Below is my code:
<?php
$text_res = array(
'eng' => array('chapter' => 'Chapter'),
'rus' => array('chapter' => 'Глава')
);
echo $text_res['eng']['chapter'];
?>
why is it printing empty string?
This particular code works. The question was asked not quite correctly. See the comments
Related
I have a problem with the array PHP function, below is my first sample code:
$country = array(
"Holland" => "David",
"England" => "Holly"
);
print_r ($country);
This is the result Array ( [Holland] => David [England] => Holly )
I want to ask, is possible to make the array data become variables? For second example like below the sample code, I want to store the data in the variable $data the put inside the array.:
$data = '"Holland" => "David","England" => "Holly"';
$country = array($data);
print_r ($country);
But this result is shown me like this: Array ( [0] => "Holland" => "David","England" => "Holly" )
May I know these two conditions why the results are not the same? Actually, I want the two conditions can get the same results, which is Array ( [Holland] => David [England] => Holly ).
Hope someone can guide me on how to solve this problem. Thanks.
You can use the following Code.
<?php
$country = array(
"Holland" => "David",
"England" => "Holly"
);
foreach ($country as $index => $value)
{
$$index = $value;
}
?>
Now, Holland & England are two variables. You can use them using $Holland etc.
A syntax such as $$variable is called Variable Variable. Actually The inner $ resolves the a variable to a string, and the outer one resolves a variable by that string.
So there is this thing called
Destructuring
You can do it something like ["Holland" => $eolland, "England" => $england] = $country;
And now you have your array elements inside the variables.
Go read the article above if you want more information about this because it gets really useful (especially in unit tests usind data provders from my experience).
If you want to extract elements from an associative array such that the keys become variable names and values become the value of that variable you can use extract
extract($country);
To check what changed you can do
print_r(get_defined_vars());
Explanation on why the below does not work
$data = '"Holland" => "David","England" => "Holly"';
When you enclose the above in single quotes ' php would recognise it as a string. And php will parse a string as a string and not as an array.
Do note it is not enough to create a string with the same syntax as the code and expect php to parse it as code. The codes will work if you do this
$data = ["Holland" => "David","England" => "Holly"];
However, now $data itself is an array.
A simple copy of an array can be made by using
$data = $country;
I have an array which I create. When reading the array with print_r it is not returning with the correct data inputted! I am missing specific sectionsn such as < & > brackets with its headings.
How can i preserve these?
Code:
$params = array(
"Parm1" => "test",
"Parm2" => "hi",
"Parm3" => GUID(),
"Parm4" => "lol",
"Parm5" => "
<R>
<R1>the</R1>
<R2>dog</R2>
<R3>is</R3>
<R15>happy</R15>
<R20>today</R20>
</R>
");
Basically the only data that is jumbled up is the Parm5 section. I want everything inside to return exactly as it is! EG: Reading as is i only receive Array ( [Parm1] => test [Parm2] => hi [Parm3] => B18BE727-8F79-4D4A-80EA-3974B1429F78 [Parm4] => lol [Parm5] => the dog is happy today ) from print_r
I want to return:
Array ( [Parm1] => test [Parm2] => hi [Parm3] => B18BE727-8F79-4D4A-80EA-3974B1429F78 [Parm4] => lol [Parm5] => <R><R1>the</R1> <R2>dog</R2> <R3>is</R3> <R15>happy</R15> <R20>today</R20></R> )
escape param5 with htmlspecialchars('<R> ..... </R>'). Your browser currently sees it as html tags and parses it.
Use htmlspecialchars on the return value of print_r:
echo "<pre>";
echo htmlspecialchars(print_r($params, true));
echo "</pre>";
This question already has answers here:
How can I access an array/object?
(6 answers)
Closed 4 months ago.
I'm not understanding why the array:
<? $data = array( 'items[0][type]' => 'screenprint'); ?>
Is not the same as
<? echo $data['items'][0]['type']; ?>
I'm trying to add to the array but can't seem to figure out how?
array( 'items[0][type]' => 'screenprint')
This is an array which has one key which is named "items[0][type]" which has one value. That's not the same as an array which has a key items which has a key 0 which has a key type. PHP doesn't care that the key kinda looks like PHP syntax, it's just one string. What you want is:
$data = array('items' => array(0 => array('type' => 'screenprint')));
I hope it's obvious that that's a very different data structure.
It should be:
$data = [
'items' => [['type' => 'screenprint']]
];
echo $data['items'][0]['type'];
I'm currently reading through some code in a drupal module and have come across the following in an associative array.
$this->replacements = array(
'%field' => $this->instance['label'],
'%bundle' => $bundles[$this->instance['entity_type']][$this->instance['bundle']]['label'],
);
What does the % in the key mean or is it just a string label
I think its just sting label.
$a = array("%name" => "pugazh", "vaalue" => "value");
print_r($a);
If you try like this in corephp it will return an output like this
Array ( [%name] => pugazh [vaalue] => value )
But i don't know what its mean in drupal.
i'm trying to insert an implode generated string to an array that then later be used for json implementation
the implode generated string is look like this
'id' => $this->_SqlResult[0],'UserId' => $this->_SqlResult[1],'Msg' => $this->_SqlResult[2],'MsgStamp' => $this->_SqlResult[3]
i would like to used it in this code
$this->_JsonArr[]=array($Generated string);
to achieve something like this
$this->_JsonArr[]=array('id' => $this->_SqlResult[0],'UserId' => $this->_SqlResult[1],'Msg' => $this->_SqlResult[2],'MsgStamp' => $this->_SqlResult[3]);
instead i got something like this
$this->_JsonArr[]=array(" 'id' => $this->_SqlResult[0],'UserId' => $this->_SqlResult[1],'Msg' => $this->_SqlResult[2],'MsgStamp' => $this->_SqlResult[3]");
seem like generated string is treated as one element as key and value pair.
obviously i can get expected output from mysql because of this, can anybody help me with this
Why do you need to implode anything? Just pass the array:
$this->_JsonArr[] = your-non-imploded-array-here;
I think a full solution to what you want to do is something like this (i.e., the third code box in your question):
$row = array(
'id' => $this->_SqlResult[0],
'UserId' => $this->_SqlResult[1],
'Msg' => $this->_SqlResult[2],
'MsgStamp' => $this->_SqlResult[3]
);
$this->_JsonArr[] = $row;
$this->_JsonArr[]=array($Generated
string);
Looks like you want use arrays keys and values, but as I see you put into array plain string with expectation that array parse your plain string in format: keys => values.
You can try create array like below:
$this->_JsonArr[ $Generated_key ] = array( $Generated_value );
(Please correct me if I wrong understand your question).