Put status on item - php

Question

I would like to put status on item. When the quantity is 0 it should come out Sold Out else Available. But I'm getting a parse error on line 16. Why is that?
<?php
// Connect to the MySQL database
include "storescripts/connect_to_mysql.php";
$dynamicList = "";
$status = "";
$sql = mysql_query("SELECT * FROM products ORDER BY date_added");
$productCount = mysql_num_rows($sql); // count the output amount
if ($productCount > 0) {
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
$product_name = $row["product_name"];
$price = $row["price"];
$quantity = $row["quantity"];
$date_added = strftime("%b %d, %Y", strtotime($row["date_added"]));
$status = if($quantity == 0) echo "Sold Out";
else echo "Available";
$dynamicList .= '<table width="100%" border="0" cellspacing="1" cellpadding="6">
<tr>
<td width="17%" valign="top"><img style="border:#666 0px solid;" src="inventory_images/' . $id . '.jpg" alt="' . $product_name . '" width="77" height="102" border="1" /></td>
<td width="83%" valign="top">
' . $product_name . '<br />
$' . $price . '<br />
Quantity =' .$quantity . '
<br /> Status = ' . $status . ' <br />
</td>
</tr>
</table>';
}
} else {
$dynamicList = "We have no products listed in our store yet";
}
mysql_close();
?>

Answer 1

You have syntax errors in your code : you can't assign value to the if statement while echoing something in it.Try the following :
$status = $quantity == 0 ? "Sold Out" : "Available";
echo $status;

Answer 2

This is completely wrong syntax-wise:
$status = if($quantity == 0) echo "Sold Out";
else echo "Available";
Try this instead:
if ($quantity == 0)
$status = "Sold Out";
else
$status = "Available";
echo $status;