Query:
SELECT l.id, l.userid, l.checktime, l.SN, u.name, u.badgenumber
FROM kio_checkinout l
LEFT JOIN userinfo u ON l.userid = u.userid
GROUP BY l.userid DESC
i need show the data first order by id descending and then group by userid (latest user id) value.
i am trying this sql query but i can not get the data as i need to show.
Use ORDER BY clause:
SELECT l.id, l.userid, l.checktime, l.SN, u.name, u.badgenumber
FROM kio_checkinout l
LEFT JOIN userinfo u ON l.userid = u.userid
GROUP BY l.userid
ORDER BY l.id DESC
Try something like this
SELECT l.userid, GROUP_CONCAT(l.checktime,'-',l.checktype), u.name, u.badgenumber
FROM kio_checkinout l
LEFT JOIN userinfo u ON l.userid = u.userid
GROUP BY l.userid
ORDER BY l.id DESC
Related
Here is my SQL query which joins 4 tables and it works correctly.
SELECT pl.lms_id, u.id, REPLACE(trim(u.`url`), 'www.', '') AS url, trim(u.`name`) as name, p.date_removed, p.status, p.ignore_status FROM `adl_seo_status` p INNER JOIN `adl_user_profiles` u on p.profile_id = u.id INNER JOIN adl_tw_profile_acc_type ac on p.profile_id = ac.profile_id LEFT JOIN `adl_lms_prof_list` pl on u.id = pl.profile_id WHERE u.`vpg_id`='2' AND u.`status` = 'Y' and ac.acc_type_id = '2' ORDER BY u.`url` ASC, p.id DESC
I am facing an issue that, the table adl_seo_status has multiple entries for a single profile_id. So, that accounts are repeating in my listing. I want that account as a single row which means the distinct value of accounts based on profile_id.
You need to use group by, for example:
SELECT
pl.lms_id,
u.id,
REPLACE(trim(u.`url`), 'www.', '') AS url,
trim(u.`name`) AS name,
p.date_removed,
p.status,
p.ignore_status
FROM `adl_seo_status` p INNER JOIN `adl_user_profiles` u ON p.profile_id = u.id
INNER JOIN adl_tw_profile_acc_type ac ON p.profile_id = ac.profile_id
LEFT JOIN `adl_lms_prof_list` pl ON u.id = pl.profile_id
WHERE u.`vpg_id` = '2' AND u.`status` = 'Y' AND ac.acc_type_id = '2'
ORDER BY u.`url` ASC, p.id DESC GROUP BY p.profile_id;
Okay, so I have a query below I am trying to get to work.
Basically everything works up until the inner join of the 'votes' table. What I am trying to do is order the results of this query in accordance with the number of votes each content row has in another table called votes. I know I'm not too far off from what I need to do!
Thanks in advance!!
mysql_query("
SELECT content.id, content.type, content.title, content.url, users.username
FROM content
INNER JOIN users ON content.uploaderuid = users.id
INNER JOIN votes ON votes.id = content.id
WHERE (content.type = 'pic')
ORDER BY COUNT(votes.id) DESC");
Try doing:
SELECT content.id, content.type, content.title, content.url, users.username
FROM content
INNER JOIN users ON content.uploaderuid = users.id
INNER JOIN (
SELECT id,COUNT(*) as voteCount
FROM votes
GROUP BY id
) v ON v.id = content.id
WHERE (content.type = 'pic')
ORDER BY v.voteCount DESC
When you do an INNER JOIN with votes table directly, if you have multiple occurrences of the same id, you will get a lot more rows than before you did the JOIN.
If you are only interested in the number of votes for each id, by doing a JOIN with a subquery that calculates the count of votes for each id, will leave your previous query results as they were, and lets you use the voteCount to order by it.
You could try this:
SELECT c.id, c.type, c.title, c.url, u.username, COUNT(v.id) votes
FROM content c
INNER JOIN users u ON c.uploaderuid = u.id
INNER JOIN votes v ON v.id = c.id
WHERE c.type = 'pic'
GROUP BY c.id, c.type, c.title, c.url, u.username
ORDER BY votes DESC
Here is the SQL Fiddle that demonstrates the below query:
SELECT c.id, c.type, c.title, c.url, u.username, COUNT(v.id)
FROM content AS c
INNER JOIN users AS u ON c.uploaderuid = u.id
INNER JOIN votes AS v ON v.id = c.id
WHERE c.type = 'pic'
GROUP BY c.id, c.type, c.title, c.url, u.username
ORDER BY COUNT(v.id) DESC
Hello I added GROUP_CONCAT function to my query and that function killed my query :/.
My query is :
SELECT u.username,a.user_id,a.id,a.text,a.lang as fromLang,b.lang as toLang,GROUP_CONCAT(DISTINCT b.id) AS translation_ids FROM sentence as a
INNER JOIN sentence_relationship as sr ON
(sr.sentence_id = a.id)
INNER JOIN sentence as b ON
(b.id = sr.translation_id AND a.id = sr.sentence_id)
INNER JOIN users as u ON
(u.id = a.user_id) GROUP BY a.id LIMIT 10;
What is wrong with that query ?
This is your query (somewhat formatted):
SELECT u.username, a.user_id, a.id,a.text,a.lang as fromLang, b.lang as toLang,
GROUP_CONCAT(DISTINCT b.id) AS translation_ids
FROM sentence a INNER JOIN
sentence_relationship sr
ON sr.sentence_id = a.id INNER JOIN
sentence b
ON b.id = sr.translation_id AND a.id = sr.sentence_id INNER JOIN
users as u
ON u.id = a.user_id
GROUP BY a.id
LIMIT 10;
It is unclear from your question whether the group_concat() was added with the group by. That could slow things down.
The limit 10 is taking the first 10 a.ids that match (the group by does an implicit ordering). If you do this with a subquery, it will probably speed up the query:
SELECT u.username, a.user_id, a.id,a.text,a.lang as fromLang, b.lang as toLang,
GROUP_CONCAT(DISTINCT b.id) AS translation_ids
FROM (select s.*
from sentence s
order by a.id
limit 10
) a INNER JOIN
sentence_relationship sr
ON sr.sentence_id = a.id INNER JOIN
sentence b
ON b.id = sr.translation_id AND a.id = sr.sentence_id INNER JOIN
users as u
ON u.id = a.user_id
GROUP BY a.id;
This assumes that all the joins do work and match records. If the joins are used for filtering, then you may get fewer than 10 rows back.
// Edit:
All work fine with:
SELECT u.*,
l.cod AS loans_cod,
l.step AS loans_step
FROM users AS u
LEFT JOIN loans AS l
ON u.id = l.users_id
WHERE l.step < 12
OR NOT EXISTS
(SELECT l.id
FROM loans
WHERE l.users_id = u.id
)
GROUP BY u.id
Now, I can select all user, and his last loan. Thanks, and I think my solution will help future users.
if you want the last loan, you could append something like this
ORDER BY l.date DESC GROUP BY u.id
SELECT u.*,
l.cod AS loans_cod,
l.step AS loans_step
FROM users AS u
LEFT JOIN loans AS l
ON u.id = l.users_id
WHERE u.id != :id
AND l.timestamp = (SELECT MAX(l.timestamp)
FROM loans AS l2
WHERE l2.users_id = l.users_id)
Where timestamp is a column on your table that indicates when the loan was created or otherwise gives you a time that you can compare to.
Try this:
SELECT u.*, l.cod AS loans_cod,
l.step AS loans_step
FROM users AS u inner join
(
select max(l.loan_id) as loan_id, l.users_id , l.cod, l.step
from loans l
group by
l.users_id,l.cod,l.step
) as l
ON u.id = l.users_id
WHERE u.id != :id
Note: Avoid doing select * it's a very bad practice. List all the columns you need only.
Hello can anybody see why this query fails?
SELECT A.idAd, A.ads_in_Cat, A.title, A.currency, A.price,
A.in_dpt, A.description, A.featured FROM ads A
LEFT JOIN featured F ON F.ad = A.idAd
INNER JOIN dept D ON D.id_dept = A.in_dpt
INNER JOIN sub_cat_ad S ON S.id_sub_cat = A.ads_in_Cat
INNER JOIN cat_ad C ON C.idCat_ad = S.from_cat_ad
ORDER BY A.featured DESC LIMIT :limit, :offset
But this one works:
SELECT *FROM ads
LEFT JOIN featured ON featured.ad = ads.idAd
INNER JOIN dept ON dept.id_dept = ads.in_dpt
INNER JOIN sub_cat_ad ON id_sub_cat = ads.ads_in_Cat
INNER JOIN cat_ad ON idCat_ad = sub_cat_ad.from_cat_ad
ORDER BY featured DESC LIMIT :limit, :offset
In the first one, I don't want all columns from the table "ads", the query returns only columns till ...FROM ads A.
If you specify to only select fields from A that's what you get: Only fields from A.
If you want fields from other tables too you have to specify them as well.
SELECT
A.idAd, A.ads_in_Cat, A.title, A.currency, A.price, A.in_dpt, A.description, A.featured,
F.*,
D.*,
S.*,
C.*
FROM ads A
LEFT JOIN featured F ON F.ad = A.idAd
INNER JOIN dept D ON D.id_dept = A.in_dpt
INNER JOIN sub_cat_ad S ON S.id_sub_cat = A.ads_in_Cat
INNER JOIN cat_ad C ON C.idCat_ad = S.from_cat_ad
ORDER BY A.featured DESC LIMIT :limit, :offset