$location')");
?>
after I click SAVE not an error, but the database is stored in an empty field. Submit form after form load is blank
Thanks.

You need to separate the logic of loading and saving like this:
Here's an example (based on your code) as a single page script test.php:
<?php
// Load Form
if (isset($_GET['loadForm']))
{
exit('<form method="post" name="form1" id="form1" action="test.php">
<table>
<tr>
<td>Date</td><td>:</td><td><input name="date" id="date"/></td>
</tr>
<tr>
<td>Location</td><td>:</td><td><input name="location" id="location" /></td>
</tr>
</table>
</form>');
}
// Handle Form Save
if (count($_POST) > 0)
{
// TODO
exit('got form data: '. print_r($_POST, true));
}
?>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
<script type="text/javascript">
// When Page Loads
$(document).ready(function()
{
// Load Form
$('#sload').load('test.php?loadForm');
// Handle Save Click
$('.csave').click(function()
{
$.ajax({
type: 'POST',
url: $('#form1').attr('action'),
data: $('#form1').serialize(),
success: function(data) {
alert(data);
}
});
});
});
</script>
SAVE
<div id="sload"></div>
When I click save, this is what the output is:
To complete this code, add the db row inserting code where it says TODO. Hope this helps.
Update
Here's the split version:
index.php
<script type="text/javascript" src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
<script type="text/javascript">
// When Page Loads
$(document).ready(function()
{
// Load Form
$('#sload').load('save1.php');
// Handle Save Click
$('.csave').click(function()
{
$.ajax({
type: 'POST',
url: $('#form1').attr('action'),
data: $('#form1').serialize(),
success: function(data) {
alert(data);
}
});
});
});
</script>
SAVE
<div id="sload"></div>
save1.php
<form method="post" name="form1" id="form1" action="input1.php">
<table>
<tr>
<td>Date</td><td>:</td><td><input name="date" id="date"/></td>
</tr>
<tr>
<td>Location</td><td>:</td><td><input name="location" id="location" /></td>
</tr>
</table>
</form>
input1.php
<?php
session_start(); // what's this for? you aren't using session on this file
// this is not safe! use mysqli or pdo and escape post values!!!
include "db.php";
$date=$_POST['date'];
$location=$_POST['location'];
mysql_query("insert into hal (date,location) values ('$date','$location')");
?>

Related

Jquery and form with same name issue

Well i'm working on a small php script and in the admin panel i've added a page to manage comments. Following is the html markup for comment:
<form name="form" action="">
<tr>
<td>COMMENT ID</td><td><button value="0" name="choice">Delete</button><button value="1" name="choice">Accept</button></td>
</form>
For every comment i'm posting this info to a file comment.php using the following jquery code:
<script type="text/javascript">
$(document).ready(function(){
$("#form").submit(function(){
$.get("response.php", $(this).serialize(), function(a){
$("#info").html(a)
});
return false
})
});
</script>
My issue is i can't get the choice Value using this code $_REQUEST['choice'] because both <button>s have the same name and this is the same thing for forms. How can i fix this ?
The are some mistakes on your code:
1) You forgot to put the id attribute that your JS is calling
<form name="form" action="">
Change it to this:
<form name="form" action="" id="form">
Since it has the same name, use the .click() event instead.
Complete Code:
<form name="form" action="" id="form">
<table>
<tr>
<td>COMMENT ID</td>
<td>
<button value="0" name="choice">Delete</button>
<button value="1" name="choice">Accept</button>
<input type="hidden" name="id" value="100">
</td>
</tr>
</table>
</form>
<script type="text/javascript" src="jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("button[name='choice']").click(function(e){
var form_data = {};
form_data.choice = $(this).val();
form_data.id = $(this).siblings('input[name="id"]').val();
e.preventDefault(); // stops the normal submission
$.post("index.php", form_data, function(a){
console.log(a); // check the values on browser console
});
});
});
</script>
On your PHP:
if(isset($_POST['choice'])) {
$action = $_POST['choice'];
$data = $_POST;
// its inside $_POST['id'];
echo json_encode($data);
exit;
}
Sample Output
You can do this by binding the ajax request to the button.click() instead of form.submit()
$(function(){ // $(document).ready() shorthand
$("button[name=choice]").click(function(){
var data = 'choice='+ $(this).val() + '&' + $(this).closest('form').serialize();
$.get("response.php", data, function(a){
$("#info").html(a)
});
return false
})
});

how to insert value in database using php, jquery and ajax

I am struggling very hard to get this to work and I don't know what I'm doing wrong. I have a register page that I want to take the data inserted into the form and INSERT it to the database with jQuery and AJAX. I'm not very experienced with AJAX AND jQuery so be gentle! :P I will show you the files that I have...this is a msg.php page when i have submit data sometimes post submit in database`
mostly not so i want to know that why it s happening i am new in this field
<?
php $id=$_GET['id'];
$id1=$_SESSION['id'];
?>
<form method="post" class="msgfrm" id="msgfrm">
<input type="hidden" value="<?php echo $_GET['id']; ?>" name="rcvrid" id="rcvrid">
<input type="hidden" name="senderid" id="senderid" value="<?php echo $id1;?>" >
<div class="msgdiv" id="chatbox"></div>
<div class="textdiv">
<input type="text" name="msg" id="msg" class="textmsg">
<input type="submit" value="Send" onClick="sendChat()">
</div>
</form>
function sendChat()
{
$.ajax({
type: "POST",
url: "msg_save.php",
data: {
senderid:$('#senderid').val(),
rcvrid:$('#rcvrid').val(),
msg: $('#msg').val(),
},
dataType: "json",
success: function(data){
},
});
}
msg_save.php file
<?php
require_once('include/util.php');
$rcvrid=$_POST['rcvrid'];
$senderid=$_POST['senderid'];
$msg=$_POST['msg'];
$sql="insert into message(rcvrid,senderid,msg) values($rcvrid,$senderid,'$msg')";
mysql_query($sql);
?>
$.ajax({
type: "POST",
url: "msg_save.php",
data: " senderid="+$('#senderid').val()+"rcvrid="+$('#rcvrid').val()+"msg="+$('#msg').val(),
dataType: "json",
success: function(data){
},
});
please try this code and send data ,and use post method in php to get data,it will work
if you are trying chat application check this, it is old but just for idea:
http://www.codeproject.com/Articles/649771/Chat-Application-in-PHP
use mysqli_query instead of mysql_query recommended
<?php
$id=$_GET['id'];
//$id1=$_SESSION['id']; COMMENTED THIS AS I AM NOT IN SESSION. HARDCODED IT IN THE FORM AS VALUE 5
?>
<html>
<head>
<script src="//code.jquery.com/jquery-1.10.2.min.js"></script>
</head>
<body>
<form method="post" class="msgfrm" id="msgfrm">
<input type="hidden" value="<?php echo $_GET['id']; ?>" name="rcvrid" id="rcvrid">
<input type="hidden" name="senderid" id="senderid" value="5" >
<div class="msgdiv" id="chatbox"></div>
<div class="textdiv">
<input type="text" name="msg" id="msg" class="textmsg">
<input type="submit" value="Send" >
</div>
</form>
<script>
$("#msgfrm").on("submit", function(event) {
event.preventDefault();
$.ajax({
type: "POST",
url: "msg_save.php",
data: $(this).serialize(),
success: function(data) {
$("#chatbox").append(data+"<br/>");//instead this line here you can call some function to read database values and display
},
});
});
</script>
</body>
</html>
msg_save.php
<?php
//require_once('include/util.php');
$rcvrid = $_POST['rcvrid'];
$senderid = $_POST['senderid'];
$msg = $_POST['msg'];
echo $rcvrid.$senderid.$msg;
$con = mysqli_connect("localhost", "root", "", "dummy");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "insert into message(rcvrid,senderid,msg) values($rcvrid,$senderid,'$msg')";
mysqli_query($con,$sql);
mysqli_close($con);
echo "successful"
?>
check that whether you have inserted jquery file or not.
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
Then include your function sendChat() inside <script> tags.
On submit button
<button type="submit" id="button">SAVE</button>
<script>
$(document).ready(function(){
$("#button").click(function(){
var firstname=$("#firstname").val();
var lastname=$("#lastname").val();
var email=$("#email").val();
$.ajax({
url:'dbConfigAndInsertionQuery.php',
method:'POST',
data:{
firstname:firstname,
lastname:lastname,
email:email
},
success:function(data){
alert(data);
}
});
});
});
</script>

multiple select with checkbox in php

i am making a website in which i am to embbed the functionality of delete using multiple checkbox. here is my code. my problem is
1. Ajax call is not working.
2. how can i make search from database for array .
<?php
if(isset($_POST['Delete']))
{
$array=$_POST['check_box'];
}
?>
<form method="post" id="form">
<table width="200" border="1">
<tr>
<td>select</td>
<td>NAme</td>
<td>Action</td>
</tr>
<?php
while($selectnumberarr=mysql_fetch_array($selectnumber))
{
?>
<tr>
<td><input type="checkbox" name="check_box[]" class="check_box" id="<?php $selectnumberarr[0]; ?>" /> </td>
<td><?php echo $selectnumberarr[1]; ?></td>
</tr>
<?php
}?>
<input type="submit" name="Delete" id="delete">
</table>
</form>
and below is my ajax and javascript code.
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#delete').click(function() {
$.ajax({
type: "POST",
url: "checkbox.php",
data: $('#form').serialize(),
cache: false,
success: function(html)
{
alert("true");
}
});//end ajax
});
});
</script>
any help would be appriciated
your code is almost correct. You need to remove `onChange="show()" for input checkbox, because if you have jquery then you don't need to put events on HTML elements.
Use jquery 'on' method for compatibility for latest php library.
Replace your jquery code with following jquery code :-
<script>
$(document).ready(function(){
$('#delete').on('click',function()
{
var cat_id = $('.check_box:checked').map(function() {
return this.id;
}).get().join(',');
console.log(cat_id);
$.ajax({
type: "POST",
url: "checkbox.php",
data: { "kw ":cat_id },
datatype:'json',
success: function(html)
{
alert("true");
}
});//end ajax
});
});
</script>
Use ".check_box" instead of "element" in jquery to prevent checks for all checkboxes, instead of desired ones.
Hope it helps.
Why you don't use an array for sending the checkboxes like:
HTML part:
<?php
if (isset($_POST['check_box'])) {
var_dump($_POST['check_box']);
echo "ajax call is working";
}
?>
<form id="form">
<table width="200" border="1">
<tr>
<td>select</td>
<td>NAme</td>
<td>Action</td>
</tr>
<?php
while ($selectnumberarr = mysql_fetch_array($selectnumber)) {
?>
<tr>
<td><input type="checkbox" name="check_box[]" class="check_box" value="<?php echo $selectnumberarr[0]; ?>" /> </td>
<td><?php echo $selectnumberarr[1]; ?></td>
</tr>
<?php
}
?>
</table>
<input type="button"name="delete" id="delete" value="Delete" />
</form>
JQuery part:
<script type="text/javascript">
$(document).ready(function(){
$('#delete').click(function() {
$.ajax({
type: "POST",
url: "checkbox.php",
data: $('#form').serialize(),
cache: false,
success: function(html)
{
alert("true");
}
});//end ajax
});
});
</script>
So you can easily get an array of the selected checkboxes in php with:
$idsArray = $_POST["check_box"];
this looks now like:
array(
"1", "2","etc.."
);
so this array contains all the ids of the selected checkboxes for delete.

jquery post form

I have this code for send simple data using jquery , but no works , all time reload de page and no load contents i send by post
My code it´s this :
<script>
$(document).ready(function() {
$("#form_order").submit( function () {
$.ajax({
type: "POST",
data : $(this).serialize(),
cache: false,
url: "indexer_adm.php?send_order2=ok",
success: function(data){
$("#load_order").html(data);
}
});
return false;
});
</script>
<form name="forma" id="form_order" method="post" action="">
<table width="100%" border="1">
<tr>
<td height="30" align="center" valign="middle">
<select name="select_order">
<option value="articles">Articles</option>
<option value="blogs">Blogs</option>
<option value="products">Products</option>
</select>
<input type="submit" name="Submit" value="Acceder">
<input type="hidden" name="send_order2" value="ok">
<input type="hidden" name="action_load" value="<?php echo $_REQUEST['action_load'];?>">
</td>
</tr>
<tr>
<td height="30" align="center" valign="middle"> </td>
</tr>
</table>
</form>
<div id="load_order"></div>
In the div called load_order , it must load the result of this send by post from the form , but the page reload and no works , i see the code many times but i don´t understand what happen
Thank´s for All
There is a syntax error in your code, you haven't closed the submit handler.
$(document).ready(function() {
$("#form_order").submit( function () {
$.ajax({
type: "POST",
data : $(this).serialize(),
cache: false,
url: "indexer_adm.php?send_order2=ok",
success: function(data){
$("#load_order").html(data);
}
});
return false;
}); // <---
});
Try returning false inside of the submit block, rather than of the ready block.
You may have a syntax error since return false should stop the form from refreshing. I would use the post function instead:
<script>
$(function() {
$("#form_order").submit( function () {
$.post('indexer_adm.php?send_order2=ok', $(this).serialize(), function(data) {
$("#load_order").html(data);
});
return false;
});
</script>
Ok !!! , Thank´s everybody
The Right code :
<script>
$(document).ready(function() {
/*
$("#load_order").show(1000);
$("#load_order").load("<?php print "".$ruta_path_adm."".$ruta_modulos."/mod_order/indexer_adm.php?send_order2=ok";?>");
*/
$("#form_order").submit( function () {
$.ajax({
type: "POST",
data : $(this).serialize(),
cache: false,
url: "<?php print "".$ruta_path_adm."".$ruta_modulos."/mod_order/indexer_adm.php?send_order2=ok";?>",
success: function(data){
$("#load_order").html(data);
}
});
return false;
});
});
</script>
Thank´s for the help i put bad the script and no see this , thank´s

Please help me out with suggestion list

<html>
<head>
<script src="jquery.min.js" type="text/javascript"></script>
<script type="text/javascript">
function getsuggestion()
{
var seltxt=$('#selstate').val();
//alert(seltxt);
$.ajax({
type: "POST",
url: "getstate.php",
data:{state: seltxt },
dataType: 'json',
success: function(data){
//alert(data['test']);
if(data['test']==0)
{
$("#suggestion").text("");
alert("No suggestion");
}
$.each(data,function(key,value)
{
//alert(key);
if(key!="test")
{
str=str+value+",";
$("#suggestion").text(str);
}
});
},
error: function(error,txtStatus) { alert(txtStatus);}
});
}
</script>
</head>
<body>
<form name=f1 method=post>
<table>
<tr>
<td>Select State:</td>
<td><input type=text id=selstate onkeyup="getsuggestion();">
</td>
</tr>
<tr> <td></td>
<td><div id="suggestion"></div>
</td>
</tr>
</table>
</form>
</body>
</head>
</html>
Hi,I want to make a suggestion list.For that I've used text box for getting input from the user.But now I want the values, stored in database,to be retrieved in the form of list.Here I am getting values in text the format.How do I conver text box into list?Or what should I do to append list to the text box?
You can use autocomplete feature of jQuery UI.You can download from http://jqueryui.com/download
You should use something like jQuery UI-Autocomplete: http://jqueryui.com/demos/autocomplete/
It provides all the stuff needed to do as you ask and also the demos required for you to learn how to do it yourself.

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